I need to configure classpath for MLCP tool in Windows 10 system.Can anyone please let me know what is the configuration to include in the classpath and system variables?If you have a sample path configuration, Please provide it to me.
Related
I'm setting up the spring webmvc project using spring boot 2.0.0 version. If i run the application inside the embedded tomcat, it runs fine. I tried deploying it in external standalone tomcat-8 server, it is working fine over there too. But i if package the war and deploy it in the tomcat-8 server configured within eclipse, then it throws below exception.
The absolute uri: http://tiles.apache.org/tags-tiles cannot be
resolved in either web.xml
I included the dependency in the pom file as below.
<dependency>
<groupId>org.apache.tiles</groupId>
<artifactId>tiles-jsp</artifactId>
<version>3.0.4</version>
</dependency>
I ensured that the tiles-jsp jar is present inside the WEB-INF/lib folder. But still its failing as it is not able to scan the jar for TLD. I tried changing the catalina.properties to include tiles-jsp*.jar. But it is still failing.
Please help me to fix this error.
Does your IDE automatically import dependencies?
Try cleaning your maven dependencies.
Maven clean.
Or try the more brutal command dependency:purge-local-repository.
By the way notice that there's a newer version of your dependency 3.0.8 of 2017. The one that you are trying to use, the 3.0.4, is of 2014.
For me, war file when deployed works perfect. Had an issue where, when I run it under tomcat from inside IDE(Eclipse/STS), it threw error. Maven clean really helped, no other change needed. MAven clean-->build--> restart eclipse/sts tomcat. it works like a charm. Answer by desoss prompted me to perform maven clean. Thanks #desoss.
I've tried to check one way to discover the version of the glassfish server checking the domain folder but I didn't find it. I didn't find the version in domain.xml or another file. I know we can use "asadmin version" command to check the version, but I need to find it on the domain folder because the structure of my project and some limitations that there is. Do you know some way to check the version? One difference maybe, like one file that not exists in glassfish 3.0 domain folder but there is in glasshfish 4 domain folder...
Thank you so much!
You could check the index.html in the docroot of your domain folder. It contains the Glassfish Version.
The file is located in GLASSFISH_INSTALL/glassfish/domains/domain1/docroot
It should contain a line like
<title>GlassFish Server 3.1.1 - Server Running</title>
For Glassfish 4 it only contains a line like:
<title>GlassFish Server - Server Running</title>
So this is one option to distinguish.
If this is not specific enough, you can just parse the server.log file for the version. In the file GLASSFISH_INSTALL/glassfish/domains/domain1/logs/server.log you should find a string like:
GlassFish Server Open Source Edition 3.1.1 (12) startup time : Felix (6.971ms), startup services(2.353ms), total(9.324ms)|]
or
GlassFish Server Open Source Edition 4.1.1 (1) startup time : Felix (6.175ms), startup services(5.352ms), total(11.527ms)]]
i want to know how to make a jar app which will run on java mobile platform using class file of java.
i know basics of java like inheritance,interface,string.....I tried this thing by compiling my java program of simple input/output and then converting it to jar using -jar in cmd.but i dont know why it is not working on mobile showing invalid file.
plz help me.
If you want to create a jar application, starting from a java class,you don't have to use java -jar filename.jar, this is only for execution.
Try this: jar cf your_jar_app.jar your_class_file.class
c option is needed to create file and f option is needed because you want an output file.
Then you can execute typing: java -jar your_jar_app.jar
Hope this can help you.
For documentation: Oracle Documentation for creating JAR file
If you are using NetBeans IDE, take a look to: NetBeans Packaging and Deploying Java Applications
Not a very common implementation, but using Processing as a Java Servlet has been discussed in previous posts before (1, 2). I have been developing a program in Processing to use as a Java servlet. However, when I have code (such as like the first linked example) in a Processing sketch, I get the error message
The package 'javax.servlet' does not exist. You might be missing a library.
I have Tomcat 5.5 service running on XP, and my environment variables are as follows
CLASSPATH = C:\tomcat\common\lib\servlet-api.jar
CATALINA_HOME = C:\tomcat
JAVA_HOME = C:\Program Files\Java\jdk1.6.0_21
JRE_HOME = C:\Program Files\Java\jre6
I have been trying to diagnose why the javax.servlet packages are not recognized by Processing for many hours and there is nothing online that seems to yield an explanation other than fixing the environment variables to recognize the tomcat libraries. I have also tried to put the servlet-api.jar and jsp-api.jar files in Processing as a kind of custom Processing library but they are not recognized there either, nor when I try to run the program within the tomcat/webapps folder.
I also have tried
javap -classpath my;class;path javax.servlet.Servlet
on the cmd and it gave me the same error.
