I'm using Firebase Cloud Firestore and can't figure out how to access documents without knowing the specific path. The database structure is users/{user id}/favourites/{favourite id}. There are no fields in users/{user id} only subcollections. Knowing the user id, i can get the favourites for the user, but I can't get a list of users to get everyone's favourites. Here is the code I am trying (Java admin SDK):
db.collection("users").get().get()
which results in an empty Iterable with no DocumentSnapshots.
How can I get a list of the most popular favourites?
EDIT: I've discovered I can get a list of users with no fields if I add a field. Even if I delete it later, it still appears as a document in the collection.
EDIT2: I've discovered that I can create an empty document, so I'm just doing that for now. As a one-off, I can get a list of all users from firebase auth and look up which ones have a favourites collection and just set those to empty documents.
Related
Say I have the following structure:
collectionA/documentA/collectionB/documentB
But I have set documentB directly to the above path (without explicitly creating collectionA, documentA or collectionB), so the document "documentA" is a non existent document that does not show in queries if I list all documents of collectionA even with admin sdk.
However the firebase web console somehow manages to list such documents. Not only that, I have also seen a third party app Firefoo list such documents and somehow even paginate the results. How can I achieve this?
Turns out this can be achieved with the
Firestore REST API v1
using the listDocuments endpoint and setting query param showMissing to true.
All Firestore queries are based on having some data about that document present in the index that is used for the query. There is no public API to show non-existing documents.
The Firebase console shows these documents based on getting a list of all collections, and then building a data model from that.
I have a field in my Firestore documents that happens to be an array of user IDs, this field is called "tempID", I want to run a query that return all documents that do not contain a particular user ID stored in "tempID". I did my research and found two useful articles.
Firebase check if item is not in array in Flutter
I tried what was suggested in this link but I am not getting desired outcome.
https://firebase.google.com/docs/firestore/query-data/queries#dart_8
I read official documentation from this link but still have not been able to implement desired outcome.
So few day ago I moved my apps posts to cloud firestore from realtime database because of the more flexable querying that firestore apparently has. I have been modifying my code to work with firestore as the new database. Now I ran into a problem. How can I retrieve every document within "Posts" collection that has "Likes" collection that contains a specifically named document? I don't know if that makes sense so here's an image showcasing the problem:
I had a working query for firebase realtime database but can't figure out how to do it with firestore. Is it possible or do I have to change the structure of my database? If I do have to change the structure, what would be the most convenient way of getting the same result?
This is currently not possible with collection group queries. You might be tempted to put a filter on the query for FieldPath.documentId() == 'your-doucment-id', but that just isn't supported. FieldPath.documentId() is actually a token that refers to to fully unique document id, which includes the entire path of the document.
The workaround is to store the document ID as a field in the document, and filter on the contents of that field instead. So, if the document had a field called id with the ID of the document, you could query for collectionGroup("Likes").whereEquals('id', 'your-document-id').
I'd like my web app router slugs to correspond to my Firestore documents data.
For example:
www.mysite.com/restaurants/burger-king
/restaurants <- Firestore Collection
/restaurants/mcdonalds <- Firestore Document
/restaurants/burger-king <- Firestore Document
This is easy enough, as I can assign the name as a slug-friendly UID in Firestore. The difficulty arises with CRUD functionality. I need to be able to rename my item titles, but Firestore does not permit you to rename indexes, which is the issue I'm facing.
One SO solution I saw was to delete the old record and creates a new one at the updated index. That's problematic for me, because sub-collections would be hard to transfer from the client side.
Are there more elegant solutions?
You don't have to identify a document by its ID. If you're able to ensure uniqueness of a document field value, you could instead query a collection for an ID value in a known field, then use the results of that query to satisfy your REST API. Then, you can change the value of that document field as often as you want, in order to satisfy required changes to the public API.
I want to search the "displayName" in documents nested within a collection, or more specifically the data is as follows:
users -> $idstring -> displayName
Ive come up with the following using AngularFire but its still not quite working for me.. I need to check displayName against the first 3 chars of val (user entered) and bring back results that start with that, I need a kind of LIKE search operation to occur, is this possible with firestore.. so far its just returning almost everything in my users collection
this.itemsCollection = this.aft.collection<iUser>('users', ref => ref.orderBy("displayName").startAt(val))
As mentioned on the Cloud Firestore Documentation:
Cloud Firestore doesn't support native indexing or search for text
fields in documents. Additionally, downloading an entire collection to
search for fields client-side isn't practical.
And to enable full text search of your data, you'd need to use a third-party search service like Algolia or ElasticSearch.
The documentation actually provides a guide on how to integrate Algolia with Firebase.