I have multiple dataframes and would like to remove the first row in all of them.
I have tried using a for loop but cannot understand what I am doing wrong
for (i in cities){
i <- i[-1, ]
}
I get the following error code:
Error in i[-1, ] : incorrect number of dimensions
If we assume that the only objects in your workspace are dataframes then this might succeed:
cities <- objects() )
for (i in cities) { assign(i, get(i)[-1,])}
Explanation:
Two thing wrong with original codes:
One was already mentioned in comments. "df" is not the same as df. You need to use get to convert a character value to a "true" R name that is used to retrieve an object having that name. The result of object() is only a character value. In R the term "name" means a "language object". See the help page: ?mode. (There is potential confusion about rownames and columnnames which are always "character"-class.) It's not like SAS which is a macro language that has no such distinction.
The second error was trying to get substitution for the i on the left-hand side of <-. The would have failed even if you were working with actual R names. The assign function is designed to handle character values that are then converted to R names.
say you get a list of all the tables in your environment, and you call that list cities. You can't just iterate over each value of cities and change things, because in the list they are just characters.
Here is what you need:
for (i in cities){
tmp <- get(i) # load the actual table
tmp <- tmp[-1, ] # remove first column
assign(i, tmp) # re-assign table to original table name
}
Related
I'm having issues with a specific problem I have a dataset of a ton of matrices that all have V1 as their column names, essentially NULL. I'm trying to write a loop to replace all of these with column names from a list but I'm running into some issues.
To break this down to the most simple form, this code isn't functioning as I'd expect it to.
nameofmatrix <- paste('column_', i, sep = "")
colnames(eval(as.name(nameofmatrix))) <- c("test")
I would expect this to take the value of column_1 for example, and replace (in the 2nd line) with "test" as the column name.
I tried to break this down smaller, for example, if I run print(eval(as.name(nameofmatrix)) I get the object's column/rows printed as expected and if I run print(colnames(eval(as.name(nameofmatrix))) I'm getting NULL as expected for the column header (since it was set as V1).
I've even tried to manually type in the column name, such as colnames(column_1) <- c("test) and this successfully works to rename the column. But once this variable is put in the text's place as shown above, it does not work the same. I'm having difficulties finding a solution on how to rename several matrix columns after they have been created with this method. Does anyone have any advice or suggestions?
Note, the error I'm receiving on trying to run this is
Error in eval([as.name](nameofmatrix)) <- \`vtmp\` : could not find function "eval<-"
We could return the values of the objects in a list with get (if there are multiple objects use mget, then rename the objects in the list and update those objects in the global env with list2env
list2env(lapply(mget(nameofmatrix), function(x) {colnames(x) <- newnames
x}), .GlobalEnv)
It can also be done with assign
data(mtcars)
nameofobject <- 'mtcars'
assign(nameofobject, `colnames<-`(get(nameofobject),
c('mpg1', names(mtcars)[-1])))
Now, check the names of 'mtcars'
names(mtcars)[1]
#[1] "mpg1"
I am learning R, and I am trying to understand the indexing properties. I cannot seem to understand why the following code to change a column name does not work:
state.all <- as.data.frame(state.x77)
head(state.all)
state.all$States <- rownames(state.all)
rownames(state.all) <- NULL
# why the following row does not work?
names(state.all["States"]) <- "Test"
colnames(state.all)
While this works:
state.all <- as.data.frame(state.x77)
head(state.all)
state.all$States <- rownames(state.all)
rownames(state.all) <- NULL
# This work
names(state.all)[which(colnames(state.all)=="States")] <- "Test"
colnames(state.all)
Shouldn't the function be able to overwrite the name of the column also in the first example? Is it something to do with the local vs. global environment?
Thanks in advance!
What you're trying to do is replacing the name of column number 9.
the expression which(colnames(state.all)=="States") results in the index if the column named "States" (if there is any) and then takes this index and replaces the value in the names vector.
the expression state.all["States"] just returns the values of this column so of course nothing will happen.
I suggest something like colnames(state.all)[which(colnames(state.all)=="States")] <- "Test".
setwd("C:\\Users\\DATA")
temp = list.files(pattern="*.dta")
for (i in 1:length(temp)) assign(temp[i], read.dta13(temp[i], nonint.factors = TRUE))
grep(pattern="_m", temp, value=TRUE)
Here I create a list of my datasets and read them into R, I then attempt to use grep in order to find all variable names with pattern _m, obviously this doesn't work because this simply returns all filenames with pattern _m. So essentially what I want, is my code to loop through the list of databases, find variables ending with _m, and return a list of databases that contain these variables.
Now I'm quite unsure how to do this, I'm quite new to coding and R.
Apart from needing to know in which databases these variables are, I also need to be able to make changes (reshape them) to these variables.
First, assign will not work as you think, because it expects a string (or character, as they are called in R). It will use the first element as the variable (see here for more info).
What you can do depends on the structure of your data. read.dta13 will load each file as a data.frame.
