When adding data with the block call.StorageValue, the string is saved in firebase with "/" before and after the string,
There does not seem to be any block to remove it, How can I do it?
It's a normal firebase function that allows to separate the values and read them as such.
Example :
on Firebase, "\"English-EN\"" is a single value sent from the app as English-EN
and "[\"863674037411046\",\"863674037411046\",\"863674037411046\",\"863674037411046\"]" is a list of numbers sent as 863674037411046.
Try to retrieve the value with a button and to a simple label and you should see that it's displayed without the extra characters.
Source:check my app "harpokrates". I've made it as a firebase DB management demo and it uses nothing else. All values are stored as you describe and are retrieved just fine, without extra symbols or any need to trim the text.
ps:However if you do have extra symbols at some point, check your use of lists and lists of lists that might generate excessive "\" if you made a mistake somewhere. You can also use the "trim" or "split text" blocks but that would be bad practice. Finding the code error is best.
This is likely an escape character that escapes the special character " (quotation marks). This is common practice to use \ as an escape character to indicate that the next character has special meaning, in this case it is not the start or end of a string but actually part of it.
As such you can't actually remove it (just the escape character) and should consider how you got a quotation mark in the string to begin with.
You should however be able to remove the entire quotation mark \"
Related
Let me preface this by stating very clearly that I am not a developer and I'm new to NetSuite formulas.
I have a NetSuite saved search that include the Web Address (field id: {url})
I need to remove everything except the main part of the domain (end result should look like abc.com).
I have attempted to use REPLACE({url}, 'http://[,' ']) unsuccessfully.
I have also attempted various LTRIM, RTRIM, TRIM formulas without luck.
I found some information on using REGEXP_SUBSTR, but wasn't successful there either.
I was able to accomplish my goal in Excel using Excel string functions MID, LEN, and RIGHT, but that doesn't seem to translate in NetSuite.
I'd love some assistance.
REGEXP_SUBSTR({url}, '//(.)+') --> get substring starting with //
REPLACE({text}, '/') --> replace / with nothing
The final formula is:
REPLACE(REGEXP_SUBSTR({url}, '//(.)+'), '/')
Jala's answer doesn't seem to work for URLs such as https://stdun7.wixsite.com/stdunstansparish where it returns stdun7.wixsite.comstdunstansparish
In your saved search create a Forumula (Text) field with the following formula
REGEXP_REPLACE({url},'(^http[s]?://)([a-zA-Z0-9.-])(/?.)', '\2')
I'll break down the arguments for the REGEXP_REPLACE function and how it all works...
First argument - {url} the Field containing the url information to parse
Second argument - regexp string
Third argument = replace regexp string
the regexp string has parentheses to denote capture groups of portions of the regular expression.
The first capture group captures the protocol portion of the URL.
The second capture group captures the next part, all permissible hostname characters until the end of the string, or until a '/'
The third capture group captures the remaining portion of the string.
The replace string is used to prepare the return value of the REGEXP_SUBSTR function. Since the entire url is matched by the regexp, the entire string will be replaced by this expression, referencing the second capture group. (aka the hostname)
Since you say you're new to NetSuite formulas, I'll note that those functions are based on Oracle PL/SQL so if you want additional info or examples of how they work beyond what NetSuite provide, sometimes it's instructive to just google things like "pl/sql REGEXP_SUBSTR" etc. to get additional documentation how how they work.
Another good resource is regex101.com, a helpful site to test regular expressions in advance....
Can anyone tell me how to remove unwanted characters from username field.
ex: i:0#.w|abcventures\sreekiran.k I need to remove the characters which are generated before abcventures\sreekiran.k.
I have used translate() to eliminate those characters, but, it is removing i & w characters also, from the username.
To expand on the current answers, I think they meant to use substring-after(). This will do the trick:
substring-after(userName(), "i:0#.w|")
To expand on Mekalikot's answer -
substring-before(userName(), "i:0#.w|")
Will return just the string after the "i:0#.w|" from the user name function. If the user name function does not include that string, however, the formula will return nothing. Since you'll get a different value from the user name function in preview vs. the browser, you'll probably need to test this with the published form.
Use substring-before to remove those characters.
What is the default regular expression used by asp.net create user wizard?
According to the MSDN documentation, it should be something like this:
Regular Expression: #\"(?:.{7,})(?=(.*\d){1,})(?=(.*\W){1,})
Validation Message: Your password must be 7 characters long, and contain at least one number and one special character.
However, it does not work as it does not accept something like 3edc£edc, which is actually accepted when using the default create user wizard.
Any idea about how can I get this regular expression?
The error is in the ?: in (?:.{7,})(?=(.*\d){1,})(?=(.*\W){1,}) that is "consuming" the fist seven characters or more characters. It should be ?= OR you can invert the order: (?=(.*\d){1,})(?=(.*\W){1,})(?:.{7,})
Just change the order
^(?=(.*\d))(?=(.*\W)).{7,}
I additionally removed the {1,} and anchored it to the start of the string and you don't need a group around the last part
See it here on Regexr
Looks like a simple task - get a regex that tests a string for particular length:
^.{1,500}$
But if a string has "\r\n" than the above match always fails!
How should the correct regex look like to accept new line characters as part of the string?
I have a <asp:TextBox TextMode="Multiline"> and use a RegularExpressionValidator to check the length of what user types in.
Thank you,
Andrey
You could use the RegexOptions.Singleline option when validating input. This treats the input as a single line statement, and parses it as such.
Otherwise you could give the following expression a try:
^(.|\s){1,500}$
This should work in multiline inputs.
Can you strip the line breaks before checking the length of the string? That'd be easy to do when validating server-side. (In .net you could use a custom validator for that)
From a UX perspective, though, I'd implement a client-side 'character counter' as well. There's plenty to be found. jQuery has a few options. Then you can implement the custom validator to only run server-side, and then use the character counter as your client-side validation. Much nicer for the user to see how many characters they have left WHILE they are typing.
The inability to set the RegexOptions is screwing you up here. Since this is in a RegularExpressionValidator, you could try setting the options in the regular expression itself.
I think this should work:
(?s)^.{1,500}$
The (?s) part turns on the Singleline option which will allow the dot to match every character including line feeds. For what it's worth, the article here also lists the other RegexOptions and the notation needed to set them as an inline statement.
I'm using an asp.net Web Forms RegularExpressionValidator Control to validate a text field to ensure it contains a series of email addresses separated by semicolons.
What is the proper regex for this task?
I think this one will work:
^([A-Za-z0-9._%+-]+#[A-Za-z0-9.-]+\.[A-Za-z]{2,4}(;|$))+
Breakdown:
[A-Za-z0-9._%+-]+#[A-Za-z0-9.-]+\.[A-Za-z]{2,4} : valid email (from http://www.regular-expressions.info/)
(;|$) : either semicolon or end of string
(...)+ : repeat all one or more times
Make sure you are using case-insensitive matching. Also, this pattern does not allow whitespace between emails or at the start or end of the string.
The 'proper' (aka RFC2822) regex is too complicated. Try something like (\S+#[a-zA-Z0-9-.]+(\s*;\s*|\s*\Z))+
Not perfect but should be there 90% (haven't tried it, so it might need some alteration)
Note: Not too sure about \Z it might be a Perl only thing. Try $ as well if it doesn't work.