As you can see I would like to read a csv-table into my data-pool. The table has multiple columns but when i simply try following code:
reviews <- read.table("Sz-Iraki2.csv", fileEncoding = "UTF-8")
i get the error: Error in scan(file = file, what = what, sep = sep, quote = quote, dec = dec, :
line 1 did not have 22 elements
When i Add header=True i get the error: more columns than column names. Seems like a basic problem but i can´t find the answer :(strong text
but should look like this
Data looks like this
You have to define a separator otherwise R fail to read data properly. Suppose your data structure is the following:
structure(list(month = 2:5, titles_tmp = structure(c(1L, 1L,
1L, 1L), .Label = "some text", class = "factor"), info_tmp = structure(c(1L,
1L, 1L, 1L), .Label = "More text", class = "factor"), unlist.text = structure(c(1L,
1L, 1L, 1L), .Label = "http://somelink.com", class = "factor")), .Names = c("month",
"titles_tmp", "info_tmp", "unlist.text"), class = "data.frame", row.names = c(NA,
-4L))
That means you separate each columns with single tab. Meaning you need to use sep = " " as a data separator. Provided your data file name is "df.csv" the following should import your data nicely:
df = read.csv("Sz-Iraki2.csv", sep= " ", fileEncoding = "UTF-8")
I like to use:
require(readr)
read_csv("myData.csv")
Seems more appropriate, if your file type is csv.
Also comes with some useful options like defining 'coltype' on import.
Related
This thread follows on from this answered qestion: Matching strings loop over multiple columns
I opened a new thread as I would like to make an update to flag for exact matches only..
I have a table of key words in separate colums as follows:
#codes table
codes <- structure(
list(
Support = structure(
c(2L, 3L, NA),
.Label = c("",
"help", "questions"),
class = "factor"
),
Online = structure(
c(1L,
3L, 2L),
.Label = c("activities", "discussion board", "quiz", "sy"),
class = "factor"
),
Resources = structure(
c(3L, 2L, NA),
.Label = c("", "pdf",
"textbook"),
class = "factor"
)
),
row.names = c(NA,-3L),
class = "data.frame"
)
I also have a comments table structured as follows:
#comments table
comments <- structure(
list(
SurveyID = structure(
1:5,
.Label = c("ID_1", "ID_2",
"ID_3", "ID_4", "ID_5"),
class = "factor"
),
Open_comments = structure(
c(2L,
4L, 3L, 5L, 1L),
.Label = c(
"I could never get the pdf to download",
"I could never get the system to work",
"I didn’t get the help I needed on time",
"my questions went unanswered",
"staying motivated to get through the textbook",
"there wasn’t enough engagement in the discussion board"
),
class = "factor"
)
),
class = "data.frame",
row.names = c(NA,-5L)
)
What I am trying to do:
Search for an exact match keyword. The following working code has been provided by #Len Greski and #Ronak Shah from the previous thread (with huge thanks to both):
resultsList <- lapply(1:ncol(codes),function(x){
y <- stri_detect_regex(comments$Open_comments,paste(codes[[x]],collapse = "|"))
ifelse(y == TRUE,1,0)
})
results <- as.data.frame(do.call(cbind,resultsList))
colnames(results) <- colnames(codes)
mergedData <- cbind(comments,results)
mergedData
and
comments[names(codes)] <- lapply(codes, function(x)
+(grepl(paste0(na.omit(x), collapse = "|"), comments$Open_comments)))
Both work great but I have come across a snag and now need to match the keywords exactly. As per the example tables above, if I have a keyword "sy", the code will flag any comment with the word "system". I would modify either of the above pieces of code to flag the comment where only "sy" exact match is present.
Many thanks
I am creating a shiny app where I want the user to download data from the shiny app into one single excel file with multiple(more than one) datasets in the same sheet. I looked at the other similar questions but I am not able to get my code working with that help.
