Stacked barplot in UpSetR - r

I have been looking for a way of having a stacked bar plot in an upsetR graph.
I downloaded the movies data set (from here) and added a column having only two values "M" and "C".
Below, information on how I loaded the data and added the "x" column.
Edit:
m <- read.csv(system.file("extdata", "movies.csv", package = "UpSetR"),
header = T, sep = ";")
nrow(m)
[1] 3883
x<-c(rep("M", 3000), rep("C", 883))
m<-cbind(m, x)
unique(m$x)
[1] M C
This is the structure of the data frame:
str(m)
'data.frame': 3883 obs. of 22 variables:
$ Name : Factor w/ 3883 levels "$1,000,000 Duck (1971)",..: 3577 1858 1483 3718 1175 1559 3010 3548 3363 1420 ...
$ ReleaseDate: int 1995 1995 1995 1995 1995 1995 1995 1995 1995 1995 ...
$ Action : int 0 0 0 0 0 1 0 0 1 1 ...
$ Adventure : int 0 1 0 0 0 0 0 1 0 1 ...
$ Children : int 1 1 0 0 0 0 0 1 0 0 ...
$ Comedy : int 1 0 1 1 1 0 1 0 0 0 ...
$ Crime : int 0 0 0 0 0 1 0 0 0 0 ...
$ Documentary: int 0 0 0 0 0 0 0 0 0 0 ...
$ Drama : int 0 0 0 1 0 0 0 0 0 0 ...
$ Fantasy : int 0 1 0 0 0 0 0 0 0 0 ...
$ Noir : int 0 0 0 0 0 0 0 0 0 0 ...
$ Horror : int 0 0 0 0 0 0 0 0 0 0 ...
$ Musical : int 0 0 0 0 0 0 0 0 0 0 ...
$ Mystery : int 0 0 0 0 0 0 0 0 0 0 ...
$ Romance : int 0 0 1 0 0 0 1 0 0 0 ...
$ SciFi : int 0 0 0 0 0 0 0 0 0 0 ...
$ Thriller : int 0 0 0 0 0 1 0 0 0 1 ...
$ War : int 0 0 0 0 0 0 0 0 0 0 ...
$ Western : int 0 0 0 0 0 0 0 0 0 0 ...
$ AvgRating : num 4.15 3.2 3.02 2.73 3.01 3.88 3.41 3.01 2.66 3.54 ...
$ Watches : int 2077 701 478 170 296 940 458 68 102 888 ...
$ x : Factor w/ 2 levels "M","C": 1 1 1 1 1 1 1 1 1 1 ...
Now I tried to implement the stacked bar plot as follow:
upset(m,
queries = list(
list(query = elements,
params = list("x", "M"), color = "#e69f00", active = T),
list(query = elements,
params = list("x", "C"), color = "#cc79a7", active = T)))
The result looks like this:
As you can see the proportions are wrong as there should be in each bar only two colors (factor) either "M" or "C".
This issue seems to be not a trivial one, as also pointed out here.
Does anyone have an idea on how to implement this in UpsetR?
Thanks a lot

Here is a way to create an upset plot with stacked barplot, but using my ComplexUpset rather than UpSetR:
library(ComplexUpset)
movies = as.data.frame(ggplot2movies::movies)
genres = colnames(movies)[18:24]
# for simplicity of examples, only use the complete data points
movies[movies$mpaa == '', 'mpaa'] = NA
movies = na.omit(movies)
upset(
movies,
genres,
base_annotations=list(
'Intersection size'=intersection_size(
counts=FALSE,
mapping=aes(fill=mpaa)
)
),
width_ratio=0.1
)
Please see more examples in the documentation.
The Installation instructions are available on GitHub: krassowski/complex-upset (there is also a comparison to UpSetR and other packages).