I'm not that good with Tomcat yet so please forgive me if this is a result of my unfamiliarity. If anyone more knowledgeable than I can shed some light as to why Processing cannot recognize this package would be tremendous. Thanks so much~
CLASSPATH = C:\tomcat\common\lib\servlet-api.jar
This is the problem . Your classpath should be one level up i.e
CLASSPATH = C:\tomcat\common\lib\
This should work fine.
Right Click on MyComputer->Properties->Advanced->Environment Variables->
Set a new user variable name as classpath and give the variable value where your servlet-api.jar file is located (applicable for tomcat webserver), for example:->
variablename: classpath
variablevalue: D:\Tomcat\lib\servlet-api.jar
Now you can run your disassembler to find out the servlet class and interface information
If you are not able to load the servlet package, try setting the environment variable CLASSPATH to .;C:\tomcat\common\lib\servlet-api.jar. That should help.
Ok!.. i bought a new laptop and was faced the same problem, well i hope this would fix the issue on your windows 10 device as well.
First of all know that the error is just due to incorrect or incomplete path or classpath. After Installing Tomcat and JDK set the environment variable as follows(Location may vary as per your installation):
JAVA_HOME = C:\Program Files (x86)\Java\jdk1.7.0_80
JRE_HOME = C:\Program Files (x86)\Java\jre7
CATALINA_HOME = C:\Program Files (x86)\Apache Software Foundation\Tomcat 7.0
PATH = C:\Program Files (x86)\Java\jdk1.7.0_80\bin; C:\Program Files (x86)\Apache Software Foundation\Tomcat 7.0\bin;
CLASSPATH = C:\Program Files (x86)\Apache Software Foundation\Tomcat 7.0\lib\servlet-api.jar; C:\Program Files (x86)\Java\jdk1.7.0_80\lib\tools.jar; JAVA_HOME\lib
make sure that your classpath directs the mentioned jar files, as javax is included in it(try using winrar for checking the inner contents).
After saving the setting, Test using javap javax.servlet.Servlet
Well if you still face any issue please share the error message and screenshot.
Probably because Tomcat is not in the Java Build Path. Try add Tomcat to your library
1) Right-click on your project folder > Build Path > Configure Build Path
2) Click on Library tab > click Add Library button
3) Select Server Runtime > click Next button
4) Select your server > click Finish button
I have installed Tomcat 5.5 in windows vista home basic. I have set classpath to
"C:\program files\apache software foundation\tomcat 5.5\common\lib\servlet-api.jar".
now there are two problems.
1. I could not compile my servlets. It says package javax.servlet.* dosenot exist.
2. I could not connect with local host in chrome nor in explorer.
these errors are appearing inspite of server instance running.
Classpath to java sdk and tomcat are different. is it the matter of concern.
Please help.
I have invested considerable amount of time figuring out the problem.
thanx in advance.
I could not compile my servlets. It says package javax.servlet.* dosenot exist.
It means that the classpath for javac is not been correctly specified. It should go like so:
javac -cp .;"/path with spaces/to/servlet-api.jar" com/example/YourServlet.class
Note that you need to surround a path with spaces by doublequotes.
I could not connect with local host in chrome nor in explorer. These errors are appearing inspite of server instance running.
Then you used the wrong domain/port. When running Tomcat at the local machine, the domain should at least be localhost. The actual port can be determined in Tomcat/conf/server.xml file. It defaults to 8080, but can be changed during the Windows setup wizard. The final URL should look like http://localhost:8080. If you use port 80 which is the default HTTP port, then the :80 part can be omitted from the URL.
Classpath to java sdk and tomcat are different.
The %CLASSPATH% environment variable is worthless. Use -cp argument. If you want to avoid long typing/remembering everytime, consider using a .bat file with the command, or a build tool like Ant, or an IDE like Eclipse.
The %JAVA_HOME% environment variable is however important. Tomcat needs to know it in order to have access to the toolset to compile JSP files. The %JAVA_HOME% should point to the installation directory of the JDK.
I have set classpath to "C:\program
files\apache software
foundation\tomcat
5.5\common\lib\servlet-api.jar"
If this means CLASSPATH environment variable, you're learning a valuable lesson: it's worthless. javac.exe and java.exe ignore it; so do all Java EE app servers like Tomcat; so do all IDEs like IntelliJ.
You'll have to add servlet-api.jar to your CLASSPATH using javac.exe -cp every time you compile in a command shell, or add it to your IDE project CLASSPATH, or set it up in Ant.
If you can't connect to localhost using Chrome or Explorer, it probably means that you haven't packaged or deployed your app properly. Make sure you create a valid WAR file and put it in the Tomcat 5.x /webapps directory to deploy.