Datasets Used:
sample <- structure(list(type = structure(c(1L, 5L, 3L, 5L, 2L, 4L), .Label = c("add select multiple prompt using alphaOptions",
"add select multiple prompt using imageOptions", "add select one prompt using alphaOptions",
"add select one prompt using imageOptions", "add select one prompt using numOptions"
), class = "factor"), name = structure(c(4L, 5L, 3L, 6L, 1L,
2L), .Label = c("grid", "grid_two_columns", "quick_advance",
"select", "select1", "spinner"), class = "factor"), caption = structure(c(4L,
5L, 3L, 6L, 1L, 2L), .Label = c("grid widget", "grid with a maximum of two columns",
"quick advance select widget", "select multiple widget", "select one widget",
"spinner widget"), class = "factor"), hint = structure(c(4L,
6L, 1L, 3L, 2L, 5L), .Label = c("click a choice to select it and advance to the next question",
"click an image to select it (you must have the images on your sdcard to see them)",
"click the button to provide a response", "don't pick c and d together",
"regardless of screen size this widget will only show two columns of images",
"scroll down to see default selection"), class = "factor")), .Names = c("type",
"name", "caption", "hint"), class = "data.frame", row.names = c(NA,
-6L))
profile <- structure(list(Company.Name = structure(c(1L, 3L, 4L, 2L, 5L), .Label = c("Address",
"Assigned MB", "Contact Name", "Contact Phone", "Website"), class = "factor"),
ABC = structure(c(2L, 5L, 1L, 3L, 4L), .Label = c("(398) 657-8401",
"48,S St, Denver, CO, 80233", "Bob Harris, Active", "www.abc.com",
"John Gardner"), class = "factor")), .Names = c("Company.Name",
"ABC"), class = "data.frame", row.names = c(NA, -5L))
I have this same data as csv files.
Below is my code for excel with two sheets:
ui.R
shinyUI(pageWithSidebar(
headerPanel('Download'),
sidebarPanel(
downloadButton('downloadData', 'Download')
),
mainPanel(
)
))
server.R
sample <- read.csv("sample.csv")
profile <- read.csv("profile.csv")
shinyServer(function(input, output) {
output$downloadData <- downloadHandler(
filename = "test.xlsx",
content = function(file) {
write.xlsx2(profile, file, sheetName = "Sheet1")
write.xlsx2(sample, file, sheetName = "Sheet2", append = TRUE)
}
)
})
This is what I am trying for downloading both datasets in the same sheet.
shinyServer(function(input, output) {
output$downloadData <- downloadHandler(
filename = "test.xlsx",
content = function(file) {
write.xlsx2(profile, file, sheetName = "Sheet1")
write.xlsx2(sample, file, sheetName = "Sheet1", append = TRUE)
}
)
})
This is the error I get:
Error : java.lang.IllegalArgumentException: The workbook already contains a sheet of this name
Warning: Error in .jcall: java.lang.IllegalArgumentException: The workbook already contains a sheet of this name
Stack trace (innermost first):
I am expecting the profile and sample datasets to be one below the other in one sheet with some space between them something like in the image below:
I don't think append() works within a given sheet, but you can use the addDataFrame() function:
data <- data.frame(a = 1:3, b = 4:6, c = 7:9)
wb <- createWorkbook()
sheet <- createSheet(wb, sheetName="addDataFrame1")
addDataFrame(data, sheet, row.names = FALSE)
addDataFrame(data, sheet, startRow = nrow(data) + 3, , row.names = FALSE)
saveWorkbook(wb, file = "test.xlsx")
I am learning the use of the ifelse function from Zuur et al (2009) A Beginners guide to R. In one exercise, there is a data frame called Owls which contains data about about 27 nests and two night of observations.
structure(list(Nest = structure(c(1L, 1L, 1L, 1L), .Label = "AutavauxTV", class = "factor"),
FoodTreatment = structure(c(1L, 2L, 1L, 1L), .Label = c("Deprived",
"Satiated"), class = "factor"), SexParent = structure(c(1L,
1L, 1L, 1L), .Label = "Male", class = "factor"), ArrivalTime = c(22.25,
22.38, 22.53, 22.56), SiblingNegotiation = c(4L, 0L, 2L,
2L), BroodSize = c(5L, 5L, 5L, 5L), NegPerChick = c(0.8,
0, 0.4, 0.4)), .Names = c("Nest", "FoodTreatment", "SexParent",
"ArrivalTime", "SiblingNegotiation", "BroodSize", "NegPerChick"
), row.names = c(NA, 4L), class = "data.frame")
The two nights differed as to the feeding regime (satiated or deprived) and are indicated in the Foodregime variable. The task is to use ifelse and past functions that make a new categorical variable that defines observations from a single night at a particular nest.
