How to coerce stslist.freq to dataframe - r

I am doing some describtive sequence analysis using the "TraMineR" library. I want to report my findings via R-Markdown in html format. For formating tables I use "kable" and "kableExtra".
To get the frequency and propotions of the most common sequences I use seqtab(). The result is an stslist.freq object. When I try to coerce it to a dataframe, the dataframe is not containing any frequencies and proportions.
I tried to print the results of seqtab() and store this result again. This gives me the dataframe I desire. However there are two "problems" with that: (1) I don't understand what is happening here and it seems like a "dirty" trick, (2) as a result I also get the output of the print command in my final html document if I don't split the code in multiple chunks and disable the ouput in the specific chunk.
Here is some code to replicate the problem:
library("TraMineR")
#Data creation
data.long <- data.frame(
id=rep(1:50, each=4),
time = c(0,1,2,3),
status = sample(letters[1:2], 200, replace = TRUE),
weight=rep(runif(50, 0, 1), each=4)
)
#reshape
data.wide <- reshape(data.long, v.names = "status", idvar="id", direction="wide", timevar="time")
#sequence
sequence <- seqdef(data.wide,
var=c("status.0", "status.1", "status.2", "status.3"),
weights=data.wide$weight)
#frequencies of sequences
##doesn't work:
seqtab.df1 <- as.data.frame(seqtab(sequence))
##works:
seqtab.df2 <- print(seqtab(sequence))
I expect the dataframe to be the same as the one saved in seqtab.df2, however either without using the print command or with "silently" (no output printed) using the print command.
Thank you very much for your help and let me know if I forgot something to make answering the question possible!

If you look at the class() of the object returned by seqtab, it has the type
class(seqtab(sequence))
# [1] "stslist.freq" "stslist" "data.frame"
so if we look at exactly, what's happening in the print statement for such an object we can get a clue what's going on
TraMineR:::print.stslist.freq
# function (x, digits = 2, width = 1, ...)
# {
# table <- attr(x, "freq")
# print(table, digits = digits, width = width, ...)
# }
# <bytecode: 0x0000000003e831f8>
# <environment: namespace:TraMineR>
We see that what it's really giving you is the "freq" attribute. You can extract this directly and skip the print()
attr(seqtab(sequence), "freq")
# Freq Percent
# a/3-b/1 4.283261 20.130845
# b/1-a/1-b/2 2.773341 13.034390
# a/2-b/1-a/1 2.141982 10.067073
# a/1-b/1-a/1-b/1 1.880359 8.837476
# a/1-b/2-a/1 1.723489 8.100203
# b/1-a/2-b/1 1.418302 6.665861
# b/2-a/1-b/1 1.365099 6.415813
# a/1-b/3 1.241644 5.835586
# a/1-b/1-a/2 1.164434 5.472710
# a/2-b/2 1.092656 5.135360

Related

Using an R function to hash values produces a repeating value across rows

I'm using the following query:
let
Source = {1..5},
#"Converted to Table" = Table.FromList(Source, Splitter.SplitByNothing(), {"Numbers"}, null, ExtraValues.Error),
#"Added Custom" = Table.AddColumn(#"Converted to Table", "Letters", each Character.FromNumber([Numbers] + 64)),
#"Run R script" = R.Execute("# 'dataset' holds the input data for this script#(lf)#(lf)library(""digest"")#(lf)#(lf)dataset$SuffixedLetters <- paste(dataset$Letters, ""_suffix"")#(lf)dataset$HashedLetters <- digest(dataset$Letters, ""md5"", serialize = TRUE)#(lf)output<-dataset",[dataset=#"Added Custom"]),
output = #"Run R script"{[Name="output"]}[Value]
in
output
which leads to the resulting table:
And the here is the R script with better formatting:
# 'dataset' holds the input data for this script
library("digest")
dataset$SuffixedLetters <- paste(dataset$Letters, "_suffix")
dataset$HashedLetters <- digest(dataset$Letters, "md5", serialize = TRUE)
output<-dataset
The 'paste' function appears to iterate over rows and resolve on each row with the new input. But the 'digest' function only appears to return the first value in the table across all rows.