I had a similar problem and found this workaround:
library("UpSetR")
m <- read.csv(system.file("extdata", "movies.csv", package = "UpSetR"),
header = T, sep = ";")
x<-c(rep("M", 2000), rep("Q", 1000), rep("C", 883))
m<-cbind(m, x)
upset(m,
queries = list(
list(query = elements,
params = list("x", c("M","Q", "C")), color = "#e69f00", active = T),
list(query = elements,
params = list("x", c("Q","C")), color = "#cc79a7", active = T),
list(query = elements,
params = list("x", "C"), color = grey(0.7), active = T)))
The problem in the original example is that every query overlays over the total bar separately and starts at y=0. Thus, the remaining black part of the bar always has the exact same height as the purple part at the bottom. The workaround is to systematically add queries of combinations of the different values the variable can take:
Start with a query and a respective color for the combination of all possible values (here c("M","Q","C") as the second parameter to params = list()).
Successively leave out one of the possible values (e.g. c("Q","C") in the first step here). The value left out will be represented by the color of the query, the last one that still included it ("M" in this example).
Continue adding queries until you have only one value left for the second parameter to params = list().
It should be possible do this programmatically for larger numbers of possible values and providing some color palette. But this remains a workaround and a native implementation of stacking the queries would be nice to have--so if you would like to see this functionality, you might consider bumping up the respective issue over at the Github repo.

Below the nice answer by #dlaehnemann but a little bit modified in order to create that list of list using a loop as well as linking wanted colors to it.
m <- read.csv(system.file("extdata", "movies.csv", package = "UpSetR"), header = T, sep = ";")
x<-c(rep("M", 2000), rep("Q", 1000), rep("C", 883))
m<-cbind(m, x)
i<-0
mylist<-list()
vectorUniqueValue <- unique(m$x)
colors = colorRampPalette(c("#332288",'#fdff00','#FF0000',"#CC6677","#88CCEE",'#36870c','#b786d2','#7c3c06',"#DDCC77",'#192194','#52cff4','#4f9c8b',"#4477AA",'#808080'))(length(vectorUniqueValue))
while ( length(vectorUniqueValue)>0 ){
i<-i+1
mylist[[i]]<-list(query = elements, params = list("x",as.character(vectorUniqueValue)), color = colors[i], active = T)
vectorUniqueValue<-vectorUniqueValue[-1]
}
upset(m, queries = mylist)
Hope it helps a bit until maybe one day someone works on the issue on github !

Related

Change a character column to numeric in a data frame

I want to change a column from a dataframe from character to numeric.
My data frame was a .txt file with 12 columns and 1000 rows.
When I passed the .txt file to R, one of my columns is now character.
I tried to use
as.numeric(my_data$iw)
But I get a "Warning message:
NAs introduced by coercion
Here is the data frame structure:
data.frame': 1000 obs. of 12 variables:
$ im : num 0 15396 16537 20252 17967 ...
$ iw : chr "20064.97" "7397.191" "18380.77" "14042.25" ...
$ r : num 5984 0 0 0 0 ...
$ am : num 0 42 33 38 24 62 27 38 0 29 ...
$ af : num 38 30 28 38 39 42 18 33 24 35 ...
$ a1c: num 0 1 1 1 1 0 0 1 0 1 ...
$ a2c: num 0 0 0 1 0 0 0 1 0 1 ...
$ a3c: num 0 0 0 0 0 0 0 1 0 0 ...
$ a4c: num 0 0 0 0 0 0 0 0 0 0 ...
$ a5c: num 0 0 0 0 0 0 0 0 0 0 ...
$ a6c: num 0 0 0 0 0 0 0 0 0 0 ...
$ a7c: num 0 0 0 0 0 0 0 0 0 0 ...
May I change it with gsub?
structure(list(im = c(0, 15395.61, 16536.74, 20251.87, 17967.04,
12686.43, 16833.22, 16919.34, 0, 20515.88, 17991.9, 15528.29,
16683.96, 14485.19, 17957.98, 19923.31, 13526.9, 16516.68, 16337.52,
12904.97, 17418.99, 12419.21, 14561.9, 12309.77, 21138.87, 0,
17315.74, 17762.09, 12678.82, 13883.37, 11140.66, 16502.91, 18293.78,
12533.36, 16536.61, 4336.741, 22449.17, 16532.1, 0, 15905.14,
0, 8542.03, 12589.29, 15154.76, 15441.59, 18575.05, 15915.47,
0, 15085.51, 16597.42, 15358.47, 22480.95, 10555.28, 21771.2,
22863.56, 15937.55, 12230.58, 17814.67, 7972.471, 10286.75, 15335.8,
10762.59, 18583.2, 12167.99, 21723.37, 15670.79, 13045.83, 13305.73,
14305.99, 10353.15, 4504.009, 10157.7, 15967.28, 23640.21, 15053.78,
21404.11, 8509.353, 15693.39, 9009.99, 17249.29, 9115.844, 16057.39,
14069.93, 0, 0, 16840.09, 0, 15289.29, 12223.93, 13048.58, 18524.13,
14344.22, 20658.66, 0, 0, 13984.69, 21636.72, 13969.12, 12919.83,
13214.16, 17066.98, 20060.25, 11414.15, 12907.53, 11289.97, 17600.97,
14741.77, 12089.57, 13603.85, 9330.662, 0, 16191.81, 12029.75,
12666.29, 8138.166, 10636.2, 22570.1, 12833.66, 12585.56, 20197.42,
12621.56, 19021.65, 9948.49, 25772.41, 15102.54, 19225.57, 11188.96,
11707.66, 9766.824, 16082.82, 17693.2......
To read in the .txt file, I wrote:
my_data <- read.table("project.txt", header=TRUE);
As some comments already said, this is because either there are some rows which cannot be coerced to numeric. An unsuitable description of missing data or maybe a comma to denote decimals as in
expl <- read.table(text = "1.0 2.0 2,3
2.0 2.1 2.5
. 2.2 2.1")
str(expl)
which leads to
> str(expl)
'data.frame': 3 obs. of 3 variables:
$ V1: chr "1.0" "2.0" "."
$ V2: num 2 2.1 2.2
$ V3: chr "2,3" "2.5" "2.1"
for the reasons stated above.
It is not always easy to find the culprid in 1000 lines, but something like this may help:
> which(is.na(as.numeric(expl$V1)))
[1] 3
This will provide you with the row numbers that produce NA in conversion.

