I wrote some code to performed oversampling, meaning that I replicate my observations in a data.frame and add noise to the replicates, so they are not exactly the same anymore. I'm quite happy that it works now as intended, but...it is too slow. I'm just learning dplyr and have no clue about data.table, but I hope there is a way to improve my function. I'm running this code in a function for 100s of data.frames which may contain about 10,000 columns and 400 rows.
This is some toy data:
library(tidyverse)
train_set1 <- rep(0, 300)
train_set2 <- rep("Factor1", 300)
train_set3 <- data.frame(replicate(1000, sample(0:1, 300, rep = TRUE)))
train_set <- cbind(train_set1, train_set2, train_set3)
row.names(train_set) <- c(paste("Sample", c(1:nrow(train_set)), sep = "_"))
This is the code to replicate each row a given number of times and a function to determine whether the added noise later will be positive or negative:
# replicate each row twice, added row.names contain a "."
train_oversampled <- train_set[rep(seq_len(nrow(train_set)), each = 3), ]
# create a flip function
flip <- function() {
sample(c(-1,1), 1)
}
In the relevant "too slow" piece of code, I'm subsetting the row.names for the added "." to filter for the replicates. Than I select only the numeric columns. I go through those columns row by row and leave the values untouched if they are 0. If not, a certain amount is added (here +- 1 %). Later on, I combine this data set with the original data set and have my oversampled data.frame.
# add percentage of noise to non-zero values in numerical columns
noised_copies <- train_oversampled %>%
rownames_to_column(var = "rowname") %>%
filter(grepl("\\.", row.names(train_oversampled))) %>%
rowwise() %>%
mutate_if(~ is.numeric(.), ~ if_else(. == 0, 0,. + (. * flip() * 0.01 ))) %>%
ungroup() %>%
column_to_rownames(var = "rowname")
# combine original and oversampled, noised data set
train_noised <- rbind(noised_copies, train_set)
I assume there are faster ways using e.g. data.table, but it was already tough work to get this code running and I have no idea how to improve its performance.
EDIT:
The solution is working perfectly fine with fixed values, but called within a for loop I receive "Error in paste(Sample, n, sep = ".") : object 'Sample' not found"
Code to replicate:
library(data.table)
train_set <- data.frame(
x = c(rep(0, 10)),
y = c(0:9),
z = c(rep("Factor1", 10)))
# changing the row name to avoid confusion with "Sample"
row.names(train_set) <- c(paste("Observation", c(1:nrow(train_set)), sep = "_"))
train_list <- list(aa = train_set, bb = train_set, cc = train_set)
for(current_table in train_list) {
setDT(current_table, keep.rownames="Sample")
cols <- names(current_table)[sapply(current_table, is.numeric)]
noised_copies <- lapply(c(1,2), function(n) {
copy(current_table)[,
c("Sample", cols) := c(.(paste(Sample, n, sep=".")),
.SD * sample(c(-1.01, 1.01), .N*ncol(.SD), TRUE)),
.SDcols=cols]
})
train_noised <- rbindlist(c(noised_copies, list(train_set)), use.names=FALSE)
# As this is an example, I did not write anything to actually
# store the results, so I have to remove the object
rm(train_noised)
}
Any ideas why the column Sample can't be found now?
Here is a more vectorized approach using data.table:
library(data.table)
setDT(train_set, keep.rownames="Sample")
cols <- names(train_set)[sapply(train_set, is.numeric)]
noised_copies <- lapply(c(1,2), function(n) {
copy(train_set)[,
c("Sample", cols) := c(.(paste(Sample, n, sep=".")),
.SD * sample(c(-1.01, 1.01), .N*ncol(.SD), TRUE)),
.SDcols=cols]
})
train_noised <- rbindlist(c(noised_copies, list(train_set)), use.names=FALSE)
With data.table version >= 1.12.9, you can pass is.numeric directly to .SDcols argument and maybe a shorter way (e.g. (.SD) or names(.SD)) to pass to the left hand side of :=
address OP's updated post:
The issue is that although each data.frame within the list is converted to a data.table, the train_list is not updated. You can update the list with a left bind before the for loop:
library(data.table)
train_set <- data.frame(
x = c(rep(0, 10)),
y = c(0:9),
z = c(rep("Factor1", 10)))
# changing the row name to avoid confusion with "Sample"
row.names(train_set) <- c(paste("Observation", c(1:nrow(train_set)), sep = "_"))
train_list <- list(aa = train_set, bb = copy(train_set), cc = copy(train_set))
train_list <- lapply(train_list, setDT, keep.rownames="Sample")
for(current_table in train_list) {
cols <- names(current_table)[sapply(current_table, is.numeric)]
noised_copies <- lapply(c(1,2), function(n) {
copy(current_table)[,
c("Sample", cols) := c(.(paste(Sample, n, sep=".")),
.SD * sample(c(-1.01, 1.01), .N*ncol(.SD), TRUE)),
.SDcols=cols]
})
train_noised <- rbindlist(c(noised_copies, train_list), use.names=FALSE)
# As this is an example, I did not write anything to actually
# store the results, so I have to remove the object
rm(train_noised)
}
I have a data.frame in the narrow format like that:
test_data<-data.frame(id=rep(1:200,50),
variable=sample(LETTERS,10000,T),
value=sample(letters,10000,T), stringsAsFactors = F)
I want to get a list containing lists for each id with each variable as a vector inside (something like simple JSON format):
list("1"=list(A=c("a","b"), B=character(), C="v" ...