I don't know why the behavior of the two functions would seem to operate differently. Can anyone advise how to get the 'HashedLetters' column to resolve using the values from each row instead of just the initial one?
Use:
dataset$HashedLetters <- sapply(dataset$Letters, digest, algo = "md5", serialize = TRUE)
digest works on a whole object at a time, not individual elements of a vector.
vec <- letters[1:3]
digest::digest(vec, algo="md5", serialize=TRUE)
# [1] "38ce1fe9e19a222505e693e8bdd8aeec"
sapply(vec, digest::digest, algo="md5", serialize=TRUE)
# a b c
# "127a2ec00989b9f7faf671ed470be7f8" "ddf100612805359cd81fdc5ce3b9fbba" "6e7a8c1c098e8817e3df3fd1b21149d1"

How does R Markdown automatically format print effects into dataframes? Or how can I access special print methods?

I'm working with the WRS2 package and there are cases where it'll output its analysis (bwtrim) into a list with a special class of the analysis type class = "bwtrim". I can't as.data.frame() it, but I found that there is a custom print method called print.bwtrim associated with it.
As an example let's say this is the output: bwtrim.out <- bwtrim(...). When I run the analysis output in an Rmarkdown chunk, it seems to "steal" part of the text output and make it into a dataframe.
So here's my question, how can I either access print.bwtrim or how does R markdown automatically format certain outputs into dataframes? Because I'd like to take this outputted dataframe and use it for other purposes.
Update: Here is a minimally working example -- put the following in a chunk in Rmd file."
```{r}
library(WRS2)
df <-
data.frame(
subject = rep(c(1:100), each = 2),
group = rep(c("treatment", "control"), each = 2),
timepoint = rep(c("pre", "post"), times = 2),
dv = rnorm(200, mean = 2)
)
analysis <- WRS2::bwtrim(dv ~ group * timepoint,
id = subject,
data = df,
tr = .2)
analysis
```
With this, a data.frame automatically shows up in the chunk afterwards and it shows all the values very nicely. My main question is how can I get this data.frame for my own uses. Because if you do str(analysis), you see that it's a list. If you do class(analysis) you get "bwtrim". if you do methods(class = "bwtrim"), you get the print method. And methods(print) will have a line that says print.bwtrim*. But I can't seem to figure out how to call print.bwtrim myself.
Regarding what Rmarkdown is doing, compare the following
If you run this in a chunk, it actually steals the data.frame part and puts it into a separate figure.
```{r}
capture.output(analysis)
```
However, if you run the same line in the console, the entire output comes out properly. What's also interesting is that if you try to assign it to another object, the output will be stolen before it can be assigned.
Compare x when you run the following in either a chunk or the console.
```{r}
x<-capture.output(analysis)
```
This is what I get from the chunk approach when I call x
[1] "Call:"
[2] "WRS2::bwtrim(formula = dv ~ group * timepoint, id = subject, "
[3] " data = df, tr = 0.2)"
[4] ""
[5] ""
This is what I get when I do it all in the console
[1] "Call:"
[2] "WRS2::bwtrim(formula = dv ~ group * timepoint, id = subject, "
[3] " data = df, tr = 0.2)"
[4] ""
[5] " value df1 df2 p.value"
[6] "group 1.0397 1 56.2774 0.3123"
[7] "timepoint 0.0001 1 57.8269 0.9904"
[8] "group:timepoint 0.5316 1 57.8269 0.4689"
[9] ""
My question is what can I call whatever Rstudio/Rmarkdown is doing to make data.frames, so that I can have an easy data.frame myself?
Update 2: This is probably not a bug, as discussed here https://github.com/rstudio/rmarkdown/issues/1150.
Update 3: You can access the method by using WRS2:::bwtrim(analysis), though I'm still interested in what Rmarkdown is doing.
Update 4: It might not be the case that Rmarkdown is stealing the output and automatically making dataframes from it, as you can see when you call x after you've already captured the output. Looking at WRS2:::print.bwtrim, it prints a dataframe that it creates, which I'm guessing Rmarkdown recognizes then formats it out.
