I want to select the first and the last child with CSS but it does not work. Please take a look at my Fiddle and help me:
.area {
height: 100px;
width: 100px;
}
.area:first-child {
background-color: red;
}
.area:last-child {
background-color: green;
}
<div class="area">1</div>
<div class="area">2</div>
<div class="area">3</div>
<div class="area">4</div>
https://jsfiddle.net/rbw8dpsb/1/
I advise you to add a container as in your code they are childs of body BUT you don't know the last-child or the first-child of body as you may have other elements like script tags or other tags dynamically added (like in the snippet here or with jsfiddle or any other online coding tools).
.area {
height: 100px;
width: 100px;
}
.area:first-child {
background-color: red;
}
.area:last-child {
background-color: green;
}
<div>
<div class="area">1</div>
<div class="area">2</div>
<div class="area">3</div>
<div class="area">4</div>
</div>
Here is a screenshot to show what is inside your body when you run the snippet:
As you may clearly notice, there is a div added at the end which is the last-child of the body. Adding a container will avoid you dealing with random settings and hidden elements added.
If you don't want to let all that divs in another structure you should use first-of-type and last-of-type instead of first-child and last-child
.area {
height: 100px;
width: 100px;
}
.area:first-of-type {
background-color: red;
}
.area:last-of-type {
background-color: green;
}
<div class="area">1</div>
<div class="area">2</div>
<div class="area">3</div>
<div class="area">4</div>
As Temani Afif pointed, this solution is arbitrary and may not work in all the situations. As shown, it is not properly working on the code snippet but it does on JSFiddle for example. I.E. https://jsfiddle.net/vm1scerv/
Related
I've currently got a few buttons with the .continue class on a webpage, structured with the following code:
<div class="continue" data-section="1">
Continue
<i class="fas fa-arrow-right" id="continueArrow1"></i>
</div>
Each of the continue buttons have a different "data-section" values, and are also placed against different backgrounds on the webpage. I'm wondering if there is a way I am able to target one of these continue button divs that have a certain data-section value, and change the styling of those who match.
Something like:
.continue:data-section=1{
//css that styles button with data-section1
}
.continue:data-section=2{
//css that styles button with data-section2
}
Obviously I could always just give them different IDs, but that leads to a lot of code duplication for the JS and JQuery animations.
Use the attribute selector:
.continue[data-section="1"] {
...
}
Example:
div {
width: 100px;
height: 100px;
background: blue;
display: inline-block;
margin: 5px;
}
.continue[data-section="2"] {
background: red;
}
/*We can combine this selector with other selectors as we normally would:*/
.continue[data-section="2"]:hover {
background: yellow;
}
<div class="continue" data-section="1"></div>
<div class="continue" data-section="2"></div>
<div class="continue" data-section="3"></div>
<div class="continue" data-section="4"></div>
<div class="continue" data-section="5"></div>
Read more on MDN
I understand that I can change another element's style when hovering on a different element like this:
.element-one:hover .element-two {
opacity: 0.8;
}
But how can I change the style of all the elements in the page except element-two when I hover on element-one?
You can use .element-one:hover :not(.element-two).
Here is an example:
.element-one:hover :not(.element-two) {
opacity: 0.8;
}
.element-one {
background: black;
margin: 10px;
}
.element-one div {
background: green;
border: 1px solid blue;
margin: 10px;
padding: 10px;
}
<div class="element-one">
<div class="element-two">
element-two
</div>
<div class="element-three">
element-three
</div>
<div class="element-four">
element-four
</div>
</div>
However - note that it will work only for elements inside element-one and not for all the elements in the page.
You can do this with body for example, but the problem there is that .element-two is probably also inside some other element that exists inside body, and in such case the .element-two will get the opacity from it's containing element.
I have some pseudo code like this:
<div class="container">
<div class="hiddenatfirst">
<img>
<img>
<img>
</div>
</div>
and css like so:
.hiddenatfirst{
display:none;
}
.container:hover .hiddenatfirst{
display:block;
}
.hiddenatfirst:hover{
display:block;
}
The problem is - I have a design website and a lot of visitors have the pinterst extension installed. When someone hovers over the pin-it button that gets added to the images inside the .hiddenatfirst div the div gets hidden again.
I don't want to remove the pin-it buttons from the images but I don't want them to get in the way of the :hover events.
Any ideas?
Apologies for the pseudo-code, the real code is pretty messy and in staging! Hopefully this explains what I need.
