Standard ML : Check conditions when iterating a list - functional-programming

i'm studying the programming language Standard ML and i am wondering how i can iterate a list with a check condition.
In other languages we have for loops like :
var input;
for(var i = 0; i < arr.length; i++) {
if(arr[i] == input) {
//you have arrived at your condition...
} else {
//other case
}
}
f.ex
i want to iterate through a list and check if the input variable matches a existing element in the list.
i = 5
xs = [1,5,2,3,6] --> the element matches after one iteration.
fun check i nil = []
| check i (x::xs) = if i=x
then //dowork
else //iterate;
I've gone through many documentations on how to implement this without success.
It would be really helpful if someone could give me some explaining regarding how i can use let val A in B end; inside or outside of if conditions for this kind of work.

how i can iterate a list with a check condition
fun check i nil = []
| check i (x::xs) = if i=x
then //dowork
else //iterate;
i want to iterate through a list and check if the input variable matches a existing element in the list.
I would call this a predicate combinator. It already exists in the standard library and is called List.exists. But you can also make it yourself:
fun exists p [] = false
| exists p (x::xs) = p x orelse exists p xs
This is a simplification of the if-then-else you're attempting, which would look like:
fun exists p [] = false
| exists p (x::xs) = if p x then true else exists p xs
If-then-else isn't really necessary when the result type is a boolean, since orelse, andalso and not are short-circuiting (will not evaluate their second operand if the result can be determined with the first).
Using this List.exists function to check if a list contains a specific element, you have to construct a p that compares the list element with some given value, e.g.:
fun check y xs = List.exists (fn x => ...) xs
This may seem a bit more complicated than simply writing check recursively from scratch,
fun check y [] = false
| check y (x::xs) = ... orelse check y xs
but a solution using higher-order functions is preferred for several reasons.
One is that a seasoned reader will quickly detect what you're doing when seeing List.exists: Ah, you're scanning a list for an element given a predicate. Whereas if your function is explicitly recursive, the reader will have to read the entire recursion scheme: OK, the function doesn't do anything funky, which I'd have known if I'd seen e.g. List.exists.

Related

Handle recursive function within an other function ocaml

If I have one or more recursive functions inside an Ocaml function how can I call them without exit from the main function taking their value as return of the main function?
I'm new in Ocaml so I'll try to explain me better...
If I have :
let function =
let rec recursive1 = ...
...
let rec recursive2 = ...
...
How can I call them inside function to tell it "Hey, do you see this recursive function? Now call it and takes its value."
Because my problem is that Ocaml as return of my functions sees Unit instead of the right return.
I will post the code below :
let change k v list_ =
let rec support k v list_ =
match list_ with
| [] -> []
| (i,value) :: tl -> if i = k
then (k,v) :: tl
else (i,value) :: support k v tl in
let inserted = support k v list_ in inserted
let () =
let k = [ (1,"ciao");(2,"Hola");(3,"Salut") ] in
change 2 "Aufwidersen" k
Change takes as input a key, a value and a (int * string )list and should return the same list of the input but changing the value linked to the key selected ( if in list ).
support, instead, makes the dirty job. It builds a new list and when k is found i = k it changes value and attach the tile, closing the function.
The return of change is unit when it should be (int * string) list. I think because inserted isn't taken as return of the function.
change does not return unit. The error in fact tells you exactly the opposite, that it returns (int * string) list but that it expects unit. And it expects unit because you're assigning it to a () pattern.
I don't know what you actually intend to do with the return value, as right now you don't seem to care about it, but you can fix the error by just assigning it to a name:
let result: (int * string) list =
let k = [ (1,"ciao");(2,"Hola");(3,"Salut") ] in
change 2 "Aufwidersen" k
Since it's not used I've added a type annotation to make sure we're getting what we expect here, as otherwise result could be anything and the compiler wouldn't complain. You don't typically need this if you're going to use result however, as you'd then get an error if the type doesn't unify with its usage.

