I'm using pseudo selectors for my hover and active classes. In this case the color for the hover and active is the same. The way to do it would be like this:
a {
color: #0090B2;
&:hover {
color: #FF7A00;
}
&.active {
color: #FF7A00;
}
}
but I would like to not repeat the same attributes, I'm looking for something like this, of course that doesn't work but you get the idea what I wanna do. How would be the right way to do it?. Should I just use a mixin?
a {
color: #0090B2;
&:hover, &.active {
color: #FF7A00;
}
}
Option 1
I don't understand what is wrong with your way, it's work for me:
a {
color: #0090B2;
&:hover, &.active {
color: #FF7A00;
}
}
Which will give you:
a {
color: #00acc1;
}
a:hover, a.active {
color: #0f9d58;
}
Option 2
a {
color : #00acc1;;
&:hover {
#extend %active_link;
}
&.active {
#extend %active_link;
}
}
%active_link {
color: #0f9d58;
}
Same results as before.
But, here you can do things like:
a {
color : #00acc1;;
&:hover {
#extend %active_link;
content: "AAA";
}
&.active {
#extend %active_link;
content: "BBB";
}
}
%active_link {
color: #0f9d58;
}
and get:
a {
color: #00acc1;
}
a:hover {
content: "AAA";
}
a.active {
content: "BBB";
}
a:hover, a.active {
color: #0f9d58;
}
Related
Apologies for the vague title; I appreciate suggestions. I've looked for similar questions but none seem (to me) to be asking the exact same thing.
Say I have this piece of CSS:
nav a {
color: blue;
}
nav li.selected a {
color: red;
}
What would be the recommended/preferred/easiest way to achieve this with nesting in Sass? I'd like to target a when it's a child of li.selected (i.e., referring to exactly one level above itself).
nav {
a {
color: blue;
??? {
color: red;
}
}
}
Here's what I've tried to no avail:
nav {
a {
color: blue;
li.selected & {
color: red;
}
}
}
/* results in li.selected nav a, not nav li.selected a */
nav {
$foo: &;
a {
color: blue;
#at-root #{$foo} li.selected & {
color: red;
}
}
}
/* results in nav li.selected nav a, not nav li.selected a */
Sorry if i get it wrong, but is this what you mean?
nav {
a {
color: blue;
}
li.selected a {
color: red;
}
}
I have this scss:
.nav {
&__item {
color: black;
}
}
This compiles to:
.nav__item
Is it possible to modify the above sccs so that it compiles with a tag in front of it, like the following?
a.nav__item
OR
li.nav_item
Here is one way using #at-root. This way avoids having to declare &__item twice.
.nav {
&__item {
color: black;
#at-root {
ul#{&} {
display: block;
}
}
}
}
Complies to
.nav__item {
color: black;
}
ul.nav__item {
display: block;
}
Try this:
.nav {
a#{&}__item {
color: black;
}
}
Output
.nav a.nav__item {
color: black;
}
Even though this is possible using
.nav {
a#{&}__item {
color: black;
}
}
I would highly encourage you to write it like this
a,
li {
&.nav {
&__item {
color: black;
}
}
}
I have to convert some SCSS files to LESS. For most part it is just case of changing $ with # but there are style that use the scss parent selector & that I don't know how to convert.
Here is example
// Sidebar
.sidebar {
.block {
&.newsletter {
.btn {
&:before {
background: transparent;
}
}
}
&.filter {
ol {
li {
a {
color: #blue;
&:before {
display: none;
}
}
}
}
}
.filter-options-title, .block-title {
color: #444;
padding-bottom: 10px;
font-size: 12px;
&:after {
color: #666;
}
}
}
}
How would I replace out those parent selectors to make it the same generated CSS?
The & parent selector is actually the same syntax in Less and SCSS!
