QML: Bind loop detected without double assignment - qt

Question

As far as I know the bind loop happens when I try to assign two properties each other. Example:
CheckBox {
checked: Settings.someSetting
onCheckedChanged: {
Settings.someSetting = checked;
}
}
but in my scenario I can't see such a "double assignment". I report here the full code:
import QtQuick 2.7
import QtQuick.Window 2.3
Window {
visible: true;
width: 500
height: 500
Rectangle {
id: main
anchors.fill: parent
color: "black"
property bool spinning: true
property bool stopping: false
Rectangle {
x: 0.5 * parent.width
y: 0.5 * parent.height
width: 10
height: 200
radius: 5
color: 'red'
transformOrigin: Item.Top
rotation: {
if (main.stopping)
{
main.spinning = false;
main.stopping = false;
}
return timer.angle
}
}
Timer {
id: timer
interval: 5
repeat: true
running: true
onTriggered: {
if (main.spinning) angle += 1;
}
property real angle
}
MouseArea {
id: control
anchors.fill: parent
onClicked: {
main.stopping = true;
}
}
}
}
When you click with the mouse you will get the warning:
qrc:/main.qml:17:9: QML Rectangle: Binding loop detected for property "rotation"
I don't see my mistake. I'm using flags (bool variables) to control the execution of my code. I know in this case I can just stopping the timer directly, but the actual program is more complex than this example.

Answer 1

The binding is in the following lines:
rotation: {
if (main.stopping)
{
main.spinning = false;
main.stopping = false;
}
return timer.angle
}
The change of rotation is triggered by the change of main.stopping: let's say that change main.stopping is given by the mouseArea, then it will be called a rotation, but inside this there is an if, and in this you are changing back to main.stopping , where he will call rotation back.
If a property in QML changes all the elements that depend on it will change