NA in time series handling? - r

I am dealing with a forecast of time series in R. I have several questions:
I would like to ask how we can handle missing values in time series?
I guess we can somehow interpolate them?
Can you suggest some solution in R for this?

One of the solutions imputeTS library.
library(imputeTS)
# amount of NA
table(is.na(tsAirgap))
# Kalman smoothing imputation (one of the best)
imp_tsAirgap <- na_kalman(tsAirgap)
# Imputed time-series, no NAs
table(is.na(imp_tsAirgap))

If you would like to delete the missing values and their corresponding time-stamps, you can also use the na.remove function within the tseries package.

Related

Analyzing disparate time series in R

Are there tools in R that simplify analysis of lagged and disparate time series. For example:
Daily values that only occur on weekdays (no entry on weekends or holidays)
vs
Bi-annual values
What I'm seeking is ways to:
Complete the missing daily values (with interpolated, or last value rolled forward, etc.)
Look for correlation between daily values and the bi-annual value (only the values that came before the bi-annual event)
As an example:
10-year treasury note interest rate (daily on non-holiday weekdays) as "X" and i-bond fixed rate as "Y" (set May 1/Nov 1)
Any suggestions appreciated.
I've built a test dataset manually for "x" and used functions in zoo to populate the missing values (interpolated), but I'm hoping for a less "brute-force" method for looking at analyzing the disparate time series. I've used lag functions in the past, but those were on matching interval time series.
What Jon commented is what I had in mind:
expand a weekday time series to full week using missing value function(s) in zoo
Sample the daily value - say April 15 for the May 1, Oct 15 for Nov 1
Ideally be able to automate - say loop through April 1-30, Oct 1-30 to look for highest RSqr for the model of choice (linear, polynomial, etc.)
Not have to build discrete datasets for each of the above - but if that is what is required I can do it programmatically - I've done that with stock data in the past. I was looking for a more efficient means of selecting the datasets ad hoc during the analysis.
I don't have code to post, because I'm clueless as to the feature/function that would make the date selection I'm after possible (at least in R).
Thanks for the input so far. It has already been useful in helping me look at alternative methods to achieve what I'm after.

How to calculate daily standard deviation from data collected hourly in R?

I calculated daily means from hourly data for all four variables in the dataset without any issues using the xts function daily.apply(df.xts, FUN=mean). By doing that I get daily averages of each of my variables. However, I am not being able to do the same for the standard deviation. When using daily.apply(df.xts, FUN=sd) I just get the index (time stamps) and only one column with values as an output. What am I missing? Similar issue for var.
Thank you
See issue's 124 and 128 on github to see the reasoning why.
Solution (for now?), use an extra package called matrixStats. The code below will return the standard deviation per column of an xts object.
apply.daily(df.xts, matrixStats::colSds)

