I am trying to create firebase dynamic links manually but I didn't understand which domain should I provide for 'link' parameter as shown below:
"https://YourDynamicLinkIdentifier.app.goo.gl/link=https://example.com?offer="+myOfferVar+"&apn=com.your.apn";
Here link = www.example.com but I don't have any domain and I am not intended to pass any.
I am just trying to pass a variable with this link so that the end user can receive the passed variable by clicking on the created dynamic link.
I am really stuck with this. Please help me with this.
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I created a Firebase Deep Link for my Flutter app to open the app after the registration process was successful. The link looks like the following:
https://myLinkDomain.page.link/routeName/
During the registration process, a parameter must be appended to the end of the link, which I must read out in the app for successful completion.
The problem is that if I append the parameter to the end of the link, I can no longer access it. The link in this case looked like this:
https://myLinkDomain.page.link/routeName/?myCustomParam=myValue
If the parameter is given in the middle of the link, I can use it in the app. Like this:
https://myLinkDomain.page.link/routeName/?myCustomParam=myValue&apn=someStuff&isi=someStuff&ibi=someStuff&ifl=someStuff
However, the registration process requires that the parameter be added to the end of the link.
Is there a way to build the Firebase Deep Link so that the parameter can be added at the end and still be recognised in the app?
Thanks for any help!
No matter when this parameter goes - at start or at the end of the line.
I had the same problem with passing some custom parameters to my app.
Here is we should start with manual url construction:
firebase manual link construction
I have no easy way to pass parameters, so I just change the link parameter body to put here more parameters:
https://example.page.link/?link=https://example.com/?route%3Dprofile%26param1%3DA%26param2%3DB&apn=some&isi=some&ibi=some
prefix: https://redecor.page.link/
main body in link parameter (should be encoded). There is the place for all needed parameters you want to pass (route=profile¶m1=A¶m2=B) - all parameters should be encoded!
encoded should be like this: route%3Dprofile%26param1%3DA%26param2%3DB
other parameters (what are they means you could read here) for firebase proposes (no needs to encode):
apn=some&isi=some&ibi=some
Never mind. The solution is to change the order of the url parameters: myLinkDomain.page.link/routeName/…
I am trying to create my custom dynamic link: share.grabhotel.net of my custom domain : grabhotel.net. I follow these steps :
Step 1: Add URL Prefix
Step 2 : Verify domain
I passed TXT value to my DNS like this
Step 3 : Add custom domain in Firebase Hosting
Step 4 : Add A records in DNS
But when I go back to my dynamic links, I get this error
Can you show me how to fix it ? And how to add custom dynamic link successfully ? Thank you very much
Please click to the link:"[enter image description here]" for image
In your domain registrar, the first field to the left(either Name, Host, or Alias) is set to grabhotel.net This is the root domain. You want to create dynamic links on the subdomain share.grabhotel.net. You need to set the first field to share.grabhotel.net. Also, it can take a few days for DNS records to propagate. Let me know if you need any help.
I am trying to notify users whenever a site is created in alfresco share. I created a rule for the site folder in the repository.
In Define Rule, I selected:
When: Items are created or entered in the folder
If all criteria are met: Description contains "a"
Perform Action: Send email
But in the message of the email I need to give the site name.
For example:
A new site named "Sample" is created. Click the link to join the site.
How can I get the site name and corresponding link to join the site?
You can do something like this.
var currentSite = Alfresco.constants.SITE;
var siteObject = siteService.getSite(currentSite );
If you are using javascript directly to send mail you you will have site object available .
You can also try this
siteId = page.url.templateArgs.site;
If you are using ftl you can probably pass sitename from script file to FTL file.
You have multiple options to get current site name depending on the context where you are trying to access it.
How could i pass custom mail tokens from my custom module to the admin user settings page.In the admin user settings page I see a part like Welcome, awaiting administrator approval.In this part it shows the available variables are: !username, !site, !password, !uri, !uri_brief, !mailto, !date, !login_uri, !edit_uri, !login_url.Is there any way by which i could add my own custom variables so that it can be accessed in the corresponding mail body..?I need to pass some variables from my custom module to this user setings part.Could some one help me with this..
For someone who might be looking for the solution,here is how i solved it.Do check the link below to see how to create your own tokens in the user admin settings.Its was a very quite useful piece of code .Anyways thanks to the uploader.. :)
http://www.innoraft.com/blog/use-profile-fields-tokens-user-emails-drupal
I have been trying to create a page using views that will list down all the nodes authored by a specific user.
The user name will be specified in the path (like - stuff/[user-name] )
Can someone please tell me how to do this using Views.
I am stuck on a dead end
for the views url path specify: stuff/%
in the arguments section add: user -> user: name
Should do it, but I'm not sure if it isn't buggy (see this issue: http://drupal.org/node/744468)
If you use user:id instead of username, you will be fine.