Matter-js - How to get width and height of rectangle? - matter.js

Matter-js - How to get width and height of rectangle ?
I need to know is there distance return method implemented in Matter-js .
// part.vertices[0] and part.vertices[1]
I wanna integrate tiles option.
This is how looks critical part (i use override function for Render.bodies it is most interest for me) .:
for (let x = 0; x < this.tiles; x++) {
c.drawImage(
texture,
texture.width * -part.render.sprite.xOffset * part.render.sprite.xScale,
texture.height * -part.render.sprite.yOffset * part.render.sprite.yScale,
texture.width * part.render.sprite.xScale,
texture.height * part.render.sprite.yScale);
}

const { min, max } = part.bounds
it will contain what you need in { x, y }
just substract max.x - min.x & max.y - min.y

I went with a solution very similar to the following:
var width = 30;
var height = 30;
var rect = Bodies.rectangle(150, 100, width, height, {density:0.01, className:"brick", width:width, height:height});
console.log(rect.className, rect.width); // "brick", 30
I decided to carry the original width/height information along with other custom properties such as className
The reason why is because bounds is affected by the rotation of any non perfectly-circular object eg. a rotated rectangle's bounds could be up to ~30% wider than it's actual width.

There are two solutions that I've found.
1- Create a class to wrap the matter.js body, which will also hold onto the height and width. ie:
class rectWrapper {
constructor(x, y, width, height, options){
this.width = width
this.height = height
this.body = Matter.Bodies.rectangle(x, y, width, height, options)
}
}
2- Another way is to use the magic of math to determine the distance between two coordinate points, using Body.vertices[0] and Body.vertices[1] for the width, and Body.vertices[0] and Body.vertices[3] for height. This would also account for any rotation. This link explains it clearly, for 2 and 3 dimensions:
https://sciencing.com/calculate-distance-between-two-coordinates-6390158.html
I would recommend writing your own "utility function" to do this. A heavy handed example might look like this:
function distance(x1, y1, x2, y2){
var x = Math.abs(x1-x2)
var y = Math.abs(y1-y2)
return Math.sqrt((x*x)+(y*y))
}
So a call might look like:
var rect = Matter.Bodies.rectangle(0,0,10,50)
var width = distance(rect.vertices[0].x, rect.verticies[0].y, rect.vertices[1].x, rect.vertices[1].y)
var height = distance(rect.vertices[0].x, rect.vertices[0].y, rect.vertices[3].x, rect.vertices[3].y)
Alternatively, if you happen to be using p5.js as your renderer, you can use p5.dist() which takes x1, y1, x2, y2 as arguments and returns the distance (basically the same as the function above):
https://p5js.org/reference/#/p5/dist
Note, this will only work for rectangles. If you're using different kinds of geometry, I would probably just make a wrapper class myself.

Related

Three.js calculate object distance required to fill screen

I've seen lots of questions on how to zoom the camera so an object fills the screen, but I'm trying to move the object to fill the screen.
I've been trying something like this using the original photos pixel size, and these objects have been scaled:
var dist = object.originalSize.height > $(window).height()
|| object.originalSize.width > $(window).width()
? ( $(window).height() / object.originalSize.height ) * 100
: 10;
var pLocal = new THREE.Vector3( 0, 0, -dist);
var target = pLocal.applyMatrix4( camera.matrixWorld );
var tweenMove = new TWEEN.Tween(object.position).to(target, 1500).easing(TWEEN.Easing.Cubic.InOut);
To come up with a vector to move the object to, however, I can't get the object to fill the screen. Any idea of the maths I need to calculate how far an object needs to be to fill the screen?
The object is a Object3D with different children depending on it's type.
I know the original photographs dimensions (object.originalSize.height) and I know the geometry that has been scaled up to fit with power of 2.
Any clue gratefully received on how to calculate the distance required from the camera to ensure the object fits inside the bounds of the screen.
I also know the bounding box of the item, i.e. from 1024 to 128.
This works, not sure why..
var vFOV = camera.fov * Math.PI / 180;
var ratio = 2 * Math.tan( vFOV / 2 );
var screen = ratio * (window.innerWidth / window.innerHeight) ;
var size = getCompoundBoundingBox( object ).max.y;
var dist = (size/screen) / 4;