dealing with NA in seasonal cycle analysis R

I have a timeseries of monthly data with lots of missing datapoints, set to NA. I want to simply subtract the annual cycle from the data, ignoring the missing entries. It seems that the decompose function can't handle missing data points, but I have seen elsewhere that the seasonal package is suggested instead. However I am also running into problems there too with the NA.
Here is a minimum reproducible example of the problem using a built in dataset...
library(seasonal)
# set range to missing NA in Co2 dataset
c2<-co2
c2[c2>330 & c2<350]=NA
seas(c2,na.action=na.omit)
Error in na.omit.ts(x) : time series contains internal NAs
Yes, I know! that's why I asked you to omit them! Let's try this:
seas(c2,na.action=na.x13)
Error: X-13 run failed
Errors:
- Adding MV1981.Apr exceeds the number of regression effects
allowed in the model (80).
Hmmm, interesting, no idea what that means, okay, please just exclude the NA:
seas(c2,na.action=na.exclude)
Error in na.omit.ts(x) : time series contains internal NAs
that didn't help much! and for good measure
decompose(c2)
Error in na.omit.ts(x) : time series contains internal NAs
I'm on the following:
R version 3.4.4 (2018-03-15) -- "Someone to Lean On"
Copyright (C) 2018 The R Foundation for Statistical Computing
Platform: x86_64-pc-linux-gnu (64-bit)
Why is leaving out NA such a problem? I'm obviously being completely stupid, but I can't see what I'm doing wrong with the seas function. Happy to consider an alternative solution using xts.
My first solution, simply manually calculating the seasonal cycle, converting to a dataframe to subtract the vector and then transforming back.
# seasonal cycle
scycle=tapply(c2,cycle(c2),mean,na.rm=T)
# converting to df
df=tapply(c2, list(year=floor(time(c2)), month = cycle(c2)), c)
# subtract seasonal cycle
for (i in 1:nrow(df)){df[i,]=df[i,]-scycle}
# convert back to timeseries
anomco2=ts(c(t(df)),start=start(c2),freq=12)
Not very pretty, and not very efficient either.
The comment of missuse lead me to another Seasonal decompose of monthly data including NA in r I missed with a near duplicate question and this suggested the package zoo, which seems to work really well for additive series
library(zoo)
c2=co2
c2[c2>330&c2<350]=NA
d=decompose(na.StructTS(c2))
plot(co2)
lines(d$x,col="red")
shows that the series is very well reconstructed through the missing period.
The output of deconstruct has the trend and seasonal cycle available. I wish I could transfer my bounty to user https://stackoverflow.com/users/516548/g-grothendieck for this helpful response. Thanks to user missuse too.
However, if the missing portion is at the end of the series, the software has to extrapolate the trend and has more difficulties. The original series (in black) maintains the trend, while the trend is smaller in the reconstructed series (red):
c2=co2
c2[c2>350]=NA
d=decompose(na.StructTS(c2))
plot(co2)
lines(d$x,col="red")
Lastly, if instead the missing portion is at the start of the series, the software is unable to extrapolate backwards in time and throws an error... I feel another SO question coming on...
c2=co2
c2[c2<330]=NA
d=decompose(na.StructTS(c2))
Error in StructTS(y) :
the first value of the time series must not be missing
You could just use some algorithm that fills the missing data before.
(e.g. from package imputeTS or zoo)
imputeTS for example has extra imputation algorithms for seasonal time series e.g.:
x <- na_seadec(co2)
Another good option for seasonal data:
x <- na_kalman(co2)
And now just go on without the missing data.
An important hint from Adrian Tompkins (see also comment below):
This will work best, when the missing data is somewhere in the middle. For a lot of leading NAs the method is no good choice. In this case it fills the NAs, but it is not able to extrapolate the trend backwards:
c2<-co2
c2[c2<330]<-NA
c3<-na_kalman(c2)
c4<-na_seadec(c2)
plot(co2)
lines(c3,col="blue")
lines(c4,col="red")

Correct imputation for a zooreg object?

