How do I transform a string of expression into a quotable expression?
Example:
This is the result I want:
mutate(mtcars,answer=wt+wt)
# mpg cyl disp hp drat wt qsec vs am gear carb answer
# 1 21.0 6 160.0 110 3.90 2.620 16.46 0 1 4 4 5.240
# 2 21.0 6 160.0 110 3.90 2.875 17.02 0 1 4 4 5.750
# 3 22.8 4 108.0 93 3.85 2.320 18.61 1 1 4 1 4.640
# 4 21.4 6 258.0 110 3.08 3.215 19.44 1 0 3 1 6.430
# 5 18.7 8 360.0 175 3.15 3.440 17.02 0 0 3 2 6.880
# 6 18.1 6 225.0 105 2.76 3.460 20.22 1 0 3 1 6.920
...
Here's the function I am writing:
f<-function(df,string_expression){
se<-enexpr(string_expression)
mutate(df,answer=!!se)
}
It will work if I use the following functional call:
f(mtcars,wt+wt)
# mpg cyl disp hp drat wt qsec vs am gear carb answer
# 1 21.0 6 160.0 110 3.90 2.620 16.46 0 1 4 4 5.240
# 2 21.0 6 160.0 110 3.90 2.875 17.02 0 1 4 4 5.750
# 3 22.8 4 108.0 93 3.85 2.320 18.61 1 1 4 1 4.640
# 4 21.4 6 258.0 110 3.08 3.215 19.44 1 0 3 1 6.430
# 5 18.7 8 360.0 175 3.15 3.440 17.02 0 0 3 2 6.880
# 6 18.1 6 225.0 105 2.76 3.460 20.22 1 0 3 1 6.920
...
However, I would like to provide the expression as a string, so I must use the following function call:
f(mtcars,'wt+wt')
# mpg cyl disp hp drat wt qsec vs am gear carb answer
# 1 21.0 6 160.0 110 3.90 2.620 16.46 0 1 4 4 wt+wt
# 2 21.0 6 160.0 110 3.90 2.875 17.02 0 1 4 4 wt+wt
# 3 22.8 4 108.0 93 3.85 2.320 18.61 1 1 4 1 wt+wt
# 4 21.4 6 258.0 110 3.08 3.215 19.44 1 0 3 1 wt+wt
# 5 18.7 8 360.0 175 3.15 3.440 17.02 0 0 3 2 wt+wt
...
How do I make it (either change the function definition or function call) to get the result I want?
What I have tried:
I have tried to sym(string_expression) -- didn't work.
I have tried to quo(string_expression) -- didn't work.
Thank you!
You could change your f function to something this:
f<-function(df,string_expression){
mutate(df, answer = eval(parse(text = string_expression)))
}
head(f(mtcars,'wt+wt'))
mpg cyl disp hp drat wt qsec vs am gear carb answer
1 21.0 6 160 110 3.90 2.620 16.46 0 1 4 4 5.24
2 21.0 6 160 110 3.90 2.875 17.02 0 1 4 4 5.75
3 22.8 4 108 93 3.85 2.320 18.61 1 1 4 1 4.64
4 21.4 6 258 110 3.08 3.215 19.44 1 0 3 1 6.43
5 18.7 8 360 175 3.15 3.440 17.02 0 0 3 2 6.88
6 18.1 6 225 105 2.76 3.460 20.22 1 0 3 1 6.92
Related
This question already has answers here:
adding last value to the top of the data frame.
(4 answers)
Closed 3 years ago.
I have a data frame and I'd like to reorder it. I'd like to make the last row the top row.
Example, if I type mtcars into the console the last car listed is a volvo 142E. Suppose I wanted to make this the first row, how would I do that?
dplyr/tidyverse or base r preferred.
