Firebase Request Timeout Feature [duplicate] - firebase

Question

I'm trying to create a cloud function for firebase that remove a user depending on the delay value and insert back the after the number of delay.
exports.delayqueue = functions.database.ref('/queues/{queueid}/members/{memberid}').onWrite(event => {
var members = event.data.ref.parent;
var user = event.data;
var queueid = members.parent;
var userid = event.params.memberid;
var delayfor = user.child('delay').val();
var name = user.child('name').val();
if(delayfor != 0){
members.child(event.params.memberid).remove();
join(userid,queueid,delayfor,name);
return;
}else{
return;
}
});
function join(userid,queueid,delayfor,name){
setTimeout(function(){
var ref = db.ref("queues/queueid/members/userid");
ref.set({
name: name,
timestamp: Date.now(),
delay : 0
});
}, delayfor*1000);
};
But it's not working can someone help?

Answer 1

You'll need to wrap your setTimeout in a Promise:
exports.delayqueue = functions.database.ref('/queues/{queueid}/members/{memberid}').onWrite(event => {
var members = event.data.ref.parent;
var user = event.data;
var queueid = members.parent;
var userid = event.params.memberid;
var delayfor = user.child('delay').val();
var name = user.child('name').val();
if (delayfor !== 0){
members.child(event.params.memberid).remove();
return join(userid,queueid,delayfor,name);
} else {
return;
}
});
function join(userid,queueid,delayfor,name){
return new Promise((resolve, reject) => {
setTimeout(function(){
var ref = db.ref("queues/queueid/members/userid");
ref.set({
name: name,
timestamp: Date.now(),
delay : 0
}).then(resolve, reject);
}, delayfor*1000);
});
};
Note that the time spent waiting for setTimeout is billed as function execution time and is also subject to the function timeout. If you're only delaying a few seconds, that might be okay, but if the delay is expected to be minutes this solution isn't going to be viable or cost-effective.