Firebase Functions - Delete data without knowing the key - firebase

I am inserting data in Firebase Realtime Database in a table with the above structure. The key of the data is auto-generated based on push. After several such entries are created, sometime due to certain conditions I may need to delete one of the entries. At the point of deleting the entry, I may know some of the values of the node that I want to delete like createdAt and createdForPostID. But I will not know the key as it was auto-generated using push feature of firebase database. A combination of createdAt and createdForPostID makes a unique combination and only one such entry should exist in the database.
What would be the most efficient way to identify the entry without having to retrieve the entire node at OUTBOUND?
The reason I am using push is because Firebase claims it to be efficient and not subject to write conflicts. I also rely on the auto-sorting by date/time offered by push.
If no efficient way can be found, then I will generate my own key using date/time stamp. But I am hoping that this is a problem that someone has solved before and hence can guide me.
Any suggestions are welcome.

You'll need to run a query to find the items that match your conditions.
Since you seem to have multiple properties in your conditions, and the Firebase Database can only query on a single property, you'll need to combine the values into a single property as shown here.
Then you can run a query on that combined property and delete the items it returns:
var query = ref.orderByChild("createForPostID-createdAt").equalTo("20171229_124904-20171230_200343");
query.once("value", function(snapshot) {
snapshot.forEach(function(child) {
child.ref.remove();
})

Given Frank's answer I realised, I needed to create a unique property as per his suggestion because I will need it to do the future query. But then it seemed that I may be better off using that unique property as the key instead of using push
So it seems from an overall perspective, it might be more efficient to create your own key instead of push, if the app needs both create and delete functions. Reliance on push makes sense only if data is being created and deletion is not a big functionality of your app.
So, in conclusion, for Firebase data, the most efficient way to do both data create and delete needs creation of a unique key on your own.

Related

Changing data model in existing cloud firestore collection?

Suppose I have a users collection. The users collection has a large number of documents in it. Now in my app, I have a feature request that forces me to add or remove a field in my users collection data model. How can I add a new field or remove an existing field from all my users documents? Is there any best practice that the community recommends here?
How can I add a new field or remove an existing field from all my users documents?
While #AdityaNandardhane solution might work, please note that if you have a lot of documents, then you have a lot of update operations to perform, which also means that you have to play a lot of writes.
So the best approach would be to perform the update, only when the user reads the document. When it comes to users, most likely the details of the users are displayed on a profile screen. This means that when the users want to check the profile, before displaying the data, check for the existence of the new field. If it doesn't exist, then perform the update operation, and right after that display the data, otherwise, just display the data. This means that you'll have to pay for an update operation only when needed. It doesn't make any sense to update all documents, of all users, since there may be users that will never use their accounts anymore. So there is no need to pay for them.
As I understood, You can do the following thing
1. Add New Field
If you are using Firebase Functions- you can create one function and write an update query with a new field and set one default value and Run the function. You can do the same from android also with kotlin/java.
2. Remove existing Field
If you are using Firebase Functions- you can create one function and write a query to delete one field and Run the function. You can do the same from android also with kotlin/java.
Look for a better approach If any, Its suggestion as per my knowledge.

