How do I make UpdateOrInsert in Kotlin collections - collections

I have a list of items, and one of item copies is changed by user, how do I find it in my collection by Id and update, or if it's not found I'd like to add the item? my best guess is, but it requires ugly indexOf(v)
fun updateOrInsert(note : UserNote) {
val list = notes.value!!
val v = list.firstOrNull{(Id) -> Id ==note.Id}
if (v==null) {
list.add(note)
} else {
val i = list.indexOf(v)
list[i] = note
}
notes.value = list
}

Use indexOfFirst to find the index of the first element with the given ID. If -1, add the item to the list, otherwise, change the value at the found index.

Related

How to add any symbols after prefix_?

is there any solution? e.g. I have data in Map with key favorites_ prefix and values _suffix (for example: favorites_jeans, favorites_suit,...,). I want to by dint of loop get that values and set in List, because of it I must give keys of map, right?
I want to know how can I get values of myMap["favorites_*"] (* - after the favorites_ any symbols).
List<String> favoritesStrings = ['favorite_name','favorite_jeans',];
Map<String,dynamic> myMap = {
favoritesStrings[0]:'0',
favoritesStrings[1]:'1',
'someKey':'2',
'anotherKey':'3',
};
favoritesStrings.forEach((favorite)=>print(myMap[favorite]));//prints 0 1
As per what I understood, you want to fetch value from map using "favorites_" + a dynamic value from list as key.
You just have to use String templates and use $ to insert suffix variable to build key dynamically:
List<String> suffixList = ["jeans", "suit", "shirt"];
for(String suffix in suffixList) {
var item = myMap["favorites_$suffix"];
// Do something with item
}
Hope it helps

How to add new item in specific index?

I new in kotlin , i want to update an item in lists.
I use this code:
var index: Int
for (record in recordList)
if (record.id == updatedHeader?.id) {
index = recordList.indexOf(record)
recordList.add(index, updatedHeader)
}
but it cant do this, because of ConcurrentModificationException
Assuming that recordList is a MutableList and val (so, you'd like to modify the records in place), you can use forEachIndexed to find the records you care about and replace them.
This did not cause a ConcurrentModificationException:
recordList.forEachIndexed { index, record ->
if(record.id == updatedHeader?.id) recordList[index] = updatedHeader
}
On the other hand, if you redefine recordList as a non-mutable list, and a var, you could rewrite the entire list using map:
recordList = recordList.map { if(it.id == updatedHeader?.id) updatedHeader else it }
Of course, you could call .toMutableList() on the end of that if you wanted to turn your List into a MutableList.
If there's a single record with the given id in the list, you can find its index and add the header at that index:
val index = recordList.indexOfFirst { it.id == updatedHeader.id }
if (index >= 0)
recordList.add(index, updatedHeader)
If there are multiple records with the given id and you want to prepend header before each of them, you can use get listIterator and use its methods to modify the list during the iteration without getting ConcurrentModificationException:
val iterator = recordList.listIterator()
for (record in iterator) {
if (record.id == updatedHeader.id) {
iterator.previous() // move to the position before the record
iterator.add(updatedHeader) // prepend header
iterator.next() // move next, back to the record
}
}

kotlin adding pair to map when value is a list

I know this is basic but can I do this in a shorter way:
val ss = mutableMapOf<String, MutableList<String>>()
if(ss["new_key"] != null){
ss["new_key"]!!.add("NEW")
}
else{
ss["new_key"] = mutableListOf("OLD")
}
This basically checks if the key exists in the map
if it does an element is appended to the list(value) otherwise a new key-value pair is created
Can't I create a new key on the go? like this:
ss["new_key"].add("OLD")
ss["new_key"].add("NEW")
You have at least 2 options:
use computeIfAbsent:
ss.computeIfAbsent("new_key") { mutableListOf() } += "NEW"
use getOrPut:
ss.getOrPut("new_key", ::mutableListOf) += "NEW"