See below for the print.bwtrim.
function (x, ...)
{
cat("Call:\n")
print(x$call)
cat("\n")
dfx <- data.frame(value = c(x$Qa, x$Qb, x$Qab), df1 = c(x$A.df[1],
x$B.df[1], x$AB.df[1]), df2 = c(x$A.df[2], x$B.df[2],
x$AB.df[2]), p.value = c(x$A.p.value, x$B.p.value, x$AB.p.value))
rownames(dfx) <- c(x$varnames[2], x$varnames[3], paste0(x$varnames[2],
":", x$varnames[3]))
dfx <- round(dfx, 4)
print(dfx)
cat("\n")
}
<bytecode: 0x000001f587dc6078>
<environment: namespace:WRS2>
In R Markdown documents, automatic printing is done by knitr::knit_print rather than print. I don't think there's a knit_print.bwtrim method defined, so it will use the default method, which is defined as
function (x, ..., inline = FALSE)
{
if (inline)
x
else normal_print(x)
}
and normal_print will call print().
You are asking why the output is different. I don't see that when I knit the document to html_document, but I do see it with html_notebook. I don't know the details of what is being done, but if you look at https://rmarkdown.rstudio.com/r_notebook_format.html you can see a discussion of "output source functions", which manipulate chunks to produce different output.
The fancy output you're seeing looks a lot like what knitr::knit_print does for a dataframe, so maybe html_notebook is substituting that in place of print.

In R how do you factorise and add label values to specific data.table columns, using a second file of meta data?

This is part of a project to switch from SPSS to R. While there are good tools to import SPSS files into R (expss) what this question is part of is attempting to get the benefits of SPSS style labeling when data originates from CSV sources. This is to help bridge the staff training gap between SPSS and R by providing a common format for data.tables irrespective of file format origin.
Whilst CSV does a reasonable job of storing data it is hopeless for providing meaningful data. This inevitably means variable and factor levels and labels have to come from somewhere else. In most short examples of this (e.g. in documentation) it is practical to simply hard code the meta data in. But for larger projects it makes more sense to store this meta data in a second csv file.
Example data file
ID,varone,vartwo,varthree,varfour,varfive,varsix,varseven,vareight,varnine,varten
1,1,34,1,,1,,1,1,4,
2,1,21,0,1,,1,3,14,3,2
3,1,54,1,,,1,3,6,4,4
4,2,32,1,1,1,,3,7,4,
5,3,66,0,,,1,3,9,3,3
6,2,43,1,,1,,1,12,2,1
7,2,26,0,,,1,2,11,1,
8,3,,1,1,,,2,15,1,4
9,1,34,1,,1,,1,12,3,4
10,2,46,0,,,,3,13,2,
11,3,39,1,1,1,,3,7,1,2
12,1,28,0,,,1,1,6,5,1
13,2,64,0,,1,,2,11,,3
14,3,34,1,1,,,3,10,1,1
15,1,52,1,,1,1,1,8,6,
Example metadata file
Rowlabels,ID,varone,vartwo,varthree,varfour,varfive,varsix,varseven,vareight,varnine,varten
varlabel,,Question one,Question two,Question three,Question four,Question five,Question six,Question seven,Question eight,Question nine,Question ten
varrole,Unique,Attitude,Unique,Filter,Filter,Filter,Filter,Attitude,Filter,Attitude,Attitude
Missing,Error,Error,Ignored,Error,Unchecked,Unchecked,Unchecked,Error,Error,Error,Ignored
vallable,,One,,No,Checked,Checked,Checked,x,One,A,Support
vallable,,Two,,Yes,,,,y,Two,B,Neutral
vallable,,Three,,,,,,z,Three,C,Oppose
vallable,,,,,,,,,Four,D,Dont know
vallable,,,,,,,,,Five,E,
vallable,,,,,,,,,Six,F,
vallable,,,,,,,,,Seven,G,
vallable,,,,,,,,,Eight,,
vallable,,,,,,,,,Nine,,
vallable,,,,,,,,,Ten,,
vallable,,,,,,,,,Eleven,,
vallable,,,,,,,,,Twelve,,
vallable,,,,,,,,,Thirteen,,
vallable,,,,,,,,,Fourteen,,
vallable,,,,,,,,,Fifteen,,
SO the common elements are the column names which are the key to both files
The first column of the metadata file describes the role of the row for the data file
so
varlabel provides the variable label for each column
varrole describes the analytic purpose of the variable
missing describes how to treat missing data
varlabel describes the label for a factor level starting at one on up to as many labels as there are.
