I have a dataset consists of 2 million samples.
I want to use k-means to cluster this dataset into 2000 clusters.
is it ok to use this number of clusters with this data size.
note: feature vector size of each sample is 1000
To predict the runtime of an algorithm, you can take a look at it's time complexity. This is a formula that relates the run time to some parameters like for instance the data points and number of clusters in k-means. Information about time complexity in k-means clustering can be found here: Computational complexity of k-means
Related
I am trying to carry out hierarchical cluster analysis (based on Ward's method) on a large dataset (thousands of records and 13 variables) representing multi-species observations of marine predators, to identify possible significant clusters in species composition.
Each record has date, time etc and presence/absence data (0 / 1) for each species.
I attempted hierarchical clustering with the function pvclust. I transposed the data (pvclust works on transposed tables), then I ran pvclust on the data selecting Jacquard distances (“binary” in R) as a distance measure (suitable for species pres/abs data) and Ward’s method (“ward.D2”). I used “parallel = TRUE” to reduce computation time. However, using a default of nboots= 1000, my computer was not able to finish the computation in hours and finally I got ann error, so I tried with lower nboots (100).
I cannot provide my dataset here, and I do not think it makes sense to provide a small test dataset, as one of the main issues here seems to be the size itself of the dataset. However, I am providing the lines of code I used for the transposition, clustering and plotting:
tdata <- t(data)
cluster <- pvclust(tdata, method.hclust="ward.D2", method.dist="binary",
nboot=100, parallel=TRUE)
plot(cluster, labels=FALSE)
This is the dendrogram I obtained (never mind the confusion at the lower levels due to overlap of branches).
As you can see, the p-values for the higher ramifications of the dendrogram all seem to be 0.
Now, I understand that my data may not be perfect, but I still think there is something wrong with the method I am using, as I would not expect all these values to be zero even with very low significance in the clusters.
So my questions would be
is there anything I got wrong in the pvclust function itself?
may my low nboots (due to “weak” computer) be a reason for the non-significance of my results?
are there other functions in R I could try for hierarchical clustering that also deliver p-values?
Thanks in advance!
.............
I have tried to run the same code on a subset of 500 records with nboots = 1000. This worked in a reasonable computation time, but the output is still not very satisfying - see dendrogram2 .dendrogram obtained for a SUBSET of 500 records and nboots=1000
I have several groups of data, with row counts ranging up to 24,000. I have manually calculated pairwise distances between the points, where the distance is based on custom text-matching rules.
I have been able to perform agglomerative clustering using hclust on groups of size ~1000, but my system's resources cannot handle the 24K x 24K / 2 comparison needed for the larger groups.
The representation of the distances takes up O[n^2] space, but the clustering representation should only take up O(n*ln(n)) space. Are there any packages in R that can perform agglomerative clustering in batches for large amounts of data?
I am clustering timeseries data using appropriate distance measures and clustering algorithms for longitudinal data. My goal is to validate the optimal number of clusters for this dataset, through cluster result statistics. I read a number of articles and posts on stackoverflow on this subject, particularly: Determining the Optimal Number of Clusters. Visual inspection is only possible on a subset of my data; I cannot rely on it to be representative of my whole dataset since I am dealing with big data.
My approach is the following:
1. I cluster several times using different numbers of clusters and calculate the cluster statistics for each of these options
2. I calculate the cluster statistic metrics using FPC's cluster.stats R package: Cluster.Stats from FPC Cran Package. I plot these and decide for each metric which is the best cluster number (see my code below).
My problem is that these metrics each evaluate a different aspect of the clustering "goodness", and the best number of clusters for one metric may not coincide with the best number of clusters of a different metric. For example, Dunn's index may point towards using 3 clusters, while the within-sum of squares may indicate that 75 clusters is a better choice.
I understand the basics: that distances between points within a cluster should be small, that clusters should have a good separation from each other, that the sum of squares should be minimized, that observations which are in different clusters should have a large dissimilarity / different clusters should ideally have a strong dissimilarity. However, I do not know which of these metrics is most important to consider in evaluating cluster quality.
How do I approach this problem, keeping in mind the nature of my data (timeseries) and the goal to cluster identical series / series with strongly similar pattern regions together?
Am I approaching the clustering problem the right way, or am I missing a crucial step? Or am I misunderstanding how to use these statistics?
Here is how I am deciding the best number of clusters using the statistics:
cs_metrics is my dataframe which contains the statistics.
Average.within.best <- cs_metrics$cluster.number[which.min(cs_metrics$average.within)]
Average.between.best <- cs_metrics$cluster.number[which.max(cs_metrics$average.between)]
Avg.silwidth.best <- cs_metrics$cluster.number[which.max(cs_metrics$avg.silwidth)]
Calinsky.best <- cs_metrics$cluster.number[which.max(cs_metrics$ch)]
Dunn.best <- cs_metrics$cluster.number[which.max(cs_metrics$dunn)]
Dunn2.best <- cs_metrics$cluster.number[which.max(cs_metrics$dunn2)]
Entropy.best <- cs_metrics$cluster.number[which.min(cs_metrics$entropy)]
Pearsongamma.best <- cs_metrics$cluster.number[which.max(cs_metrics$pearsongamma)]
Within.SS.best <- cs_metrics$cluster.number[which.min(cs_metrics$within.cluster.ss)]
Here is the result:
Here are the plots that compare the cluster statistics for the different numbers of clusters:
my aim is to cluster 126 time-series concerning 26 weeks (so each time-series has 26 observation). I used pam{cluster} = partitioning around medoids to cluster these time-series.