How to adapt the 'Oaxaca' package regression model to make the results independent from indicator variables' reference categories?

I am writing a paper on the gender pay gap in Lithuania, and my goal is to interpret statistical survey data, determining the factors partially explaining the wage gap (such as age, tenure, education, etc.), using the Oaxaca-Blinder decomposition.
I have very little knowledge of 'R', although in University I did have some classes, mostly about linear regression models. Please excuse if my questions are not well-formulated. Any comments and advice will be greatly appreciated.
I came across the 'Oaxaca' package for 'R', but have not been able to fully adapt the 'formula' function to my data. The instructions of the package:
https://cran.r-project.org/web/packages/oaxaca/oaxaca.pdf
My problem is not understanding how to properly use the 'formula' function for my data, which contains a lot of non-numeric variables that I tried to turn into indicator ("dummy") variables with values of "0" or "1".
Specifically, I cannot adjust the formula to make the result invariant to the selected reference category. When I try to do this, I get the error message: "Variables d1 + d2 + d3 + ... in argument 'formula' must indicate membership in mutually exclusive categories."
The 'Oaxaca' formula that more or less works for me looks like this:
1) y ~ x1 + x2 + x3 + ... | z
Here y is the dependent variable, x1 + x2 + x3 + ... are explanatory
variables and z is an indicator variable that states whether an observation belongs to Group B (female) or group A (male).
The formula adjusted for reference category:
2) y ~ x1 + x2 + x3 + ... | z | d1 + d2 + d3 + ...
Here, d1 + d2 + d3 + ... are indicator ("dummy") variables that will
be adjusted so that the decomposition results do not change depending on the
user’s choice of the reference category (Gardeazabal and Ugidos, 2004).
I cannot run formula 2), but I can run formula 1) when I delete a couple of dummy variables, otherwise I get an error.
I have 5 levels (separate variables) for Age (1st - 14 to 19, 2nd - 20 to 29, 3rd - 30 to 39, etc.), 4 levels for tenure (1st - 0 to 2, 1nd - 2 to 4 years), 15 levels for Industry, 63 levels for Occupation, etc. I am going to call Age, Tenure, Industry and Occupation my different 'types' that should each have their own reference category ommitted from the formula.
Since I use a lot of 'types' of indicator variables, what I don't understand is, how does 'R' recognize which reference category belongs to which 'type'?
Maybe 'R' reads all "dummy" variables as levels of the same 'type', and selects only 1 ommitted variable as reference category for all the variables?
Is there any way that you know in which I could adapt my data to specify the correct reference category for each 'type'? Judging by the example with 'Chicago' dataframe it seems like I have too many different 'types' of variables for this formula to work.
The original data I have is from the Lithuanian Structure of Earnings Survey 2014. I have created new data in excel (later converted to a .csv file) using the original, following the example of the 'Chicago' dataframe, used in the 'Oaxaca' package example. The data created is mostly made of dummy variables with the values of "0" or "1", except for the Hours column, which contains hours worked in a month, and the log.wage column, containing the natural logarythm of the hourly wage. Everything else is indicator variables. However, these indicator variables belong to different types, as mentioned already, such as Age, Tenure, etc.