My code:
return_data <-
sapply(unique(test_data$id), function (r)
sapply(LETTERS, function(q)
test_data[test_data$id == r & test_data$variable == q, "value"],
USE.NAMES = T,simplify = F),
USE.NAMES = T,simplify = F)
It works, but it is too slow with large samples. I've rewritten it with data. table, but it is still slow. I've got some improvement with parSapply, but I believe there should be more effective algorithm...
You can use split with variable being a factor, thanks to the drop = FALSE behavior (on by default but passed explicitly here for readability). With magrittr:
library(magrittr)
res = test_data %>%
transform(variable = factor(variable)) %>%
split(.["id"]) %>%
lapply(function(x) split(x$value, x["variable"], drop = FALSE))
all.equal(unname(res), return_data) # TRUE
The same without magrittr:
new_test_data = transform(test_data, variable = factor(variable))
sp_id = split(new_test_data , new_test_data["id"])
res2 = lapply(sp_id, function(x) split(x$value, x["variable"], drop = FALSE))
all.equal(unname(res2), return_data) # TRUE
Trying to get my head around Non-Standard Evaluation as used by dplyr but without success. I'd like a short function that returns summary statistics (N, mean, sd, median, IQR, min, max) for a specified set of variables.
Simplified version of my function...
my_summarise <- function(df = temp,
to.sum = 'eg1',
...){
## Summarise
results <- summarise_(df,
n = ~n(),
mean = mean(~to.sum, na.rm = TRUE))
return(results)
}
And running it with some dummy data...
set.seed(43290)
temp <- cbind(rnorm(n = 100, mean = 2, sd = 4),
rnorm(n = 100, mean = 3, sd = 6)) %>% as.data.frame()
names(temp) <- c('eg1', 'eg2')
mean(temp$eg1)
[1] 1.881721
mean(temp$eg2)
[1] 3.575819
my_summarise(df = temp, to.sum = 'eg1')
n mean
1 100 NA
N is calculated, but the mean is not, can't figure out why.
Ultimately I'd like my function to be more general, along the lines of...
my_summarise <- function(df = temp,
group.by = 'group'
to.sum = c('eg1', 'eg2'),
...){
results <- list()
## Select columns
df <- dplyr::select_(df, .dots = c(group.by, to.sum))
## Summarise overall
results$all <- summarise_each(df,
funs(n = ~n(),
mean = mean(~to.sum, na.rm = TRUE)))
## Summarise by specified group
results$by.group <- group_by_(df, ~to.group) %>%
summarise_each(df,
funs(n = ~n(),
mean = mean(~to.sum, na.rm = TRUE)))
return(results)
}
...but before I move onto this more complex version (which I was using this example for guidance) I need to get the evaluation working in the simple version first as thats the stumbling block, the call to dplyr::select() works ok.
Appreciate any advice as to where I'm going wrong.
Thanks in advance
The basic idea is that you have to actually build the appropriate call yourself, most easily done with the lazyeval package.
In this case you want to programmatically create a call that looks like ~mean(eg1, na.rm = TRUE). This is how:
my_summarise <- function(df = temp,
to.sum = 'eg1',
...){
## Summarise
results <- summarise_(df,
n = ~n(),
mean = lazyeval::interp(~mean(x, na.rm = TRUE),
x = as.name(to.sum)))
return(results)
}
Here is what I do when I struggle to get things working:
Remember that, just like the ~n() you already have, the call will have to start with a ~.
