I have an UTC time and a time offset in seconds, and need to return the corresponding Go time value.
It is trivial to instantiate the UTC time value by using the time.Unix() function. But to set the Zone, I need to determine the time.Location.
How can I find the time.Location when knowing the UTC time and time offset ?
Without an actual entry to lookup in the time zone database, you can't know the true location for the time. If you want to work with just an offset, you can create a fixed location using time.FixedZone
edt := time.FixedZone("EDT", -60*60*4)
t, _ := time.ParseInLocation("02 Jan 06 15:04", "15 Sep 17 14:55", edt)
fmt.Println(t)
// 2017-09-15 14:55:00 -0400 EDT
You can opt to specify a non-existent zone name, or none at all, as long as the output format you use doesn't require one.
minus4 := time.FixedZone("", -60*60*4)
t, _ = time.ParseInLocation("02 Jan 06 15:04", "15 Sep 17 14:55", minus4)
fmt.Println(t.Format(time.RFC3339))
// 2017-09-15T14:55:00-04:00
I have users entering a date and a time zone (e.g. "America/Los Angeles") for that date and I'd like to convert that to UTC but to do that I need the utc offset for the time on that date.
I can easily convert a date to the offset for the time zone if I already know the UTC date but I need the other way around...
The utc offset can change depending on the date due to daylight saving so I need a way to enter a date and a timezone and get back the offset from UTC using that.
Knowing the most recent switch from PST to PDT On march 11 at 2AM I tried using
var tzOffset = moment.tz("3/11/2018 3:00 AM", "America/Los_Angeles").utcOffset();
document.write('utc offset is : ' + tzOffset + '<br/>') ;
but that gives 480 when the correct answer is 420
I can get the correct answer 420 if I use parseZone like so:
var tzOffset2 = moment.parseZone("3/11/2018 3:00 AM -07:00").utcOffset();
document.write('utc offset2 is : ' + tzOffset2 + '<br/>') ;
but that means I need to already know the -7 offset that I'm trying to find...
So how do I find the utcOffset for a specific date/time like "3/11/2018 3:00 AM" and timezone like "America/Los_Angeles"? Thanks
Your input is not in a ISO 8601 or RFC 2822 format recognized by moment(String), so you have to specify the format as second parameter using moment(String, String) (please note that, as docs states: The moment.tz constructor takes all the same arguments as the moment constructor, but uses the last argument as a time zone identifier.)
Your code could be like the following:
var tzOffset = moment.tz("3/11/2018 3:00 AM", "D/M/YYYY h:mm A", "America/Los_Angeles").utcOffset();
document.write('utc offset is : ' + tzOffset + '<br/>') ;
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.1/moment.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment-timezone/0.5.14/moment-timezone-with-data-2012-2022.min.js"></script>
I'm working on a Parser which Parses log files from a game so I can do analysis on auctions made within the game, however the date format that's being written by the logger seems to be causing problems as the format seems to be custom written for the logger, an example datetime stamp looks like: [Wed Nov 23 23:26:10 2016] I try to Parse it with:
func (r *AuctionReader) extractSaleInformation(line string) {
fmt.Println("Extracting information from: ", line)
// Format mask for output
layout := "DD-MM-YYYY hh:mm:ss"
// Replace the square brackets so we're just left with the date-time string
date := strings.TrimSpace(strings.Replace((strings.Split(line, "]")[0]), "[", "", -1))
fmt.Println(time.Parse(date, layout))
}
When I attempt to Parse the above date-time string I get the following error:
0001-01-01 00:00:00 +0000 UTC parsing time "DD-MM-YYYY hh:mm:ss" as "Wed Nov 23 23:26:10 2016": cannot parse "DD-MM-YYYY hh:mm:ss" as "Wed Nov "
How am I able to get the parser to recognise this seemingly custom format, I will be saving this data to Mongo so I don't want to store the auction time as a string as I want to query the timestamps individually.
Golang handle all date formatting in a unique way - it uses the reference time Mon Jan 2 15:04:05 MST 2006 (01/02 03:04:05PM '06 -0700) to show the pattern with which to format/parse a given time/string.
So, to read the format "Wed Nov 23 23:26:10 2016" you would put the reference date into that format: "Mon Jan 2 15:04:05 2006", and then do:
t, _ := time.Parse("Mon Jan 2 15:04:05 2006", "Wed Nov 23 23:26:10 2016")
Then, to output it in the given format, if you wanted the format DD-MM-YYYY hh:mm:ss, you would put the reference time into that format: 02-01-2006 15:04:05, and then do:
t.Format("02-01-2006 15:04:05")
https://play.golang.org/p/VO5413Z7-z
So basically, the main change is
// Format mask for output
layout := "DD-MM-YYYY hh:mm:ss"
should be
// Format mask for output
layout := "02-01-2006 15:04:05"
and
time.Parse(date, layout)
should be
time.Parse(layout, date)
I have these lines
SetLocale(3081)
Response.Write "<p>TEST: " & Date() & " | " & isDate("3/22/2014") & " --> " & GetLocale() & "</p>"
which outputs
TEST: 3/07/2014 | True --> 3081
now correct me if i'm wrong but isn't there only 12 months in a year?, according to IsDate the date i've passed, which should be wrong because i have put in 22 as the month, is valid despite the local settings saying otherwise.
i want to validate the date to be the correct format to insert into the database and if it isn't give a more friendly error, "3/22/2014" will output "Error converting data type varchar to date." when i try to inster it into the database because it's getting by the IsDate check
What have i done wrong here?
Yes, this is indeed a valid date.