Managing Denormalized/Duplicated Data in Cloud Firestore

If you have decided to denormalize/duplicate your data in Firestore to optimize for reads, what patterns (if any) are generally used to keep track of the duplicated data so that they can be updated correctly to avoid inconsistent data?
As an example, if I have a feature like a Pinterest Board where any user on the platform can pin my post to their own board, how would you go about keeping track of the duplicated data in many locations?
What about creating a relational-like table for each unique location that the data can exist that is used to reconstruct the paths that require updating.
For example, creating a users_posts_boards collection that is firstly a collection of userIDs with a sub-collection of postIDs that finally has another sub-collection of boardIDs with a boardOwnerID. Then you use those to reconstruct the paths of the duplicated data for a post (eg. /users/[boardOwnerID]/boards/[boardID]/posts/[postID])?
Also if posts can additionally be shared to groups and lists would you continue to make users_posts_groups and users_posts_lists collections and sub-collections to track duplicated data in the same way?
Alternatively, would you instead have a posts_denormalization_tracker that is just a collection of unique postIDs that includes a sub-collection of locations that the post has been duplicated to?
{
postID: 'someID',
locations: ( <---- collection
"path/to/post/location1",
"path/to/post/location2",
...
)
}
This would mean that you would basically need to have all writes to Firestore done through Cloud Functions that can keep a track of this data for security reasons....unless Firestore security rules are sufficiently powerful to allow add operations to the /posts_denormalization_tracker/[postID]/locations sub-collection without allowing reads or updates to the sub-collection or the parent postIDs collection.
I'm basically looking for a sane way to track heavily denormalized data.
Edit: oh yeah, another great example would be the post author's profile information being embedded in every post. Imagine the hellscape trying to keep all that up-to-date as it is shared across a platform and then a user updates their profile.
I'm aswering this question because of your request from here.
When you are duplicating data, there is one thing that need to keep in mind. In the same way you are adding data, you need to maintain it. With other words, if you want to update/detele an object, you need to do it in every place that it exists.
What patterns (if any) are generally used to keep track of the duplicated data so that they can be updated correctly to avoid inconsistent data?
To keep track of all operations that we need to do in order to have consistent data, we add all operations to a batch. You can add one or more update operations on different references, as well as delete or add operations. For that please see:
How to do a bulk update in Firestore
What about creating a relational-like table for each unique location that the data can exist that is used to reconstruct the paths that require updating.
In my opinion there is no need to add an extra "relational-like table" but if you feel confortable with it, go ahead and use it.
Then you use those to reconstruct the paths of the duplicated data for a post (eg. /users/[boardOwnerID]/boards/[boardID]/posts/[postID])?
Yes, you need to pass to each document() method, the corresponding document id in order to make the update operation work. Unfortunately, there are no wildcards in Cloud Firestore paths to documents. You have to identify the documents by their ids.
Alternatively, would you instead have a posts_denormalization_tracker that is just a collection of unique postIDs that includes a sub-collection of locations that the post has been duplicated to?
I consider that isn't also necessary since it require extra read operations. Since everything in Firestore is about the number of read and writes, I think you should think again about this approach. Please see Firestore usage and limits.
unless Firestore security rules are sufficiently powerful to allow add operations to the /posts_denormalization_tracker/[postID]/locations sub-collection without allowing reads or updates to the sub-collection or the parent postIDs collection.
Firestore security rules are so powerful to do that. You can also allow to read or write or even apply security rules regarding each CRUD operation you need.
I'm basically looking for a sane way to track heavily denormalized data.
The simplest way I can think of, is to add the operation in a datastructure of type key and value. Let's assume we have a map that looks like this:
Map<Object, DocumentRefence> map = new HashMap<>();
map.put(customObject1, reference1);
map.put(customObject2, reference2);
map.put(customObject3, reference3);
//And so on
Iterate throught the map, and add all those keys and values to batch, commit the batch and that's it.

How to delete Single-field indexes that generated automatically by firestore?

