easyadmin entity field's dynamic custom choices - symfony

Question

Installed easyadminbundle with symfony 4, configured for an entity name Delivery and it has a field associated to another entity name WeeklyMenu:
easy_amin.yaml:
Delivery:
...
form:
fields:
- { property: 'delivered'}
- { property: 'weeklyMenu', type: 'choice', type_options: { choices: null }}
I need a dynamically filtered results of weeklyMenu entity here, so I can get a list of the next days menus and so on. It's set to null now but have to get a filtered result here.
I've read about overriding the AdminController which I stucked with it. I believe that I have to override easyadmin's query builder that listing an associated entity's result.

Answer 1

i've figured out, here is the solution if someone looking for:
namespace App\Controller;
use Doctrine\ORM\EntityRepository;
use EasyCorp\Bundle\EasyAdminBundle\Controller\EasyAdminController;
use Symfony\Bridge\Doctrine\Form\Type\EntityType;
use Symfony\Component\Form\FormBuilder;
class AdminController extends EasyAdminController {
public function createDeliveryEntityFormBuilder($entity, $view) {
$formBuilder = parent::createEntityFormBuilder($entity, $view);
$fields = $formBuilder->all();
/**
* #var $fieldId string
* #var $field FormBuilder
*/
foreach ($fields as $fieldId => $field) {
if ($fieldId == 'weeklyMenu') {
$options = [
'attr' => ['size' => 1,],
'required' => true,
'multiple' => false,
'expanded' => false,
'class' => 'App\Entity\WeeklyMenu',
];
$options['query_builder'] = function (EntityRepository $er) {
$qb = $er->createQueryBuilder('e');
return $qb->where($qb->expr()->gt('e.date', ':today'))
->setParameter('today', new \DateTime("today"))
->andWhere($qb->expr()->eq('e.delivery', ':true'))
->setParameter('true', 1)
->orderBy('e.date', 'DESC');
};
$formBuilder->add($fieldId, EntityType::class, $options);
}
}
return $formBuilder;
}
}
so the easyAdmin check if a formbuilder exists with the entity's name i.e. create<ENTITYNAME>FormBuilder(); and you can override here with your own logic.

Answer 2

Another approach to this would be to create new FormTypeConfigurator and overwrite choices and/or labels. And tag it as:
App\Form\Type\Configurator\UserTypeConfigurator:
tags: ['easyadmin.form.type.configurator']
and the configurator looks like this:
<?php
declare(strict_types = 1);
namespace App\Form\Type\Configurator;
use App\Entity\User;
use EasyCorp\Bundle\EasyAdminBundle\Form\Type\Configurator\TypeConfiguratorInterface;
use Symfony\Component\Form\Extension\Core\Type\ChoiceType;
use Symfony\Component\Form\FormConfigInterface;
final class UserTypeConfigurator implements TypeConfiguratorInterface
{
/**
* {#inheritdoc}
*/
public function configure($name, array $options, array $metadata, FormConfigInterface $parentConfig)
{
if ($parentConfig->getData() instanceof User) {
$options['choices'] = User::getUserStatusAvailableChoices();
}
return $options;
}
/**
* {#inheritdoc}
*/
public function supports($type, array $options, array $metadata)
{
return in_array($type, ['choice', ChoiceType::class], true);
}
}