I need to count the number of unique values and to group them by day.
For example, I have :
user id | Date
1 | 01.-11-2018
1 | 01-11-2018
2 | 02-11-2018
3 | 03-11-2018
1 | 03-11-2018
In result i need
01-11-2018 | 1
02-11-2018 | 1
03-11-2018 | 2
I need do it in Klipfolio
You can use the GROUPBY() function with the aggregation in the method parameter set to Count Distinct. For example, if your dates are in column A of a spreadsheet and your values are in column B, your formula would look like this:
GROUPBY(#A:A,#B:B,Count Distinct)
Related
I have a table with a large amount of data; moving forward, I would like to enforce uniqueness for a given column in this table. However, the table contains a large amount of rows where that column is non-unique. I am not able to delete or alter these rows.
Is it possible to enforce uniqueness over a given date range, or since a specific date, or based on the value of another column (or something else like that) in MariaDB?
You can create a UNIQUE index on multiple columns, where one column is nullable. MariaDB will see each column with NULL values as a different value regarding the UNIQUE index, even if the other column values of the UNIQUE index are the same. Check the MariaDB documentation Getting Started with Indexes - Unique Index:
The fact that a UNIQUE constraint can be NULL is often overlooked. In SQL any NULL is never equal to anything, not even to another NULL. Consequently, a UNIQUE constraint will not prevent one from storing duplicate rows if they contain null values:
CREATE TABLE t1 (a INT NOT NULL, b INT, UNIQUE (a,b));
INSERT INTO t1 values (3,NULL), (3, NULL);
SELECT * FROM t1;
+---+------+
| a | b |
+---+------+
| 1 | 1 |
| 2 | 1 |
| 2 | 2 |
| 3 | NULL |
| 3 | NULL |
+---+------+
You can create such a UNIQUE index on the date column you already have and a new column which indicates if the date value should be unique or not:
CREATE TABLE Foobar(
id INT AUTO_INCREMENT PRIMARY KEY NOT NULL,
createdAt DATE NOT NULL,
dateUniqueMarker BIT NULL DEFAULT 0,
UNIQUE KEY uq_createdAt(createdAt, dateUniqueMarker)
);
INSERT INTO Foobar(createdAt) VALUES ('2021-11-04'),('2021-11-05'),('2021-11-06');
SELECT * FROM Foobar;
+----+------------+------------------------------------+
| id | createdAt | dateUniqueMarker |
+----+------------+------------------------------------+
| 1 | 2021-11-04 | 0x00 |
| 2 | 2021-11-05 | 0x00 |
| 3 | 2021-11-06 | 0x00 |
+----+------------+------------------------------------+
INSERT INTO Foobar(createdAt) VALUES ('2021-11-05');
ERROR 1062 (23000): Duplicate entry '2021-11-05-\x00' for key 'Foobar.uq_createdAt'
UPDATE Foobar SET dateUniqueMarker = NULL WHERE createdAt = '2021-11-05';
INSERT INTO Foobar(createdAt, dateUniqueMarker) VALUES ('2021-11-05', NULL);
SELECT * FROM Foobar;
+----+------------+------------------------------------+
| id | createdAt | dateUniqueMarker |
+----+------------+------------------------------------+
| 1 | 2021-11-04 | 0x00 |
| 2 | 2021-11-05 | NULL |
| 5 | 2021-11-05 | NULL |
| 3 | 2021-11-06 | 0x00 |
+----+------------+------------------------------------+
Without any data example and scenario illustration, it's hard to know. If you can update your question with those information, please do.
"Is it possible to enforce uniqueness over a given date range, or since a specific date, or based on the value of another column (or something else like that) in MariaDB?"
If by "enforce" you mean to create a new column then populate it with unique identifier, then yes it is possible. If what you really mean is to generate a unique value based on other column, that's also possible. Question is, how unique do you want it to be?
Is it like this unique?
column1
column2
column3
unique_val
2021-02-02
ABC
DEF
1
2021-02-02
CBD
FEA
1
2021-02-03
BED
GER
2
2021-02-04
ART
TOY
3
2021-02-04
ZSE
KSL
3
Whereby if it's the same date (on column1), it should have the same unique value regardless of column2 & column3 data.
