This question already has an answer here:
Convert date to character in a data frame
(1 answer)
Closed 5 years ago.
I have a POSIXct datetime column in a file.
$date
[1] "POSIXct" "POSIXt"
"2005-10-13 14:13:08 UTC"
I would like to convert it to character column.
Any ideas?
Just cast your POSIXCT object to character, e.g.
date <- as.POSIXct("20-Jan-2018 19:06:08.314", format="%d-%b-%Y %H:%M:%OS")
date.str <- as.character(date)
date.str
[1] "2018-01-20 19:06:08"
Related
This question already has an answer here:
Milliseconds in POSIXct Class
(1 answer)
Closed 1 year ago.
I have a dataframe in r which consists of a column with the following DateTime format with character class.
dt<-2021-03-01 06:10:31.346
I need to convert it into the following format with datetime class.
2021-03-01 06:10:31
I have tried the following solution but it didn't work.
Df$Dt<- as.POSIXct(Df$Dt,format="%Y-%m-%dT%H:%M:%S")
The T is not needed as it was not present in the original string
as.POSIXct(dt, format="%Y-%m-%d %H:%M:%S")
#[1] "2021-03-01 06:10:31 CST"
If we want to take care of the microseconds
as.POSIXct(dt, format="%Y-%m-%d %I:%M:%OS")
Also, the format is not really needed here as the input is in the accepted format for as.POSIXct
as.POSIXct(dt)
#[1] "2021-03-01 06:10:31 CST"
data
dt <- '2021-03-01 06:10:31.346'
This question already has an answer here:
converting datetime string to POSIXct date/time format in R
(1 answer)
Closed 2 years ago.
Using R, how do I transform the date and time from here, into a "standard" date/time string format?
2020-12-30T03:32:30.000Z
Use ?strptime
strptime("2020-12-30T03:32:30.000Z", "%Y-%m-%dT%H:%M:%S")
# [1] "2020-12-30 03:32:30 CET"
You can also use:
#Code
as.POSIXct(gsub('T|Z',' ','2020-12-30T03:32:30.000Z'),'%Y-%m-%d %H:%M:%S.%OS')
Output:
[1] "2020-12-30 03:32:30 GMT"
This question already has answers here:
strptime, as.POSIXct and as.Date return unexpected NA
(2 answers)
Closed 4 years ago.
I have a vector of strings which I need to convert to dates. This only works for some of the dates which are in the format of "dd-mmm-YYYY".
Example: this works: strptime("21-Sep-2017", format = "%d-%b-%Y")
This does not work and returns NA: strptime("21-Dec-2017", format = "%d-%b-%Y")
What am I doing wrong or not seeing?
This is because your locale is probably one where December is not abbreviated as Dec. Without changing your session settings, you could simply do
lubridate::parse_date_time("21-Dec-2017", orders = "d-b-Y", locale = "us")
[1] "2017-12-21 UTC"
This question already has an answer here:
Extract time from datatime in R
(1 answer)
Closed 6 years ago.
My dataset df has datetime column,
this column's format is YYYY-MM-DD HH:MM
I made new column that has only YYYY-MM-DD using
df$date <- factor(as.Date(df$datetime))
but I can't make column that has only time,
I want to make new column 'time' that has format HH:MM
Use strptime and strftime, the former convert character vectors to POSIXct and POSIXlt class( or date time class) and the latter does the opposite. With the format parameter, you can easily convert and format your datetime:
s = "2016-01-01 10:20"
strftime(strptime(s, "%Y-%m-%d %H:%M"), "%H:%M")
# [1] "10:20"
strftime(strptime(s, "%Y-%m-%d %H:%M"), "%Y-%M-%d")
# [1] "2016-20-01"
This question already has an answer here:
R convert character vector values to Date values
(1 answer)
Closed 7 years ago.
I have a large number of strings of the following format:
a <- "19260701"
I would like to convert these do the following date format:
1926-07-01
when I try:
as.Date(a, "%Y-%m-%d")
I get
NA
You need to put the format of a in the function as.Date() :
a <- "19260701"
as.Date(a,format="%Y%m%d")
[1] "1926-07-01"
a<- "19260701"
library(lubridate)
ymd(a)
[1] "1926-07-01 UTC"