I have a pixicam connected to an Arduino Uno. The pixi.init() method seems to be interfering with a normal blinky program. Here is the smallest reproducable program:
#include<SPI.h>
#include<Pixy.h>
Pixy pixy;
// the setup function runs once when you press reset or power the board
void setup() {
// initialize digital pin LED_BUILTIN as an output.
pinMode(LED_BUILTIN, OUTPUT);
pixy.init();
}
// the loop function runs over and over again forever
void loop() {
digitalWrite(LED_BUILTIN, HIGH); // turn the LED on (HIGH is the voltage level)
delay(1000); // wait for a second
digitalWrite(LED_BUILTIN, LOW); // turn the LED off by making the voltage LOW
delay(1000); // wait for a second
}
If I comment out the pixi.init() line then the program works as normal (blinking on and off). When the line is not commented out, the light fails to blink.
Related
Trying to run arduino code through pyserial,
Trying to run a code which communicates to the arduino to turn an LED on/off and stays in that HIGH/LOW state until otherwise communicated via the serial port again
the problem I am having is as soon as the python code has run the LED turns off and I can't figure out why its doing this.. any help would be much appreciated.
Arduino CODE
int data;
int EM=13;
#define ever
void setup() {
Serial.begin(9600); //initialize serial COM at 9600 baudrate
pinMode(EM, OUTPUT); //declare the LED pin (13) as output
digitalWrite (EM, LOW); //Turn OFF the Led in the beginning
Serial.println("Actuating Electromagnet");
}
void loop() {
if (Serial.available()>0) //whatever the data that is coming in serially and assigning the value to the variable “data”
{
data = Serial.read();
Serial.println(data);
}
if (data == '1')
digitalWrite (EM, HIGH); //Turn On the Led
else if (data == '0')
digitalWrite (EM, LOW); //Turn OFF the Led
PYTHON SCRIPT
import serial
import time
ArduinoUnoSerial = serial.Serial('/dev/cu.usbmodem1411',9600)
time.sleep(2)
print ArduinoUnoSerial.readline()
ArduinoUnoSerial.write('1')
Here i commented the pinmode section:
void setup() {
//pinMode(10, OUTPUT);
}
// the loop function runs over and over again forever
void loop() {
digitalWrite(10, HIGH); // turn the LED on (HIGH is the voltage level)
delay(1000); // wait for a second
digitalWrite(10, LOW); // turn the LED off by making the voltage LOW
delay(1000); // wait for a second
}
in my test is equal to:
void setup() {
// initialize digital pin LED_BUILTIN as an output.
pinMode(10, OUTPUT);
}
// the loop function runs over and over again forever
void loop() {
digitalWrite(10, HIGH); // turn the LED on (HIGH is the voltage level)
delay(1000); // wait for a second
digitalWrite(10, LOW); // turn the LED off by making the voltage LOW
delay(1000); // wait for a second
}
it only seems that the LED blinks weakly.
Thanks for your time.
From the documentation for digitalWrite():
Write a HIGH or a LOW value to a digital pin.
If the pin has been configured as an OUTPUT with pinMode(), its
voltage will be set to the corresponding value: 5V (or 3.3V on 3.3V
boards) for HIGH, 0V (ground) for LOW.
If the pin is configured as an INPUT, digitalWrite() will enable
(HIGH) or disable (LOW) the internal pullup on the input pin. It is
recommended to set the pinMode() to INPUT_PULLUP to enable the
internal pull-up resistor. See the digital pins tutorial for more
information.
If you do not set the pinMode() to OUTPUT, and connect an LED to a
pin, when calling digitalWrite(HIGH), the LED may appear dim. Without
explicitly setting pinMode(), digitalWrite() will have enabled the
internal pull-up resistor, which acts like a large current-limiting
resistor.
I've got an Arduino which works with the following basic example for blinking:
void setup() {
pinMode(13, OUTPUT);
}
void loop() {
digitalWrite(13, HIGH); // turn the LED on (HIGH is the voltage level)
delay(1000); // wait for a second
digitalWrite(13, LOW); // turn the LED off by making the voltage LOW
delay(1000); // wait for a second
}
But if I add Serial.println it doesn't blink and doesn't output anything to the Serial moniter:
void setup() {
pinMode(13, OUTPUT);
Serial.begin(115200);
}
void loop() {
Serial.println("Loop");
digitalWrite(13, HIGH); // turn the LED on (HIGH is the voltage level)
delay(1000); // wait for a second
digitalWrite(13, LOW); // turn the LED off by making the voltage LOW
delay(1000); // wait for a second
}
What am I doing wrong?
You're not doing anything wrong you may have a bad chip, or your baud rate too high, try 9600
Also can you give me details on your chip, some chips don't have serial.
If you're using the same chip as the leonardo you may need this:
Serial.begin(9600);
while (!Serial) {} //Wait for serial port to connect
When you change the baud rate in Serial.begin(115200) the receiving terminal should have the same baud rate or you will see nothing there.
I am doing a basic project in Arduino UNO connecting an Ultra Sonic sensor (HC-SR04) which should print in the serial monitor the distance of the closest object but it always print 0.