Tiled MapObject size

I am loading Tiled map via TmxMapLoader and I have no trouble getting tiles, etc. But when I want to extract values from Object Layer, I am only able to get x, y with this code:
MapProperties props = layer.getObjects().get(i).getProperties();
float x = (float) props.get("x");
float y = (float) props.get("y");
Which gets me the right values, but when I try to add this:
float width = (float) props.get("width");
float height = (float) props.get("height");
It throws me this error:
Exception in thread "LWJGL Application" java.lang.NullPointerException
at cz.vilix.managers.MapManager.<init>(MapManager.java:67)
at cz.vilix.main.Game.create(Game.java:50)
at com.badlogic.gdx.backends.lwjgl.LwjglApplication.mainLoop(LwjglApplication.java:136)
at com.badlogic.gdx.backends.lwjgl.LwjglApplication$1.run(LwjglApplication.java:114)
(Line 67 in MapManager is where I try to get the width value.) It seems a bit ood to me, because I though, that I can get anything from the properties of an object, which is listed in the properties window:
Also using "Width" & "Height" instead of "width" & "height" doesn't work.
Changing the type to Object like this:
Object width = props.get("Width");
Object height = props.get("Height");
System.out.println(width + " " + height);
Prints: null null.
The solution that works is to get RectangleMapObject (or any other shape), and the get the basic Rectangle with this code: Rectangle r = rect.getRectangle() and the you can use parameters of the Rectangle.
Or you can skip the step of creating a new Rectangle object and use it as in this code:
RectangleMapObject rect = (RectangleMapObject) layer.getObjects().get(i);
float x = (float) rect.getRectangle().x;
float y = (float) rect.getRectangle().y;
float width = rect.getRectangle().width;
float height = rect.getRectangle().height;

How to do Joint tracking in Kinect with a scaled Image

I trying to do some Joint Tracking with kinect (just put a ellipse inside my right hand) everything works fine for a default 640x480 Image, i based myself in this channel9 video.
My code, updated to use the new CoordinateMapper classe is here
...
CoordinateMapper cm = new CoordinateMapper(this.KinectSensorManager.KinectSensor);
ColorImagePoint handColorPoint = cm.MapSkeletonPointToColorPoint(atualSkeleton.Joints[JointType.HandRight].Position, ColorImageFormat.RgbResolution640x480Fps30);
Canvas.SetLeft(elipseHead, (handColorPoint.X) - (elipseHead.Width / 2)); // center of the ellipse in center of the joint
Canvas.SetTop(elipseHead, (handColorPoint.Y) - (elipseHead.Height / 2));
This works. The question is:
How to do joint tracking in a scaled image, 540x380 for example?
The solution for this is pretty simple, i fugured it out.
What a need to do is find some factor to apply to the position.
This factor can be found takin the atual ColorImageFormat of the Kinect and dividing by the desired size, example:
Lets say i am working with the RgbResolution640x480Fps30 format and my Image (ColorViewer) have 220x240. So, lets find the factor for X:
double factorX = (640 / 220); // the factor is 2.90909090...
And the factor for y:
double factorY = (480/ 240); // the factor is 2...
Now, i adjust the position of the ellipse using this factor.
Canvas.SetLeft(elipseHead, (handColorPoint.X / (2.909090)) - (elipseHead.Width / 2));
Canvas.SetTop(elipseHead, (handColorPoint.Y / (2)) - (elipseHead.Height / 2));
I've not used the CoordinateMapper yet, and am not in front on my Kinect at the moment, so I'll toss out this first. I'll see about an update when I get working with the Kinect again.
The Coding4Fun Kinect Toolkit has a ScaleTo extension as part of the library. This adds the ability to take a joint and scale it to any display resolution.
The scaling function looks like this:
private static float Scale(int maxPixel, float maxSkeleton, float position)
{
float value = ((((maxPixel / maxSkeleton) / 2) * position) + (maxPixel/2));
if(value > maxPixel)
return maxPixel;
if(value < 0)
return 0;
return value;
}
maxPixel = the width or height, depending on which coordinate your scaling.
maxSkeleton = set this to 1.
position = the X or Y coordinate of the joint you want to scale.
If you were to just include the above function you could call it like so:
Canvas.SetLeft(e, Scale(640, 1, joint.Position.X));
Canvas.SetTop(e, Scale(480, 1, -joint.Position.Y));
... replacing your 640 & 480 with a different scale.
If you include the Coding4Fun Kinect Toolkit, instead of re-writing code, you could just call it like so:
scaledJoin = rawJoint.ScaleTo(640, 480);
... then plug in what you need.

How do I get the visual width and height of a rotated component?