F# define search function

I am new to F# and am having trouble with my code. Its a simple problem to define a function, search, with that take a boolean function and a list and return an index. So for example:
> search (fun x -> x > 10) [ 2; 12; 3; 23; 62; 8; 2 ];;
val it : int = 1
> search (fun s -> s < "horse") [ "pig"; "lion"; "horse"; "cow"; "turkey" ];;
val it : int = 3
What I have as of right now finds the right match but what I cant figure out is how to return a number instead of the rest of the list. I know I'm getting the list instead of a value back because I wrote "if f head then list". What I don't know is what I should put there instead or if what I have is not going to get the result I want.
Below is the code I have written.
let rec search f list =
match list with
| [] -> [-1]
| head::tail ->
if f head then list
else search f tail
Returning a number is easy, you just... return it. Your problem is that you don't have a number to return, because you can't derive it directly from the current state. You have to keep track of the number yourself, using some internal state variable.
When using recursion you change state by calling your function recursively with "modified" arguments. You're already doing that with the list here. To keep internal state in a recursive function you have to introduce another argument, but not expose it outside. You can solve that by using an internal recursive helper function. Here's one that keeps track of the previous item and returns that when it encounters a match:
let search f list =
let rec loop list prev =
match list with
| [] -> None
| head::tail ->
if f head then prev
else loop tail (Some head)
in
loop list None
That's a silly example, but I don't want to just solve your homework for you, because then you wouldn't learn anything. Using this you should be able to figure out how to keep a counter of which position the current item is in, and return that when it matches. Good luck!
You typically define an inner recursive function to help you carry state as you loop, and then call the inner function with an initial state.
let search predicate list =
let rec loop list index =
match list with
| [] -> -1
| head::tail ->
if predicate head then index
else loop tail (index + 1)
loop list 0

Function with an arbitrary number of arguments in F#

I want to write a function that will take an arbitrary number of (curried) arguments and simply print them out (or perform some other unspecified action with them). Here is what I have come up with:
let print arg =
let rec print args arg =
if not (FSharpType.IsFunction(typeof<'t>)) then
printfn "%A" args
Unchecked.defaultof<'t>
else
print (box arg::args)
print []
When I try to compile this I get the error The resulting type would be infinite when unifying ''t' and ''a -> 't.
I know I could just pass the arguments as a list, but I am trying to develop an API of sorts where this would be a useful idiom to have.
Is there some clever compiler trick to make such a function possible in F# or is it a lost cause?
It seems that the two branches of the inner print want to return different types: the "then" part wants to return 't, but the "else" part wants to return 'a -> 't, where 't is necessarily the same in both branches. That is, your function tries to return either its own return type or a function from another type to its own return type. Such combined return type would, indeed, be infinite, which is in perfect accordance with what you set out to do - namely, create a function with infinite number of arguments. Though I do not know how to formally prove it, I would say this is indeed impossible.
If your goal is to simply create a list of boxed values, you could get away with defining a few infix operators.
let (<+>) a b = a # [(box b)]
let (<&>) a b = [(box a); (box b)]
let xs = 5 <&> "abc" <+> 3.0 <+> None <+> true
>> val xs : obj list = [5; "abc"; 3.0; null; true]
Alternatively, with carefully chosen operator precedence, you can apply a function (but then you'll need a terminator):
let (^>) a b = (box a)::b
let (<&>) f xs = f xs
let print xs = sprintf "%A" xs
let xs = print <&> 5 ^> "abc" ^> 3.0 ^> None ^> true ^> []
>> val xs : string = "[5; "abc"; 3.0; null; true]"

OCaml - Traversing a list without recursion

I'm trying to write following code without recursion:
let rec traverse lst =
match lst with
| a::b::t ->
(* Something that return None*)
traverse (b::t)
| _ -> ()
How to do it in imperative way ?
In an imperative way:
let traverse li =
let state = ref li in
while !state <> [] do
let x = List.hd !state in
state := List.tl !state;
(* do whatever you want *)
done
If you need to access the second element of the list, just use the appropriate List.hd call. But you may need to check that the list isn't empty first.
I see no reason to do that this way, which is heavier, less efficient and less flexible than a recursive loop.