Before clustering I wanted to compare which distance measure is the most appropriate: euclidean, manhattan or dynamic time warping. I used each distance to cluster and compare by silhouette plot. Is there any way I can compare different distance measure?
For example I know that procedure clValid {clValid} to validate cluster results, however I cannot implement dtw to calculate indexes.
So how can I compare different distance metrics (not only by silhouette)?
Additional question: is GAP statistic enough to decide how many clusters choose? Or should I evaluate number of clusters with different methods or compare two or three ways how to do it?
I would be grateful for any suggestions.
I have just read the book "cluster analysis, fifth edition" by Brian S. Everitt, etc. And currently, I adopt the following strategy to select method to calculate distance matrix, clustering and validation:
for distance: using cmdscale{stats} function to calculate multidimentional scaling, and plot the scatterplot of the two scaling dimensions with density information. As expected, if there is distinct clusters or nested clusters, the scatterplot will give some hints.
for clustering: for every clustering method, calculate cophenetic correlation between clustering results and the distance, this can be calculated using cophenetic{stats} function. The best clustering method will give higher correlation. However, this is only working for hierarchical clustering. I haven't idea for other clustering methods, like pam, or kmeans.
for partition evaluation: package {clusterSim} give several function to calculate the index to evaluate the clustering quality. Another package {NbClust} also calculate so many as 30 index to evaluate the combination of "distance", "clustering" and "number of clusters". However, this package partition the hierarchical tree using {cutree}, which is not suitable for nested clustering structure. Another method provided by {dynamicTreeCut} give reasonable results.
for cluster number determination: will added later.
Cluster data for which you have class labels, and use the RAND index to measure cluster quality.
50 such datasets are at the UCR time series archive
This paper does something similar
http://www.cs.ucr.edu/~eamonn/ClusteringTimeSeriesUsingUnsupervised-Shapelets.pdf
I have a matrix of 62 columns and 181408 rows that I am going to be clustering using k-means. What I would ideally like is a method of identifying what the optimum number of clusters should be. I have tried implementing the gap statistic technique using clusGap from the cluster package (reproducible code below), but this produces several error messages relating to the size of the vector (122 GB) and memory.limitproblems in Windows and a "Error in dist(xs) : negative length vectors are not allowed" in OS X. Does anyone has any suggestions on techniques that will work in determining optimum number of clusters with a large dataset? Or, alternatively, how to make my code function (and does not take several days to complete)? Thanks.
library(cluster)
inputdata<-matrix(rexp(11247296, rate=.1), ncol=62)
clustergap <- clusGap(inputdata, FUN=kmeans, K.max=12, B=10)
At 62 dimensions, the result will likely be meaningless due to the curse of dimensionality.
k-means does a minimum SSQ assignment, which technically equals minimizing the squared Euclidean distances. However, Euclidean distance is known to not work well for high dimensional data.
If you don't know the numbers of the clusters k to provide as parameter to k-means so there are three ways to find it automaticaly:
G-means algortithm: it discovers the number of clusters automatically using a statistical test to decide whether to split a k-means center into two. This algorithm takes a hierarchical approach to detect the number of clusters, based on a statistical test for the hypothesis that a subset of data follows a Gaussian distribution (continuous function which approximates the exact binomial distribution of events), and if not it splits the cluster. It starts with a small number of centers, say one cluster only (k=1), then the algorithm splits it into two centers (k=2) and splits each of these two centers again (k=4), having four centers in total. If G-means does not accept these four centers then the answer is the previous step: two centers in this case (k=2). This is the number of clusters your dataset will be divided into. G-means is very useful when you do not have an estimation of the number of clusters you will get after grouping your instances. Notice that an inconvenient choice for the "k" parameter might give you wrong results. The parallel version of g-means is called p-means. G-means sources:
source 1
source 2
source 3
x-means: a new algorithm that efficiently, searches the space of cluster locations and number of clusters to optimize the Bayesian Information Criterion (BIC) or the Akaike Information Criterion (AIC) measure. This version of k-means finds the number k and also accelerates k-means.
Online k-means or Streaming k-means: it permits to execute k-means by scanning the whole data once and it finds automaticaly the optimal number of k. Spark implements it.
This is from RBloggers.
https://www.r-bloggers.com/k-means-clustering-from-r-in-action/
You could do the following:
data(wine, package="rattle")
head(wine)
df <- scale(wine[-1])
wssplot <- function(data, nc=15, seed=1234){
wss <- (nrow(data)-1)*sum(apply(data,2,var))
for (i in 2:nc){
set.seed(seed)
wss[i] <- sum(kmeans(data, centers=i)$withinss)}
plot(1:nc, wss, type="b", xlab="Number of Clusters",
ylab="Within groups sum of squares")}
wssplot(df)
this will create a plot like this.
From this you can choose the value of k to be either 3 or 4. i.e
there is a clear fall in 'within groups sum of squares' when moving from 1 to 3 clusters. After three clusters, this decrease drops off, suggesting that a 3-cluster solution may be a good fit to the data.
But like Anony-Mouse pointed out, the curse of dimensionality affects due to the fact that euclidean distance being used in k means.
I hope this answer helps you to a certain extent.