I have plotted a scatter graph in R, comparing expected to observed values,using the following script:
library(ggplot2)
library(dplyr)
r<-read_csv("Uni/MSci/Project/DATA/new data sheets/comparisons/for comarison
graphs/R Regression/GAcAs.csv")
x<-r[1]
y<-r[2]
ggplot()+geom_point(aes(x=x,y=y))+
scale_size_area() +
xlab("Expected") +
ylab("Observed") +
ggtitle("G - As x Ac")+ xlim(0, 40)+ylim(0, 40)
My plot is as follows:
I then want to add an orthogonal regression line (as there could be errors in both the expected and observed values). I have calculated the beta value using the following:
v <- prcomp(cbind(x,y))$rotation
beta <- v[2,1]/v[1,1]
Is there a way to add an orthogonal regression line to my plot?
Borrowed from this blog post & this answer. Basically, you will need Deming function from MethComp or prcomp from stats packages together with a custom function perp.segment.coord. Below is an example taken from above mentioned blog post.
library(ggplot2)
library(MethComp)
data(airquality)
airquality <- na.exclude(airquality)
# Orthogonal, total least squares or Deming regression
deming <- Deming(y=airquality$Wind, x=airquality$Temp)[1:2]
deming
#> Intercept Slope
#> 24.8083259 -0.1906826
# Check with prcomp {stats}
r <- prcomp( ~ airquality$Temp + airquality$Wind )
slope <- r$rotation[2,1] / r$rotation[1,1]
slope
#> [1] -0.1906826
intercept <- r$center[2] - slope*r$center[1]
intercept
#> airquality$Wind
#> 24.80833
# https://stackoverflow.com/a/30399576/786542
perp.segment.coord <- function(x0, y0, ortho){
# finds endpoint for a perpendicular segment from the point (x0,y0) to the line
# defined by ortho as y = a + b*x
a <- ortho[1] # intercept
b <- ortho[2] # slope
x1 <- (x0 + b*y0 - a*b)/(1 + b^2)
y1 <- a + b*x1
list(x0=x0, y0=y0, x1=x1, y1=y1)
}
perp.segment <- perp.segment.coord(airquality$Temp, airquality$Wind, deming)
perp.segment <- as.data.frame(perp.segment)
# plot
plot.y <- ggplot(data = airquality, aes(x = Temp, y = Wind)) +
geom_point() +
geom_abline(intercept = deming[1],
slope = deming[2]) +
geom_segment(data = perp.segment,
aes(x = x0, y = y0, xend = x1, yend = y1),
colour = "blue") +
theme_bw()
Created on 2018-03-19 by the reprex package (v0.2.0).
The MethComp package seems to be no longer maintained (was removed from CRAN).
Russel88/COEF allows to use stat_/geom_summary with method="tls" to add an orthogonal regression line.
Based on this and wikipedia:Deming_regression I created the following functions, which allow to use noise ratios other than 1:
deming.fit <- function(x, y, noise_ratio = sd(y)/sd(x)) {
if(missing(noise_ratio) || is.null(noise_ratio)) noise_ratio <- eval(formals(sys.function(0))$noise_ratio) # this is just a complicated way to write `sd(y)/sd(x)`
delta <- noise_ratio^2
x_name <- deparse(substitute(x))
s_yy <- var(y)
s_xx <- var(x)
s_xy <- cov(x, y)
beta1 <- (s_yy - delta*s_xx + sqrt((s_yy - delta*s_xx)^2 + 4*delta*s_xy^2)) / (2*s_xy)
beta0 <- mean(y) - beta1 * mean(x)
res <- c(beta0 = beta0, beta1 = beta1)
names(res) <- c("(Intercept)", x_name)
class(res) <- "Deming"
res
}
deming <- function(formula, data, R = 100, noise_ratio = NULL, ...){
ret <- boot::boot(
data = model.frame(formula, data),
statistic = function(data, ind) {
data <- data[ind, ]