What is 'Pattern Matching' in functional languages?

I'm reading about functional programming and I've noticed that Pattern Matching is mentioned in many articles as one of the core features of functional languages.
Can someone explain for a Java/C++/JavaScript developer what does it mean?
Understanding pattern matching requires explaining three parts:
Algebraic data types.
What pattern matching is
Why its awesome.
Algebraic data types in a nutshell
ML-like functional languages allow you define simple data types called "disjoint unions" or "algebraic data types". These data structures are simple containers, and can be recursively defined. For example:
type 'a list =
| Nil
| Cons of 'a * 'a list
defines a stack-like data structure. Think of it as equivalent to this C#:
public abstract class List<T>
{
public class Nil : List<T> { }
public class Cons : List<T>
{
public readonly T Item1;
public readonly List<T> Item2;
public Cons(T item1, List<T> item2)
{
this.Item1 = item1;
this.Item2 = item2;
}
}
}
So, the Cons and Nil identifiers define simple a simple class, where the of x * y * z * ... defines a constructor and some data types. The parameters to the constructor are unnamed, they're identified by position and data type.
You create instances of your a list class as such:
let x = Cons(1, Cons(2, Cons(3, Cons(4, Nil))))
Which is the same as:
Stack<int> x = new Cons(1, new Cons(2, new Cons(3, new Cons(4, new Nil()))));
Pattern matching in a nutshell
Pattern matching is a kind of type-testing. So let's say we created a stack object like the one above, we can implement methods to peek and pop the stack as follows:
let peek s =
match s with
| Cons(hd, tl) -> hd
| Nil -> failwith "Empty stack"
let pop s =
match s with
| Cons(hd, tl) -> tl
| Nil -> failwith "Empty stack"
The methods above are equivalent (although not implemented as such) to the following C#:
public static T Peek<T>(Stack<T> s)
{
if (s is Stack<T>.Cons)
{
T hd = ((Stack<T>.Cons)s).Item1;
Stack<T> tl = ((Stack<T>.Cons)s).Item2;
return hd;
}
else if (s is Stack<T>.Nil)
throw new Exception("Empty stack");
else
throw new MatchFailureException();
}
public static Stack<T> Pop<T>(Stack<T> s)
{
if (s is Stack<T>.Cons)
{
T hd = ((Stack<T>.Cons)s).Item1;
Stack<T> tl = ((Stack<T>.Cons)s).Item2;
return tl;
}
else if (s is Stack<T>.Nil)
throw new Exception("Empty stack");
else
throw new MatchFailureException();
}
(Almost always, ML languages implement pattern matching without run-time type-tests or casts, so the C# code is somewhat deceptive. Let's brush implementation details aside with some hand-waving please :) )
Data structure decomposition in a nutshell
Ok, let's go back to the peek method:
let peek s =
match s with
| Cons(hd, tl) -> hd
| Nil -> failwith "Empty stack"
The trick is understanding that the hd and tl identifiers are variables (errm... since they're immutable, they're not really "variables", but "values" ;) ). If s has the type Cons, then we're going to pull out its values out of the constructor and bind them to variables named hd and tl.
Pattern matching is useful because it lets us decompose a data structure by its shape instead of its contents. So imagine if we define a binary tree as follows:
type 'a tree =
| Node of 'a tree * 'a * 'a tree
| Nil
We can define some tree rotations as follows:
let rotateLeft = function
| Node(a, p, Node(b, q, c)) -> Node(Node(a, p, b), q, c)
| x -> x
let rotateRight = function
| Node(Node(a, p, b), q, c) -> Node(a, p, Node(b, q, c))
| x -> x
(The let rotateRight = function constructor is syntax sugar for let rotateRight s = match s with ....)
So in addition to binding data structure to variables, we can also drill down into it. Let's say we have a node let x = Node(Nil, 1, Nil). If we call rotateLeft x, we test x against the first pattern, which fails to match because the right child has type Nil instead of Node. It'll move to the next pattern, x -> x, which will match any input and return it unmodified.
For comparison, we'd write the methods above in C# as:
public abstract class Tree<T>
{
public abstract U Match<U>(Func<U> nilFunc, Func<Tree<T>, T, Tree<T>, U> nodeFunc);
public class Nil : Tree<T>
{
public override U Match<U>(Func<U> nilFunc, Func<Tree<T>, T, Tree<T>, U> nodeFunc)
{
return nilFunc();
}
}
public class Node : Tree<T>
{
readonly Tree<T> Left;
readonly T Value;
readonly Tree<T> Right;