Or like this?
column1
column2
column3
unique_val
2021-02-02
ABC
DEF
1
2021-02-02
CBD
FEA
2
2021-02-03
BED
GER
3
2021-02-04
ART
TOY
4
2021-02-04
ZSE
KSL
5
Taking all (or certain) columns to consider the unique value.
Both of the scenario above can be achieved in query without the need to alter the table, adding and populate a new column but of course, the latter is also possible.
Let say I have a table with partition key "ID" and range key "Time" with the following items:
ID | Time | Data
------------------
A | 1 | abc
A | 2 | def
B | 2 | ghi
B | 3 | jkl
And I want to scan only one item in each partition that has the highest time value in each partition. So the outcome of the scan should look like:
ID | Time | Data
------------------
A | 2 | def
B | 3 | jkl
Is this possible with the DynamoDB's scan feature?
(I want to avoid scan all and do such filtering by myself).
If you want to fetch just a few IDs along with their highest Time, you can query with reverse index, so for every ID, you will have only 1 item read. But for this you need an existing list of IDs.
So for each ID, there will be:
1 query
1 item read
Otherwise, the only way is to scan everything unfortunately.
I have a dataset like shown below (except the Ser_NO, this is the field i want to create).
+--------+------------+--------+
| CaseID | Order_Date | Ser_No |
+--------+------------+--------+
| 44 | 22-01-2018 | 1 |
+--------+------------+--------+
| 44 | 24-02-2018 | 3 |
+--------+------------+--------+
| 44 | 12-02-2018 | 2 |
+--------+------------+--------+
| 100 | 24-01-2018 | 1 |
+--------+------------+--------+
| 100 | 26-01-2018 | 2 |
+--------+------------+--------+
| 100 | 27-01-2018 | 3 |
+--------+------------+--------+
How can i achieve a serial number for each CaseId based on my dates. So the first date in a specific CaseID gets number 1, the second date in this CaseID gets number 2 and so on.
I'm working with T-SQL btw,
I've tried a few things:
CASE
WHEN COUNT(CaseID) > 1
THEN ORDER BY (Order_Date)
AND Ser_no +1
END
Thanks in advance.
First of all, although I don't understand what you did, it gives you what you wanted. The serial number is assigned by date order. The problem I can see is that the result shows you the rows in the wrong order (1, 3, 2 instead of 1, 2, 3).
To sort that order you can try this:
SELECT *, ROW_NUMBER() OVER (PARTITION BY caseid ORDER BY caseid, order_date) AS ser_no
FROM [Table]
Thanks for your reply,
Sorry for the misunderstanding, because the ser_no is not yet in my table. That is the field a want to calculate.
I finished it myself this morning, but it looks almost the same like your measure:
RANK() OVER(PARTITION BY CaseID ORDER BY CaseID, Order_Date ASC
Assume I have the following SQLite table "foobar":
id | start | duration
---+------------+---------
1 | 2016-05-12 | 2
2 | 2016-01-01 | 5
My goal is to get the sum of the start-date and the duration (durations are in years).
So my desired result is the following:
id | end
---+-----------
1 | 2018-05-12
2 | 2021-01-01
Is this possible with a single query?
I know it is possible to add static values as follows
SELECT date(start, "+2 years") FROM foobar;
but I could not find a way to replace the static 2 with the dynamic value of duration.
SELECT date(start, "+" || duration || " years")
FROM foobar;
SQLFiddle demo
I have a table with this structure:
id | IDs | Name | Type
1 | 10 | A | 1
2 | 11 | B | 1
3 | 12 | C | 2
4 | 13 | D | 3
except id nothing else is a FOREIGN or PRIMARY KEY. I want to select a row based on it's column values that are not PRIMARY KEY. I have tried the following syntax but it yields no results.
SELECT * FROM MyTable WHERE Name = 'A', Type = 1;
what am I doing wrong? What is exactly returned by a SELECT statement? I'm totally new to Data Base and I'm currently experimenting and trying to learn it. so far my search has not yield any results regarding this case.
Use and to add multiple conditions to your query
SELECT *
FROM MyTable
WHERE Name = 'A'
AND Type = 1;