I have been unsuccessful in trying to manipulate the original dataset to create indicator variables using 'R', because I need to create specific new variables from a variety of the existing ones, for example all the occupations coded 431 and 432 should be merged into 1 variable titled 'prof43'. I have not found out how to do this so far.
My data contains mostly indicator variables and the variable types look like this:
str(S14)
'data.frame': 44952 obs. of 71 variables:
$ hours : int 1 1 1 1 2 1 1 2 1 1 ...
$ female : int 0 1 1 1 0 0 0 1 0 0 ...
$ age0 : int 0 0 0 0 0 0 0 0 0 0 ...
$ age1 : int 1 1 0 0 0 0 0 1 1 0 ...
$ age2 : int 0 0 0 1 0 1 0 0 0 0 ...
$ age3 : int 0 0 1 0 1 0 0 0 0 1 ...
$ age4 : int 0 0 0 0 0 0 0 0 0 0 ...
$ age5 : int 0 0 0 0 0 0 1 0 0 0 ...
$ prof11 : int 0 0 0 0 0 0 0 0 0 0 ...
......
$ prof96 : int 0 0 0 0 1 0 0 0 0 0 ...
$ edu1 : int 0 0 0 0 0 0 0 0 1 0 ...
$ edu2 : int 0 1 0 0 1 1 0 1 0 1 ...
$ edu3 : int 1 0 1 1 0 0 1 0 0 0 ...
$ ten1 : int 1 1 1 1 1 1 1 1 1 1 ...
$ ten2 : int 0 0 0 0 0 0 0 0 0 0 ...
$ ten3 : int 0 0 0 0 0 0 0 0 0 0 ...
$ ten4 : int 0 0 0 0 0 0 0 0 0 0 ...
$ size1to50: int 1 1 0 1 1 1 0 1 1 1 ...
$ nace1 : int 0 0 0 0 0 0 0 0 0 0 ...
$ nace2 : int 0 0 0 0 0 0 0 0 0 0 ...
......
$ nace15 : int 0 0 0 0 0 0 0 0 0 0 ...
$ pubcon : int 0 0 0 0 0 0 0 0 0 0 ...
$ temp : int 0 0 0 0 0 0 0 0 0 0 ...
$ log.wage : num 1.79 1.79 1.79 1.79 1.79 ...
I run the 'Oaxaca' function using these codes:
library(oaxaca)
set.seed(03104) #random seed
I get results from this, yet I doubt their validity due to the fact that I delete 1 non-zero indicator variable (prof 62) (otherwise it doesn't run):
results0 <- oaxaca(log.wage ~ hours + pubcon + temp + size1to50 + age0 + age1 + age2 +
age4 + age5 + ten1 + ten2 + ten4 + edu1 + edu3 + prof11 + prof12 + ..... +
prof96 + nace1 + nace2 + ... + nace14 | female, data = S14, R = 30)
# 1) y ~ x1 + x2 + x3 + ... | z
The code that gets the error message for me:
results1 <- oaxaca(log.wage ~ hours + pubcon + temp + size1to50 +
age0 + age1 + age2 + age4 + age5 + ten1 + ten2 + ten4 + edu1 + edu3 +
prof11 + prof12 + ..... + prof96 + nace1 + nace2 + ... + nace14 | female |
pubcon + temp + size1to50 + age0 + age1 + age2 + age4 + age5 + ten1 + ten2 +
ten4 + edu1 + edu3 + prof11 + prof12 + ..... + prof96 + nace1 + nace2 + ... + nace14,
data = S14, R = 30) # 2) y ~ x1 + x2 + x3 + ... | z | d1 + d2 + d3 + ...
Running this, I get the error message:
Variables d1 + d2 + d3 + ... in argument 'formula' must indicate membership in mutually exclusive categories.
Does anyone have any suggestions?
Do you think using the original dataset and sorting it into indicator variables using 'R' would work, and I could select the reference category which the function 'formula' would recognize?
If so, what package and formulas do you suggest using to adapt my data?
Or do you think I am using too many variables for this 'Oaxaca' package and I should restrict my data?
Also, do the resulsts I get with formula 1) make sense? I am worried that 'R' does not choose the correct reference category for each 'type' of variable set resulting in all the indicator variables being dependent on some random ommitted variable, which would make the results nonsensical.
Excuse my lengthly ramblings, I hope I made some sense and if anyone has any experience of working with the 'Oaxaca' package or any ideas on what to do here and want to voice them - I am extremely grateful in advance!
I wrote the creator of the package and sent him a link to this page since I was having the same problem. Here is what he responded: "It looks like you are trying to include several (independent) sets of dummy variables, hence the error message. The oaxaca package, unfortunately, does not support this."
For what it's worth, it appears like oaxaca in Stata does support this, if you are looking for an alternative.

