Xamarin Switch Toggled event : get bound item of list - xamarin.forms

Question

Latest Xamarin on Mac as of writing:
<ContentPage.Content>
<StackLayout>
<ListView x:Name="ItemsListView" ItemsSource="{Binding Items}" VerticalOptions="FillAndExpand" HasUnevenRows="true" RefreshCommand="{Binding LoadItemsCommand}" IsPullToRefreshEnabled="true" IsRefreshing="{Binding IsBusy, Mode=OneWay}" CachingStrategy="RecycleElement" ItemSelected="OnItemSelected">
<ListView.ItemTemplate>
<DataTemplate>
<ViewCell>
<StackLayout Orientation="Horizontal">
<StackLayout Padding="10">
<Label Text="{Binding Summary}" LineBreakMode="NoWrap" Style="{DynamicResource ListItemTextStyle}" FontSize="Medium" />
<Label Text="{Binding Reporter}" LineBreakMode="NoWrap" Style="{DynamicResource ListItemDetailTextStyle}" FontSize="Micro" />
</StackLayout>
<StackLayout Orientation="Horizontal" HorizontalOptions="EndAndExpand">
<Label Text="{Binding Start}" FontSize="Medium" VerticalOptions="Center"/>
<Switch IsToggled="{Binding Result}" Toggled="Handle_Toggled" VerticalOptions="Center"/>
</StackLayout>
</StackLayout>
</ViewCell>
</DataTemplate>
</ListView.ItemTemplate>
</ListView>
</StackLayout>
</ContentPage.Content>
How do I get the bound item to a Switch control in a ListView. The item is in the list of items bound to the ListView, provided by the ViewModel. You can 'switch' the item's toggle without selecting the row.
void Handle_Toggled(object sender, Xamarin.Forms.ToggledEventArgs e)
{
// In this event handler, how do I get the bound item from the ListView??
}

Answer 1

Normally, what you'd need to do, is to react to the changes of property "Result" in your item class, and keep your logic out of the Page class.
If you need to handle in the event, you can do it this way:
void Handle_Toggled(object sender, Xamarin.Forms.ToggledEventArgs e)
{
var switch = sender as Switch;
var item = switch.Parent.BindingContext as ItemViewModel;
}
Replace ItemViewModel by your item's type.