This is my code:
long distance;
long time;
void setup(){
Serial.begin(9600);
pinMode(4, OUTPUT);
pinMode(2, INPUT);
}
void loop(){
digitalWrite(2,LOW);
delayMicroseconds(5);
digitalWrite(2, HIGH);
delayMicroseconds(10);
time = pulseIn(4, HIGH);
distance = int(0.017*time);
Serial.print("Distance: ");
Serial.print(distance);
Serial.println(" cm.");
delay(1000);
}
And this is the breadboard:
The primary issue that I see is that your code doesn't match your wiring diagram.
For example, your diagram shows Trig connected to pin 4. The Trig should be the output from your Arduino but you have it defined as an input.
The Echo is connected to pin 2 and it should be an input, but you have it defined as an output.
Finally, in your loop(), you are not even using pin 2 or pin 4, but pins 9 and 8. Another issue is the timing you use in setting the trigger pulse - it does not match the datasheet. I would do something like this (assuming that you are actually connected to the pins shown in your diagram):
#define sensorTrigPin 4
#define sensorEchoPin 2
void setup()
{
Serial.begin(9600);
pinMode(sensorTrigPin, OUTPUT);
pinMode(sensorEchoPin, INPUT);
}
void loop()
{
int pulseWidth = 0;
digitalWrite(sensorTrigPin, HIGH);
delayMicroseconds(10);
digitalWrite(sensorTrigPin, LOW);
pulseWidth = pulseIn(sensorEchoPin, HIGH);
Serial.print("Pulse Width: ");
Serial.print(pulseWidth);
delay(1000);
}
Note that pulseWidth is just the amount of time that it takes from the beginning of the Echo pulse going high to the end of the same pulse (when it goes low). You would still have to calculate the distance based on the value of pulseWidth.
UPDATE BASED ON RECENT EDIT TO THE QUESTION
If you change a portion of your loop() code to this, it should work:
void loop(){
digitalWrite(4, HIGH); //was (2, LOW)
delayMicroseconds(10); //was (5)
digitalWrite(4, LOW); //was (2, HIGH)
//REMOVED EXTRA DELAY
time = pulseIn(2, HIGH); //was (4,HIGH);
... //Keep the rest of your code the same.
}
Try connecting your VCC of the sensor to 3V3 instead of 5V. This might sound odd, but I tried it and it worked well. Also, please make sure that your echo and trig pin match the code.
I am trying to finish a small project with a moisture sensor connected to a Fio V3.
I have also attach a Xbee S1 module to Fio's socket.
I have upload the following code to Fio:
int igrasia = 7;
void setup()
{
Serial1.begin(9600);
pinMode(igrasia, INPUT_PULLUP);
}
void loop(){
int sensorVal = digitalRead(igrasia);
if (sensorVal == HIGH) {
Serial1.println("0"); // Send OK to xbee
}
else {
Serial1.println("1"); // Send NOT OK to xbee
}
delay(5000);
}
On my computer using the Xbee USB explorer I am receiving correct data on X-CTU every 5 seconds.
Zero (0) while the sensor is outside a glass of water and one (1) while the sensor is in the glass of water.
I want to read these bytes to an Arduino Uno with a LCD screen attached and an Xbee shield. For this reason I have uploaded to Uno the following code:
#include <SPI.h>
#include <Wire.h>
#include <LiquidCrystal_I2C.h>
LiquidCrystal_I2C lcd(0x38,16,2); // set the LCD address to 0x20 for a 16 chars
void setup(){
Serial.begin(9600);
//configure pin2 as an input and enable the internal pull-up resistor
// pinMode(8, INPUT_PULLUP);
pinMode(13, OUTPUT);
digitalWrite(13, LOW);
lcd.init(); // initialize the lcd
}
void loop(){
if(Serial.available())
{
char getData = Serial.read();
if (getData == '1')
{
Serial.print(getData);
digitalWrite(13, HIGH);
lcd.clear();
lcd.setCursor (0,0); // go to start of 1st line
lcd.print("ATTENTION !!!!");
lcd.setCursor (0,1); // go to start of 1st line
lcd.print("WET environment");
}
else {
Serial.print(getData);
digitalWrite(13, LOW);
lcd.clear();
lcd.setCursor (0,0); // go to start of 1st line
lcd.print("dry environment");
lcd.setCursor (0,1); // go to start of 1st line
lcd.print("all looks good!");
}
}
}
It doesn't work properly :- (
I have correct functionality for 0 and while the sensor is outside the water. LCD monitor shows "dry environment".
But as soon as I place the sensor in the water, LCD is not working as required.
Even if I leave the sensor in the water the LCD still displays "dry environment".
I tried the sensor connected directly to Uno with the LCD attached and it works!
I suppose something is wrong with the serial.read() and/or my If / loop statement on UNO.
Any suggestions or advice?
When you transmit the data, you're sending it as a String "1", "0".
On the receiver, you're testing for characters '1', '0'. Strings are terminated with a null character (/u0000), whereas characters are not. Therefore the condition is always failed. You could try transmitting and testing characters only.