Why? Because VBScript is smart/generous/stupid (choose your favorite) enough to treat numbers as dates. And "3/22/2014" can be parsed as formula: 3 / 22 / 2014 = 6.770786313983931e-5
Now take this number and convert to date:
Dim myNumber, myDate
myNumber = 6.770786313983931e-5
myDate = CDate(myNumber)
The variable myDate will be perfectly valid date, which is December 30th 1899, 00:00:06
So bottom line: the value is a date, just not what you expect. You've done nothing wrong, but to really check if a string is valid date you will have to check it yourself, no out of the box methods.
I have a tab delimited file where each record has a timestamp field in 12-hour format:
mm/dd/yyyy hh:mm:ss [AM|PM].
I need to quickly convert these fields to 24-hour time:
mm/dd/yyyy HH:mm:ss.
What would be the best way to do this? I'm running on a Windows platform, but I have access to sed, awk, perl, python, and tcl in addition to the usual Windows tools.
Using Perl and hand-crafted regexes instead of facilities like strptime:
#!/bin/perl -w
while (<>)
{
# for date times that don't use leading zeroes, use this regex instead:
# (?:\d{1,2}/\d{1,2}/\d{4} )(\d{1,2})(?::\d\d:\d\d) (AM|PM)
while (m%(?:\d\d/\d\d/\d{4} )(\d\d)(?::\d\d:\d\d) (AM|PM)%)
{
my $hh = $1;
$hh -= 12 if ($2 eq 'AM' && $hh == 12);
$hh += 12 if ($2 eq 'PM' && $hh != 12);
$hh = sprintf "%02d", $hh;
# for date times that don't use leading zeroes, use this regex instead:
# (\d{1,2}/\d{1,2}/\d{4} )(\d{1,2})(:\d\d:\d\d) (?:AM|PM)
s%(\d\d/\d\d/\d{4} )(\d\d)(:\d\d:\d\d) (?:AM|PM)%$1$hh$3%;
}
print;
}
That's very fussy - but also converts possibly multiple timestamps per line.
Note that the transformation for AM/PM to 24-hour is not trivial.
12:01 AM --> 00:01
12:01 PM --> 12:01
01:30 AM --> 01:30
01:30 PM --> 13:30
Now tested:
perl ampm-24hr.pl <<!
12/24/2005 12:01:00 AM
09/22/1999 12:00:00 PM
12/12/2005 01:15:00 PM
01/01/2009 01:56:45 AM
12/30/2009 10:00:00 PM
12/30/2009 10:00:00 AM
!
12/24/2005 00:01:00
09/22/1999 12:00:00
12/12/2005 13:15:00
01/01/2009 01:56:45
12/30/2009 22:00:00
12/30/2009 10:00:00
Added:
In What is a Simple Way to Convert Between an AM/PM Time and 24 hour Time in JavaScript, an alternative algorithm is provided for the conversion:
$hh = ($1 % 12) + (($2 eq 'AM') ? 0 : 12);
Just one test...probably neater.
It is a 1-line thing in python:
time.strftime('%H:%M:%S', time.strptime(x, '%I:%M %p'))
Example:
>>> time.strftime('%H:%M:%S', time.strptime('08:01 AM', '%I:%M %p'))
'08:01:00'
>>> time.strftime('%H:%M:%S', time.strptime('12:01 AM', '%I:%M %p'))
'00:01:00'
Use Pythons datetime module someway like this:
import datetime
infile = open('input.txt')
outfile = open('output.txt', 'w')
for line in infile.readlines():
d = datetime.strptime(line, "input format string")
outfile.write(d.strftime("output format string")
Untested code with no error checking. Also it reads the entire input file in memory before starting.
(I know there is plenty of room for improvements like with statement...I make this a community wiki entry if anyone likes to add something)
To just convert the hour field, in python:
def to12(hour24):
return (hour24 % 12) if (hour24 % 12) > 0 else 12
def IsPM(hour24):
return hour24 > 11
def to24(hour12, isPm):
return (hour12 % 12) + (12 if isPm else 0)
def IsPmString(pm):
return "PM" if pm else "AM"
def TestTo12():
for x in range(24):
print x, to12(x), IsPmString(IsPM(x))
def TestTo24():
for pm in [False, True]:
print 12, IsPmString(pm), to24(12, pm)
for x in range(1, 12):
print x, IsPmString(pm), to24(x, pm)
This might be too simple thinking, but why not import it into excel, select the entire column and change the date format, then re-export as a tab delimited file? (I didn't test this, but it somehow sounds logical to me :)
Here i have converted 24 Hour system to 12 Hour system.
Try to use this method for your problem.
DateFormat fmt = new SimpleDateFormat("yyyyMMddHHssmm");
try {
Date date =fmt.parse("20090310232344");
System.out.println(date.toString());
fmt = new SimpleDateFormat("dd-MMMM-yyyy hh:mm:ss a ");
String dateInString = fmt.format(date);
System.out.println(dateInString);
} catch (Exception e) {
System.out.println(e.getMessage());
}
RESULT:
Tue Mar 10 23:44:23 IST 2009
10-March-2009 11:44:23 PM
In Python: Converting 12hr time to 24hr time
import re
time1=input().strip().split(':')
m=re.search('(..)(..)',time1[2])
sec=m.group(1)
tz=m.group(2)
if(tz='PM'):
time[0]=int(time1[0])+12
if(time1[0]=24):
time1[0]-=12
time[2]=sec
else:
if(int(time1[0])=12):
time1[0]-=12
time[2]=sec
print(time1[0]+':'+time1[1]+':'+time1[2])
Since you have multiple languages, I'll suggest the following algorithm.
1 Check the timestamp for the existence of the "PM" string.
2a If PM does not exist, simply convert the timestamp to the datetime object and proceed.
2b If PM does exist, convert the timestamp to the datetime object, add 12 hours, and proceed.