public Node(Tree<T> left, T value, Tree<T> right)
{
this.Left = left;
this.Value = value;
this.Right = right;
}
public override U Match<U>(Func<U> nilFunc, Func<Tree<T>, T, Tree<T>, U> nodeFunc)
{
return nodeFunc(Left, Value, Right);
}
}
public static Tree<T> RotateLeft(Tree<T> t)
{
return t.Match(
() => t,
(l, x, r) => r.Match(
() => t,
(rl, rx, rr) => new Node(new Node(l, x, rl), rx, rr))));
}
public static Tree<T> RotateRight(Tree<T> t)
{
return t.Match(
() => t,
(l, x, r) => l.Match(
() => t,
(ll, lx, lr) => new Node(ll, lx, new Node(lr, x, r))));
}
}
For seriously.
Pattern matching is awesome
You can implement something similar to pattern matching in C# using the visitor pattern, but its not nearly as flexible because you can't effectively decompose complex data structures. Moreover, if you are using pattern matching, the compiler will tell you if you left out a case. How awesome is that?
Think about how you'd implement similar functionality in C# or languages without pattern matching. Think about how you'd do it without test-tests and casts at runtime. Its certainly not hard, just cumbersome and bulky. And you don't have the compiler checking to make sure you've covered every case.
So pattern matching helps you decompose and navigate data structures in a very convenient, compact syntax, it enables the compiler to check the logic of your code, at least a little bit. It really is a killer feature.
Short answer: Pattern matching arises because functional languages treat the equals sign as an assertion of equivalence instead of assignment.
Long answer: Pattern matching is a form of dispatch based on the “shape” of the value that it's given. In a functional language, the datatypes that you define are usually what are known as discriminated unions or algebraic data types. For instance, what's a (linked) list? A linked list List of things of some type a is either the empty list Nil or some element of type a Consed onto a List a (a list of as). In Haskell (the functional language I'm most familiar with), we write this
data List a = Nil
| Cons a (List a)
All discriminated unions are defined this way: a single type has a fixed number of different ways to create it; the creators, like Nil and Cons here, are called constructors. This means that a value of the type List a could have been created with two different constructors—it could have two different shapes. So suppose we want to write a head function to get the first element of the list. In Haskell, we would write this as
-- `head` is a function from a `List a` to an `a`.
head :: List a -> a
-- An empty list has no first item, so we raise an error.
head Nil = error "empty list"
-- If we are given a `Cons`, we only want the first part; that's the list's head.
head (Cons h _) = h
Since List a values can be of two different kinds, we need to handle each one separately; this is the pattern matching. In head x, if x matches the pattern Nil, then we run the first case; if it matches the pattern Cons h _, we run the second.
Short answer, explained: I think one of the best ways to think about this behavior is by changing how you think of the equals sign. In the curly-bracket languages, by and large, = denotes assignment: a = b means “make a into b.” In a lot of functional languages, however, = denotes an assertion of equality: let Cons a (Cons b Nil) = frob x asserts that the thing on the left, Cons a (Cons b Nil), is equivalent to the thing on the right, frob x; in addition, all variables used on the left become visible. This is also what's happening with function arguments: we assert that the first argument looks like Nil, and if it doesn't, we keep checking.
It means that instead of writing
double f(int x, int y) {
if (y == 0) {
if (x == 0)
return NaN;
else if (x > 0)
return Infinity;
else
return -Infinity;
} else
return (double)x / y;
}
You can write
f(0, 0) = NaN;
f(x, 0) | x > 0 = Infinity;
| else = -Infinity;
f(x, y) = (double)x / y;
Hey, C++ supports pattern matching too.
static const int PositiveInfinity = -1;
static const int NegativeInfinity = -2;
static const int NaN = -3;
template <int x, int y> struct Divide {
enum { value = x / y };
};
template <bool x_gt_0> struct aux { enum { value = PositiveInfinity }; };
template <> struct aux<false> { enum { value = NegativeInfinity }; };
template <int x> struct Divide<x, 0> {