args <- rlang::parse_exprs(colnames(data))
names(args) <- c("y", "x")
rlang::eval_tidy(rlang::expr(deming.fit(!!!args, noise_ratio = noise_ratio)), data, env = rlang::current_env())
},
R=R
)
class(ret) <- c("Deming", class(ret))
ret
}
predictdf.Deming <- function(model, xseq, se, level) {
pred <- as.vector(tcrossprod(model$t0, cbind(1, xseq)))
if(se) {
preds <- tcrossprod(model$t, cbind(1, xseq))
data.frame(
x = xseq,
y = pred,
ymin = apply(preds, 2, function(x) quantile(x, probs = (1-level)/2)),
ymax = apply(preds, 2, function(x) quantile(x, probs = 1-((1-level)/2)))
)
} else {
return(data.frame(x = xseq, y = pred))
}
}
# unrelated hlper function to create a nicer plot:
fix_plot_limits <- function(p) p + coord_cartesian(xlim=ggplot_build(p)$layout$panel_params[[1]]$x.range, ylim=ggplot_build(p)$layout$panel_params[[1]]$y.range)
Demonstration:
library(ggplot2)
#devtools::install_github("Russel88/COEF")
library(COEF)
fix_plot_limits(
ggplot(data.frame(x = (1:5) + rnorm(100), y = (1:5) + rnorm(100)*2), mapping = aes(x=x, y=y)) +
geom_point()
) +
geom_smooth(method=deming, aes(color="deming"), method.args = list(noise_ratio=2)) +
geom_smooth(method=lm, aes(color="lm")) +
geom_smooth(method = COEF::tls, aes(color="tls"))
Created on 2019-12-04 by the reprex package (v0.3.0)
I'm not sure I completely understand the question, but if you want line segments to show errors along both x and y axis, you can do this using geom_segment.
Something like this:
library(ggplot2)
df <- data.frame(x = rnorm(10), y = rnorm(10), w = rnorm(10, sd=.1))
ggplot(df, aes(x = x, y = y, xend = x, yend = y)) +
geom_point() +
geom_segment(aes(x = x - w, xend = x + w)) +
geom_segment(aes(y = y - w, yend = y + w))
Related
I am a beginner at multilevel analysis and try to understand how I can do graphs with the plot functions from base-R. I understand the output of fit below but I am struggeling with the visualization. df is just some simple test data:
t <- seq(0, 10, 1)
df <- data.frame(t = t,
y = 1.5+0.5*(-1)^t + (1.5+0.5*(-1)^t) * t,
p1 = as.factor(rep(c("p1", "p2"), 10)[1:11]))
fit <- lm(y ~ t * p1, data = df)
# I am looking for an automated version of that:
plot(df$t, df$y)
lines(df$t[df$p1 == "p1"],
fit$coefficients[1] + fit$coefficients[2] * df$t[df$p1 == "p1"], col = "blue")
lines(df$t[df$p1 == "p2"],
fit$coefficients[1] + fit$coefficients[2] * df$t[df$p1 == "p2"] +
+ fit$coefficients[3] + fit$coefficients[4] * df$t[df$p1 == "p2"], col = "red")
It should know that it has to include p1 and that there are two lines.
The result should look like this:
Edit: Predict est <- predict(fit, newx = t) gives the same result as fit but still I don't know "how to cluster".
Edit 2 #Keith: The formula y ~ t * p1 reads y = (a + c * p1) + (b + d * p1) * t. For the "first blue line" c, d are both zero.
This is how I would do it. I'm including a ggplot2 version of plot as well because I find it better fitted for the way I think about plots.
This version will account for the number of levels in p1. If you want to compensate for the number of model parameters, you will just have to adjust the way you construct xy to include all the relevant variables. I should point out that if you omit the newdata argument, fitting will be done on the dataset provided to lm.