Write the correct call with the actual variable and see if it works (~mean(eg1, na.rm = TRUE)).
Use lazyeval::interp to recreate that call, and check this by running only the interp to visually see what it is doing.
In this case I would probably often write interp(~mean(x, na.rm = TRUE), x = to.sum). But running that will give us ~mean("eg1", na.rm = TRUE) which is treating eg1 as a character instead of a variable name. So we use as.name, as is taught to us in vignette("nse").
I wrote a special "impute' function that replaces the column values that have missing (NA) values with either mean() or mode() based on the specific column name.
The input dataframe is 400,000+ rows and its vert slow , how can i speed up the imputation part using lapply() or apply().
Here is the function , mark section I want optimized with START OPTIMIZE & END OPTIMIZE:
specialImpute <- function(inputDF)
{
discoveredDf <- data.frame(STUDYID_SUBJID=character(), stringsAsFactors=FALSE)
dfList <- list()
counter = 1;
Whilecounter = nrow(inputDF)
#for testing just do 10 iterations,i = 10;
while (Whilecounter >0)
{
studyid_subjid=inputDF[Whilecounter,"STUDYID_SUBJID"]
vect = which(discoveredDf$STUDYID_SUBJID == studyid_subjid)
#was discovered and subset before
if (!is.null(vect))
{
#not subset before
if (length(vect)<1)
{
#subset the dataframe base on regex inputDF$STUDYID_SUBJID
df <- subset(inputDF, regexpr(studyid_subjid, inputDF$STUDYID_SUBJID) > 0)
#START OPTIMIZE
for (i in nrow(df))
{
#impute , add column mean & add to list
#apply(df[,c("y1","y2","y3","etc..")],2,function(x){x[is.na(x)] =mean(x, na.rm=TRUE)})
if (is.na(df[i,"y1"])) {df[i,"y1"] = mean(df[,"y1"], na.rm = TRUE)}
if (is.na(df[i,"y2"])) {df[i,"y2"] =mean(df[,"y2"], na.rm = TRUE)}
if (is.na(df[i,"y3"])) {df[i,"y3"] =mean(df[,"y3"], na.rm = TRUE)}
#impute using mean for CONTINUOUS variables
if (is.na(df[i,"COVAR_CONTINUOUS_2"])) {df[i,"COVAR_CONTINUOUS_2"] =mean(df[,"COVAR_CONTINUOUS_2"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_3"])) {df[i,"COVAR_CONTINUOUS_3"] =mean(df[,"COVAR_CONTINUOUS_3"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_4"])) {df[i,"COVAR_CONTINUOUS_4"] =mean(df[,"COVAR_CONTINUOUS_4"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_5"])) {df[i,"COVAR_CONTINUOUS_5"] =mean(df[,"COVAR_CONTINUOUS_5"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_6"])) {df[i,"COVAR_CONTINUOUS_6"] =mean(df[,"COVAR_CONTINUOUS_6"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_7"])) {df[i,"COVAR_CONTINUOUS_7"] =mean(df[,"COVAR_CONTINUOUS_7"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_10"])) {df[i,"COVAR_CONTINUOUS_10"] =mean(df[,"COVAR_CONTINUOUS_10"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_14"])) {df[i,"COVAR_CONTINUOUS_14"] =mean(df[,"COVAR_CONTINUOUS_14"], na.rm = TRUE)}
if (is.na(df[i,"COVAR_CONTINUOUS_30"])) {df[i,"COVAR_CONTINUOUS_30"] =mean(df[,"COVAR_CONTINUOUS_30"], na.rm = TRUE)}
#impute using mode ordinal & nominal values
if (is.na(df[i,"COVAR_ORDINAL_1"])) {df[i,"COVAR_ORDINAL_1"] =Mode(df[,"COVAR_ORDINAL_1"])}