In the solutions the following code is suggested:
Owls <- read.table(file = "Owls.txt", header = TRUE, dec = ".")
ifelse(Owls$FoodTreatment == "Satiated", Owls$NestNight <- paste(Owls$Nest, "1",sep = "_"), Owls$NestNight <- paste(Owls$Nest, "2",sep = "_"))
and apparently it creates a new variable with values the endings of which vary ("-1" or "-2")
however when I call the original dataframe, all "-1" endings in the NestNight variable disappears and are turned to "-2."
Why does this happen? Did the authors miss something from the code or it's me who is not getting it?
Many thanks
EDIT: Sorry, I wanted to give a reproducible example by copying my data using dput but it did not work. If you can let me know how I can correct it so that it appears properly, I'd be grateful too!
Solution
If you do the assignment outside the ifelse structure, it works:
Owls$NestNight <- ifelse(Owls$FoodTreatment == "Satiated",
paste(Owls$Nest, "1",sep = ""),
paste(Owls$Nest, "2",sep = ""))
Explanation
What happens in your case is simply if you would execute the following two lines:
Owls$NestNight <- paste(Owls$Nest, "1",sep = "")
Owls$NestNight <- paste(Owls$Nest, "2",sep = "")
You first assign paste(Owls$Nest, "1",sep = "") to Owls$NestNight and then you reassign paste(Owls$Nest, "2",sep = "") to it. The ifelse is not affected by this, but you don't assign it's result to any variable.
Maybe it is more clear if you test this simple code:
c(a <- 1:5, a <- 6:10) #c is your ifelse, a is your Owls$NestNight
a #[1] 6 7 8 9 10
I'm using a markdown document to write text from R. At some point, I want to add a table that I calculated using the table() function. But it's not working.
library(stargazer)
x=structure(c(2075L, 49L), .Dim = 2L, .Dimnames = structure(list(
c("0", "1")), .Names = ""), class = "table")
stargazer(x)
Error in objects[[i]]$zelig.call :
$ operator is invalid for atomic vectors
What's going on and how do I fix it?
How about something like this?
stargazer(as.data.frame(x),
type = 'text',
summary = FALSE,
rownames = FALSE)
I have a dataframe (df):
df = structure(list(site = c(989L, 989L, 990L, 990L), filename = structure(1:4, .Label = c("989_1.csv", "989_5.csv", "990_2.csv", "990_9.csv"), class = "factor"), sourceA = structure(1:4, .Label = c("FolderA/989/989_1.csv", "FolderA/989/989_5.csv", "FolderA/990/990_2.csv", "FolderA/990/990_9.csv" ), class = "factor"), destination = structure(c(3L, 1L, 4L, 2L ), .Label = c("FolderB/989/989_5.csv", "FolderB/990/990_9.csv", "FolderC/989/989_1.csv", "FolderD/990/990_2.csv"), class = "factor")), .Names = c("site",
"filename", "sourceA", "destination"), class = "data.frame", row.names = c(NA,
-4L))
'FolderA' has a series of subfolders containing a number of files. I wish to copy subsets of these files to other folders (shown here as 'destination'). Note: 1) the destination varies from file to file, and 2) the primary folders (FolderB,FolderC,and FolderD) exist, but the subfolders do not (e.g., FolderC/989/).
I believe my solution may involve the file.copy() function, but I am having no success.
file.copy(df$sourceA, df$destination)
results in
Error in file.exists(from) : invalid 'file' argument
Ideas?
Edit: using column name 'source' was causing problems - changed to 'sourceA'.
I think it's because the class of df$sourceA is 'factor' and copy.file wants a 'character'.