enum { value = aux<(x>0)>::value };
};
template <> struct Divide<0, 0> {
enum { value = NaN };
};
#include <cstdio>
int main () {
printf("%d %d %d %d\n", Divide<7,2>::value, Divide<1,0>::value, Divide<0,0>::value, Divide<-1,0>::value);
return 0;
};
Pattern matching is sort of like overloaded methods on steroids. The simplest case would be the same roughly the same as what you seen in java, arguments are a list of types with names. The correct method to call is based on the arguments passed in, and it doubles as an assignment of those arguments to the parameter name.
Patterns just go a step further, and can destructure the arguments passed in even further. It can also potentially use guards to actually match based on the value of the argument. To demonstrate, I'll pretend like JavaScript had pattern matching.
function foo(a,b,c){} //no pattern matching, just a list of arguments
function foo2([a],{prop1:d,prop2:e}, 35){} //invented pattern matching in JavaScript
In foo2, it expects a to be an array, it breaks apart the second argument, expecting an object with two props (prop1,prop2) and assigns the values of those properties to variables d and e, and then expects the third argument to be 35.
Unlike in JavaScript, languages with pattern matching usually allow multiple functions with the same name, but different patterns. In this way it is like method overloading. I'll give an example in erlang:
fibo(0) -> 0 ;
fibo(1) -> 1 ;
fibo(N) when N > 0 -> fibo(N-1) + fibo(N-2) .
Blur your eyes a little and you can imagine this in javascript. Something like this maybe:
function fibo(0){return 0;}
function fibo(1){return 1;}
function fibo(N) when N > 0 {return fibo(N-1) + fibo(N-2);}
Point being that when you call fibo, the implementation it uses is based on the arguments, but where Java is limited to types as the only means of overloading, pattern matching can do more.
Beyond function overloading as shown here, the same principle can be applied other places, such as case statements or destructuring assingments. JavaScript even has this in 1.7.
Pattern matching allows you to match a value (or an object) against some patterns to select a branch of the code. From the C++ point of view, it may sound a bit similar to the switch statement. In functional languages, pattern matching can be used for matching on standard primitive values such as integers. However, it is more useful for composed types.
First, let's demonstrate pattern matching on primitive values (using extended pseudo-C++ switch):
switch(num) {
case 1:
// runs this when num == 1
case n when n > 10:
// runs this when num > 10
case _:
// runs this for all other cases (underscore means 'match all')
}
The second use deals with functional data types such as tuples (which allow you to store multiple objects in a single value) and discriminated unions which allow you to create a type that can contain one of several options. This sounds a bit like enum except that each label can also carry some values. In a pseudo-C++ syntax:
enum Shape {
Rectangle of { int left, int top, int width, int height }
Circle of { int x, int y, int radius }
}
A value of type Shape can now contain either Rectangle with all the coordinates or a Circle with the center and the radius. Pattern matching allows you to write a function for working with the Shape type:
switch(shape) {
case Rectangle(l, t, w, h):
// declares variables l, t, w, h and assigns properties
// of the rectangle value to the new variables
case Circle(x, y, r):
// this branch is run for circles (properties are assigned to variables)
}
Finally, you can also use nested patterns that combine both of the features. For example, you could use Circle(0, 0, radius) to match for all shapes that have the center in the point [0, 0] and have any radius (the value of the radius will be assigned to the new variable radius).
This may sound a bit unfamiliar from the C++ point of view, but I hope that my pseudo-C++ make the explanation clear. Functional programming is based on quite different concepts, so it makes better sense in a functional language!
Pattern matching is where the interpreter for your language will pick a particular function based on the structure and content of the arguments you give it.
It is not only a functional language feature but is available for many different languages.