My objective is to impute NAs in a zooreg time series object. The pattern of the time series is cyclic. My code is:
#load libraries required
library("zoo")
# create sequence every 15 minutes from 1st Dec to 20th Dec, 2018
timeStamp <- seq.POSIXt(from=as.POSIXct('2018-01-01 00:00:00', tz="UTC"), to=as.POSIXct('2018-01-20 23:45:00', tz="UTC"), by = "15 min")
# data which increases from 12am to 12pm, then decreases till 12 am of next day, for 20 days
readings <- rep(c(seq(1,48,1), seq(48,1,-1)), 20)
dF <- data.frame(timeStamp=timeStamp, readings=readings)
# create a regular zooreg object, frequency is 1 day( 4 readings * 24 hours)
readingsZooReg <- zooreg(dF$readings, order.by = dF$timeStamp, frequency = 4*24)
plot(readingsZooReg)
# force some data to be NAs
window(readingsZooReg, start = as.POSIXct("2018-01-14 00:00:00", tz="UTC"), end = as.POSIXct("2018-01-16 23:45:00", tz="UTC")) <- NA
plot(readingsZooReg)
# plot imputed values
plot(na.approx(readingsZooReg))
The plots are:
Full time series, NAs added, Imputed time series
I'm purposely using zoo here, since the time series I work on are irregular(eg. solar, oil wells, etc)
1) Is my usage of "zooreg" correct? Or would a "zoo" object suffice ?
2) Is my frequency variable right?
3) Why won't na.approx work? I've also tried na.StructTs, the R script hangs.
4) Is there a solution using any other package? xts, ts, etc?
Your current example time-series is a regular time-series.
(a irregular time series would have time-steps with different time distances between observations)
E.g.:
10:00:10, 10:00:20, 10:00:30, 10:00:40, 10:00:50 (regular spaced)
10:00:10, 10:00:17, 10:00:33, 10:00:37, 10:00:50 (irregular spaced)
If you really need to handle irregular spaced time-series, zoo is your go to package. Otherwise you can also use other time series classes as xts and ts.
About the frequency:
You set the frequency of a time-series usually according to a value where you expect patterns to repeat. (in your example this could be 96). In real live this is often 1 day, 1 week, 1 month,....but it can be also different from these like 1,5 days. (e.g. if you have daily returning patterns and 1 minute observations you would set the frequency to 1440).
na.approx of zoo workes perfectly. It is exactly doing what it is expected to. A interpolation between the points 0 before the gap and 0 at the end of the gap will give a straight line at 0. Of course that is probably not the result you expected, because it does not account for seasonality. That is why G. Grothendieck suggests you na.StructTS as a method to choose. (this method is usually better in accounting for seasonality)
The best choice if you are not bound to zoo would in this specific case be using na_seadec from the imputeTS package ( a package solely dedicated to time series imputation).
I have added you a example also with nice plots from the imputeTS package
library(imputeTS)
yourTS <- ts(coredata(readingsZooReg), frequency = 96)
ggplot_na_distribution(yourTS)
imputedTS <- na_seadec(yourTS)
ggplot_na_imputations(yourTS, imputedTS)
Usually imputeTS also works perfectly with zoo time-series as input. I only changed it to ts again, because something with your zoo object seems odd...that is also why na.StructTS from zoo itself breaks. Maybe somebody with better knowledge can help out here.
Beware, if you really should have irregular time series do not use other packages / imputation functions than from zoo. Because they all assume the data to be regular spaced and will give results accordingly.

Interpolation in R

I have hourly time series and would like to interpolate sub-hourly values like every 15 min. Linear interpolation will do. But if there is any way to specify Gaussian, Polynomial, that would be great.
For example if I have
a<-c(4.5,7,3.3) which is the first three hour data. How can I get 15 min sub-hourly data, total of 9 values in this case? I have been using approx function and studying zoo package and still don't know how I can do it. Thank you very much!
How about this:
b<-xts(c(4.5,7,3.3), order.by=as.POSIXct(c('2013-07-26 0:00',
'2013-07-26 2:00',
'2013-07-26 3:00')))
approx(b, n=13) ,
adjusting n for the appropriate time interval?
Within xts package, you can either na.approx or na.spline.
Coerce you times series to an xts object
Create a new index having 15 minutes intervals
Use this new index to create a NULL xts object that you merge with your object
Approximate missing values using na.approx for linear/constant approx or na.spline for polynomial one.
here a complete example:
library(xts)
set.seed(21)
## you create the xts object
x <- xts(rnorm(10),
seq(from=as.POSIXct(Sys.Date()),
length.out=10,
by=as.difftime(1,units='hours')))
## new index to be used
new.index <-
seq(min(index(x)),max(index(x)), by=as.difftime(15,units='mins'))
## linear approx
na.approx(merge(x,xts(NULL,new.index)))
## polynomial approx
na.spline(merge(x,xts(NULL,new.index)))

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