Right! Here's the code that works:
```#Libraries
library(expss)
library(data.table)
library(magrittr)```
readcsvdata <- function(dfile)
{
# TESTED - Working
print("OK Lets read some comma separated values")
rdata <- fread(file = dfile, sep = "," , quote = "\"" , header = TRUE, stringsAsFactors = FALSE,
na.strings = getOption("datatable.na.strings",""))
return(rdata)
}
rawdatafilename <- "testdata.csv"
rawmetadata <- "metadata.csv"
mdt <- readcsvdata(rawmetadata)
rdt <- readcsvdata(rawdatafilename)
names(rdt)[names(rdt) == "ï..ID"] <- "ID" # correct minor data error
commonnames <- intersect(names(mdt),names(rdt)) # find common variable names so metadata applies
commonnames <- commonnames[-(1)] # remove ID
qlabels <- as.list(mdt[1, commonnames, with = FALSE])
(Here I copy the rdt datatable simply so I can roll back to the original data without re-running the previous read chunks and tidying whenever I make changes that don't work out.
# set var names to columns
for (each_name in commonnames) # loop through commonnames and qlabels
{
expss::var_lab(tdt[[each_name]]) <- qlabels[[each_name]]
}
OK this is where I fall down.
Failure from here
factorcols <- as.vector(commonnames) # create a vector of column names (for later use)
for (col in factorcols)
{
print( is.na(mdt[4, ..col])) # print first row of value labels (as test)
if (is.na(mdt[4, ..col])) factorcols <- factorcols[factorcols != col]
# if not a factor column, remove it from the factorcol list and dont try to factor it
else { # if it is a vector factorise
print(paste("working on",col)) # I have had a lot of problem with unrecognised ..col variables
tlabels <- as.vector(na.omit(mdt[4:18, ..col])) # get list of labels from the data column}
validrange <- seq(1,lengths(tlabels),1) # range of valid values is 1 to the length of labels list
print(as.character(tlabels)) # for testing
print(validrange) # for testing
tdt[[col]] <- factor(tdt[[col]], levels = validrange, ordered = is.ordered(validrange), labels = as.character(tlabels))
# expss::val_lab(tdt[, ..col]) <- tlabels
tlabels = c() # flush loop variable
validrange = c() # flush loop variable
}
}
So the problem is revealed here when we check the data table.
tdt
the labels have been applied as whole vectors to each column entry except where there is only one value in the vector ("checked" for varfour and varfive)
tdt
id (int) 1
varone (fctr) c("One", "Two", "Three") 1 (should be "One" 1)
vartwo (S3: labelled) 34
varthree (fctr) c("No", "Yes") 1 (should be "No" 1)
varfour (fctr) NA
varfive (fctr) Checked
And a mystery
this code works just fine on a single columns when I don't use a for loop variable
# test using column name
tlabels <- c("one","two","three")
validrange <- c(1,2,3)
factor(tdt[,varone], levels = validrange, ordered=is.ordered(validrange), labels = tlabels)
It seems the issue is in the line tlabels <- as.vector(na.omit(mdt[4:18, ..col])). It doesn't make vector as you expect. Contrary to usual data.frame data.table doesn't drop dimensions when you provide single column in the index. And as.vector do nothing with data.frames/data.tables. So tlabels remains data.table. This line need to be rewritten as tlabels <- na.omit(mdt[[col]][4:18]).