How to pre-select an option in a dropdown knockout js

I've looked at this other question, but can't get my select box to work correctly:
Binding initial/default value of dropdown (select) list
I've got the following Game object:
function Game(visitingTeamDetails, homeTeamDetails, game) {
if (arguments.length > 0) {
this.VisitingTeamDetails = visitingTeamDetails;
this.HomeTeamDetails = homeTeamDetails;
this.GameId = ko.observable(game.GameId);
this.HomeTeamName = ko.observable(game.HomeTeamName);
this.VisitingTeamName = ko.observable(game.VisitingTeamName);
this.SportTypeName = ko.observable(game.SportTypeName);
this.HomeAccountName = ko.observable(game.HomeAccountName);
this.VisitingAccountName = ko.observable(game.VisitingAccountName);
this.GameDateString = ko.observable(game.GameDateString);
this.GameTimeString = ko.observable(game.GameTimeString);
this.AvailableSportTypes = ko.observableArray(game.Sports);
this.sportTypeFunction = function () {
for (sportType in this.AvailableSportTypes()) {
if (this.AvailableSportTypes()[sportType].Name == this.SportTypeName()) {
return this.AvailableSportTypes()[sportType];
}
}
return null;
};
this.SportType = ko.observable(game.SportType);
}
}
SportType is an object with Name and SportTypeId.
I have the following template:
<td rowspan="3"><select data-bind="options: AvailableSportTypes, value: SportType, optionsText:'Name', optionsCaption: 'Choose...'" class="sportType"></select></td>
AvailableSportTypes is a list of SportType.
The list is coming in with the names of the SportTypes in the drop down list, but I can't make the initial selection be SportType. I wrote sportTypeFunction to show myself that the data was coming in correctly, and it would select the correct value, but changing my selection in the drop down would not update SportType.
I'm sure I'm doing something wrong. Anyone see it?
Thanks
When game.SportType gets passed in, it needs to be a reference to the an item in the game.AvailableSportTypes and not just an object that looks the same.
Basically two objects are not equal unless they are actually a reference to the same object.
var a = { name: "test" },
b = { name: "test" };
alert(a === b); //false
So, you would need to call your function to locate the correct object in the array and set it as the value of your observable.
Not that it is way better, but in KO 1.3 you can extend .fn of observables, observableArrays, and dependentObservables to add additional functionality.
Here is a sample: http://jsfiddle.net/rniemeyer/ZP79w

Reflection on a Scala case class

I'm trying to write a trait (in Scala 2.8) that can be mixed in to a case class, allowing its fields to be inspected at runtime, for a particular debugging purpose. I want to get them back in the order that they were declared in the source file, and I'd like to omit any other fields inside the case class. For example:
trait CaseClassReflector extends Product {
def getFields: List[(String, Any)] = {
var fieldValueToName: Map[Any, String] = Map()
for (field <- getClass.getDeclaredFields) {
field.setAccessible(true)
fieldValueToName += (field.get(this) -> field.getName)
}
productIterator.toList map { value => fieldValueToName(value) -> value }
}
}
case class Colour(red: Int, green: Int, blue: Int) extends CaseClassReflector {
val other: Int = 42
}
scala> val c = Colour(234, 123, 23)
c: Colour = Colour(234,123,23)
scala> val fields = c.getFields
fields: List[(String, Any)] = List((red,234), (green,123), (blue,23))
The above implementation is clearly flawed because it guesses the relationship between a field's position in the Product and its name by equality of the value on those field, so that the following, say, will not work:
Colour(0, 0, 0).getFields
Is there any way this can be implemented?
Look in trunk and you'll find this. Listen to the comment, this is not supported: but since I also needed those names...
/** private[scala] so nobody gets the idea this is a supported interface.
*/
private[scala] def caseParamNames(path: String): Option[List[String]] = {
val (outer, inner) = (path indexOf '$') match {
case -1 => (path, "")
case x => (path take x, path drop (x + 1))
}
for {
clazz <- getSystemLoader.tryToLoadClass[AnyRef](outer)
ssig <- ScalaSigParser.parse(clazz)
}
yield {
val f: PartialFunction[Symbol, List[String]] =
if (inner.isEmpty) {
case x: MethodSymbol if x.isCaseAccessor && (x.name endsWith " ") => List(x.name dropRight 1)
}
else {
case x: ClassSymbol if x.name == inner =>
val xs = x.children filter (child => child.isCaseAccessor && (child.name endsWith " "))
xs.toList map (_.name dropRight 1)
}
(ssig.symbols partialMap f).flatten toList
}
}
Here's a short and working version, based on the example above
trait CaseClassReflector extends Product {
def getFields = getClass.getDeclaredFields.map(field => {
field setAccessible true
field.getName -> field.get(this)
})
}
In every example I've seen the fields are in reverse order: the last item in the getFields array is the first one listed in the case class. If you use case classes "nicely", then you should just be able to map productElement(n) onto getDeclaredFields()( getDeclaredFields.length-n-1).
But this is rather dangerous, as I don't know of anything in the spec that insists that it must be that way, and if you override a val in the case class, it won't even appear in getDeclaredFields (it'll appear in the fields of that superclass).
You might change your code to assume things are this way, but check that the getter method with that name and the productIterator return the same value and throw an exception if they don't (which means that you don't actually know what corresponds to what).
You can also use the ProductCompletion from the interpreter package to get to attribute names and values of case classes:
import tools.nsc.interpreter.ProductCompletion
// get attribute names
new ProductCompletion(Colour(1, 2, 3)).caseNames
// returns: List(red, green, blue)
// get attribute values
new ProductCompletion(Colour(1, 2, 3)).caseFields
Edit: hints by roland and virtualeyes
It is necessary to include the scalap library which is part of the scala-lang collection.
Thanks for your hints, roland and virtualeyes.

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