I'm playing around with code like this:
<s:Button id="test" label="test" transformX="{Math.floor(test.width/2)}" rotationY="20" x="20" y="20" />
The button is rotated on the Y axis and the rotate pivot is in the middle of the button.
This will create a button that looks something like this:
(source: jeffryhouser.com)
The rotated button is, visually, filling a different space than the x, y, height, and width values would you have believe.
The "A" value in my image is the height of the button. But, what I want to use for calculation and placement purposes is the B value.
Additionally, I'd like to perform similar calculations with the width; getting the width from the top right corner to the bottom left corner.
How do I do this?
I put together a sample to show off the various approaches for calculating this that people are suggesting. The source code is also available. Nothing is quite working like I'd expect. For example, turn the rotationSlider to 85. The button is effectively invisible, yet all approaches are still giving it height and width.
My math may be a bit rusty, but this is how I would find the answer :
You would extend a right-triangle from the right edge of the button to the bottom-most point of the diagram you have (A-B). You can then use the Law of Sines to get three angles : 90', 20' and 70' (90 will always be there, and then your variable - 180 for the third angle).
You can then use the following formula to find your answer :
B = ((button.width * sin(button.rotationY)) / (sin(90 -button.rotationY)) + (button.height)
getBounds(..) and getRect(..) are supposed to be the methods for getting the width and height of transformed objects.
Not tried them in Flex 4 yet, but they always worked for me in Flex 3.
The answer was in one of the comments from James Ward on this question and is located at this blog post.
The one thing the blog post doesn't say is that in many cases, the perspectiveProjection property of the transform property on the class in question will be null. The linked to example took care of this by setting the maintainProjectionCenter property to true. But, you could also create a new perspectiveProjection object like this:
object.transform.perspectiveProjection = new PerspectiveProjection();
I wrapped up the function from evtimmy into a class:
/**
* DotComIt/Flextras
* Utils3D.as
* Utils3D
* jhouser
* Aug 5, 2010
*/
package com.flextras.coverflow
{
import flash.geom.Matrix3D;
import flash.geom.PerspectiveProjection;
import flash.geom.Rectangle;
import flash.geom.Utils3D;
import flash.geom.Vector3D;
public class TransformUtilities
{
public function TransformUtilities()
{
}
//--------------------------------------------------------------------------
//
// Methods
//
//--------------------------------------------------------------------------
//----------------------------------
// projectBounds
//----------------------------------
// info from
// http://evtimmy.com/2009/12/calculating-the-projected-bounds-using-utils3dprojectvector/
/**
* Method retrieved from
* http://evtimmy.com/2009/12/calculating-the-projected-bounds-using-utils3dprojectvector/
*
* #param bounds: The rectangle that makes up the object
* #param matrix The 3D Matrix of the item
* #param the projection of the item's parent.
*/
public static function projectBounds(bounds:Rectangle,
matrix:Matrix3D,
projection:PerspectiveProjection):Rectangle
{
// Setup the matrix
var centerX:Number = projection.projectionCenter.x;
var centerY:Number = projection.projectionCenter.y;
matrix.appendTranslation(-centerX, -centerY, projection.focalLength);
matrix.append(projection.toMatrix3D());
// Project the corner points
var pt1:Vector3D = new Vector3D(bounds.left, bounds.top, 0);
var pt2:Vector3D = new Vector3D(bounds.right, bounds.top, 0)
var pt3:Vector3D = new Vector3D(bounds.left, bounds.bottom, 0);
var pt4:Vector3D = new Vector3D(bounds.right, bounds.bottom, 0);
pt1 = Utils3D.projectVector(matrix, pt1);
pt2 = Utils3D.projectVector(matrix, pt2);
pt3 = Utils3D.projectVector(matrix, pt3);
pt4 = Utils3D.projectVector(matrix, pt4);
// Find the bounding box in 2D
var maxX:Number = Math.max(Math.max(pt1.x, pt2.x), Math.max(pt3.x, pt4.x));
var minX:Number = Math.min(Math.min(pt1.x, pt2.x), Math.min(pt3.x, pt4.x));
var maxY:Number = Math.max(Math.max(pt1.y, pt2.y), Math.max(pt3.y, pt4.y));
var minY:Number = Math.min(Math.min(pt1.y, pt2.y), Math.min(pt3.y, pt4.y));
// Add back the projection center
bounds.x = minX + centerX;
bounds.y = minY + centerY;
bounds.width = maxX - minX;
bounds.height = maxY - minY;
return bounds;
}
}
}
Although that is the answer to my question, I'm not sure if it was the solution to my problem. Thanks everyone!

