I was trying to see if it is possible to set the start and end parameters of the ts() function in the forecast R package. The reason for this is to then use window() to subset a train and test set by date.
The time frame is from 2015-01-01 00:00:00 to 12/31/2017 23:00
index esti
2015-01-01 00:00:00 1
2015-01-01 01:00:00 2
2015-01-01 02:00:00 3
2015-01-01 03:00:00 2
2015-01-01 04:00:00 5
2015-01-01 05:00:00 2
...
2017-12-31 18:00:00 0
2017-12-31 19:00:00 1
2017-12-31 20:00:00 0
2017-12-31 21:00:00 2
2017-12-31 22:00:00 0
2017-12-31 23:00:00 4
I used the following syntax to create the time series object:
tmp <- ts(dat, start = c(2015,1), frequency=24)
The returned object is this:
Time Series:
Start = c(2015, 1)
End = c(2015, 6)
Frequency = 24
It looks as if the ts object isn't correct here...
As far as I understand, the ts object does not work well with hourly input. It is recommended that you work with xts or zoo package instead. See this SO post.
Try the following:
## Creating an entire hourly dataframe similar to the example dat
x <-
lubridate::parse_date_time(
c("2015-01-01 00:00:00", "2017-12-31 23:00:00"),
orders = "ymdHMS"
)
y <- seq(x[1], x[2], by = "hour")
dat <- data.frame(
index = y, esti = sample(seq(0, 10), size = length(y),
replace = TRUE)
)
## xts package
library(xts)
tmp <- xts(dat, order.by = dat$index)
## Example window-ing
window(tmp, end = y[100])
Let me know if this does not work out.
Related
I have a time series (xts) of rain gage data and I would like to be able to sum all the rain amounts between a beginning and end time point from a list. And then make a new data frame that is StormNumber and TotalRain over that time
> head(RainGage)
Rain_mm
2019-07-01 00:00:00 0
2019-07-01 00:15:00 0
2019-07-01 00:30:00 0
2019-07-01 00:45:00 0
2019-07-01 01:00:00 0
2019-07-01 01:15:00 0
head(StormTimes)
StormNumber RainStartTime RainEndTime
1 1 2019-07-21 20:00:00 2019-07-22 04:45:00
2 2 2019-07-22 11:30:00 2019-07-22 23:45:00
3 3 2019-07-11 09:15:00 2019-07-11 19:00:00
4 4 2019-05-29 17:00:00 2019-05-29 20:45:00
5 5 2019-06-27 14:30:00 2019-06-27 17:15:00
6 6 2019-07-11 06:15:00 2019-07-11 09:00:00
I have this code that I got from the SO community when I was trying to do something similar in the past (but extract data rather than sum it). However, I have no idea how it works so I am struggling to adapt it to this situation.
do.call(rbind, Map(function(x, y) RainGage[paste(x, y, sep="/")],
StormTimes$RainStartTime, StormTimes$RainEndTime)
In this case I would suggest just to write your own function and then use apply to achieve what you want, for example:
dates <- c('2019-07-01 00:00:00', '2019-07-01 00:15:00',
'2019-07-01 00:30:00', '2019-07-01 00:45:00',
'2019-07-01 01:00:00', '2019-07-01 01:15:00')
dates <- as.POSIXct(strptime(dates, '%Y-%m-%d %H:%M:%S'))
mm <- c(0, 10, 10, 20, 0, 0)
rain <- data.frame(dates, mm)
number <- c(1,2)
start <- c('2019-07-01 00:00:00','2019-07-01 00:18:00')
start <- as.POSIXct(strptime(start, '%Y-%m-%d %H:%M:%S'))
end <- c('2019-07-01 00:17:00','2019-07-01 01:20:00')
end <- as.POSIXct(strptime(end, '%Y-%m-%d %H:%M:%S'))
storms <- data.frame(number, start, end)
# Sum of rain
f = function(x, output) {
# Get storm number
number = x[1]
# Get starting moment
start = x[2]
# Get ending moment
end = x[3]
# Calculate sum
output <- sum(rain[rain$dates >= start & rain$dates < end, 'mm'])
}
# Apply function to each row of the dataframe
storms$rain <- apply(storms, 1, f)
print(storms)
This yields:
number start end rain
1 1 2019-07-01 00:00:00 2019-07-01 00:17:00 10
2 2 2019-07-01 00:18:00 2019-07-01 01:20:00 30
So a column rain in storms now holds the sum of rain$mm, which is what you're after.
Hope that helps you out!
