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How to generate dates between tow date column based on each row
A row generator technique should be used, such as:
SQL> alter session set nls_date_format = 'dd.mm.yyyy';
Session altered.
SQL> with test (sno, start_date, end_date) as
2 (select 1, date '2018-01-01', date '2018-01-05' from dual union
3 select 2, date '2018-01-03', date '2018-01-05' from dual
4 )
5 select sno, start_date + column_value - 1 datum
6 from test,
7 table(cast(multiset(select level from dual
8 connect by level <= end_date - start_date + 1)
9 as sys.odcinumberlist))
10 order by sno, datum;
SNO DATUM
---------- ----------
1 01.01.2018
1 02.01.2018
1 03.01.2018
1 04.01.2018
1 05.01.2018
2 03.01.2018
2 04.01.2018
2 05.01.2018
8 rows selected.
SQL>
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I have a table with columns as id,date,name
id date name
1 2019-08-01 00:00:00 abc
1 2019-08-01 00:00:00 def
2 2019-08-01 00:00:00 pqr
1 2019-08-31 00:00:00 def
I want to get the count of id for given month.
The expected result for count of id for month 8 must be 3
SELECT strftime('%Y/%m/%d', date) as vdate,count(DISTINCT vdate,id) AS totalcount FROM cardtable WHERE date BETWEEN date('" + $rootScope.mydate + "', 'start of month') AND date('" + $rootScope.mydate + "','start of month','+1 month','-1 day') group by vdate
Basically i want to count if id and date both are distinct.for example if there are 2 entries on date 2019-08-01 with same id than it should give count as 1,if there 3 entries on date 2019-08-01 in which 2 entries are with id 1 and 3rd entry with 2 than it should count 2 and when there are 2 entries with id 1 and on different date lets say 1 entry on 2019-08-01 with id 1 and other on 2019-08-31 with id 1 than count id for month 8 must 2.How can i modify the above query.
Use a subquery which returns the distinct values that you want to count:
SELECT COUNT(*) AS totalcount
FROM (
SELECT DISTINCT strftime('%Y/%m/%d', date), id
FROM cardtable
WHERE date(date) BETWEEN
date('" + $rootScope.mydate + "', 'start of month')
AND
date('" + $rootScope.mydate + "','start of month','+1 month','-1 day')
)
See the demo.
Results:
| totalcount |
| ---------- |
| 3 |
I have a table(pay_period) as following
pay_period
period_id list_id start_date end_date price
1 100 2017-01-01 2017-08-31 100
2 100 2017-09-01 2017-12-31 110
3 101 2017-01-01 2017-08-31 75
Now I have list_id, checkin_date, checkout_date
list_id 100
checkin_date 2017-08-25
checkout_date 2017-09-10
I need to calculate the price of a list for the period from checkin date to checkout date.
therefore the calculation is supposed to be
7 * 100 + 10 * 110
I am thinking to do it with a for loop, if there is any other better way to do it, can you please suggest?
You have to see if the checkin_date and checkout_date are into the same period_id.
1.1 If yes, you multiply the price with the nunmber of days.
1.2 If no, you have count the days between checkin_day untill the end of your period 1 and multiply with the corresponding price, then do the same with checkout_day and beginning of next period.
Note: i guess it might happen to have more than 2 prices per list_id. for example:
period_id list_id start_date end_date price
1 100 2017-01-01 2017-04-30 100
2 100 2017-05-01 2017-09-30 110
3 100 2017-10-01 2017-12-31 120
4 101 2017-01-01 2017-08-31 75
and the calculation period to be:
list_id 100
checkin_date 2017-03-01
checkout_date 2017-11-10
In this case, yes, the solution would be to have a CURSOR where to keep the prices for list_id and periods; loop through it and compare the checkin_date and checkout_date with each record.
Best,
Mikcutu.
You can do the following for a much cleaner code. Although it is purely sql, I am using a function to make it code better to understand.
Create a generic function which gets you the number of overlapping days in 2 different date range.
CREATE OR REPLACE FUNCTION fn_count_range
( p_start_date1 IN DATE,
p_end_date1 IN DATE,
p_start_date2 IN DATE,
p_end_date2 IN DATE ) RETURN NUMBER AS
v_days NUMBER;
BEGIN
IF p_end_date1 < p_start_date1 OR p_end_date2 < p_start_date2 THEN
RETURN 0;
END IF;
SELECT COUNT(*) INTO v_days
FROM (
(SELECT p_start_date1 + LEVEL - 1
FROM dual CONNECT BY LEVEL <= p_end_date1 - p_start_date1 + 1 ) INTERSECT
(SELECT p_start_date2 + LEVEL - 1
FROM dual CONNECT BY LEVEL <= p_end_date2 - p_start_date2 + 1 ) );
RETURN v_days;
END;
/
Now, your query to calculate the total price is simplified.
WITH lists ( list_id,
checkin_date,
checkout_date) AS
( SELECT 100,
TO_DATE('2017-08-25','YYYY-MM-DD'),
TO_DATE('2017-09-10','YYYY-MM-DD')
FROM dual) --Not required if you have a lists table.
