In wordpress, when using a theme, how can I prevent a click event from happening on a custom link. I am thinking of adding the following:
onClick="return false"
I am trying to prevent the page from scrolling down unexpectedly, when clicked.
do you have access to the theme edition? If so, you can try to use something like the code below, it's
add in footer.php
if you do not have access, but the theme has some custom field.
<script>
//JQUERY
(function ($) {
$('a[href=#]').click(function (e) {
e.preventDefault();
})
})(jQuery)
//JS PURE
document.querySelectorAll('a[href="#"]').forEach(function(ele, i){
ele.addEventListener('click', function (e) {
e.preventDefault();
})
})
</script>
Related
Hello I would like to disable the woocommmerce register page button after one click to avoid multiple clicks.
I have searched the forums and found a bunch of solutions for custom forms and I've tried the following JS code but had no luck. I have a feeling I am setting the wrong selector because I cannot for the life of me figure out what the correct selector for the default register button is.
<script>
function disableButton() {
var btn = document.getElementById('woocommerce-register-nonce');
btn.disabled = true;
btn.innerText = 'Posting...'
}
</script>
I've also tried :
<script>
jQuery('woocommerce-Button.woocommerce-button.button.woocommerce-form-register__submit').live('click', function (e) {
var self = this;
$(this).attr("disabled", "disabled");
do_something();
setTimeout(function () {
$(self).removeAttr('disabled');
}, 10000);
});
</script>
Some guidance would be very much appreciated.
Update!
Based on Onboardmass's suggestion I have corrected the selector and got it partially working using jquery.
<script>
jQuery('.woocommerce-Button.woocommerce-button.button.woocommerce-form-register__submit').click(function(){
jQuery(this).attr("disabled", "disabled");
});
</script>
The button now gets disabled on click however the issue I'm facing now is that the form does not get submitted.
The issue you're facing is because the selector is incorrect. It should be .woocommerce-Button.woocommerce-button.button.woocommerce-form-register__submit.
For anyone else who may need this I was able to figure this one out by reading through the suggestions and other threads I found. Thank you Onboardmass & Martin for the guidance!
The time out function is required for the click to register.
<script>
$(document).ready(function () {
$(".woocommerce-Button.woocommerce-button.button.woocommerce-form-register__submit").click(function () {
setTimeout(function () { disableButton(); }, 0);
});
function disableButton() {
$(".woocommerce-Button.woocommerce-button.button.woocommerce-form-register__submit").prop('disabled', true);
}
});
</script>
I have created a registration plugin in WordPress and I want to display my register-employee.php(under view folder) file. When a user click on a button(used that url to display the file, something like that). Below is my folder structure hope would help.
>controller
>model
>public
>view
register-employee.php
register-member.php
Altough your description is very little,
I give you a really simple guide on how to do this:
First thing, opening a form on click is a javascript thing so the first thing you need to do is add your JavaScript file,
let's assume you have a file assets/js/register.js which looks like this:
var btn = document.querySelector('button.my-register-button');
btn.addEventListener('click', function(e) {
e.preventDefault();
document.querySelector('#my_registration_popup').style.display = 'block';
});
Then we need to add this file to wp_enqueue_scripts action in order to be added to Wordpress pages
add_action('wp_enqueue_scripts', function() {
wp_register_script('my-registration-plugin', YOUR_PLUGIN_URL . '/assets/js/register.js', [], null, true);
});
assuming that your register-employee.php file looks something like this:
<div id="my_registration_popup" style="display: none">
<!-- my form -->
</div>
First thing you need to do is to add above view to wp_footer action:
add_action('wp_footer', function() {
include PATH_TO_YOUR_PLUGIN . '/view/register-employee.php';
});
How to call JavaScript function on click of menu URL link of WordPress?
I have tried
jQuery(document).ready(function($) {
$(".menu-item-2916").on("click", function(){
getServerPath('signin.html?reqType=login');
});
});
which is not working for me. This menu is LOGIN menu for my website.
you have not clarify whats you need exact. but try this one if you need to change with this url on click.
menu-item-24 replace your menu id
jQuery(document).ready(function ($) {
$("nav li#menu-item-24").on("click", function (e) {
e.preventDefault();
window.open('/signin.html?reqType=login','_self');
return false;
});
});
Try it
jQuery(document).ready(function($) {
$(".nav li.menu-item-2916").on("click", function(){
getServerPath('signin.html?reqType=login');
});
});
I am using offline.js (0.7.18) and its working fine, when I go on/offline the indicator changes state, all good so far.
I can also see on Offline JS Simulate UI, that a login panel is having its style toggled between display:block and display:none when on/offline is triggered. But I can't discover how this works.
I want to hide a 'Submit' button when offline is triggered.
You can use the sample from the Offline JS Simulate UI page that uses jQuery:
<script>
$(function(){
var
$online = $('.online'),
$offline = $('.offline');
Offline.on('confirmed-down', function () {
$online.fadeOut(function () {
$offline.fadeIn();
});
});
Offline.on('confirmed-up', function () {
$offline.fadeOut(function () {
$online.fadeIn();
});
});
});
</script>
Give the class "online" to any element you want shown when the system is online and give the class "offline" to any element you want shown when the system is offline.
<button class="online">ABC</button>
right now I have a huge Solution in which we use javascript alerts via RegisterStartupScript for all messages and errors.. We were willing to modify all this to making something similar to the modalPopupExtender, or the extender itself in a way that doesn't require too much effort... I mean, to show a modalpopup on a single page I need to create it on the aspx file, setting the attributes etc... So i'm just asking for Ideas, want to know how you guys deal with this..
I'd probably use jQuery dialog and put the markup and initialization code in a MasterPage, set with autoOpen false and hidden by default. I'd inject code that interacts with the dialog into each page as needed.
<div id="modalDialog" title="Error">
<p id='modalDialogMsg'>An error has occurred.</p>
</div>
<script type="text/javascript">
$(function() {
$('#modalDialog').dialog({
autoOpen: false;
modal: true,
buttons: {
"OK" : function() {
$(this).dialog('close');
}
}
});
});
// You could "objectify" this, but I'll show as a global function
function showError( title, msg )
{
if (!title) {
title = 'Error';
}
if (!msg) {
msg = 'An error occurred.';
}
$('#modalDialogMessage').html(msg);
$('#modalDialog').attr('title',title)
.dialog('open');
}
</script>
Then, in your page you'd inject code that calls showError. Note this would need to be after the script above in order to make sure that the function has been defined. What would spit out would render like:
<script type="text/javascript">
$(function() {
showError('Database connection error', 'There was an error connecting to the database.' )'
});
</script>
Could you not place the modal popup/ modal popup extender into a user a control and embed the user control into each page?