First variable replacing others - python-3.6

Question

I have the following code:
from a3_functions import convert_date
date=int(input('Please enter the date in the format: ddmmyyyy'))
days, months, years=convert_date(date)
print("{0:02d}/{0:02d}/{0:04d}".format(days, months, years))
print(days)
print(months)
print(years)
But when I run it outputs the following:
Please enter the date in the format: ddmmyyyy03061314
03/03/0003
3
6
1314
Why does the sentence form of my output just output the first variable three times? Even though when I print them individually they print their respective values.

Answer 1

Your format string is using positional indices (which all are 0 and thus taking the first element).
Try this format string instead (I basically only removed all the 0 in front of the :):
>>> print("{:02d}/{:02d}/{:04d}".format(days, months, years))
03/06/1314
If you want to keep the positional arguments, you could just increment the numbers like this:
>>> print("{0:02d}/{1:02d}/{2:04d}".format(days, months, years))
03/06/1314
Alternatively, you could also name the positions to use an even more readable format string:
>>> print("{day:02d}/{month:02d}/{year:04d}".format(day=days, month=months, year=years))
03/06/1314
PyFormat has a great overview over the new-style format strings:
With new style formatting it is possible (and in Python 2.6 even
mandatory) to give placeholders an explicit positional index.
This allows for re-arranging the order of display without changing the
arguments.
This operation is not available with old-style formatting.
New: '{1} {0}'.format('one', 'two')
Output: two one