From the Less Documentation on Parent Selectors:
The & operator
represents the parent selectors of a nested rule and is most commonly
used when applying a modifying class or pseudo-class to an existing
selector
In comparison, here's the SASS/ SCSS documentation on parent selectors for pseudo classes: http://sass-lang.com/documentation/Sass/Selector/Pseudo.html
So in the case of your code, it would be:
SCSS
$blue: blue;
.sidebar {
.block {
&.newsletter {
.btn {
&:before {
background: transparent;
}
}
}
&.filter {
ol li a {
color: $blue;
&:before {
display: none;
}
}
}
.filter-options-title, .block-title {
color: #444;
padding-bottom: 10px;
font-size: 12px;
&:after {
color: #666;
}
}
}
}
(try compiling/ validating here: https://www.sassmeister.com/)
LESS
#blue: blue;
.sidebar {
.block {
&.newsletter {
.btn {
&:before {
background: transparent;
}
}
}
&.filter {
ol li a {
color: #blue;
&:before {
display: none;
}
}
}
.filter-options-title, .block-title {
color: #444;
padding-bottom: 10px;
font-size: 12px;
&:after {
color: #666;
}
}
}
}
(try compiling/ validating here: http://winless.org/online-less-compiler)
As well as the official documentation, this article on CSS Tricks is helpful too: https://css-tricks.com/the-sass-ampersand
Hope that helps :)
Just when I thought Sass was the coolest thing since sliced bread, it had to go and let me down. I'm trying to use the ampersand to select a parent of a nested item. It's a complex selection and its returning some unexpected results...
My sass:
.page--about-us {
a {
text-decoration:none;
}
.fa-stack {
.fa {
color:pink;
}
a & {
&:hover {
.fa-circle-thin {
color:red;
}
.fa-twitter {
color:blue;
}
}
}
}
}
Outputted CSS:
.page--about-us a {
text-decoration: none;
}
.page--about-us .fa-stack .fa {
color: pink;
}
a .page--about-us .fa-stack:hover .fa-circle-thin {
color: red;
}
a .page--about-us .fa-stack:hover .fa-twitter {
color: blue;
}
Expected Output (Note the placement of the a tag):
.page--about-us a {
text-decoration: none;
}
.page--about-us .fa-stack .fa {
color: pink;
}
.page--about-us a .fa-stack:hover .fa-circle-thin {
color: red;
}
.page--about-us a .fa-stack:hover .fa-twitter {
color: blue;
}
Demo:
http://sassmeister.com/gist/8ed68bbe811bc9526f15
You can store the parent selector in a variable!
Take the following BEM-like SASS:
.content-block {
&__heading {
font-size: 2em;
}
&__body {
font-size: 1em;
}
&--featured {
&__heading {
font-size: 4em;
font-weight: bold;
}
}
}
The selector inside of .content-block--featured is going to be .content-block--featured .content-block--featured__heading which might not be what you're after.
It's not as elegant as the single ampersand but you can stash the parent selector into a variable! So to get what you might be after from the above example without hard-coding the parent selector:
.content-block {
$p: &; // store parent selector for nested use
&__heading {
font-size: 2em;
}
&__body {
font-size: 1em;
}
&--featured {
#{$p}__heading {
font-size: 4em;
font-weight: bold;
}
}
}
So, OP, in your case you might try something like this:
.page--about-us {
$about: &; // store about us selector
a {
text-decoration:none;
}
.fa-stack {
.fa {
color:pink;
}
#{$about} a & {
&:hover {
.fa-circle-thin {
color:red;
}
.fa-twitter {
color:blue;
}
}
}
}
}
This is the normal behavior, as described in Sass documentation (link):
& will be replaced with the parent selector as it appears in the CSS. This means that if you have a deeply nested rule, the parent selector will be fully resolved before the & is replaced.
Meaning:
.foo {
.bar {
.baz & {
color: red;
}
}
}
Will render as:
.baz .foo .bar {
color: red;
}
And not:
.baz .bar {
color: red;
}
The right way to get your expected result is this one:
.page--about-us {
a {
text-decoration:none;
.fa-stack:hover {
.fa-circle-thin {
color:red;
}
.fa-twitter {
color:blue;
}
}
}
.fa-stack {
.fa {
color:pink;
}
}
}
Is there any way I can reference parent value, like per example
.btn-blue {
background-color: $light-blue;
&:hover {
background-color: rgba($light-blue,.7);
}
}
.btn-green {
background-color: $light-green;
&:hover {
background-color: rgba($light-green,.7);
}
}
I would like to write one :hover selector which would get the value of the parent. Something like
.btn-blue {
background-color: $light-blue;
}
.btn-green {
background-color: $light-green;
}
.btn-green, .btn-blue {
&:hover {
background-color: rgba($parent_color,.7);
}
}
Any ideas?
You can use mxins and pass the color in:
#mixin btn-color($selColor)
{
background-color: $selColor;
&:hover { background-color: rgba($selColor,.7);
}
}
And use it like so:
.btn-green { #include btn-color($light-green); }
.btn-blue { #include btn-color($light-blue); }