I have a problem applying a function (min) to a specific repeating time-period. Basically my data looks like in that sample:
library(xts)
start <- as.POSIXct("2018-05-18 00:00")
tseq <- seq(from = start, length.out = 1440, by = "10 mins")
Measurings <- data.frame(
Time = tseq,
Temp = sample(10:37,1440, replace = TRUE, set.seed(seed = 10)))
)
Measurings_xts <- xts(Measurings[,-1], Measurings$Time)
with much appreciated help (here), I managed to find out that min and max functions (contrary to mean, which works right away in period.apply) must be defined by a helper function and can then be calculated for logical datetime arguments(hours, days, years...) by using this solution:
colMin <- function(x, na.rm = FALSE) {
apply(x, 2, min, na.rm = na.rm)
}
epHours <- endpoints(Measurings_xts, "hours")
Measurings_min <- period.apply(Measurings_xts, epHours, colMin)
For meteorological analyses I need to calculate further minima for a less intuitive timespan, crossing the calendar day, that I fail to define in code:
I need to output the minimum nighttime temperature from e.g. 2018-05-18 19:00 to 2018-05-19 7:00 in the morning for each night in my dataset.
I have tried to move the timespan by manipulating(moving) the time column up or down, to include the nighttime in one calendar day. Since this solution is error-prone and doesn´t work for my real data, where some observations are missing. How do I use the POSIXct datetime and/or xts functionalities to calculate minima in this case?
You could solve this by creating your own "end points" when you use period.apply
# Choose the appropriate time ranges
z <- Measurings_xts["T19:00/T07:00"]
# Creating your own "endpoints":
epNights <- which(diff.xts(index(z), units = "mins") > 10) - 1
Subtract one off each index because the jumps are recorded at the start of the next "night interval" in the output from which().
Then add the last data point in the data set to your end points vector, and you can then use this in period.apply
epNights <- c(epNights, nrow(z))
Measurings_min <- period.apply(z, epNights, colMin)
Measurings_min
# [,1]
# 2018-05-18 07:00:00 10
# 2018-05-19 07:00:00 10
# 2018-05-20 07:00:00 10
# 2018-05-21 07:00:00 10
# 2018-05-22 07:00:00 10
# 2018-05-23 07:00:00 10
# 2018-05-24 07:00:00 11
# 2018-05-25 07:00:00 10
# 2018-05-26 07:00:00 10
# 2018-05-27 07:00:00 10
# 2018-05-27 23:50:00 12
here is one approach that works by defining a new group for each night interval
# define the time interval, e.g. from 19:00 to 7:00
from <- 19
to <- 7
hours <- as.numeric(strftime(index(Measurings_xts), format="%H"))
y <- rle(as.numeric(findInterval(hours, c(to,from)) != 1))
y$values[c(TRUE, FALSE)] <- cumsum(y$values[c(TRUE, FALSE)])
grp <- inverse.rle(y)
# grp is a grouping variable that is 0 for everything outside the
# defined interval , 1 for the first night, 2 for the second...
s <- split(Measurings_xts, grp); s$`0` <- NULL
# min_value will contain the minimum value for each night interval
min_value <- sapply(s, min)
# to see the date interval for each value
start <- sapply(s, function(x) as.character(index(x)[1]))
end <- sapply(s, function(x) as.character(index(x)[length(x)]))
data.frame(start, end, min_value)
# start end min_value
#1 2018-05-18 2018-05-18 06:50:00 10
#2 2018-05-18 19:00:00 2018-05-19 06:50:00 10
#3 2018-05-19 19:00:00 2018-05-20 06:50:00 10
#4 2018-05-20 19:00:00 2018-05-21 06:50:00 10
#5 2018-05-21 19:00:00 2018-05-22 06:50:00 10
#6 2018-05-22 19:00:00 2018-05-23 06:50:00 10
#7 2018-05-23 19:00:00 2018-05-24 06:50:00 11
#8 2018-05-24 19:00:00 2018-05-25 06:50:00 10
#9 2018-05-25 19:00:00 2018-05-26 06:50:00 10
#10 2018-05-26 19:00:00 2018-05-27 06:50:00 10
#11 2018-05-27 19:00:00 2018-05-27 23:50:00 12
How do you set 0:00 as end of day instead of 23:00 in an hourly data? I have this struggle while using period.apply or to.period as both return days ending at 23:00. Here is an example :
x1 = xts(seq(as.POSIXct("2018-02-01 00:00:00"), as.POSIXct("2018-02-05 23:00:00"), by="hour"), x = rnorm(120))
The following functions show periods ends at 23:00
to.period(x1, OHLC = FALSE, drop.date = FALSE, period = "days")
x1[endpoints(x1, 'days')]
So when I am aggregating the hourly data to daily, does someone have an idea how to set the end of day at 0:00?
As already pointed out by another answer here, to.period on days computes on the data with timestamps between 00:00:00 and 23:59:59.9999999 on the day in question. so 23:00:00 is seen as the last timestamp in your data, and 00:00:00 corresponds to a value in the next day "bin".
