I have this command in cURL and it works
curl -X GET \
-H "X-Parse-Application-Id: APP_ID" \
-H "X-Parse-REST-API-Key: API_KEY" \
-G \ https://parseapi.back4app.com/classes/Books
I want create a url that will execute the same way on the browser.
The website that I'm working with is back4app.
There is no way to achieve the same thing with just a URL. This relies on HTTP Headers (both -H parameters) that can't be translated to something else easily. To set these headers in a web browser, you'd at least need to execute JavaScript.
There might be a way if the target API supports reading the same fields from the url in some way (technically, there's no reason not to do this). I haven't found something on that topic in their docs, though.
Related
I am using the here-api to get a 7 day forecast for my application. When I copy and paste the code onto my browser from the Here documentation using my app-code and app-id, it says that my app-id and app-code are invalid. I am wondering why this is happening since i have an account with Here and am using the code they provided.
I have already tried switching them.
https://weather.api.here.com/weather/1.0/report.json
?app_id={xxxxxx}
&app_code={xxxxxx}
&product=forecast_7days_simple
&latitude=41.83
&longitude=-87.68
When i enter this request i expected json in return but instead get a page that says my code is invalid. I am using safari but have tried chrome and i still get the same problem
Make sure to remove the curly brackets around the credentials, and to remove newlines (if any) that were added in the documentation for readability.
If you do have valid credentials, the following request should work:
https://weather.api.here.com/weather/1.0/report.json?app_id=xxxx&app_code=yyyy&product=forecast_7days_simple&latitude=41.83&longitude=-87.68
Use the query like below. For any query you can use the swagger here . And, from the "view code" button you can download either the curl or the jQuery snippet.
curl \
-X GET \
-H 'Content-Type: *' \
--get 'https://weather.api.here.com/weather/1.0/report.json' \
--data-urlencode 'product=forecast_7days_simple' \
--data-urlencode 'latitude=52.516' \
--data-urlencode 'longitude=13.389' \
--data-urlencode 'oneobservation=true' \
--data-urlencode 'app_id={YOUR_APP_ID}' \
--data-urlencode 'app_code={YOUR_APP_CODE}'
In slack you can script slackbot to post messages to a channel like this:
curl --data "$msg" $'https://<yourteam>.slack.com/services/hooks/slackbot?token=<yourtoken>&channel=#random'
Now i'd like to mention a username as the first part of the message like msg="#joernhees hello self".
The problem with this is that if the --data argument of curl starts with an # sign it will interpret the string after the # as filename and post its content. Is there a way to make curl ignore the # sign and to send a literal # as the first char of a post request?
If you are on a new version of cURL you can also use the --data-raw option:
http://curl.haxx.se/docs/manpage.html#--data-raw
A word of warning is that looking my laptop it appears Yosemite ships with an older version of cURL.
In general if you're creating tools to post to Slack I'd recommend using an HTTP library in your script rather than calling out to a shell and invoking the curl command.
Actually i just found out i can do this (not sure it's the best option though):
curl --data '#-' $'https://<yourteam>.slack.com/services/hooks/slackbot?token=<yourtoken>&channel=#random' <<< "$msg"
The trick is to tell curl to read from stdin #- and then pass the message in via that.
I am trying to send a DELETE request with a url parameter using CURL. I am doing:
curl -H application/x-www-form-urlencoded -X DELETE http://localhost:5000/locations` -d 'id=3'
However, the server is not seeing the parameter id = 3. I tried using some GUI application and when I pass the url as: http://localhost:5000/locations?id=3, it works. I really would rather use CURL rather than this GUI application. Can anyone please point out what I'm doing wrong?
The application/x-www-form-urlencoded Content-type header is not required (well, kinda depends). Unless the request handler expects parameters coming from the form body. Try it out:
curl -X DELETE "http://localhost:5000/locations?id=3"
or
curl -X GET "http://localhost:5000/locations?id=3"
#Felipsmartins is correct.
It is worth mentioning that it is because you cannot really use the -d/--data option if this is not a POST request. But this is still possible if you use the -G option.
Which means you can do this:
curl -X DELETE -G 'http://localhost:5000/locations' -d 'id=3'
Here it is a bit silly but when you are on the command line and you have a lot of parameters, it is a lot tidier.