if (is.na(df[i,"COVAR_ORDINAL_2"])) {df[i,"COVAR_ORDINAL_2"] =Mode(df[,"COVAR_ORDINAL_2"])}
if (is.na(df[i,"COVAR_ORDINAL_3"])) {df[i,"COVAR_ORDINAL_3"] =Mode(df[,"COVAR_ORDINAL_3"])}
if (is.na(df[i,"COVAR_ORDINAL_4"])) {df[i,"COVAR_ORDINAL_4"] =Mode(df[,"COVAR_ORDINAL_4"])}
#nominal
if (is.na(df[i,"COVAR_NOMINAL_1"])) {df[i,"COVAR_NOMINAL_1"] =Mode(df[,"COVAR_NOMINAL_1"])}
if (is.na(df[i,"COVAR_NOMINAL_2"])) {df[i,"COVAR_NOMINAL_2"] =Mode(df[,"COVAR_NOMINAL_2"])}
if (is.na(df[i,"COVAR_NOMINAL_3"])) {df[i,"COVAR_NOMINAL_3"] =Mode(df[,"COVAR_NOMINAL_3"])}
if (is.na(df[i,"COVAR_NOMINAL_4"])) {df[i,"COVAR_NOMINAL_4"] =Mode(df[,"COVAR_NOMINAL_4"])}
if (is.na(df[i,"COVAR_NOMINAL_5"])) {df[i,"COVAR_NOMINAL_5"] =Mode(df[,"COVAR_NOMINAL_5"])}
if (is.na(df[i,"COVAR_NOMINAL_6"])) {df[i,"COVAR_NOMINAL_6"] =Mode(df[,"COVAR_NOMINAL_6"])}
if (is.na(df[i,"COVAR_NOMINAL_7"])) {df[i,"COVAR_NOMINAL_7"] =Mode(df[,"COVAR_NOMINAL_7"])}
if (is.na(df[i,"COVAR_NOMINAL_8"])) {df[i,"COVAR_NOMINAL_8"] =Mode(df[,"COVAR_NOMINAL_8"])}
}#for
#END OPTIMIZE
dfList[[counter]] <- df
#add to discoveredDf since already substed
discoveredDf[nrow(discoveredDf)+1,]<- c(studyid_subjid)
counter = counter +1;
#for debugging to check progress
if (counter %% 100 == 0)
{
print(counter)
}
}
}
Whilecounter = Whilecounter -1;
}#end while
return (dfList)
}
Thanks
It's likely that performance can be improved in many ways, so long as you use a vectorized function on each column. Currently, you're iterating through each row, and then handling each column separately, which really slows you down. Another improvement is to generalize the code so you don't have to keep typing a new line for each variable. In the examples I'll give below, this is handled because continuous variables are numeric, and categorical are factors.
To get straight to an answer, you can replace your code to be optimized with the following (though fixing variable names) provided that your numeric variables are numeric and ordinal/categorical are not (e.g., factors):
impute <- function(x) {
if (is.numeric(x)) { # If numeric, impute with mean
x[is.na(x)] <- mean(x, na.rm = TRUE)
} else { # mode otherwise
x[is.na(x)] <- names(which.max(table(x)))
}
x
}
# Correct cols_to_impute with names of your variables to be imputed
# e.g., c("COVAR_CONTINUOUS_2", "COVAR_NOMINAL_3", ...)
cols_to_impute <- names(df) %in% c("names", "of", "columns")
library(purrr)
df[, cols_to_impute] <- dmap(df[, cols_to_impute], impute)
Below is a detailed comparison of five approaches:
Your original approach using for to iterate on rows; each column then handled separately.
Using a for loop.
Using lapply().
Using sapply().
Using dmap() from the purrr package.
The new approaches all iterate on the data frame by column and make use of a vectorized function called impute, which imputes missing values in a vector with the mean (if numeric) or the mode (otherwise). Otherwise, their differences are relatively minor (except sapply() as you'll see), but interesting to check.