Flex/ActionScript - rotate Sprite around its center

I have created a Sprite in Actionscript and rendered it to a Flex Canvas. Suppose:
var fooShape:Sprite = new FooSpriteSubclass();
fooCanvas.rawChildren.addChild(myshape);
//Sprite shape renders on screen
fooShape.rotation = fooNumber;
This will rotate my shape, but seems to rotate it around the upper-left
point of its parent container(the canvas).
How can I force the Sprite to rotate about is own center point? I could obviously
write code to calculate the rotation, and then have it re-render, but I think there
must be a built-in way to do this, and certainly do not want to 'reinvent the wheel'
if possible.
I am using FlexBuilder, and therefore do not have access to the full Flash API.
Thank you much!
The following steps are required to rotate objects based on a reference point (using Matrix object and getBounds):
Matrix translation (moving to the reference point)
Matrix rotation
Matrix translation (back to original position)
For example to rotate an object 90 degrees around its center:
// Get the matrix of the object
var matrix:Matrix = myObject.transform.matrix;
// Get the rect of the object (to know the dimension)
var rect:Rectangle = myObject.getBounds(parentOfMyObject);
// Translating the desired reference point (in this case, center)
matrix.translate(- (rect.left + (rect.width/2)), - (rect.top + (rect.height/2)));
// Rotation (note: the parameter is in radian)
matrix.rotate((90/180)*Math.PI);
// Translating the object back to the original position.
matrix.translate(rect.left + (rect.width/2), rect.top + (rect.height/2));
Key methods used:
Matrix.rotate
Matrix.translate
DisplayObject.getBounds
Didn't have much luck with the other examples. This one worked for me. I used it on a UIComponent.
http://www.selikoff.net/2010/03/17/solution-to-flex-image-rotation-and-flipping-around-center/
private static function rotateImage(image:Image, degrees:Number):void {
// Calculate rotation and offsets
var radians:Number = degrees * (Math.PI / 180.0);
var offsetWidth:Number = image.contentWidth/2.0;
var offsetHeight:Number = image.contentHeight/2.0;
// Perform rotation
var matrix:Matrix = new Matrix();
matrix.translate(-offsetWidth, -offsetHeight);
matrix.rotate(radians);
matrix.translate(+offsetWidth, +offsetHeight);
matrix.concat(image.transform.matrix);
image.transform.matrix = matrix;
}
Actually I had to add this code to make above solutions work for me.
private var _rotateCount = 0;
var _origginalMatrix:Matrix=new Matrix();
.........
if (_rotateCount++ >= 360 / angleDegrees)
{
myObject.transform.matrix = _origginalMatrix;
_rotateCount = 0;
return;
}
var matrix:Matrix = myObject.transform.matrix;
....
Without that after some long time rotated object slowly moves somewhere right top.
An alternative solution is to put your object inside another View, move it so that your image's center is at the container's top-left corner, and then rotate the container.
import spark.components.*;
var myContainer:View = new View();
var myImage:Image = new Image();
myContainer.addElement(myImage);
myImage.x = myImage.width / -2;
myImage.y = myImage.height / -2;
addElement(myContainer);
myContainer.rotation = whateverAngle;
One issue might be that the width of the image isn't know at the moment it is created, so you might want to find a way around that. (Hardcode it, or see if myImage.preliminaryWidth works)
/**
* Rotates the object based on its center
* Parameters: #obj => the object to rotate
* # rotation => angle to rotate
* */
public function RotateAroundCenter(obj:Object, rotation:Number):void
{
var bound:Rectangle = new Rectangle();
// get the bounded rectangle of objects
bound = obj.getRect(this);
// calculate mid poits
var midx1:Number = bound.x + bound.width/2;
var midy1:Number = bound.y + bound.height/2;
// assign the rotation
obj.rotation = rotation;
// assign the previous mid point as (x,y)
obj.x = midx1;
obj.y = midy1;
// get the new bounded rectangle of objects
bound = obj.getRect(this);
// calculate new mid points
var midx2:Number = bound.x + bound.width/2;
var midy2:Number = bound.y + bound.height/2;
// calculate differnece between the current mid and (x,y) and subtract
//it to position the object in the previous bound.
var diff:Number = midx2 - obj.x;
obj.x -= diff;
diff = midy2 - obj.y;
obj.y -= diff;
}
//////////////////
Usage:
you can use the above function as described below,
var img:Canvas = new Canvas()
RotateAroundCenter(img, rotation);
This will help you
REf: http://subashflash.blogspot.in/2010/08/rotation-of-object-based-on-center.html
If you want to rotate around the center, merely center the asset inside your sprite by setting the internal assets x and y to half of the width and height of the asset. This swill center your content and allow it to rotate around a center point.
An example of runtime loaded assets is as follows:
var loader:Loader = new Loader():
var request:URLRequest = new URLRequest(path/to/asset.ext);
loader.contentLoaderInfo.addEventListener(Event.COMPLETE, _onLoaderComplete);
loader.load(request);
private function _onLoaderComplete(e:Event):void
{
var mc:MovieClip = e.target.content as MovieClip;
mc.x = -mc.width * 0.5;
mc.y = -mc.height * 0.5;
mc.rotation = 90;
addChild(mc);
}

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