Example:
library(data.table)
mdt = as.data.table(mtcars)
col = "am"
tlabels <- as.vector(na.omit(mdt[3:6, ..col])) # ! tlabels is data.table
str(tlabels)
# Classes ‘data.table’ and 'data.frame': 4 obs. of 1 variable:
# $ am: num 1 0 0 0
# - attr(*, ".internal.selfref")=<externalptr>
as.character(tlabels) # character vector of length 1
# [1] "c(1, 0, 0, 0)"
tlabels <- na.omit(mdt[[col]][3:6]) # vector
str(tlabels)
# num [1:4] 1 0 0 0
as.character(tlabels) # character vector of length 4
# [1] "1" "0" "0" "0"

Different spacing while printing to log

I am printing importance matrix of xgBoost into log using write command (write works with file connection and direct it to stderr well). Here is the command I am using:
importance_matrix <- xgb.importance(names, model=bst)
write("The top 30 variables are:",stderr())
write(paste0("Feature",'\t','\t','Gain','\t','Cover','\t','Frequency'),stderr())
write(t(as.matrix(importance_matrix[1:30,])),sep="\t",ncolumns = length(names(importance_matrix)),stderr())
Output comes in format:
Feature Gain Cover Frequency
pctTillDate 0.560359696 0.1314074664 0.024278250
colr_per 0.183149483 0.0962457545 0.049618673
date 0.050528297 0.1143752021 0.066395735
GREG_D 0.025648433 0.0381476142 0.018070143
LNGTD_I 0.020346020 0.0485235001 0.101322109
LATTD_I 0.019241497 0.0421892270 0.093867103
which make it look a bit clumsy (much clumsy in log than appearing here in SO). So in order to make it better looking I want to change last line of t(as.matrix(importance_matrix[1:30,])),sep="\t" such that first sep will be 2 tabs ('\t','\t') and rest single tab ('\t'); instead of current uniform spacing. Simple but search doesn't give any idea. Any suggestions?
Consider padding the column names and first char column of matrix with whitespace to align each to largest character size of first column:
write.table(importance_matrix, sep="\t", row.names = FALSE, quote = FALSE)
# Feature Gain Cover Frequency
# pctTillDate 0.56035970 0.13140747 0.02427825
# colr_per 0.18314948 0.09624575 0.04961867
# date 0.05052830 0.11437520 0.06639573
# GREG_D 0.02564843 0.03814761 0.01807014
# LNGTD_I 0.02034602 0.04852350 0.10132211
# LATTD_I 0.01924150 0.04218923 0.09386710
new_matrix <- importance_matrix
# FIRST COLUMN LARGEST CHAR LENGTH
charmax <- max(nchar(new_matrix[,1]))
# PAD COLUMN HEADERS
colnames(new_matrix) <- lapply(1:ncol(new_matrix), function(i)
paste0(colnames(new_matrix)[i],
paste(rep(" ", charmax - nchar(colnames(new_matrix)[i])), collapse=""))
)
# PAD FIRST COLUMN
new_matrix[,1] <- sapply(1:nrow(new_matrix), function(i)
paste0(new_matrix[i,1],
paste(rep(" ", charmax - nchar(new_matrix[i,1])), collapse=""))
)
write.table(new_matrix, sep="\t", row.names = FALSE, quote = FALSE)
# Feature Gain Cover Frequency
# pctTillDate 0.56035970 0.13140747 0.02427825
# colr_per 0.18314948 0.09624575 0.04961867
# date 0.05052830 0.11437520 0.06639573
# GREG_D 0.02564843 0.03814761 0.01807014
# LNGTD_I 0.02034602 0.04852350 0.10132211
# LATTD_I 0.01924150 0.04218923 0.09386710

Huge data file and running multiple parameters and memory issue, Fisher's test