In base R -
mtcars[c(nrow(mtcars), seq(nrow(mtcars)-1)), ]
# top 6 rows
mpg cyl disp hp drat wt qsec vs am gear carb
Volvo 142E 21.4 4 121 109 4.11 2.780 18.60 1 1 4 2
Mazda RX4 21.0 6 160 110 3.90 2.620 16.46 0 1 4 4
Mazda RX4 Wag 21.0 6 160 110 3.90 2.875 17.02 0 1 4 4
Datsun 710 22.8 4 108 93 3.85 2.320 18.61 1 1 4 1
Hornet 4 Drive 21.4 6 258 110 3.08 3.215 19.44 1 0 3 1
Hornet Sportabout 18.7 8 360 175 3.15 3.440 17.02 0 0 3 2
Here's a generalized function for moving any row to top -
move_to_top <- function(df, n) {
df[c(n, setdiff(1:nrow(df), n)), ]
}
head(move_to_top(mtcars, 32))
mpg cyl disp hp drat wt qsec vs am gear carb
Volvo 142E 21.4 4 121 109 4.11 2.780 18.60 1 1 4 2
Mazda RX4 21.0 6 160 110 3.90 2.620 16.46 0 1 4 4
Mazda RX4 Wag 21.0 6 160 110 3.90 2.875 17.02 0 1 4 4
Datsun 710 22.8 4 108 93 3.85 2.320 18.61 1 1 4 1
Hornet 4 Drive 21.4 6 258 110 3.08 3.215 19.44 1 0 3 1
Hornet Sportabout 18.7 8 360 175 3.15 3.440 17.02 0 0 3 2
Here's a base R method which also works for rows other than the last row
to_top <- nrow(mtcars)
mtcars[order(seq(nrow(mtcars)) != to_top),]
# mpg cyl disp hp drat wt qsec vs am gear carb
# Volvo 142E 21.4 4 121.0 109 4.11 2.780 18.60 1 1 4 2
# Mazda RX4 21.0 6 160.0 110 3.90 2.620 16.46 0 1 4 4
# Mazda RX4 Wag 21.0 6 160.0 110 3.90 2.875 17.02 0 1 4 4
# Datsun 710 22.8 4 108.0 93 3.85 2.320 18.61 1 1 4 1
# Hornet 4 Drive 21.4 6 258.0 110 3.08 3.215 19.44 1 0 3 1
# ...
to_top <- which(rownames(mtcars) == 'Valiant')
mtcars[order(seq(nrow(mtcars)) != to_top),]
# mpg cyl disp hp drat wt qsec vs am gear carb
# Valiant 18.1 6 225.0 105 2.76 3.460 20.22 1 0 3 1
# Mazda RX4 21.0 6 160.0 110 3.90 2.620 16.46 0 1 4 4
# Mazda RX4 Wag 21.0 6 160.0 110 3.90 2.875 17.02 0 1 4 4
# Datsun 710 22.8 4 108.0 93 3.85 2.320 18.61 1 1 4 1
# Hornet 4 Drive 21.4 6 258.0 110 3.08 3.215 19.44 1 0 3 1
# Hornet Sportabout 18.7 8 360.0 175 3.15 3.440 17.02 0 0 3 2
# Duster 360 14.3 8 360.0 245 3.21 3.570 15.84 0 0 3 4
# Merc 240D 24.4 4 146.7 62 3.69 3.190 20.00 1 0 4 2
# ...
You can also use setdiff for the same result
mtcars[c(to_top, setdiff(seq(nrow(mtcars)), to_top)),]
Or the order method in dplyr
library(dplyr)
mtcars %>%
rownames_to_column() %>%
arrange(row_number() != n())
# rowname mpg cyl disp hp drat wt qsec vs am gear carb
# 1 Volvo 142E 21.4 4 121.0 109 4.11 2.780 18.60 1 1 4 2
# 2 Mazda RX4 21.0 6 160.0 110 3.90 2.620 16.46 0 1 4 4
# 3 Mazda RX4 Wag 21.0 6 160.0 110 3.90 2.875 17.02 0 1 4 4
# 4 Datsun 710 22.8 4 108.0 93 3.85 2.320 18.61 1 1 4 1
# 5 Hornet 4 Drive 21.4 6 258.0 110 3.08 3.215 19.44 1 0 3 1
# 6 Hornet Sportabout 18.7 8 360.0 175 3.15 3.440 17.02 0 0 3 2
# ...
Another idea is to subset and bind rowwise, i.e.
