Count number of lines in each directory - unix

Question

I have a directory structure as below
output/a/1/multipleFiles
output/a/2/multipleFiles
output/a/3/multipleFiles
output/b/1/multipleFiles
output/b/2/multipleFiles
output/b/3/multipleFiles
I want to know number of lines each directory has. So basically, number of lines at each inner most directory level instead of file level. The innermost directories 1, 2, 3 are different kinds of output we generate for our analytics which contains multiple hadoop part-xxxx files.
I moved to output directory and tried the below command.
find . -maxdepth 2 -type d -name '*' | awk -F "/" 'NF==3' | awk '{print $0"/*"}' | xargs wc -l
But I am getting an error as
wc: ./a/1/*: No such file or directory
wc: ./a/2/*: No such file or directory
wc: ./a/3/*: No such file or directory
but if I try
wc -l ./a/1/*
I am getting correct output for that specific folder.
What am I missing here.
EDIT:
I updated my command as below to remove unnecessary awk commands.
find . -mindepth 2 -maxdepth 2 -type d -name '*' | xargs wc -l
This again results in error as
wc: ./a/1: Is a directory
wc: ./a/2: Is a directory
wc: ./a/2: Is a directory

Answer 1

Give a try to execdir, for example:
find . -maxdepth 2 -type f -execdir wc -l {} \;
This will run the command wc -l {} only within the directory that the file has been found, from the man:
-execdir The -execdir primary is identical to the -exec primary with
the exception that utility will be executed from the
directory that holds the current file.