Error return by R predict function or underlying Rcpp

I apparently have successively used a newer R package called milr, multiple instance logistic regression. Admittedly, I do not make any claims regarding the goodness of the model. However, when I try to use the model to predict I get the error
Error in logit(cbind(1, newdata), .) : not compatible with requested type
when I call predict as follows:
miltp <- predict(milt, SQFM.te, SQFM.teb, type="bag") and
miltp <- predict(milt, SQFM.te, SQFM.teb)
However I get a NULL return when I call it as:
miltp <- predict(milt, SQFM.te, SQFM.teb, type="response") and
miltp <- predict(milt, SQFM.te, SQFM.teb, type="class")
I have tried using factors, integers and numerics, I am perplexed. My online search only yielded
Rcpp: Error: not compatible with requested type
which is not helpful for me as R and C++ is over my head. All comments are appreciated, some input info is given below I have tried some conversions
str(SQFM.te)
'data.frame': 100369 obs. of 5 variables:
$ arstmade: int 0 0 0 0 0 0 0 0 0 0 ...
$ perstop : int 0 0 0 0 0 0 0 0 0 0 ...
$ trhsloc : int 0 0 0 0 0 0 0 0 0 0 ...
$ acrept : int 0 0 0 0 0 0 0 0 0 0 ...
$ radio : int 1 1 1 1 1 1 1 1 1 1 ...
str(SQFM.teb)
int [1:100369] 3 3 3 3 3 3 3 3 3 3 ...
print(milt)
Coefficients:
intercept arstmade perstop trhsloc acrept radio
-1.69306 -0.09544 -7.95369 -0.53375 0.16506 -0.61778
Residual Deviance: Inf
BIC: Inf

Reorder a list of dataframes before rbind (R)

I'm working with R and I have a problem with rbinding dataframe.
My data come from a Json file and the first think I have done is to split it accordingly to Chromosome number
#Input
Control <- fromJSON(file=O5)
RNAi <- fromJSON(file=s25p5)
#Loop throug each chromosome
Control.1 <- lapply(Control, function(I)
{
data.frame(matrix(unlist(I),ncol = 1, byrow = TRUE))
})
The problem is that now I have a list of 6 data.frame but on a random order
str(Control.1)
List of 6
$ II :'data.frame': 1771887 obs. of 1 variable:
..$ matrix.unlist.I...ncol...1..byrow...TRUE.: num [1:1771887] 0 0 0 0 0 0 0 0 0 0 ...
$ I :'data.frame': 1507243 obs. of 1 variable:
..$ matrix.unlist.I...ncol...1..byrow...TRUE.: num [1:1507243] 0 0 0 0 0 0 0 0 0 0 ...
$ III :'data.frame': 1378370 obs. of 1 variable:
..$ matrix.unlist.I...ncol...1..byrow...TRUE.: num [1:1378370] 0 0 0 0 0 0 0 0 0 0 ...
etc.
I would like to reorder them in order to have $I as the first data.frame, then $II etc.
my aim is to use rbind after
Control.2 <-do.call(rbind,Control.1)
in order to have one data frame containing all the data frame but in the correct oder.
Does anybody have any idea how it could be done?
Thank you!
for alphabetical order you can use :
Control.2 <-do.call(rbind,Control.1[order(names(Control.1)))
or you can use any other function than order to sort the names vector.