What you can do is shift all the timestamps back 1 hour, use to.period get the daily data points from the hour points, and then using align.time to get the timestamps aligned correctly.
(More generally, to.period is useful for generating OHLCV type data, and so if you're say generating say hourly bars from ticks, it makes sense to look at all the ticks between 23:00:00 and 23:59:59.99999 in the bar creation. then 00:00:00 to 00:59:59.9999.... would form the next hourly bar and so on.)
Here is an example:
> tail(x1["2018-02-01"])
# [,1]
# 2018-02-01 18:00:00 -1.2760349
# 2018-02-01 19:00:00 -0.1496041
# 2018-02-01 20:00:00 -0.5989614
# 2018-02-01 21:00:00 -0.9691905
# 2018-02-01 22:00:00 -0.2519618
# 2018-02-01 23:00:00 -1.6081656
> head(x1["2018-02-02"])
# [,1]
# 2018-02-02 00:00:00 -0.3373271
# 2018-02-02 01:00:00 0.8312698
# 2018-02-02 02:00:00 0.9321747
# 2018-02-02 03:00:00 0.6719425
# 2018-02-02 04:00:00 -0.5597391
# 2018-02-02 05:00:00 -0.9810128
> head(x1["2018-02-03"])
# [,1]
# 2018-02-03 00:00:00 2.3746424
# 2018-02-03 01:00:00 0.8536594
# 2018-02-03 02:00:00 -0.2467268
# 2018-02-03 03:00:00 -0.1316978
# 2018-02-03 04:00:00 0.3079848
# 2018-02-03 05:00:00 0.2445634
x2 <- x1
.index(x2) <- .index(x1) - 3600
> tail(x2["2018-02-01"])
# [,1]
# 2018-02-01 18:00:00 -0.1496041
# 2018-02-01 19:00:00 -0.5989614
# 2018-02-01 20:00:00 -0.9691905
# 2018-02-01 21:00:00 -0.2519618
# 2018-02-01 22:00:00 -1.6081656
# 2018-02-01 23:00:00 -0.3373271
x.d2 <- to.period(x2, OHLC = FALSE, drop.date = FALSE, period = "days")
> x.d2
# [,1]
# 2018-01-31 23:00:00 0.12516594
# 2018-02-01 23:00:00 -0.33732710
# 2018-02-02 23:00:00 2.37464235
# 2018-02-03 23:00:00 0.51797747
# 2018-02-04 23:00:00 0.08955208
# 2018-02-05 22:00:00 0.33067734
x.d2 <- align.time(x.d2, n = 86400)
> x.d2
# [,1]
# 2018-02-01 0.12516594
# 2018-02-02 -0.33732710
# 2018-02-03 2.37464235
# 2018-02-04 0.51797747
# 2018-02-05 0.08955208
# 2018-02-06 0.33067734
Want to convince yourself? Try something like this:
x3 <- rbind(x1, xts(x = matrix(c(1,2), nrow = 2), order.by = as.POSIXct(c("2018-02-01 23:59:59.999", "2018-02-02 00:00:00"))))
x3["2018-02-01 23/2018-02-02 01"]
# [,1]
# 2018-02-01 23:00:00.000 -1.6081656
# 2018-02-01 23:59:59.999 1.0000000
# 2018-02-02 00:00:00.000 -0.3373271
# 2018-02-02 00:00:00.000 2.0000000
# 2018-02-02 01:00:00.000 0.8312698
x3.d <- to.period(x3, OHLC = FALSE, drop.date = FALSE, period = "days")
> x3.d <- align.time(x3.d, 86400)
> x3.d
[,1]
2018-02-02 1.00000000
2018-02-03 -0.09832625
2018-02-04 -0.65075506
2018-02-05 -0.09423664
2018-02-06 0.33067734
See that the value of 2 on 00:00:00 did not form the last observation in the day for 2018-02-02 (00:00:00), which went from 2018-02-01 00:00:00 to 2018-02-01 23:59:59.9999.
Of course, if you want the daily timestamp to be the start of the day, not the end of the day, which would be 2018-02-01 as start of bar for the first row, in x3.d above, you could shift back the day by one. You could do this relatively safely for most timezones, when your data doesn't involve weekend dates:
index(x3.d) = index(x3.d) - 86400
I say relatively safetly, because there are corner cases when there are time shifts in a time zone. e.g. Be careful with day light savings. Simply subtracting -86400 can be a problem when going from Sunday to Saturday in time zones where day light saving occurs:
#e.g. bad: day light savings occurs on this weekend for US EST
z <- xts(x = 9, order.by = as.POSIXct("2018-03-12", tz = "America/New_York"))
> index(z) - 86400
[1] "2018-03-10 23:00:00 EST"
i.e. the timestamp is off by one hour, when you really want the midnight timestamp (00:00:00).