Here are the utility functions we'll use:
# Function to simulate a data frame of numeric and factor variables with
# missing values and `n` rows
create_dat <- function(n) {
set.seed(13)
data.frame(
con_1 = sample(c(10:20, NA), n, replace = TRUE), # continuous w/ missing
con_2 = sample(c(20:30, NA), n, replace = TRUE), # continuous w/ missing
ord_1 = sample(c(letters, NA), n, replace = TRUE), # ordinal w/ missing
ord_2 = sample(c(letters, NA), n, replace = TRUE) # ordinal w/ missing
)
}
# Function that imputes missing values in a vector with mean (if numeric) or
# mode (otherwise)
impute <- function(x) {
if (is.numeric(x)) { # If numeric, impute with mean
x[is.na(x)] <- mean(x, na.rm = TRUE)
} else { # mode otherwise
x[is.na(x)] <- names(which.max(table(x)))
}
x
}
Now, wrapper functions for each approach:
# Original approach
func0 <- function(d) {
for (i in 1:nrow(d)) {
if (is.na(d[i, "con_1"])) d[i,"con_1"] <- mean(d[,"con_1"], na.rm = TRUE)
if (is.na(d[i, "con_2"])) d[i,"con_2"] <- mean(d[,"con_2"], na.rm = TRUE)
if (is.na(d[i,"ord_1"])) d[i,"ord_1"] <- names(which.max(table(d[,"ord_1"])))
if (is.na(d[i,"ord_2"])) d[i,"ord_2"] <- names(which.max(table(d[,"ord_2"])))
}
return(d)
}
# for loop operates directly on d
func1 <- function(d) {
for(i in seq_along(d)) {
d[[i]] <- impute(d[[i]])
}
return(d)
}
# Use lapply()
func2 <- function(d) {
lapply(d, function(col) {
impute(col)
})
}
# Use sapply()
func3 <- function(d) {
sapply(d, function(col) {
impute(col)
})
}
# Use purrr::dmap()
func4 <- function(d) {
purrr::dmap(d, impute)
}
Now, we'll compare the performance of these approaches with n ranging from 10 to 100 (VERY small):
library(microbenchmark)
ns <- seq(10, 100, by = 10)
times <- sapply(ns, function(n) {
dat <- create_dat(n)
op <- microbenchmark(
ORIGINAL = func0(dat),
FOR_LOOP = func1(dat),
LAPPLY = func2(dat),
SAPPLY = func3(dat),
DMAP = func4(dat)
)
by(op$time, op$expr, function(t) mean(t) / 1000)
})
times <- t(times)
times <- as.data.frame(cbind(times, n = ns))
# Plot the results
library(tidyr)
library(ggplot2)
times <- gather(times, -n, key = "fun", value = "time")
pd <- position_dodge(width = 0.2)
ggplot(times, aes(x = n, y = time, group = fun, color = fun)) +
geom_point(position = pd) +
geom_line(position = pd) +
theme_bw()
It's pretty clear that the original approach is much slower than the new approaches that use the vectorized function impute on each column. What about differences between the new ones? Let's bump up our sample size to check:
ns <- seq(5000, 50000, by = 5000)
times <- sapply(ns, function(n) {
dat <- create_dat(n)
op <- microbenchmark(
FOR_LOOP = func1(dat),
LAPPLY = func2(dat),
SAPPLY = func3(dat),
DMAP = func4(dat)
)
by(op$time, op$expr, function(t) mean(t) / 1000)
})
times <- t(times)
times <- as.data.frame(cbind(times, n = ns))
times <- gather(times, -n, key = "fun", value = "time")
pd <- position_dodge(width = 0.2)
ggplot(times, aes(x = n, y = time, group = fun, color = fun)) +
geom_point(position = pd) +
geom_line(position = pd) +
theme_bw()
Looks like sapply() is not great (as #Martin pointed out). This is because sapply() is doing extra work to get our data into a matrix shape (which we don't need). If you run this yourself without sapply(), you'll see that the remaining approaches are all pretty comparable.
So the major performance improvement is to use a vectorized function on each column. I suggested using dmap at the beginning because I'm a fan of the function style and the purrr package generally, but you can comfortably substitute for whichever approach you prefer.
Aside, many thanks to #Martin for the very useful comment that got me to improve this answer!
If you are going to be working with what looks like a matrix, then use a matrix instead of a dataframe, since indexing into a dataframe, like it was a matrix, is very costly. You might want to extract the numerical values to a matrix for part of your calculations. This can provide a significant increase in speed.
Here is a really simple and fast solution using data.table.
library(data.table)
# name of columns
cols <- c("a", "c")
# impute date
setDT(dt)[, (cols) := lapply(.SD, function(x) ifelse( is.na(x) & is.numeric(x), mean(x, na.rm = T),
ifelse( is.na(x) & is.character(x), names(which.max(table(x))), x))) , .SDcols = cols ]
I haven't compared the performance of this solution to the one provided by #Simon Jackson, but this should be pretty fast.
data from reproducible example
set.seed(25)
dt <- data.table(a=c(1:5,NA,NA,1,1),
b=sample(1:15, 9, replace=TRUE),
c=LETTERS[c(1:6,NA,NA,1)])