How to build this query on Symfony with QueryBuilder? - symfony

Question

Please I am a beginner on symfony and I have 2 entities: category and professionnal with ORM many to many. And 'City' is an entity with ORM oneToMany with 'professionnal'.
In professionnel I have a property city. I want to show professionnal grouped by categories who have a special cityId putted on parameter in the url.
I put this query on sql
(for example city_id= 10873)
, it gives me the results.
SELECT * FROM sub_category AS a LEFT JOIN professionnel ON professionnel.city_id = 10873
but I don't know how to write with querybuilder.
I put this solution but I have errors:
$city = $paramFetcher->get('city');
$queryBuilder = $em->getRepository(SubCategory::class)
->createQueryBuilder('a')
->leftJoin('App\Entity\Professionnel','p')
->where('p.city = :city')
->setParameter('city', $city);
return $queryBuilder->getQuery()->getResult();
in log:
request.CRITICAL: Uncaught PHP Exception Doctrine\DBAL\Exception\SyntaxErrorException: "An exception occurred while executing 'SELECT c0_.id AS id_0, c0_.name AS name_1 FROM category c0_ LEFT JOIN professionnel p1_ WHERE p1_.city_id = ?' with params ["10873"]: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'WHERE p1_.city_id = '10873'' at line 1"
I search on forums too and I found that I can replaced the 'ON' of leftJoin as following, but shows me all professionnals:
$city = $paramFetcher->get('city');
$queryBuilder = $em->getRepository(SubCategory::class)
->createQueryBuilder('a')
->leftJoin('App\Entity\Professionnel','p','WITH','p.city = :city')
->setParameter('city', $city);
return $queryBuilder->getQuery()->getResult();
For the mapping, I put it like this:
class Category
{
/**
* Many professionnels have Many categories.
* #ORM\ManyToMany(targetEntity="App\Entity\Professionnel", mappedBy="Categories")
* #ORM\JoinTable(name="professionnel_category")
*/
private $professionnels;
}
class Professionnel extends User
{
/**
* Many professionel have Many categories.
* #ORM\ManyToMany(targetEntity="App\Entity\Category", inversedBy="professionnels")
* #Groups({"Default", "professionnel", "user"})
*/
private $categories;
}
Thank you so much for your help.

Answer 1

So, assuming that you have your entity relation set up correctly (please update your question with those), I see one mistake above.
If you look at the official Doctrine Query Builder documentation, the leftJoin method's third argument is either WITH or ON constant and not join predicate. That one comes as a 4th argument. But, even then, that join predicate is only used is a very specific use-case, where you want to further define your join relation. By looking at your example, I doubt that is your case.
With that being said, I think your code should look like this:
$city = $paramFetcher->get('city');
$queryBuilder = $em->getRepository(Category::class)
->createQueryBuilder('a');
->leftJoin('App\Entity\Professionnel','p')
->where('p.city_id = :city')
->setParameter('city', $city);
return $queryBuilder->getQuery()->getResult();
Now the question: is that really just a city_id (plain integer) or is that relation to some entity named City?
Please update your question with those details and I will update the answer, if necessary...
Hope this helps...

Answer 2

Firstly, you need describe relations in entities. Read more about this here
Secondary, you must call in join field (read as property), not a Entity.
inside CategoryRepository:
/** #return ArrayCollection|Category[] */
public function getByCityId(int $cityId): ArrayCollection
{
$qb = $this->createQueryBuilder('category');
$qb->leftJoin('category.professional', 'professional')
->leftJoin('category.city', 'city')
->where($qb->expr()->eq('city.id', $cityId));
return $qb->getQuery()->getResult();
}
Inside SomeController:someAction()
$cityId = $paramFetcher->get('city');
$categoriesList = $this->get('doctrine.orm.entity_manager')
->getRepository(Category::class)
->getByCityId($cityId);
As result you'll be have list of category, with joined professional and city.
I suggest to read this article on symfony docs