rbind(tail(mtcars, 1), head(mtcars, -1))
# mpg cyl disp hp drat wt qsec vs am gear carb
#Volvo 142E 21.4 4 121.0 109 4.11 2.780 18.60 1 1 4 2
#Mazda RX4 21.0 6 160.0 110 3.90 2.620 16.46 0 1 4 4
#Mazda RX4 Wag 21.0 6 160.0 110 3.90 2.875 17.02 0 1 4 4
#Datsun 710 22.8 4 108.0 93 3.85 2.320 18.61 1 1 4 1
#Hornet 4 Drive 21.4 6 258.0 110 3.08 3.215 19.44 1 0 3 1
#Hornet Sportabout 18.7 8 360.0 175 3.15 3.440 17.02 0 0 3 2
#Valiant 18.1 6 225.0 105 2.76 3.460 20.22 1 0 3 1
#Duster 360 14.3 8 360.0 245 3.21 3.570 15.84 0 0 3 4
#Merc 240D 24.4 4 146.7 62 3.69 3.190 20.00 1 0 4 2
#Merc 230 22.8 4 140.8 95 3.92 3.150 22.90 1 0 4 2
#...
We can use slice
library(tidyverse)
mtcars%>%
rownames_to_column('rn') %>%
slice(c(n(), 1:(n()-1))) %>%
column_to_rownames('rn')
# mpg cyl disp hp drat wt qsec vs am gear carb NA_1 NA_2
#Volvo 142E 21.4 4 121.0 109 4.11 2.780 18.60 1 1 4 2 NA 21.4
#Mazda RX4 21.0 6 160.0 110 3.90 2.620 16.46 0 1 4 4 NA 21.0
#Mazda RX4 Wag 21.0 6 160.0 110 3.90 2.875 17.02 0 1 4 4 NA 21.0
#Datsun 710 22.8 4 108.0 93 3.85 2.320 18.61 1 1 4 1 NA 22.8
#Hornet 4 Drive 21.4 6 258.0 110 3.08 3.215 19.44 1 0 3 1 NA 21.4
# ...
i want to swap a specific column with the last column, and then delete the last column after swapping. After delete ncol(testFrame) will decrease by 1
Usually a reproducible example is expected but your description is clear enough to understand what you want to do.
Using mtcars as sample data
df <- mtcars
head(df)
# mpg cyl disp hp drat wt qsec vs am gear carb
#Mazda RX4 21.0 6 160 110 3.90 2.620 16.46 0 1 4 4
#Mazda RX4 Wag 21.0 6 160 110 3.90 2.875 17.02 0 1 4 4
#Datsun 710 22.8 4 108 93 3.85 2.320 18.61 1 1 4 1
#Hornet 4 Drive 21.4 6 258 110 3.08 3.215 19.44 1 0 3 1
#Hornet Sportabout 18.7 8 360 175 3.15 3.440 17.02 0 0 3 2
#Valiant 18.1 6 225 105 2.76 3.460 20.22 1 0 3 1
swap_column <- 3
cols <- seq_len(ncol(df))
df1 <- df[replace(cols, cols == swap_column, ncol(df))][-ncol(df)]
head(df1)
# mpg cyl carb hp drat wt qsec vs am gear
#Mazda RX4 21.0 6 4 110 3.90 2.620 16.46 0 1 4
#Mazda RX4 Wag 21.0 6 4 110 3.90 2.875 17.02 0 1 4
#Datsun 710 22.8 4 1 93 3.85 2.320 18.61 1 1 4
#Hornet 4 Drive 21.4 6 1 110 3.08 3.215 19.44 1 0 3
#Hornet Sportabout 18.7 8 2 175 3.15 3.440 17.02 0 0 3
#Valiant 18.1 6 1 105 2.76 3.460 20.22 1 0 3
We replace the column number swap_column with last column number (ncol(df)) and then remove the last column (-ncol(df)).