SELECT l.list_id,
SUM(fn_count_range(start_date,end_date,checkin_date,checkout_date) * price) total_price
FROM pay_period p
JOIN lists l ON p.list_id = l.list_id
GROUP BY l.list_id;
I need compare value from 1 column with previous value from 2 column. For example, I have table:
id | create_date | end_date
1 | 2016-12-31 | 2017-01-25
2 | 2017-01-26 | 2017-05-21
3 | 2017-05-22 | 2017-08-26
4 | 2017-09-01 | 2017-09-02
I need to compare create_date for id = 2 with end_date for id = 1
and compare create_date for id = 3 with end_date for id = 2 etc.
Result: show me id which has create_date (id = n) <> end_date (id = n-1) + interval '1' day
Should I use lag() function? How I can compare it? Which function I should use and how?
Thank you
Teradata doesn't have lag/lead, but you can still get the same functionality:
select
id,
create_date,
end_date,
max(end_date) over (order by id between 1 preceding and 1 preceding) as prev_end_date
...
qualify
create_date <> prev_end_date + INTERVAL '1' day;
I have the below table: I also have a calendar table if needed.
ID Start_dt End_dt
1 1/9/2016 3/10/2016
Expected Output:
ID Start_dt End_dt Month ActiveCustomerPerMonth
1 1/9/16 3/10/2016 201601 1
1 1/9/16 3/10/2016 201602 1
1 1/9/16 3/10/2016 201603 0 (Not Active end of Month)
I need this as I'm working on a current query that will utilize a case statement to count if the customer was active for that month. If the member was active on the last day of the month, the member would be considred active for that month. But I need to be able to count for al months for that customer.
CASE
WHEN LAST_DAY(x.END_DT) = x.END_DT
THEN '1'
WHEN TO_CHAR(X.END_DT,'MM/DD/YYYY') != '01/01/3000'
OR X.DISCHARGE_REASON IS NOT NULL
THEN '0'
WHEN X.FIRST_ASSGN_DT IS NULL
THEN '0'
ELSE '1'
END ActiveMemberForMonth
I'm new to Oracle and was reading about connect by but did not understand the process and not sure if this would be the proper place to use.
Something like this.
with
test_data ( id, start_dt, end_dt ) as (
select 1, to_date('1/9/2016' , 'mm/dd/yyyy'), to_date('3/10/2016', 'mm/dd/yyyy')
from dual union all
select 2, to_date('1/23/2016', 'mm/dd/yyyy'), to_date('5/31/2016', 'mm/dd/yyyy')
from dual
)
-- end of test data; solution (SQL query) begins below this line
select id, start_dt, end_dt,
to_char(add_months(trunc(start_dt, 'mm'), level - 1), 'yyyymm') as mth,
case when end_dt < last_day(end_dt)
and level = 1 + months_between(trunc(end_dt, 'mm'), trunc(start_dt, 'mm'))
then 0 else 1 end as active_at_month_end
from test_data
connect by level <= 1 + months_between(trunc(end_dt, 'mm'), trunc(start_dt, 'mm'))
and prior id = id
and prior sys_guid() is not null
order by id, mth -- optional
;
ID START_DT END_DT MTH ACTIVE_AT_MONTH_END
--- ---------- ---------- ------ -------------------
1 2016-01-09 2016-03-10 201601 1
1 2016-01-09 2016-03-10 201602 1
1 2016-01-09 2016-03-10 201603 0
2 2016-01-23 2016-05-31 201601 1
2 2016-01-23 2016-05-31 201602 1
2 2016-01-23 2016-05-31 201603 1
2 2016-01-23 2016-05-31 201604 1
2 2016-01-23 2016-05-31 201605 1
8 rows selected.
I wrote a query in SQLite that cumulates VALUE and it is good if I order by ID only (ID is auto increment int). But, if I want to order by DATE and then by ID, the query shows me wrong results. Any ideas?
Query:
select t1.ID,
t1.DATE,
t1.VALUE,
sum(t2.VALUE) as TOTAL
from test t1
inner join test t2 on t1.DATE >= t2.DATE and t1.id >= t2.id
group by t1.ID, t1.DATE
order by t1.DATE desc, t1.ID desc
Results:
ID DATE VALUE TOTAL
9 2015-01-16 55 281 -- should be 226 + 55 = 281
6 2015-01-15 10 26 -- should be 216 + 10 = 226
5 2015-01-15 5 16 -- should be 211 + 5 = 216
8 2015-01-14 100 211
7 2015-01-14 100 111
4 2015-01-13 5 11
3 2015-01-12 3 6
2 2015-01-11 2 3
1 2015-01-10 1 1
At least on the small data, changing the join to something like this:
t1.DATE||substr('00000'||t1.id,-5) >= t2.DATE||substr('00000'||t2.id,-5)
works fine... So we are building up a "sort key" based on the date and the id (padded with zeros to 5 digits) and using that in the join. It might be necessary to build an index on that to deal with performance though