update:
TLDR;
if you reached here, you should recheck the way you build your DB.
Your document(s) probably gets expended over time (due to nested list or etc.).
Original question:
I have a collection of documents that have a lot of fields. I do not query documents even no simple queries-
I am using only-
db.collection("mycollection").doc(docName).get().then(....);
in order to read the docs,
so I don't need any indexing for this collection.
The issue is that firestore generates Single-field indexes automatically, and due to the amount of fields cause limitation exceeding of indexing:
And if I trying to add a field to one of the documents it throws me an error:
Uncaught (in promise) Error: Too many indexed properties for entity: app: "s~myapp",path < Element { type: "tags", name: "aaaa" }>
at new FirestoreError (index.cjs.js:346)
at index.cjs.js:6058
at W.<anonymous> (index.cjs.js:6003)
at Ab (index.js:23)
at W.g.dispatchEvent (index.js:21)
at Re.Ca (index.js:98)
at ye.g.Oa (index.js:86)
at dd (index.js:42)
at ed (index.js:39)
at ad (index.js:37)
I couldn't find any way to delete these single-field-indexing or to tell firestore to stop generating them.
I found this in firestore console:
but there is no way to disable this, and to disable auto indexing for a specific collection.
Any way to do it?
You can delete simple Indexes in Firestore firestore.
See this answer for more up to date information on creating and deleting indexes.
Firestore composite index permutation explosion?
If you go in to Indexes after selecting the firestore database and then select "single" indexes there is an Add exemption button which allows you to specify which fields in a Collection (or Sub-collection) have simple indexes generated by Firestore. You have to specify the Collection followed by the field. You then specify every field individually as you cannot specify a whole collection. There does not seem to be any checking on valid Collections or field names.
The only way I can think to check this has worked is to do a query using the field and it should fail.
I do this on large string fields which have normal text in them as they would take a long time to index and I know I will never search using this field.
Firestore creates two indexes for every simple field (ascending and descending) but it is also possible to create an exemption which removes one of these if you will never need the second one which helps improve performance and makes it less likely to hit the index limits. In addition you can select whether arrays are indexed or not. If you create a lot of entries it an Array, then this can very quickly hit the firestore limits on the number of indexes, so care has to be taken when using indexes and it will often be best to take the indexes off Arrays since the designer may have no control over how many Array data items are added with the result that the maximum index limit is reached and the application will get an error as the original poster explained.
You can also remove any simple indexes if you are not using them even if a field is included in a complex index. The complex index will still work.
Other things to keep an eye on.
If you are indexing a timestamp field (or any field that increases or decreases sequentially between documents) and you are not using this to force a sequence in queries, then there is a maximum write rate of 500 writes per second for the collection. In this case, this limit can be removed by removing the increasing and decreasing indexes.
Note that unlike the Realtime Database, fields created with Auto-ID do not guarantee any ordering as they are generated by firestore to spread writes and avoid hotspots or bottlenecks where all writes (and therefore reads) end up at a single location. This means that a timestamp is often needed to generate ordering but you may be able to design your collections / sub-collections data layout to avoid the need for a timestamp. For example, if you are using a timestamp to find the last document added to a collection, it might be better to just store the ID of the last document added.
Large array or map fields can also cause the 20,000 index entries per document limit to be reached, so you can exempt the array from indexing (see screenshot below).
Once you have added one exemption, then you will get this screen.
See this link as well.
https://firebase.google.com/docs/firestore/query-data/index-overview
The short answer is you can't do that right now with Firebase. However, this is a good signal that you need to restructure your database models to avoid hitting limits such as the 1MB per document.
The documentation talks about the limitations on your data:
You can't run queries on nested lists. Additionally, this isn't as
scalable as other options, especially if your data expands over time.
With larger or growing lists, the document also grows, which can lead
to slower document retrieval times.
See this page for more information about the advantages and disadvantages on the different strategies for structuring your data: https://firebase.google.com/docs/firestore/manage-data/structure-data
As stated in the Firestore documentation:
Cloud Firestore requires an index for every query, to ensure the best performance. All document fields are automatically indexed, so queries that only use equality clauses don't need additional indexes. If you attempt a compound query with a range clause that doesn't map to an existing index, you receive an error. The error message includes a direct link to create the missing index in the Firebase console.
Can you update your question with the structure data you are trying to save?
A workaround for your problem would be to create compound indexes, or as a last resource, Firestore may not be suited to the needs for your app and Firebase Realtime Database can be a better solution.
See tradeoffs:
RTDB vs Firestore
I don't believe that there currently exists the switch that you are looking for, so I think that leaves the following,
Globally disable built-in indexes and create all indexes explicitly. Painful and they have limits too.
A workaround where you treat your Cloud Firestore unfriendly content like a BLOB, like so:
To store,
const objIn = {text: 'my object with a zillion fields' };
const jsonString = JSON.stringify(this.objIn);
const container = { content: this.jsonString };
To retrieve,
const objOut = JSON.parse(container.content);