I have a R code that I am trying to run in a server. But it is stopping in the middle/get frozen probably because of memory limitation. The data files are huge/massive (one has 20 million lines) and if you look at the double for loop in the code, length(ratSplit) = 281 and length(humanSplit) = 36. The data has specific data of human and rats' genes and human has 36 replicates, while rat has 281. So, the loop is basically 281*36 steps. What I want to do is to process data using the function getGeneType and see how different/independent are the expression of different replicate combinations. Using Fisher's test. The data rat_processed_7_25_FDR_05.out looks like this :
2 Sptbn1 114201107 114200202 chr14|Sptbn1:114201107|Sptbn1:114200202|reg|- 2 Thymus_M_GSM1328751 reg
2 Ndufb7 35680273 35683909 chr19|Ndufb7:35680273|Ndufb7:35683909|reg|+ 2 Thymus_M_GSM1328751 rev
2 Ndufb10 13906408 13906289 chr10|Ndufb10:13906408|Ndufb10:13906289|reg|- 2 Thymus_M_GSM1328751 reg
3 Cdc14b 1719665 1719190 chr17|Cdc14b:1719665|Cdc14b:1719190|reg|- 3 Thymus_M_GSM1328751 reg
and the data fetal_output_7_2.out has the form
SPTLC2 78018438 77987924 chr14|SPTLC2:78018438|SPTLC2:77987924|reg|- 11 Fetal_Brain_408_AGTCAA_L006_R1_report.txt reg
EXOSC1 99202993 99201016 chr10|EXOSC1:99202993|EXOSC1:99201016|rev|- 5 Fetal_Brain_408_AGTCAA_L006_R1_report.txt reg
SHMT2 57627893 57628016 chr12|SHMT2:57627893|SHMT2:57628016|reg|+ 8 Fetal_Brain_408_AGTCAA_L006_R1_report.txt reg
ZNF510 99538281 99537128 chr9|ZNF510:99538281|ZNF510:99537128|reg|- 8 Fetal_Brain_408_AGTCAA_L006_R1_report.txt reg
PPFIBP1 27820253 27824363 chr12|PPFIBP1:27820253|PPFIBP1:27824363|reg|+ 10 Fetal_Brain_408_AGTCAA_L006_R1_report.txt reg
Now I have few questions on how to make this more efficient. I think when I run this code, R takes up lots of memory that ultimately causes problems. I am wondering if there is any way of doing this more efficiently
Another possibility is the usage of double for-loop'. Will sapply help? In that case, how should I apply sapply?
At the end I want to convert result into a csv file. I know this is a bit overwhelming to put code like this. But any optimization/efficient coding/programming will be A LOT! I really need to run the whole thing at least one to get the data soon.
#this one compares reg vs rev
date()
ratRawData <- read.table("rat_processed_7_25_FDR_05.out",col.names = c("alignment", "ratGene", "start", "end", "chrom", "align", "ratReplicate", "RNAtype"), fill = TRUE)
humanRawData <- read.table("fetal_output_7_2.out", col.names = c("humanGene", "start", "end", "chrom", "alignment", "humanReplicate", "RNAtype"), fill = TRUE)
geneList <- read.table("geneList.txt", col.names = c("human", "rat"), sep = ',')
#keeping only information about gene, alignment number, replicate and RNAtype, discard other columns
ratRawData <- ratRawData[,c("ratGene", "ratReplicate", "alignment", "RNAtype")]
humanRawData <- humanRawData[, c( "humanGene", "humanReplicate", "alignment", "RNAtype")]
#function to capitalize
capitalize <- function(x){
capital <- toupper(x) ## capitalize
paste0(capital)
}
#capitalizing the rna type naming for rat. So, reg ->REG, dup ->DUP, rev ->REV
#doing this to make data manipulation for making contingency table easier.
