I was new to drupal 7 but I used the Drupal , my question is I have a view with some fields in a hidden state and I use Global text to render them using some HTML.
So, the problem is I've a field called middle name and this is wrapped inside a html tag,
for eg:
<h1>[field_middle_name]</h1>
What I need is to hide the tag if there is no middle name,
I know in D8 I can use twig to write condtions, but I dont know how to achieve this in D7.
Any help would be appreciated.
Drupal 7 templates are actually PHP files so you can use PHP for adding conditions, loops and all other actions.
Related
I'm new to drupal and reading through docs, but hoping to get an explanation for something.
I have a page called page--type-home-page.tpl.php.
Part of this page prints render($page['content'])). I want to remove something that is rendered as part of the page content from the page, but don't understand where this comes from and where/how to look.
Thanks!
Assuming you're talking about Drupal-7
Well the $page['content'] contains a string, which is a rendered version of what's injected into the content region of your theme.
By default, the only block in this region is the "Main page content" block that is generated by the Drupal core. Many things can generate this content but it always pass through the menu API. For instance, if you're viewing a node, the URL used is: node/12. The node module declares a menu entry for node/%node, this menu entry contains a callback function that will render whatever the module wants to render. The module, then, may use different strategy to render it's content from a simple function to a complex imbrication of templates.
The key to alter what's in the box, sorry, what's in the $page['content'], is to know what is rendered and to understand how it's rendered.
If it's a node, first you want to look if you can achieve your goal through the display settings of the content type. admin/structure/types/manage/page/display: And this is true for all entities (users, comments, taxonomy term etc.) Because this is the first thing the module of these entities will put together when they'll try to render your content.
If this is not enough to achieve your goal, you can look into the module that renders the path to see if it hasn't a .tpl.php. You'll be able to re-use it in your theme. You'll want to copy/paste the file in your theme and edit it.
If the module do not have a tpl file to override, try a template suggestion: here's a list from Drupal.org
Ex: node--type.tpl.php
If all this doesn't satisfy your need, you'll have to dig into preprocess functions; Those functions allow you to modify what's in the variables passed to .tpl.php files. That's a little more advanced and I recommend you to read this previous stackoverflow question/answer
Simply, don't use that $page['content'] which prints all content, but place your custom template code instead and print separate field values where you need them like:
<?php print render($content['your_field_name']); ?>
https://drupal.stackexchange.com/questions/30063/how-to-print-fields-in-node-tpl-php
If you want to do just simple styling, like excluding some field you can use content type display options like mgadrat explained, but if you want to use some complex styling, with totally custom html this solution is easier.
I have created an Article in Drupal 7 and I want to customize how the content is displayed.
I am trying to modify the node.tpl.php, which gives you access to the $content variable, but this is a multidimensional array and I cannot extract the keys or values within it.
Is there a way of seeing inside $content to find out the exact value pairs that I need?
Or is there another way of customizing the display and output of Drupal 7 content?
If you install the and enable the devel module, it gives you access to a very handy function dsm that will render a widget that lets you explore the contents of any variable or object. So in your node.tpl.php file: dsm($content); at the top will let you inspect the content. Usually you will want to create a custom node-type.tpl.php file e.g. node-article.tpl.php which is only applied to nodes of a certain type.
I have created a page view using field style to display a list of teasers as I want. fields configuration in views allows us to link the field to it's node. but what if we have created view for node detail page and want field to link to it's relevant view.
I had the same question, and after a bit of research this is what I've concluded:
The views module isn't intended to replace a default node view. I say this because of the level of difficulty involved in doing this and the lack of information on how to accomplish this. Ryan Weal has posted a way to accomplish this by editing your node template that doesn't look too difficult to accomplish, and here is the link.
However, it seems that a more popular solution, especially if you are like me and don't like to get into editing theme files. You can use the Display Suite module to effectively reformat the default node content as you would like.
I'm not sure if I understand you properly, but it sounds like you are wanting to display a view in a page view of a node?
In order to do this, you could:
create a small module, using hook_nodeapi() or one of the D7 replacements for this function in order to insert the output of the embedded view into this page's content, by conditionally adding a $content element when the node is of the appropriate id
or (easier, but requires allowing input type PHP) embed the view right on the page.
http://thedrupalblog.com/embedding-view-drupal-6-using-views-embed-view for information on embedding views
I want to create a list box in a region that has been created by me. Any help would be highly appreciated! I dont understand how to go about it. How can I add just a list box in the existing page?
You should create block (html or php filters should be enabled), put there your list box html code, then place this block into region.
But, using drupal way is recommend - drupal api - create simple module, add form function with list box (select field) and call this form from block hook.
By default for creating content a new page is opened. I want to do this inside a block. A block where there will be some fields like title body taxonomy terms and a create content button. How can I do this?
The form block module will do what you want.
You could you do the same thing in code, using hook_block to create a block. And using
drupal_get_form to render the form.
Try the Panels module.
http://drupal.org/project/panels
It will let you override and re-arrange the node add/edit form.
But, as Jeremy stated, to use this form on other pages of the site you will need to do something custom like hook_block and invoke drupal_get_form.
I agree with the answers from Jeremy and Kevin, but want to give another one.
You can use views to create the block! All you have to do is create a new view display with a block display. Add the fields you want to show, add a link field for the node/add/foo link and give it a node id filter or default argument. Here you have to choose the node id of the node to display in the block. Done!
What's nice with this solution? You can use almost every feature of views theming, drag and drop field ordering, adding new fields is cheap and no extra modules. ;)
Regards
Mike