Thanks
PS - if you look at the .third-level-menu in the navigation here you'll see it in action (note you'll need the pinterest chrome extension installed)
http://smith-hoyt.myshopify.com/?preview_theme_id=12397927
PPS - this is a crappy GIF but I think shows what's happening too:
http://recordit.co/anNtu8W1Vo
PPPS - you can see the pin-it button that pinterest adds to each image in this image: https://twitter.com/tomcritchlow/status/573920066124836864/photo/1
Most probably the problem is that 'Pin it' button is absolutely positioned on top of the image, but it's not the container's child, so hover on it hides the image like on the following sample:
.container {
display: block;
width: 500px;
height: 315px;
background-color: gray;
}
.hiddenatfirst {
display: none;
}
#pinit {
position: absolute;
top: 32px;
left: 32px;
}
.container:hover .hiddenatfirst {
display: block;
}
.hiddenatfirst:hover {
display: block;
}
<div class="container">
<div class="hiddenatfirst">
<img src='https://dq1eylutsoz4u.cloudfront.net/2014/10/sf-cat.jpg' />
</div>
</div>
<img id='pinit' src='http://www.brandaiddesignco.com/insights/PinIt.png' />
What you can do is using JavaScript or jQuery find all the 'Pin it' buttons and move them to the appropriate containers with the positions recalculation, so the result HTML will be like the following:
.container {
display: block;
width: 500px;
height: 315px;
background-color: gray;
}
.hiddenatfirst {
display: none;
}
#pinit {
position: absolute;
top: 32px;
left: 32px;
}
.container:hover .hiddenatfirst {
display: block;
}
.hiddenatfirst:hover {
display: block;
}
<div class="container">
<div class="hiddenatfirst">
<img src='https://dq1eylutsoz4u.cloudfront.net/2014/10/sf-cat.jpg' />
<img id='pinit' src='http://www.brandaiddesignco.com/insights/PinIt.png' />
</div>
</div>
Rather than use the javascript solution above, since these images are small and in the navigation I found a way to remove the pin-it button, simply add to each image:
nopin="nopin"
As per the documentation here:
https://developers.pinterest.com/on_hover_pin_it_buttons/
I'm looking for the simplest way to break up a collection of inline-blocked divs without resorting to extra markup (such as br).
I started off naively thinking that the following would do the trick except that 'four' ends up on a line of its own as well which I don't really understand.
.inline {
display:inline-block;
}
.newline {
display:block;
}
<div class="inline">one</div>
<div class="inline">two</div>
<div class="inline newline">three</div>
<div class="inline">four</div>
I have tried solutions using :after/:before found here on Stackoverflow but these only work for me if my elements are inline instead of inline-block.
Regrettably I also need to support IE6!
Attempt with floats
This example below does not display properly in IE 6
.inline {
float: left;
width: 50px;
height: 50px;
background: #F00;
}
.newline {
clear: left;
}
<div class="inline">one</div>
<div class="inline">two</div>
<div class="inline newline">three</div>
<div class="inline">four</div>
The result in IE 6
For IE6 and other old browsers you need to add a clear line for example using this code:
<div class="inline">one</div>
<div class="inline">two</div>
<div class="visualClear"></div>
<div class="inline">three</div>
<div class="inline">four</div>
.inline {
float: left;
width: 50px;
height: 50px;
background: #F00;
}
.visualClear {
clear: both;
display: block;
}
I know that it isnĀ“t very pretty but it will work for you.
I have a parent div, that holds three div's. They are basically columns. I need to remove the margin on the last one but can't get the right selector
HTML:
<div class="productContainer">
<div class="productBox"></div>
<div class="productBox"></div>
<div class="productBox"></div>
<!--/ productContainer --></div>
Here's the CSS:
.productContainer {
width: 980px;
height: 400px;
display: block;
float: left;
}
How do you target the third child div of a parent? this should work no?
.productContainer > .productBox {
width: 320px;
height: 400px;
display: block;
float: left;
margin: 0 10px 0 0;
}
.produtContainer > .productBox nth:child(3) {
margin-right: 0;
}
While you can use the :last-child selector, it's not going to work in any version of IE before 8. Generally what I do in this situation is add a last class to the last element in the list:
<div class="productContainer">
<div class="productBox"></div>
<div class="productBox"></div>
<div class="productBox last"></div>
And then add this rule below the .productContainer .productBox rule in the stylesheet:
.produtContainer .last {
margin-right: 0;
}
.productContainter div:last-child
You can do :first-child or :last child to target the first and last element.
compatibility: http://www.quirksmode.org/css/contents.html
You can use :last-child selector for the rule
.productContainer div:last-child
{
// rule
}
http://www.quirksmode.org/css/firstchild.html
You can use the last-child pseudo-selector in this case...
.productContainer > .productBox:last-child {
margin-right: 0;
}
Note: This will not work in IE8 and older, as this is a part of CSS3. For something more portable, you might want to try this...
<div class="productBox last"></div>
.productContainer > .productBox.last {
margin-right: 0;
}