How to get the number of result? - Pagerfanta and Twig (in Symfony) - symfony

Question

In my Demo application, use Pagerfanta to read only a few rows from Database.
public function findAllProductsByCategory($category, int $page = 1): Pagerfanta
{
// DQL = Always select full classes from classes
$query = $this->getEntityManager()
->createQuery('
SELECT p
FROM App\Entity\Product p
WHERE p.category = :category
')
->setParameter('category', $category);
return $this->createPaginator($query, $page);
}
Later in Twig, I loop the preselected results. Everything is fine ...
{% if products.haveToPaginate %}
<div class="navigation text-center">
{{ pagerfanta(products, 'default', {routeName: 'category_show_paginated', 'routeParams' : { 'id': category.id}}) }}
</div>
{% endif %}
<table border="1" cellpadding="5">
<tr>
<th>#</th>
<th>Name</th>
<th>Products</th>
<th>Description</th>
</tr>
{% for product in products %}
<tr>
<td>{{ loop.index }}</td>
<td>{{ product.name }}</td>
<td>{{ product.description }}</td>
</tr>
{% endfor %}
</table>
but on each page, "loop.index" is the same 1,2,3,4 ...
I would like to show the number of results 41,42,43 ... with pagerfanta ;)
Is there a special function?
Thank you

Answer 1

Haven't worked with Pagerfanta for a while, but what you want should be doable with something like this:
{{ pagerfanta.currentPageOffsetStart() + loop.index }}
Example test case: https://hotexamples.com/examples/pagerfanta/Pagerfanta/getCurrentPageOffsetStart/php-pagerfanta-getcurrentpageoffsetstart-method-examples.html