levels(ratRawData$RNAtype) <- capitalize(levels(ratRawData$RNAtype))
#spliting data in replicates
ratSplit <- split(ratRawData, ratRawData$ratReplicate)
humanSplit <- split(humanRawData, humanRawData$humanReplicate)
print("done splitting")
#HyRy :when some gene has only reg, rev , REG, REV
#HnRy : when some gene has only reg,REG,REV
#HyRn : add 1 when some gene has only reg,rev,REG
#HnRn : add 1 when some gene has only reg,REG
#function to be used to aggregate
getGeneType <- function(types) {
types <- as.character(types)
if ('rev' %in% types) {
return(ifelse(('REV' %in% types), 'HyRy', 'HyRn'))
}
else {
return(ifelse(('REV' %in% types), 'HnRy', 'HnRn'))
}
}
#logical function to see whether x is integer(0) ..It's used the for loop bellow in case any one HmYn is equal to zero
is.integer0 <- function(x) {
is.integer(x) && length(x) == 0L
}
result <- data.frame(humanReplicate = "human_replicate", ratReplicate = "rat_replicate", pvalue = "p-value", alternative = "alternative_hypothesis",
Conf.int1 = "conf.int1", Conf.int2 ="conf.int2", oddratio = "Odd_Ratio")
for(i in 1:length(ratSplit)) {
for(j in 1:length(humanSplit)) {
ratReplicateName <- names(ratSplit[i])
humanReplicateName <- names(humanSplit[j])
#merging above two based on the one-to-one gene mapping as in geneList defined above.
mergedHumanData <-merge(geneList,humanSplit[[j]], by.x = "human", by.y = "humanGene")
mergedRatData <- merge(geneList, ratSplit[[i]], by.x = "rat", by.y = "ratGene")
mergedHumanData <- mergedHumanData[,c(1,2,4,5)] #rearrange column
mergedRatData <- mergedRatData[,c(2,1,4,5)] #rearrange column
mergedHumanRatData <- rbind(mergedHumanData,mergedRatData) #now the columns are "human", "rat", "alignment", "RNAtype"
agg <- aggregate(RNAtype ~ human+rat, data= mergedHumanRatData, FUN=getGeneType) #agg to make HmYn form
HmRnTable <- table(agg$RNAtype) #table of HmRn ie RNAtype in human and rat.
#now assign these numbers to variables HmYn. Consider cases when some form of HmRy is not present in the table. That's why
#is.integer0 function is used
HyRy <- ifelse(is.integer0(HmRnTable[names(HmRnTable) == "HyRy"]), 0, HmRnTable[names(HmRnTable) == "HyRy"][[1]])
HnRn <- ifelse(is.integer0(HmRnTable[names(HmRnTable) == "HnRn"]), 0, HmRnTable[names(HmRnTable) == "HnRn"][[1]])
HyRn <- ifelse(is.integer0(HmRnTable[names(HmRnTable) == "HyRn"]), 0, HmRnTable[names(HmRnTable) == "HyRn"][[1]])
HnRy <- ifelse(is.integer0(HmRnTable[names(HmRnTable) == "HnRy"]), 0, HmRnTable[names(HmRnTable) == "HnRy"][[1]])
contingencyTable <- matrix(c(HnRn,HnRy,HyRn,HyRy), nrow = 2)
# contingencyTable:
# HnRn --|--HyRn
# |------|-----|
# HnRy --|-- HyRy
#
fisherTest <- fisher.test(contingencyTable)
#make new line out of the result of fisherTest
newLine <- data.frame(t(c(humanReplicate = humanReplicateName, ratReplicate = ratReplicateName, pvalue = fisherTest$p,
alternative = fisherTest$alternative, Conf.int1 = fisherTest$conf.int[1], Conf.int2 =fisherTest$conf.int[2],
oddratio = fisherTest$estimate[[1]])))
result <-rbind(result,newLine) #append newline to result
if(j%%10 = 0) print(c(i,j))
}
}
write.table(result, file = "compareRegAndRev.csv", row.names = FALSE, append = FALSE, col.names = TRUE, sep = ",")
Referring to the accepted answer to Monitor memory usage in R, the amount of memory used by R can be tracked with gc().
If the script is, indeed, running short of memory (which would not surprise me), the easiest way to resolve the problem would be to move the write.table() from the outside to the inside of the loop, to replace the rbind(). It would just be necessary to create a new file name for the CSV file that is written from each output, e.g. by:
csvFileName <- sprintf("compareRegAndRev%03d_%03d.csv",i,j)
If the CSV files are written without headers, they could then be concatenated separately outside R (e.g. using cat in Unix) and the header added later.
While this approach might succeed in creating the CSV file that is sought, it is possible that file might be too big to process subsequently. If so, it may be preferable to process the CSV files individually, rather than concatenating them at all.

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