If you look for column names, you can do something like that:
myList <- character()
for (i in 1:length(temp)) {
# save the content of your file in a data frame
df <- read.dta13(temp[i], nonint.factors = TRUE))
# identify the names of the columns matching your pattern
varMatch <- grep(pattern="_m", colnames(df), value=TRUE)
# check if at least one of the columns match the pattern
if (length(varMatch)) {
myList <- c(myList, temp[i]) # save the name if match
}
}
If you look for the content of a column, you can have a look at the dplyr package, which is very useful when it comes to data frames manipulation.
A good introduction to dplyr is available in the package vignette here.
Note that in R, appending to a vector can become very slow (see this SO question for more details).
Here is one way to figure out which files have variables with names ending in "_m":
# setup
setwd("C:\\Users\\DATA")
temp = list.files(pattern="*.dta")
# logical vector to be filled in
inFileVec <- logical(length(temp))
# loop through each file
for (i in 1:length(temp)) {
# read file
fileTemp <- read.dta13(temp[i], nonint.factors = TRUE)
# fill in vector with TRUE if any variable ends in "_m"
inFileVec[i] <- any(grepl("_m$", names(fileTemp)))
}
In the final line, names returns the variable names, grepl returns a logical vector for whether each variable name matches the pattern, and any returns a logical vector of length 1 indicating whether or not at least one TRUE was returned from grepl.
# print out these file names
temp[inFileVec]
I have written a loop in R. The code is expected to go through a list of variables defined in a list and then for each of the variables perform a function.
Problem 1 - I cannot loop through the list of variables
Problem 2 - I need to insert each output from the values into Mongo DB
Here is an example of the list:
121715771201463_626656620831011
121715771201463_1149346125105084
Based on this value - I am running a code and i want this output to be inserted into MongoDB. Right now only the first value and its corresponding output is inserted
test_list <-
C("121715771201463_626656620831011","121715771201463_1149346125105084","121715771201463_1149346125105999")
for (i in test_list)
{ //myfunction//
mongo.insert(mongo, DBNS, i)
}
I am able to only pick the values for the first value and not all from the list
Any help is appreciated.
Try this example, which prints the final characters
myfunction <- function(x){ print( substr(x, 27, nchar(x)) ) }
test_list <- c("121715771201463_626656620831011",
"121715771201463_1149346125105084",
"121715771201463_1149346125105999")
for (i in test_list){ myfunction(i) }
for (j in 1:length(test_list)){ myfunction(test_list[j]) }
The final two lines should each produce
[1] "31011"
[1] "105084"
[1] "105999"
It is not clear whether "variable" is the same as "value" here.
If what you mean by variable is actually an element in the list you construct, then I think Ilyas comment above may solve the issue.
If "variable" is instead an object in the workspace, and elements in the list are the names of the objects you want to process, then you need to make sure that you use get. Like this:
for(i in ls()){
cat(paste(mode(get(i)),"\n") )
}
ls() returns a list of names of objects. The loop above goes through them all, uses get on them to get the proper object. From there, you can do the processing you want to do (in the example above, I just printed the mode of the object).
Hope this helps somehow.
Sometimes I have code which references a specific dataset based on some variable ID. I have then been creating lines of code using paste0, and then eval(parse(...)) that line to execute the code. This seems to be getting sloppy as the length of the code increases. Are there any cleaner ways to have dynamic data reference?
Example:
dataset <- "dataRef"
execute <- paste0("data.frame(", dataset, "$column1, ", dataset, "$column2)")
eval(parse(execute))
But now imagine a scenario where dataRef would be called for 1000 lines of code, and sometimes needs to be changed to dataRef2 or dataRefX.
Combining the comments of Jack Maney and G.Grothendieck:
It is better to store your data frames that you want to access by a variable in a list. The list can be created from a vector of names using get:
mynames <- c('dataRef','dataRef2','dataRefX')
# or mynames <- paste0( 'dataRef', 1:10 )
mydfs <- lapply( mynames, get )
Then your example becomes:
dataset <- 'dataRef'
mydfs[[dataset]][,c('column1','column2')]
Or you can process them all at once using lapply, sapply, or a loop:
mydfs2 <- lapply( mydfs, function(x) x[,c('column1','column2')] )
#G.Grothendieck has shown you how to use get and [ to elevate a character value and return the value of a named object and then reference named elements within that object. I don't know what your code was intended to accomplish since the result of executing htat code would be to deliver values to the console, but they would not have been assigned to a name and would have been garbage collected. If you wanted to use three character values: objname, colname1 and colname2 and those columns equal to an object named after a fourth character value.
newname <- "newdf"
assign( newname, get(dataset)[ c(colname1, colname2) ]
The lesson to learn is assign and get are capable of taking character character values and and accessing or creating named objects which can be either data objects or functions. Carl_Witthoft mentions do.call which can construct function calls from character values.
do.call("data.frame", setNames(list( dfrm$x, dfrm$y), c('x2','y2') )
do.call("mean", dfrm[1])
# second argument must be a list of arguments to `mean`