t <- seq(0, 10, 1)
df <- data.frame(t = t,
y = 1.5+0.5*(-1)^t + (1.5+0.5*(-1)^t) * t,
p1 = as.factor(rep(c("p1", "p2"), 10)[1:11]))
fit <- lm(y ~ t * p1, data = df)
xy <- data.frame(t = t, p1 = rep(levels(df$p1), each = length(t)))
xy$fitted <- predict(fit, newdata = xy)
library(RColorBrewer) # for colors, you can define your own
cols <- brewer.pal(n = length(levels(df$p1)), name = "Set1") # feel free to ignore the warning
plot(x = df$t, y = df$y)
for (i in 1:length(levels(xy$p1))) {
tmp <- xy[xy$p1 == levels(xy$p1)[i], ]
lines(x = tmp$t, y = tmp$fitted, col = cols[i])
}
library(ggplot2)
ggplot(xy, aes(x = t, y = fitted, color = p1)) +
theme_bw() +
geom_point(data = df, aes(x = t, y = y)) +
geom_line()
This is my Dataset:
As you can see, there are two quantitative variables (X, Y) and 1 categorical variable (molar, with two factors: M1, M2).
I would like to represent in one single graph two polynomial regressions and their respective prediction intervals: one for the M1 factor and one for the M2 factor. Each polynomial regression has its own degree (M1 is a 4 degree polynomial regression, and M2 is a 6 degree).
I want to use ggplot() function (which is in package ggplot2 in R). I have actually performed this figure but with all data merged (I mean, with no distinction between factors). This is the code I used:
# Fit a linear model
m <- lm(Y ~ X+I(X^2)+I(X^3)+I(X^4), data = Dataset)
# cbind the predictions to Dataset
mpi <- cbind(Dataset, predict(m, interval = "prediction"))
ggplot(mpi, aes(x = X)) +
geom_ribbon(aes(ymin = lwr, ymax = upr),
fill = "blue", alpha = 0.2) +
geom_point(aes(y = Y)) +
geom_line(aes(y = fit), colour = "blue", size = 1)
With this result:
So, I would like to have two different-grade polynomial regressions (one for the M1 and one for the M2), taking into account their respective predictions intervals. Which would be the exact code?
UPDATE - New code! I run this code with no success:
M1=subset(Dataset,Dataset$molar=="M1",select=X:Y)
M2=subset(Dataset,Dataset$molar=="M2",select=X:Y)
M1.R <- lm(Y ~ X +I(X^2)+I(X^3)+I(X^4),
data=subset(Dataset,Dataset$molar=="M1",select=X:Y))
M2.R <- lm(Y ~ X +I(X^2)+I(X^3)+I(X^4),
data=subset(Dataset,Dataset$molar=="M2",select=X:Y))
newdf <- data.frame(x = seq(0, 1, c(408,663)))
M1.P <- cbind(data=subset(Dataset,Dataset$molar=="M1",select=X:Y), predict(M1.R, interval = "prediction"))
M2.P <- cbind(data=subset(Dataset,Dataset$molar=="M2",select=X:Y), predict(M2.R, interval = "prediction"))
p = cbind(as.data.frame(rbind(M1.P, M2.P)), f = factor(rep(1:2, c(408,663)), x = rep(newdf$x, 2))
mdf = with(Dataset, data.frame(x = rep(x, 2), y = c(subset(Dataset,Dataset$molar=="M1",select=Y), subset(Dataset,Dataset$molar=="M2",select=Y),
f = factor(rep(1:2, c(408,663))))
ggplot(mdf, aes(x = x, y = y, colour = f)) + geom_point() +
geom_ribbon(data = p, aes(x = x, ymin = lwr, ymax = upr,
fill = f, y = NULL, colour = NULL),
alpha = 0.2) +
geom_line(data = p, aes(x = x, y = fit))
These are the messages I get now:
[98] WARNING: Warning in if (n < 0L) stop("wrong sign in 'by' argument") :
the condition has length > 1 and only the first element will be used
Warning in if (n > .Machine$integer.max) stop("'by' argument is much too small") :
the condition has length > 1 and only the first element will be used
Warning in 0L:n :
numerical expression has 2 elements: only the first used
Warning in if (by > 0) pmin(x, to) else pmax(x, to) :
the condition has length > 1 and only the first element will be used
[99] WARNING: Warning in predict.lm(M1.R, interval = "prediction") :
predictions on current data refer to _future_ responses
[100] WARNING: Warning in predict.lm(M2.R, interval = "prediction") :
predictions on current data refer to _future_ responses
[101] ERROR: <text>
I think I am closer but still can't see it. Help!
