i have a form with some field and i want user edit only some field and the other field must be only visible .
In my controller i have the form
$element = $this->getDoctrine()->getRepository('AppBundle:Element')->find($id_element);
$form = $this->createForm(ElementType::class, $element, array('user' => $user));
code here`$form->handleRequest($request);
Now in my twig file
{{ form_start(form) }}
{{ form_widget(form.element,{ 'attr':{'disabled':'disabled'}}) }}
In this way when i click submit button say not focusable field so i add
{{ form_widget(form.element,{ 'attr':{'disabled':'disabled'}}) }}
but when i save the field element in database become null
How i can do it ??
Use readonly attribute for it
{{ form_widget(form.element,{ 'attr':{'readonly':'1'}}) }}
Values of disabled controls are not submitted with a form.
https://www.w3.org/TR/PR-html40-971107/interact/forms.html#h-17.7
Related
want to display a form in a modal in the header. In order to make the form work I call the controller Homecontroller.
I called the controller with render controller in the branch but I got a blank page.
Thanks for your help.
header.html.Twig
<h1 class="fw-bold"></h1>
<p class="lead fw-bold"></p>
{{include ('fragments/modal_form.html.twig') }}
</main>
</div>
</div>
modal_form.html.twig
{{ render(controller(
'App\\Controller\\HomeController::index',{'form' : form.createForm()} )) }}
</div>
Controller :
* #Route("/", name="home")
*/
public function index(PostsRepository $postsRepository,TagRepository $tagRepository, Request $request ):Response
{
$listTag = $tagRepository->findAll();
$listPost = $postsRepository->findByPostPHp('php');
$posts = $postsRepository->findByExampleField($value = 6);
$partage = New Posts();
$form = $this->createForm(PartagePostType::class);
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
$partage = $form->getData();
$this->entityManager->persist($partage);
$this->entityManager->flush();
$this->addFlash('success', 'Votre post a bien été partagé');
}
return $this->render('home/index.html.twig', [
'posts' => $posts,
'tag' => $listTag,
'listPost' => $listPost,
'form' => $form->createView(),
]);
}
I dont' really get how you are trying to render you form but it doesn't work that way, in your modal_form.html.twig you should use the {{ form_start() }} and {{ form_end() }} twig helpers. They take in parameters the created view of the form, i.e, the variable "form" in your case (created in your render with the createView() method).
It should look like that:
{{ form_start(form}}
{{ form_row(form.field) }}
<input type="submit" value="submit">
{{ form_end(form) }}
"field" is whatever name you defined in your FormType. Notice how I added raw HTML for the submit button, it is suggested by Symfony you add the send button that way, even though you can add it in your FormType.
You can learn more about form rendering here : How to Customize Form Rendering
And forms in general there : Forms
Last thing, if you want to use multiple forms with this modal, don't forget to change the name of the variable (also don't forget to add this variable in your controller when you render a template with a form in it, obviously)
I am getting a url variable via GET on my controller and want to set it as value of my textarea. Here's my textarea line:
{{ form.myTextArea is defined ? form_row(form.myTextArea) }}
{{ form_row(form.myTextArea, {'value': 'your text'}) }}
I have a show page and I want to add a custom value.
I have tried doing what I did in other actions which is to add an array to the
third parameter with the data key like so:
protected function configureShowFields(ShowMapper $showMapper)
{
$showMapper
->add('name')
->add('dateEnd')
->add('example', null,
array('data' => 'example value')
)
;
}
In the configureListFields action, this works. I have injected custom values with the data attribute.
But still I am not able to access key example in the show.html.twig file.
It gives me this error
Variable "example" does not exist.
What should I do to access this custom variable in the twig file ?
Try
{{ elements.elements.example.options.data }}
in your twig template
I used this solution. In the configureShowFields() method of an Admin class:
$showMapper
->with('Tab Name')
->add(
'any_name',
null,
[
'template' => 'Admin/Custom/any_name_show_template.html.twig',
'customData' => $this->someRepository->getSomeEntityBy($field),
'anotherCustomData' => $this->someService->getSomeDataBy($value),
]
)
;
In the custom template, you can access custom data by field_description.options.<customFieldName>, so for provided example data accessors would be {{ field_description.options.customData }} and {{ field_description.options.anotherCustomData }}
For the shorter field name in the Twig template, you can do like this:
{% set customData = field_description.options.customData %}
and access the custom data like {{ customData }}
Hope this helps and saves time.
I have a parent entity called Publisher and a child entity called User with a ManyToMany relation.
Inside the publisher form, I want to create/edit also the first user, which I achieve like this:
$builder
->add('title')
->add('users', 'collection', array(
'type' => new UserType(),
'allow_add' => true,
))
and in my twig template, I do
{{ form_row(edit_form.users.0.firstname) }}
{{ form_row(edit_form.users.0.lastname) }}
{{ form_row(edit_form.users.0.email) }}
This obviously only works as long as there is just one user assigned to the publisher, because otherwise symfony tries to validate the other users as well, whose data is missing.
Can someone give me a hint how to edit only the first user item in the collection from the publisher form?
You can set the field users "rendered" after having displayed the firt user:
{{ form_row(edit_form.users.0.firstname) }}
{{ form_row(edit_form.users.0.lastname) }}
{{ form_row(edit_form.users.0.email) }}
{% do edit_form.users.setRendered %}
With setRendered, Symfony2 won't try to validate the next users.
I solved the problem using Cerad's solution by introducing a getter and setter for the first user.
public function setFirstUser($user)
{
$this->users[0] = $user;
return $this;
}
public function getFirstUser()
{
return $this->users[0];
}
and in the form doing this
$builder
->add('title')
->add('firstUser', new UserType())
and calling the fields of the firstUser in the twig template The setRendered line just supresses other properties of the user object.
{{ form_row(edit_form.firstUser.firstname) }}
{{ form_row(edit_form.firstUser.lastname) }}
{{ form_row(edit_form.firstUser.email) }}
{% do edit_form.firstUser.setRendered %}
EDIT: because of Cerads feedback about the non-deterministic ordering of SQL rows I chose to create a real property "adminUser", which is a OneToOne relation to the first user attached to the entity.
I am new to symfony. I have created a registration form using the code:
$user = new Register();
$form = $this->createForm(new RegisterType(), $user);
In the RegisterType class i have 5 fields (for example).I store the values in database when the user registers with the system. Now I display the EDIT page using following code:
$user = $em->getRepository('MysiteUserBundle:Register')->find($id);
$form = $this->createForm(new RegisterType(), $user);
//edit.html.twig code
<form action="{{ path('MysiteUserBundle_register_update',{'id':user.id}) }}" method="post" {{ form_enctype(form) }} class="register">
{{ form_errors(form) }}
{{ form_row(form.firstname) }}
{{ form_row(form.lastname) }}
{{ form_row(form.username) }}
<p>
<input type="submit" value="Submit">
</p>
</form>
The problem with the EDIT code however is that it displays me all of the fields mentioned in RegisterType class.Is it possible to display only some fields. If yes how can this be achieved. Any help will be appreciated
It doesn't make sense to use the registration form type to edit a user, because registration happens once per user. Instead you could create another form type with only those fields you need when editing a user. One can extend the other to avoid duplication.
You could also:
Keep just one form type but add some fields conditionally — that is, only when the entity is new. You can get your entity in the form type as $options['data'] and check if its ID is not null or whatever.
Use form events.