The first time I came across the idea was when I learned prolog where it is really central to the language.
e.g.
last([LastItem], LastItem).
last([Head|Tail], LastItem) :-
last(Tail, LastItem).
The above code will give the last item of a list. The input arg is the first and the result is the second.
If there is only one item in the list the interpreter will pick the first version and the second argument will be set to equal the first i.e. a value will be assigned to the result.
If the list has both a head and a tail the interpreter will pick the second version and recurse until it there is only one item left in the list.
For many people, picking up a new concept is easier if some easy examples are provided, so here we go:
Let's say you have a list of three integers, and wanted to add the first and the third element. Without pattern matching, you could do it like this (examples in Haskell):
Prelude> let is = [1,2,3]
Prelude> head is + is !! 2
4
Now, although this is a toy example, imagine we would like to bind the first and third integer to variables and sum them:
addFirstAndThird is =
let first = head is
third = is !! 3
in first + third
This extraction of values from a data structure is what pattern matching does. You basically "mirror" the structure of something, giving variables to bind for the places of interest:
addFirstAndThird [first,_,third] = first + third
When you call this function with [1,2,3] as its argument, [1,2,3] will be unified with [first,_,third], binding first to 1, third to 3 and discarding 2 (_ is a placeholder for things you don't care about).
Now, if you only wanted to match lists with 2 as the second element, you can do it like this:
addFirstAndThird [first,2,third] = first + third
This will only work for lists with 2 as their second element and throw an exception otherwise, because no definition for addFirstAndThird is given for non-matching lists.
Until now, we used pattern matching only for destructuring binding. Above that, you can give multiple definitions of the same function, where the first matching definition is used, thus, pattern matching is a little like "a switch statement on stereoids":
addFirstAndThird [first,2,third] = first + third
addFirstAndThird _ = 0
addFirstAndThird will happily add the first and third element of lists with 2 as their second element, and otherwise "fall through" and "return" 0. This "switch-like" functionality can not only be used in function definitions, e.g.:
Prelude> case [1,3,3] of [a,2,c] -> a+c; _ -> 0
0
Prelude> case [1,2,3] of [a,2,c] -> a+c; _ -> 0
4
Further, it is not restricted to lists, but can be used with other types as well, for example matching the Just and Nothing value constructors of the Maybe type in order to "unwrap" the value:
Prelude> case (Just 1) of (Just x) -> succ x; Nothing -> 0
2
Prelude> case Nothing of (Just x) -> succ x; Nothing -> 0
0
Sure, those were mere toy examples, and I did not even try to give a formal or exhaustive explanation, but they should suffice to grasp the basic concept.
You should start with the Wikipedia page that gives a pretty good explanation. Then, read the relevant chapter of the Haskell wikibook.
This is a nice definition from the above wikibook:
So pattern matching is a way of
assigning names to things (or binding
those names to those things), and
possibly breaking down expressions
into subexpressions at the same time
(as we did with the list in the
definition of map).
Here is a really short example that shows pattern matching usefulness:
Let's say you want to sort up an element in a list:
["Venice","Paris","New York","Amsterdam"]
to (I've sorted up "New York")
["Venice","New York","Paris","Amsterdam"]
in an more imperative language you would write:
function up(city, cities){
for(var i = 0; i < cities.length; i++){
if(cities[i] === city && i > 0){
var prev = cities[i-1];
cities[i-1] = city;
cities[i] = prev;
}
}
return cities;
}
In a functional language you would instead write:
let up list value =
match list with
| [] -> []
| previous::current::tail when current = value -> current::previous::tail
| current::tail -> current::(up tail value)
As you can see the pattern matched solution has less noise, you can clearly see what are the different cases and how easy it's to travel and de-structure our list.
I've written a more detailed blog post about it here.

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