Regex in if else statement in R - r

Question

I have a rather simple question. I am trying to get the if else statement below to work.
It is supposed to assign '1' if the if statement is met, 0 otherwise.
My problem is that I cannot get the regex in the if statement to work ('\w*|\W*). It is supposed to specify the condition that the string either is "Registration Required" or Registration required followed by any character. I cannot specify the exact cases, because following the "Registration required" (in the cases where something follows), it will usually be a date (varying for each observation) and a few words.
Registration_cleaned <- c()
for (i in 1:length(Registration)) {
if (Registration[i] == ' Registration Required\\w*|\\W*') {
Meta_Registration_cleaned <- 1
} else {
Meta_Registration_cleaned <- 0
}
Registration_cleaned <- c(Registration_cleaned, Meta_Registration_cleaned)
}

Answer 1

You may use transform together with ifelse function to set the Meta_Registration_cleaned.
For matching the regular expression grep function can be used with pattern "Registration Required\w*".
Registration <- data.frame(reg = c("Registration Required", "Registration Required ddfdqf","some str", "Regixxstration Required ddfdqf"),stringsAsFactors = F)
transform(Registration,Meta_Registration_cleaned = ifelse(grepl("Registration Required\\w*",Registration[,"reg"]), 1, 0))
Gives result:
reg Meta_Registration_cleaned
1 Registration Required 1
2 Registration Required ddfdqf 1
3 some str 0
4 Regixxstration Required ddfdqf 0

Answer 2

I might have misunderstood the OP completely, because I have understood the question entirely differently than anyone else here.
My comment earlier suggested looking for the regex at the end of the string.
Registration <- data.frame(reg = c("Registration Required", "Registration Required ddfdqf","Registration Required 10/12/2000"),stringsAsFactors = F)
#thanks #user1653941 for drafting the sample vector
Registration$Meta_Registration_cleaned <- grepl('Registration required$', Registration$reg, ignore.case = TRUE)
Registration
1 Registration Required TRUE
2 Registration Required ddfdqf FALSE
3 Registration Required 10/12/2000 FALSE
I understand the OP as such that the condition is: Either the string "Registration required" without following characters, or... anything else. Looking forward to the OPs comment.