You could get around this problem using something much safer like this:
library(lubridate)
# right
> index(z) - days(1)
[1] "2018-03-11 EST"
I don't think this is possible because 00:00 is the start of the day. From the manual:
These endpoints are aligned in POSIXct time to the zero second of the day at the beginning, and the 59.9999th second of the 59th minute of the 23rd hour of the final day
I think the solution here is to use minutes instead of hours. Using your example:
x1 = xts(seq(as.POSIXct("2018-02-01 00:00:00"), as.POSIXct("2018-02-05 23:59:99"), by="min"), x = rnorm(7200))
to.period(x1, OHLC = FALSE, drop.date = FALSE, period = "day")
x1[endpoints(x1, 'day')]
In a dataframe, I have wind speed data measured four times a day, at 00:00, 06:00, 12:00 and 18:00 o'clock. To combine these with other data, I need to fill the time in between towards a resolution of 15 minutes. I would like to fill the gaps by simple interpolation.
The following example produces two corresponding sample dataframes. df1 and df2 need to be merged. In the resulting merged dataframe, the gap values between the 6-hourly values (where var == NA?) need to be filled by a simply mean interpolation. My problem is how to merge both and do the concrete interpolation between the given values.
First dataframe
Creation:
# create a corresponding sample data frame
df1 <- data.frame(
date = seq.POSIXt(
from = ISOdatetime(2015,10,1,0,0,0, tz = "GMT"),
to = ISOdatetime(2015,10,14,23,59,0, tz= "GMT"),
by = "6 hour"
),
windspeed = abs(rnorm(14*4, 10, 4)) # abs() because windspeed shoud be positive
)
Resulting dataframe:
> # show the head of the dataframe
> head(df1)
date windspeed
1 2015-10-01 00:00:00 17.928217
2 2015-10-01 06:00:00 11.306025
3 2015-10-01 12:00:00 6.648131
4 2015-10-01 18:00:00 10.320146
5 2015-10-02 00:00:00 2.138559
6 2015-10-02 06:00:00 9.076344
Second dataframe
Creation:
# create a 2nd corresponding sample data frame
df2 <- data.frame(
date = seq.POSIXt(
from = ISOdatetime(2015,10,1,0,0,0, tz = "GMT"),
to = ISOdatetime(2015,10,14,23,59,0, tz= "GMT"),
by = "15 min"
),
var = abs(rnorm(14*24*4, 300, 100))
)
Resulting dataframe:
> # show the head of the 2nd dataframe
> head(df2)
date var
1 2015-10-01 00:00:00 198.2657
2 2015-10-01 00:15:00 472.9041
3 2015-10-01 00:30:00 605.8776
4 2015-10-01 00:45:00 429.0949
5 2015-10-01 01:00:00 400.2390
6 2015-10-01 01:15:00 317.1503
This is a solution
First merge them to get using all = TRUE to get all values
df3 <- merge(df1, df2, all = TRUE)
Then use approx for Interpolation
df3$windspeed <- approx(x = df1$date, y = df1$windspeed, xout = df2$date)$y
The only problem there is that the las ones will be NA unless your last value of windspeed is there, but everything in between will be there
I have a table in R like:
start duration
02/01/2012 20:00:00 5
05/01/2012 07:00:00 6
etc... etc...
I got to this by importing a table from Microsoft Excel that looked like this:
date time duration
2012/02/01 20:00:00 5
etc...
I then merged the date and time columns by running the following code:
d.f <- within(d.f, { start=format(as.POSIXct(paste(date, time)), "%m/%d/%Y %H:%M:%S") })
I want to create a third column called 'end', which will be calculated as the number of hours after the start time. I am pretty sure that my time is a POSIXct vector. I have seen how to manipulate one datetime object, but how can I do that for the entire column?
The expected result should look like:
start duration end
02/01/2012 20:00:00 5 02/02/2012 01:00:00
05/01/2012 07:00:00 6 05/01/2012 13:00:00
etc... etc... etc...
Using lubridate
> library(lubridate)
> df$start <- mdy_hms(df$start)
> df$end <- df$start + hours(df$duration)
> df
# start duration end
#1 2012-02-01 20:00:00 5 2012-02-02 01:00:00
#2 2012-05-01 07:00:00 6 2012-05-01 13:00:00
data
df <- structure(list(start = c("02/01/2012 20:00:00", "05/01/2012 07:00:00"
), duration = 5:6), .Names = c("start", "duration"), class = "data.frame", row.names = c(NA,
-2L))
You can simply add dur*3600 to start column of the data frame. E.g. with one date:
start = as.POSIXct("02/01/2012 20:00:00",format="%m/%d/%Y %H:%M:%S")
start
[1] "2012-02-01 20:00:00 CST"
start + 5*3600
[1] "2012-02-02 01:00:00 CST"