We can do this conveniently with add_column from tibble. The .after and .before parameters can take either column index or column name. Suppose, we need to shift last column to third position
library(tibble)
data(mtcars)
df1 <- add_column(mtcars[-ncol(mtcars)], mtcars[ncol(mtcars)], .after = 2)
head(df1)
# mpg cyl carb disp hp drat wt qsec vs am gear
#Mazda RX4 21.0 6 4 160 110 3.90 2.620 16.46 0 1 4
#Mazda RX4 Wag 21.0 6 4 160 110 3.90 2.875 17.02 0 1 4
#Datsun 710 22.8 4 1 108 93 3.85 2.320 18.61 1 1 4
#Hornet 4 Drive 21.4 6 1 258 110 3.08 3.215 19.44 1 0 3
#Hornet Sportabout 18.7 8 2 360 175 3.15 3.440 17.02 0 0 3
#Valiant 18.1 6 1 225 105 2.76 3.460 20.22 1 0 3
I have a data frame called overlaps, with columns called sp_a and sp_b. If the same species is repeated in the same row, I want to delete the whole row. Any suggestions?
So I'm trying to delete row 3 and 4
You can try this:
overlaps[!duplicated(overlaps[c("sp_a","sp_b")]),]
So you want to delete rows where the value of sp_a is the same as the value of sp_b?
head(mtcars)
mpg cyl disp hp drat wt qsec vs am gear carb
Mazda RX4 21.0 6 160 110 3.90 2.620 16.46 0 1 4 4
Mazda RX4 Wag 21.0 6 160 110 3.90 2.875 17.02 0 1 4 4
Datsun 710 22.8 4 108 93 3.85 2.320 18.61 1 1 4 1
Hornet 4 Drive 21.4 6 258 110 3.08 3.215 19.44 1 0 3 1
Hornet Sportabout 18.7 8 360 175 3.15 3.440 17.02 0 0 3 2
Valiant 18.1 6 225 105 2.76 3.460 20.22 1 0 3 1
You can do this in one line with filter from the dplyr package. The below code filters the dataset, keeping only rows where gear != carb (that removes the first 2 rows):
head(mtcars) %>%
dplyr::filter(gear != carb)
mpg cyl disp hp drat wt qsec vs am gear carb
1 22.8 4 108 93 3.85 2.320 18.61 1 1 4 1
2 21.4 6 258 110 3.08 3.215 19.44 1 0 3 1
3 18.7 8 360 175 3.15 3.440 17.02 0 0 3 2
4 18.1 6 225 105 2.76 3.460 20.22 1 0 3 1
I've converted a Document Term Matrix to a dataframe using this simple line
dtm.df <- as.data.frame(inspect(dtm))
The problem is I want to remove the first column (filenames) but the column has no name.
There might be two different issues here: rownames vs. columns.
head(mtcars)
mpg cyl disp hp drat wt qsec vs am gear carb
Mazda RX4 21.0 6 160 110 3.90 2.620 16.46 0 1 4 4
Mazda RX4 Wag 21.0 6 160 110 3.90 2.875 17.02 0 1 4 4
Datsun 710 22.8 4 108 93 3.85 2.320 18.61 1 1 4 1
Hornet 4 Drive 21.4 6 258 110 3.08 3.215 19.44 1 0 3 1
Hornet Sportabout 18.7 8 360 175 3.15 3.440 17.02 0 0 3 2
Valiant 18.1 6 225 105 2.76 3.460 20.22 1 0 3 1
Here you see a column printed without a name. These are the rownames.
