How to retrieve website source without using ioutil.ReadAll in golang - http

Question

My code:
func getSourceUrl(url string) (string, error) {
resp, err := http.Get(url)
if err != nil {
fmt.Println("Error getSourceUrl: ")
return "", err
}
defer resp.Body.Close()
body := resp.Body
// time = 0
sourcePage, err := ioutil.ReadAll(body)
// time > 5 minutes
return string(sourcePage), err
}
I have a website link with a source of around> 100000 lines. Using ioutil.ReadAll made me get very long (about> 5 minutes for 1 link). Is there a way to get Source website faster? Thank you!

Answer 1

#Minato try this code, play with M throttling parameter. Play with it if you get too errors (reduce it).
package main
import (
"fmt"
"io"
"io/ioutil"
"log"
"net/http"
"runtime"
"time"
)
// Token is an empty struct for signalling
type Token struct{}
// N files to get
var N = 301 // at the source 00000 - 00300
// M max go routines
var M = runtime.NumCPU() * 16
// Throttle to max M go routines
var Throttle = make(chan Token, M)
// DoneStatus is used to signal end of
type DoneStatus struct {
length int
sequence string
duration float64
err error
}
// ExitOK is simple exit counter
var ExitOK = make(chan DoneStatus)
// TotalBytes read
var TotalBytes = 0
// TotalErrors captured
var TotalErrors = 0
// URLTempl is templte for URL construction
var URLTempl = "https://virusshare.com/hashes/VirusShare_%05d.md5"
func close(c io.Closer) {
err := c.Close()
if err != nil {
log.Fatal(err)
}
}
func main() {
log.Printf("start main. M=%d\n", M)
startTime := time.Now()
for i := 0; i < N; i++ {
go func(idx int) {
// slow ramp up fire getData after i seconds
time.Sleep(time.Duration(i) * time.Second)
url := fmt.Sprintf(URLTempl, idx)
_, _ = getData(url) // errors captured as data
}(i)
}
// Count N byte count signals
for i := 0; i < N; i++ {
status := <-ExitOK
TotalBytes += status.length
if status.err != nil {
TotalErrors++
log.Printf("[%d] : %v\n", i, status.err)
continue
}
log.Printf("[%d] file %s, %.1f MByte, %.1f min, %.1f KByte/sec\n",
i, status.sequence,
float64(status.length)/(1024*1024),
status.duration/60,
float64(status.length)/(1024)/status.duration)
}
// totals
duration := time.Since(startTime).Seconds()
log.Printf("Totals: %.1f MByte, %.1f min, %.1f KByte/sec\n",
float64(TotalBytes)/(1024*1024),
duration/60,
float64(TotalBytes)/(1024)/duration)
// using fatal to verify only one go routine is running at the end
log.Fatalf("TotalErrors: %d\n", TotalErrors)
}
func getData(url string) (data []byte, err error) {
var startTime time.Time
defer func() {
// release token
<-Throttle
// signal end of go routine, with some status info
ExitOK <- DoneStatus{
len(data),
url[41:46],
time.Since(startTime).Seconds(),
err,
}
}()
// acquire one of M tokens
Throttle <- Token{}
log.Printf("Started file: %s\n", url[41:46])
startTime = time.Now()
resp, err := http.Get(url)
if err != nil {
return
}
defer close(resp.Body)
data, err = ioutil.ReadAll(resp.Body)
if err != nil {
return
}
return
}
Per transfer variation is about 10-40KByte/sec and final total for all 301 files I get 928MB, 11.1min at 1425 KByte/sec. I believe you should be able to get similar results.
// outside the scope of the question but maybe useful
Also give this a try http://www.dslreports.com/speedtest/ go to settings and select bunch of US servers for testing and set duration to 60sec. This will tell you what your actual effective total rate is to US.
Good luck!

Answer 2

You could iterate sections of the response at a time, something like;
responseSection := make([]byte, 128)
body.Read(responseSection)
return string(responseSection), err
Which would read 128 bytes at a time. However would suggest confirming the download speed is not causing the slow load.

Answer 3

The 5 minutes is probably network time.
That said, you generally would not want to buffer enormous objects in memory.
resp.Body is a Reader.
So you cold use io.Copy to copy its contents into a file.
Converting sourcePage into a string is a bad idea as it forces another allocation.