Here is one way. If you have more than two models/levels in the factor you should look into code that will work over the levels of the factor and fit the models that way.
Anyway, first some dummy data:
set.seed(100)
x <- runif(100)
y1 <- 2 + (0.3 * x) + (2.4 * x^2) + (-2.5 * x^3) + (3.4 * x^4) + rnorm(100)
y2 <- -1 + (0.3 * x) + (2.4 * x^2) + (-2.5 * x^3) + (3.4 * x^4) +
(-0.3 * x^5) + (2.4 * x^6) + rnorm(100)
df <- data.frame(x, y1, y2)
Fit our two models:
m1 <- lm(y1 ~ poly(x, 4), data = df)
m2 <- lm(y2 ~ poly(x, 6), data = df)
Now precict at some new locations x and stick it together with x and f, a factor indexing the model, into a tidy format:
newdf <- data.frame(x = seq(0, 1, length = 100))
p1 <- predict(m1, newdata = newdf, interval = "prediction")
p2 <- predict(m2, newdata = newdf, interval = "prediction")
p <- cbind(as.data.frame(rbind(p1, p2)), f = factor(rep(1:2, each = 100)),
x = rep(newdf$x, 2))
Melt the original data into tidy form
mdf <- with(df, data.frame(x = rep(x, 2), y = c(y1, y2),
f = factor(rep(1:2, each = 100))))
Draw the plot, using colour to distinguish the models/data
ggplot(mdf, aes(x = x, y = y, colour = f)) +
geom_point() +
geom_ribbon(data = p, aes(x = x, ymin = lwr, ymax = upr,
fill = f, y = NULL, colour = NULL),
alpha = 0.2) +
geom_line(data = p, aes(x = x, y = fit))
This gets us
So I'm running an optimization problem and am trying to add the function at each point in time to a plot. I'm able to plot the function but I have the variables stored and it seems like r doesn't evaluate the function until it renders it. It's hard to explain, but I have a simple example that shows it.
data = data.frame(x = runif(20, -10, 10), y = runif(20, -10,10))
p <- ggplot(data, aes(x = x, y =y))
slope = 0.5
yoff = 1
p <- p + stat_function(fun = function(x) slope*x+yoff)
slope = 1
yoff = -1
p <- p + stat_function(fun = function(x) slope*x+yoff)
p
And what I want is two lines on the graph with the slope and y-intercept that I had when I added the function to the graph.
If you have a lot of them, make a list of functions:
make_fun <- function(slope,yoff) {slope; yoff; function(x) x*slope + yoff}
> l <- mapply(FUN = make_fun,slope = 1:2,yoff = 3:4)
> l[[1]](1)
[1] 4
> l[[2]](1)
[1] 6
A function is evaluated when used, so there it is at render time.
You can rename your parameters to have different function:
p <- ggplot(data, aes(x = x, y =y))
slope1 = 0.5
yoff1 = 1
p <- p + stat_function(fun = function(x) slope1*x+yoff1)
slope2 = 1
yoff2 = -1
p <- p + stat_function(fun = function(x) slope2*x+yoff2)
Many parameters in ggplot aren't evaluated until the plot is actually rendered. Here we can make the slope and yoff values arguments to the functions and then pass in values via the args= parameter which does get evaluated earlier.
library(ggplot2)
data = data.frame(x = runif(20, -10, 10), y = runif(20, -10,10))
p <- ggplot(data, aes(x = x, y =y))
slope = 0.5
yoff = 1
p <- p + stat_function(fun = function(x, slope, yoff) slope*x+yoff, args=list(slope=slope, yoff=yoff))
slope = 1
yoff = -1
p <- p + stat_function(fun = function(x, slope, yoff) slope*x+yoff, args=list(slope=slope, yoff=yoff))
p
I'm using ggplot to plot a time series with a linear regression line. I would like to have different colours for my time series depending on whether it is above or below the trend line.