mpg is the first column. If we wanted to remove this column without refering to its name, we could use
mtcars <- mtcars[,-1]
head(mtcars)
cyl disp hp drat wt qsec vs am gear carb
Mazda RX4 6 160 110 3.90 2.620 16.46 0 1 4 4
Mazda RX4 Wag 6 160 110 3.90 2.875 17.02 0 1 4 4
Datsun 710 4 108 93 3.85 2.320 18.61 1 1 4 1
Hornet 4 Drive 6 258 110 3.08 3.215 19.44 1 0 3 1
Hornet Sportabout 8 360 175 3.15 3.440 17.02 0 0 3 2
Valiant 6 225 105 2.76 3.460 20.22 1 0 3 1
On the other hand, if you are talking about the rownames, which are still printed, you can remove them with the function rownames:
rownames(mtcars) <- NULL
head(mtcars)
cyl disp hp drat wt qsec vs am gear carb
1 6 160 110 3.90 2.620 16.46 0 1 4 4
2 6 160 110 3.90 2.875 17.02 0 1 4 4
3 4 108 93 3.85 2.320 18.61 1 1 4 1
4 6 258 110 3.08 3.215 19.44 1 0 3 1
5 8 360 175 3.15 3.440 17.02 0 0 3 2
6 6 225 105 2.76 3.460 20.22 1 0 3 1
I have the following data frame:
> head(mtcars)
mpg cyl disp hp drat wt qsec vs am gear carb
Mazda RX4 21.0 6 160 110 3.90 2.620 16.46 0 1 4 4
Mazda RX4 Wag 21.0 6 160 110 3.90 2.875 17.02 0 1 4 4
Datsun 710 22.8 4 108 93 3.85 2.320 18.61 1 1 4 1
Hornet 4 Drive 21.4 6 258 110 3.08 3.215 19.44 1 0 3 1
Hornet Sportabout 18.7 8 360 175 3.15 3.440 17.02 0 0 3 2
Valiant 18.1 6 225 105 2.76 3.460 20.22 1 0 3 1
What I want to do is to insert new columns called 'new_column' with values 'foo'
resulting in this:
new_column mpg cyl disp hp drat wt qsec vs am gear carb
Mazda RX4 foo 21.0 6 160 110 3.90 2.620 16.46 0 1 4 4
Mazda RX4 Wag foo 21.0 6 160 110 3.90 2.875 17.02 0 1 4 4
Datsun 710 foo 22.8 4 108 93 3.85 2.320 18.61 1 1 4 1
Hornet 4 Drive foo 21.4 6 258 110 3.08 3.215 19.44 1 0 3 1
Hornet Sportabout foo 18.7 8 360 175 3.15 3.440 17.02 0 0 3 2
Valiant foo 18.1 6 225 105 2.76 3.460 20.22 1 0 3 1
I tried this but failed:
library(zoo)
zoo("foo",mtcars$new_columns)
What's the right way to do it?
You can just use cbind (if the position of the column must be first):
head(cbind("new_column" = "foo", mtcars))
# new_column mpg cyl disp hp drat wt qsec vs am gear carb
# Mazda RX4 foo 21.0 6 160 110 3.90 2.620 16.46 0 1 4 4
# Mazda RX4 Wag foo 21.0 6 160 110 3.90 2.875 17.02 0 1 4 4
# Datsun 710 foo 22.8 4 108 93 3.85 2.320 18.61 1 1 4 1
# Hornet 4 Drive foo 21.4 6 258 110 3.08 3.215 19.44 1 0 3 1
# Hornet Sportabout foo 18.7 8 360 175 3.15 3.440 17.02 0 0 3 2
# Valiant foo 18.1 6 225 105 2.76 3.460 20.22 1 0 3 1
If the column can be at the end, you can also do:
mtcars$new_column <- "foo"