Generate list of strings - python-3.6

Question

Here's what is inside my CSV file
Symbol
0 AACAF
1 AACAY
2 AACTF
3 AAGC
4 AAGIY
5 AAIGF
6 AAMAF
7 AAPH
8 AAPT
9 AAST
10 AATDF
11 AATGF
12 AATRL
13 AAUKF
14 AAWC
15 ABBY
16 ABCAF
17 ABCCF
18 ABCE
19 ABCFF
20 ABCZF
21 ABCZY
22 ABEPF
23 ABHD
24 ABHI
25 ABLT
26 ABLYF
27 ABNAF
28 ABNK
29 ABNRY
I would like to build a function which could create strings by batch of three symbols, e.g.
'AACAF,AACAY,AACTF'
'AAGC,AAGIY,AAIGF'
'AAMAF,AAPH,AAPT'
'AAST,AATDF,AATGF'
'AATRL,AAUKF,AAWC'
'AABY,ABCAF,ABCCF'
'ABCE,ABCFF,ABCZF'
'ABCZY,ABEPF,ABHD'
'ABHI,ABLT,ABLYF'
'ABNAF,ABNK,ABNRY'
I started what I want in using python, but I don't know how to complete it. I think I could use the csv module to do that.
with open(path, 'r') as csvfile:
rows=[row for row in csvfile]
batch_size = 100
listing = []
string = ''
count = 0
for index, row in enumerate(rows):
if count >= batch_size:
listing.append(string)
string = ''
count = 0
','.join((string,row))
count += 1
How could I do that with python 3.6?

Answer 1

arr = pandas.read_csv(path).Symbol.values
symbol_groups = numpy.split(arr, len(arr) // 3)
result = [','.join(symbols) for symbols in symbol_groups]
Should be doing what you're looking for.

Answer 2

with open(path, 'r') as csvfile:
rows=[row.strip('\n') for row in csvfile]
batch_size = 100
listing = []
string = ''
count = 0
for index, row in enumerate(rows[1:]):
if count >= batch_size or index == len(rows[1:])-1:
listing.append(string)
string = ''
count = 0
if count == 0:
string = ''.join((string,row))
else:
string = ','.join((string,row))
count += 1