Here is a code example to plot the series and the corresponding trend line with different colours for the series and the line:
x <- seq(as.Date("2000/1/1"), as.Date("2010/1/1"), "years")
y <- rnorm(length(x),0,10)
df <- data.frame(x,y)
ggplot(df, aes(x, y)) +
stat_smooth(method = 'lm', aes(colour = 'Trend'), se = FALSE) +
geom_line(aes(colour = 'Observation') ) +
theme_bw() +
xlab("x") +
ylab("y") +
scale_colour_manual(values = c("blue","red"))
Have a nice day!
I got rid of the dates, since they were driving me nuts. Perhaps someone can add a solution for that. Otherwise it seems quite doable, with some basic high school maths.
df <- data.frame(x = 2000:2010,
y = rnorm(11, 0, 10))
fm <- lm(y ~ x, data = df)
co <- coef(fm)
df$under_over <- sign(fm$residuals)
for (i in 1:(nrow(df) - 1)) {
# Get slope and intercept for line segment
slope <- (df$y[i + 1] - df$y[i]) / (df$x[i + 1] - df$x[i])
int <- df$y[i] - slope * df$x[i]
# find where they would cross
x <- (co[1] - int) / (slope - co[2])
y <- slope * x + int
# if that is in the range of the segment it is a crossing, add to the data
if (x > df$x[i] & x < df$x[i + 1])
df <- rbind(df, c(x = x, y = y, under_over = NA))
}
#order by x
df <- df[order(df$x), ]
# find color for intersections
for (i in 1:nrow(df))
if (is.na(df$under_over[i]))
df$under_over[i] <- df$under_over[i + 1]
ggplot(df) +
geom_abline(intercept = co[1], slope = co[2]) +
geom_path(aes(x, y, col = as.factor(under_over), group = 1)) +
theme_bw()
Using ggplot(), I am trying to plot the results of an ANCOVA in which slopes of the two linear components are equal: i.e., lm(y ~ x + A). The default behavior for geom_smooth(method = "lm") is to plot separate slopes and intercepts for each level of each factor. For example, with two levels of A
library(ggplot2)
set.seed(1234)
n <- 20
x1 <- rnorm(n); x2 <- rnorm(n)
y1 <- 2 * x1 + rnorm(n)
y2 <- 3 * x2 + (2 + rnorm(n))
A <- as.factor(rep(c(1, 2), each = n))
df <- data.frame(x = c(x1, x2), y = c(y1, y2), A = A)
p <- ggplot(df, aes(x = x, y = y, color = A))
p + geom_point() + geom_smooth(method = "lm")
I can fit the ANCOVA separately with lm() and then use geom_abline() to manually add the lines. This approach has a couple of drawbacks like having the lines extend beyond the range of the data and manually specify the colors.
fm <- lm(y ~ x + A, data = df)
summary(fm)
a1 <- coef(fm)[1]
b <- coef(fm)[2]
a2 <- a1 + coef(fm)[3]
p + geom_point() +
geom_abline(intercept = a1, slope = b) +
geom_abline(intercept = a2, slope = b)
I know ancova() in the HH package automates the plotting, but I don't really care for lattice graphics. So I am looking for a ggplot()-centric solution.
library(HH)
ancova(y ~ x + A, data = df)
Is there a method to accomplish this using ggplot()? For this example, A has two levels, but I have situations with 3, 4, or more levels. The formula argument to geom_smooth() doesn't seem to have the answer (as far as I can tell).
For completeness, this works:
library(ggplot2)
set.seed(1234)
n <- 20
x1 <- rnorm(n); x2 <- rnorm(n)
y1 <- 2 * x1 + rnorm(n)
y2 <- 3 * x2 + (2 + rnorm(n))
A <- as.factor(rep(c(1, 2), each = n))
df <- data.frame(x = c(x1, x2), y = c(y1, y2), A = A)
fm <- lm(y ~ x + A, data = df)
p <- ggplot(data = cbind(df, pred = predict(fm)),
aes(x = x, y = y, color = A))
p + geom_point() + geom_line(aes(y = pred))