I am saying this because cURL commands are usually quite long, so it is worth making it on more than one line escaping the line breaks.
curl -X DELETE -G \
'http://localhost:5000/locations' \
-d id=3 \
-d name=Mario \
-d surname=Bros
This is obviously a lot more comfortable if you use zsh. I mean when you need to re-edit the previous command because zsh lets you go line by line. (just saying)
I need to make a POST request via cURL from the command line. Data for this request is located in a file. I know that via PUT this could be done with the --upload-file option.
curl host:port/post-file -H "Content-Type: text/xml" --data "contents_of_file"
You're looking for the --data-binary argument:
curl -i -X POST host:port/post-file \
-H "Content-Type: text/xml" \
--data-binary "#path/to/file"
In the example above, -i prints out all the headers so that you can see what's going on, and -X POST makes it explicit that this is a post. Both of these can be safely omitted without changing the behaviour on the wire. The path to the file needs to be preceded by an # symbol, so curl knows to read from a file.
I need to make a POST request via Curl from the command line. Data for this request is located in a file...
All you need to do is have the --data argument start with a #:
curl -H "Content-Type: text/xml" --data "#path_of_file" host:port/post-file-path
For example, if you have the data in a file called stuff.xml then you would do something like:
curl -H "Content-Type: text/xml" --data "#stuff.xml" host:port/post-file-path
The stuff.xml filename can be replaced with a relative or full path to the file: #../xml/stuff.xml, #/var/tmp/stuff.xml, ...
If you are using form data to upload file,in which a parameter name must be specified , you can use:
curl -X POST -i -F "parametername=#filename" -F "additional_parm=param2" host:port/xxx
Most of answers are perfect here, but when I landed here for my particular problem, I have to upload binary file (XLSX spread sheet) using POST method, I see one thing missing, i.e. usually its not just file you load, you may have more form data elements, like comment to file or tags to file etc as was my case. Hence, I would like to add it here as it was my use case, so that it could help others.
curl -POST -F comment=mycomment -F file_type=XLSX -F file_data=#/your/path/to/file.XLSX http://yourhost.example.com/api/example_url
I was having a similar issue in passing the file as a param. Using -F allowed the file to be passed as form data, but the content type of the file was application/octet-stream. My endpoint was expecting text/csv.
You are able to set the MIME type of the file with the following syntax:
-F 'file=#path/to/file;type=<MIME_TYPE>
So the full cURL command would look like this for a CSV file:
curl -X POST -F 'file=#path/to/file.csv;type=text/csv' https://test.com
There is good documentation on this and other options here: https://catonmat.net/cookbooks/curl/make-post-request#post-form-data
I had to use a HTTP connection, because on HTTPS there is default file size limit.
https://techcommunity.microsoft.com/t5/IIS-Support-Blog/Solution-for-Request-Entity-Too-Large-error/ba-p/501134
curl -i -X 'POST' -F 'file=#/home/testeincremental.xlsx' 'http://example.com/upload.aspx?user=example&password=example123&type=XLSX'
Using REST Server 6.x-2.0-beta3, I'm trying to understand how to post to user.save.
curl -d 'XX' -v http://localhost/services/rest/service_user/save
I've tried to replace XX with:
account{'name':'myname','pass':'mypassword','mail':'my#email.org'}
account = {'name':'myname','pass':'mypassword','mail':'my#email.org'}
account="name=myname,pass=mypassword,mail=myemail.org"
account=name=myname,pass=mypassword,mail=myemail.org
account=myname,mypassword,myemail.org
But none of these seems to be right and finding any documention regarding this is next to impossible.
I've also tried the following:
curl -H "Content-Type: application/json" -d 'account={"name":"myname","pass":"mypassword","email":"123"}' -v http://localhost/services/rest/service_user/save
The error I get in this case is:
HTTP/1.0 406 Not Acceptable: Missing required argument account
Hi I also just started working with this module and wondering how to create content using JSON.
Just been able to create a simple node using this:
Post URL: http://path-to-site/services/rest/node
Request Header: Content-Type: application/json
Request Body: {"type":"story","title":"REST Test","body":"REST using JSON"}
I think you're using the wrong URL
I figured it out:
curl -H “application/x-www-form-urlencoded” -d "sessid=xxxx" -d "account[name]=MyName&account[pass]=mypass&account[mail]=myemail#gmail.com&account[conf_mail]=myemail#gmail.com" -v http://path-to-site/services/rest/service_user/save
You only have to add -d "sessid=xxxx" if you have configured Services to require a session. Make sure in that case to replace xxxx with your actual session id (from system.connect).