How to calculate time difference in HH:MM:SS format in SQLite?
SELECT time(strftime('%s','2017-11-01 22:25:28') - strftime('%s','2017-11-01'));
gives me:
12:00:00
and
SELECT datetime(strftime('%s','2017-11-01 22:25:28') - strftime('%s','2017-11-01'));
gives me:
-4492-12-04 12:00:00
As documented in the documentation, numbers are interpreted as Julian date numbers by default.
If your value is a number of seconds, you have to interpret it as a number of seconds, i.e., as a Unix timestamp:
SELECT time(strftime('%s','2017-11-01 22:25:28') - strftime('%s','2017-11-01'), 'unixepoch');
Related
I have two columns, DATE_A and DATE_B.
I need to find how much time is between the two dates.
Usually, I would use JULIANDAY() and subtract one date from another, but the output is null because of the "+0000" part.
Below you'll find an example of values contained in the two columns:
DATE_A - '2022-05-12 00:16:17.553 +0000'
DATE_B - '2022-06-02 00:02:01.158 +0000'
Please tell me what '+0000' means and how can I find the time elapsed between the two dates.
+0000 is the offset from UTC this time represents in hours and minutes. For example, here in the US Pacific it's daylight savings time and we're 7 hours behind UTC so we're -0700. 2022-05-12 08:00:00+0000 and 2022-05-12 01:00:00-0700 are the same point in time.
SQLite will accept a slightly different format. There has to be the : separator between hours and minutes.
2022-05-12 00:16:17.553 +00:00
^
You'll have to change the format. Use your programming language's date and time functions.
See "Time Values" in SQLite Date and Time Functions for valid formats.
I want to calculate the difference between two columns containing datetime stamps in db browser SQLite, I want the answers in minutes, and it keeps returning "Null". Please what could be the reason and how can I solve it?
I tried using this;
SELECT
started_at,
ended_at,
(strftime('%M','ended_at') - strftime('%M','started_at'))as duration
FROM citi1;
You have 'started_at' and 'ended_at' which are string literals and not identifiers and SQLite returns null when you use them in strftime().
But, even if you remove the single quotes you will not get the timestamp difference, because subtracting only the minutes parts of 2 timestamps does not return their difference.
For example, the difference that you would get for started_at = '2022-03-31 13:15:00' and ended_at = '2022-03-31 14:00:00' would be -15 (= 0 - 15).
Use strftime('%s', some_date) which returns the number of seconds since 1970-01-01 00:00:00 for both timestamps, subtract and divide by 60 to get the correct difference in minutes:
SELECT started_at, ended_at,
(strftime('%s', ended_at) - strftime('%s', started_at)) / 60 AS duration
FROM citi1;
See the demo.
I have a table Orders with Order_Date datatype is smalldatetime and my Order_Date Format is 01/10/2018 10:00:00 PM
Now I want to filter data between 01/10/2018 04:00:00 PM AND 02/10/2018 04:00:00 AM
What I tried
SELECT distinct(Order_No),Order_Date from Orders WHERE Order_Date BETWEEN '01/10/2018 04:00:00 PM' and '02/10/2018 04:00:00 AM'
This query is showing only 01/10/2018 Data but I want the data BETWEEN 01/10/2018 04:00:00 PM and 02/10/2018 04:00:00 AM
Is there any way to get the data from today 4PM To Next Day 4AM?
First off, sqlite does not have actual date/time types. It's a simple database with only a few types. Your smalldatetime column actually has NUMERIC affinity (See the affinity rules).
For Sqlite's builtin functions to be able to understand them, date and times can be stored as numbers or text; numbers are either the number of seconds since the Unix epoch, or a Julian day. Text strings can be one of a number of formats; see the list in the docmentation. All these have the additional advantage that, when compared to other timestamps in the same format, they can be properly sorted.
You seem to be using text strings like '01/10/2018 04:00:00 PM'. This is not one of the formats that sqlite date and time functions understand, and it doesn't sort naturally, so you can't use it in comparisons aside from testing equality. Plus it's ambiguous: Is it October 1, or January 10? Depending on where you're from you'll have a different interpretation of it.
If you change your timestamp format to a better one like (Assuming October 1) '2018-10-01 16:00:00', you'll be able to sort and compare ranges, and use it with sqlite functions.
I want to select the dates in ascending order. Dates are stored in dd-MMM-yy(02-Mar-12) format. Here is my query:
SELECT EventDate,Event,ID from EventCalenderTable Order By EventDate ASC
output is:
10-03-12
12-02-12
15-01-12
18-07-12
But the output should like:
15-01-12
12-02-12
10-03-12
18-07-12
Event Date is date datatype.
I have seen number of post about storing date in sql. I noticed that Convert function done the tricks in sql server. But how can I do this in Sqlite??
Thanks in advance.
SQLite only knows three date formats:
Text ISO8601 strings ("YYYY-MM-DD HH:MM:SS.SSS")
Real Julian day numbers since November 24, 4714 B.C
Integer number of seconds since 1970-01-01 00:00:00 UTC
SQLite does have five date/time functions for converting between formats.
I have a table that stores date/time values as julian days in SQLite (using the julianday() function). I can't seem to figure out how to convert them back to ISO 8601 style strings (YYYY-mm-ddThh:m:ss.sss) when I read them?
Just feed the Julian day number to the datetime function:
A time string can be in any of the following formats:
[...]
12. DDDDDDDDDD
[...]
Format 12 is the Julian day number expressed as a floating point value.
So datetime(julianday_output) goes in the opposite direction as the julianday function:
sqlite> select datetime(julianday(current_timestamp)) as dt_from_jd, current_timestamp as dt;
dt_from_jd | dt
2011-09-30 14:46:52 | 2011-09-30 14:46:52
Have you tried strftime? http://www.sqlite.org/lang_datefunc.html