Conditional input using read.table or readLines

I'm struggling with using readLines() and read.Table() to get a well formatted data frame in R.
I want to read files like this which are Hockey stats. I'd like to get a nicely formatted data frame, however, specifying the concrete amount of lines to read is difficult because in other files like this the number of players is different. Also, non-players, signed as #.AC, #.HC and so on, should not be read in.
I tried something like this
LINES <- 19
stats <- read.table(file=Datei, skip=11, header=FALSE, stringsAsFactors=FALSE,
encoding="UTF-8", nrows=LINES)
but as mentioned above, the value for LINES is different each time.
I also tried readLines as in this post, but had no luck with it.
Is there a way to integrate a condition in read.table, like (pseudo code)
if (first character == "AC") {
break read.table
}
Sorry if this looks strange, I don't have that much experience in scripting or coding.
Any help is appreciated, thanks a lot!
Greetz!
Your data show a couple of difficulties which should be handled in a sequence, which means you should not try to read the entire file with one command:
Read plain lines and find start and stop row
Depending on the specification of the files you read in my suggestion is to first find the the first row you actually want to read in by any indicator. So this can be a lone number which is always the same or as in my example two lines after the line "TEAM STATS". Finding the last line is then simple again by just looking for the first line containing only whitespaces after the start line:
lines <- readLines( Datei )
start <- which(lines == "TEAM STATS") + 2
end <- start + min( grep( "^\\s+$", lines[ start:length(lines) ] ) ) -2
lines <- lines[start:end]
Read the data to data.frame
In your case you meet a couple of complications:
Your header line starts with an # which is on default recognized as a comment character, ignoring the line. But even if you switch this behavior off (comment.char = "") it's not a valid column name.
If we tell read.table to split the columns along whitespaces you end up with one more column in the data, than in the header since the Player column contains white spaces in the cells. So the best is at the moment to just ignore the header line and let read.table do this with it's default behavior (comment.char = "#"). Also we let the PLAYER column be split into two and will fix this later.
You won't be able to use the first column as row.names since they are not unique.
The rows have unequal length, since the POS column is not filled everywhere.
:
tab <- read.table( text = lines[ start:end ], fill = TRUE, stringsAsFactors=FALSE )
# fix the PLAYER column
tab$V2 <- paste( tab$V2, tab$V3 )
tab <- tab[-3]
Fix the header
Just split the start line at multiple whitespaces and reset the first entry (#) by a valid column name:
colns <- strsplit( lines[start], "\\s+" )[[1]]
colns[1] <- "code"
colnames(tab) <- colns
Fix cases were "POS" was empty
This is done by finding the rows which last cell contains NAs and shift them by one cell to the right:
colsToFix <- which( is.na(tab[, "SHO%"]) )
tab[ colsToFix, 4:ncol(tab) ] <- tab[ colsToFix, 3:(ncol(tab)-1) ]
tab[ colsToFix, 3 ] <- NA
> str(tab)
'data.frame': 25 obs. of 20 variables:
$ code : chr "93" "91" "61" "88" ...
$ PLAYER: chr "Eichelkraut, Flori" "Müller, Lars" "Alt, Sebastian" "Gross, Arthur" ...
$ POS : chr "F" "F" "D" "F" ...
$ GP : chr "8" "6" "7" "8" ...
$ G : int 10 1 4 3 4 2 0 2 1 0 ...
$ A : int 5 11 5 5 3 4 6 3 3 4 ...
$ PTS : int 15 12 9 8 7 6 6 5 4 4 ...
$ PIM : int 12 10 12 6 2 36 37 29 6 0 ...
$ PPG : int 3 0 1 1 1 1 0 0 1 0 ...
$ PPA : int 1 5 2 2 1 2 4 2 1 1 ...
$ SHG : int 0 1 0 1 1 0 0 0 0 0 ...
$ SHA : int 0 0 1 0 1 0 0 1 0 0 ...
$ GWG : int 2 0 1 0 0 0 0 0 0 0 ...
$ FG : int 1 0 1 1 1 0 0 0 0 0 ...
$ OTG : int 0 0 0 0 0 0 0 0 0 0 ...
$ UAG : int 1 0 1 0 0 0 0 0 0 0 ...
$ ENG : int 0 0 0 0 0 0 0 0 0 0 ...
$ SHOG : int 0 0 0 0 0 0 0 0 0 0 ...
$ SHOA : num 0 0 0 0 0 0 0 0 0 0 ...
$ SHO% : num 0 0 0 0 0 0 0 0 0 0 ...

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