Fetch new entities only

I thought Datastore's key was ordered by insertion date, but apparently I was wrong. I need to periodically look for new entities in the Datastore, fetch them and process them.
Until now, I would simply store the last fetched key and wrongly query for anything greater than it.
Is there a way of doing so?
Thanks in advance.
Datastore automatically generated keys are generated with uniform distribution, in order to make search more performant. You will not be able to understand which entity where added last using keys.
Instead, you can try couple of different approaches.
Use Pub/Sub and architecture your app so another background task will consume this last added entities. On entities add in DB, you will just publish new Event into Pub/Sub with key id. You event listener (separate routine) will receive it.
Use names and generate you custom names. But, as you want to create sequentially growing names, this will case performance hit on even not big ranges of data. You can find more about this in Best Practices of Google Datastore.
https://cloud.google.com/datastore/docs/best-practices#keys
You can add additional creation time column, and still use automatic keys generation.

Get an object from a bucket in riak without knowing its key

I am using a riak bucket to store a list of messages, using a UUID as the key and a json message as value. This is working fine.
What I need is an efficient way to get a single message from the bucket without knowing its key, at least in one of these two scenarios:
Get the last inserted object (this is my prefered approach).
Get a random object from the bucket (if the first alternative is not possible).
Is there any efficient way to achieve that?
I think one alternative could be to retrieve the keys in the bucket and then get the first one. But this means making two calls to riak, one to obtain all the keys (just to discard all but one) and a second one to obtain the object. It does not seem very efficient.
As Riak is a key-value store, the by far most efficient way to retrieve data is through the keys. Listing or retrieving all keys in a bucket, even if you only end up using the one returned first, is one of the least efficient operations you can perform as it causes Riak to scan ALL keys in the system (not just the bucket), and it is usually recommended NEVER to use this on a production system.
The most efficient way to get the last inserted object would probably be to store the id in a separate, known record in a different bucket. This would however require you to perform two writes on every insert and two reads for every read, but would do so in the most efficient way. You could possibly implement a post-commit hook (would have to be in Erlang as it is not currently not possible to write records using JavaScript functions) on the bucket containing messages to get the system to perform the update for you, which would remove the need for the last write.
If you write a lot of data to the bucket containing messages, you may want to adjust the separate bucket so that it does not allow multiple values and that the last value wins. This way you would reduce the risk of having lots of siblings created due to frequent updates to this single record across the system. This would always give you one of the last written records, but not necessarily the last one (especially if you frequently write messages to the database), as Riak does not support any type of atomicity and is an eventually consistent database.
You could also create one or more secondary indexes if you are using the leveldb backend, and use this to limit your scan to only recent records, which would be more efficient than a scann of all keys. You could then either select the most recent key or a random one through mapreduce, but this would be much less efficient than the previously described approach.
I can not think of any efficient way to retrieve a random record in a bucket from Riak unless you know the range of keys you have inserted and can decide randomly on the client which one to get. One way to do this would be to generate all keys in sequence rather than using a UUID, but that is naturally not a good idea in a highly concurrent distributed system.
1st task is pretty easy to implement:
Add post-commit hook that will write the last inserted key to some predefined key/bucket place
Get the key from that predefined key/bucket and issue a get query using them
It's still two operations but both are just gets that are fast. Plus additional overhead on hook but nothing too heavy either.
2nd scenario is also easy, but it is way too inefficient to be used practically:
Get all keys (extremely expensive operation)
Pick random
Issue get
I have come up with the same scenario. In My scenario I have to save the users. For that I required an auto increment Id. So what I did is, I placed the last inserted key in a separate bucket as like mentioned by "Christian Dahlqvist", every time I want to insert new record I fetch the last inserted key from that key bucket. Here we have only one value in that bucket with the key as "LastKey" which is always known to us. And I incremented the key based on the fetched key and again updated the key bucket. So always the key bucket contains the latest key in it.

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