multiple dispatch in redux action - redux

Question

I wanted to dispatch an action from another action but not able to do so. When I try to do so it not able to found getAllUser method.
Below is my action class.
export const myActions = {
getAllUser() {
return (dispatch) => {
makeApiCall()
.then((response) => {
dispatch({
type: USER_SUCCESS,
payload: response,
});
})
.catch((error) => {
dispatch({
type: USER_FAILURE,
payload: error,
});
});
};
},
addUser(user) {
return (dispatch) => {
makeApiCall(user)
.then((response) => {
/*
Need help here :
wants to call above getAllUser()
.then(() =>
dispatch({
type: ADD_SUCCESS,
payload: response,
});
)
*/
};
},
};
I have tried various approaches like,
myActions.getAllUser()
.then((response) =>
dispatch({
type: ADD_SUCCESS,
payload: response,
});
);
and trying do dispatch directly,
const self = this;
dispatch(self.getAllUser());
dispatch({
type: ADD_SUCCESS,
payload: response,
});
One more way around this is after addUser success, update the reducer and than from UI call getAccount again to refresh the results, but just curious to know on how can I achieve this using multiple dispatch.

Answer 1

You can export the functions individually instead of wrapping it under the same object:
export const getAllUser = () => dispatch => { ... }
export const addUser = () => dispatch => {
...
dispatch(getAllUser());
}
You can still import them all if desired:
import * as myActions from '...';
Or you can declare getAllUser first then add to myActions, but the above solution is much cleaner.
const getAllUser = ...
const myActions = {
getAllUser,
addUser = ... { dispatch(getAllUser()) }
}