can you tell me how I can best calculate C.04 (which is a hexadecimal number)* 16^2 (decimal) in my head. I first converted the hexadecimal number to decimal and then multiplied the result by the 16^2, but that should be faster because the 16 implies hexadecimal.
Thanks :)
How can I know what these bunch of hex code means?
02 00 A0 E3 1E FF 2F E1
Any convertor of these codes to decimal code like 1,2,3 etc or vice versa like deciaml code to this type of hex code?
Thanks
This is my first response in stack overflow. So here goes...
What Hex Code (a.k.a. hexadecimal) represents purely depends on its context, or what does it mean to the program or machine. It could be a string, machine code (assembly language), flags, pointers to memory, data, part of an image or whatever. And this is dependent on the processor where this code is located also.
Each 2-digit hex code is a byte and represents decimal number (0-255 or 00-FF), half of a byte or 1 digit hex code is called a nibble.
Converting Hex Code to decimal is trivial. Convert from decimal to hex, not as trivial.
There are many calculators that have this functionality built in.
0-9 => 0 – 9, A=10, B=11, C=12, D=13, E=14, F=15.
Now, if you want to convert a 2 digit number like 12 hex (i.e. 0x12 or 12h ). Here is the formula.
(16 x 1) + (1 x 2) = 18 (decimal)
A four-digit hexadecimal 4A3E =>
(4096 x 4) + (256 x 10) + (16 x 3) + (1 x 14) = 19006 (decimal)
An integer in C# is 4 bytes, so your example hex code could also represent 2 integers in C#. Or it could be simply 1 number in C# called a “long” which is 8 bytes and could represent a number between:
0 to 18,446,744,073,709,551,615 unsigned long OR
-9,223,372,036,854,775,808 to 9,223,372,036,854,775,807 signed long
Also something to note hex code also represent characters called ASCII (pronounced a·skee) This is an internal mapping within the microprocessor and could be different. 00 is not mapped so it typically means the end of the string.
Hex codes like that could represent a binary number. You could paste "0200A0E31EFF2FE1" into a converter like this to find out that the decimal representation of that number is "144292085413916641", for example.
But, from the way that your hex codes are grouped, it appears that you're looking at binary data, rather than a single integer that's represented in hexadecimal. When hex codes are grouped in pairs, each group of two characters represents one byte. https://en.wikipedia.org/wiki/Hexadecimal#Written_representation
Assume this number 173250103518582539668252657343418508842, if I wanted to convert it to a hexadecimal number such that a 10 = F, 11 = E, etc. where are the breaks/how does that work?
I've done a bit of research online and I can't seem to find the answer. It's a really low-level question, I know.
6 characters in there's a 10, would that be flipped to an F or would that get missed because whatever triggers the flip in the int -> string hexadecimal conversion happens another way?
Hexadecimal is an encoding used to express binary data in base-16 where the ascending sequence is 0-9a-f (upper or lower case a-f), once character per 4-bits (4-bits has 16 possible values). Thus 2 hex characters per byte.
binary bits (msb on left) and hexadecimal:
0000 0
0001 1
0010 2
0011 3
...
1001 9
1010 a
...
1111 f
To say "10 = F, 11 = E" is not hexadecimal.
To encode the decimal number 173250103518582539668252657343418508842 convert it is a Big Integer and then hexadecimal encode the underlying bytes to hexadecimal.
or
To encode the ASCI string "173250103518582539668252657343418508842" to hexadecimal convert each letter to the underlying ASCII binary code and then encode that into hexadecimal: "313733323530313033353138353832353339363638323532363537333433343138353038383432".
See Hexadecimal and ASCII.
Aside: My first day as a programmer I had to know hex, binary and ASCII encoding, funny how things change.
I would like to covert a decimal number (between 0 to 65536) to a hex number. Can I do it in Arduino script? Thanks
You can use sprintf to format a number as hex, e.g. something like
//lets be sure our integer is in desired range
myinteger=min(max(myinteger, 0), 65535);
//buffer big enough for 4 hex digits + terminating null
char hexbuffer[5];
sprintf(hexbuffer, "%04x", myinteger);
I have known till date that %x prints in hexadecimals
Now, when I write printf("%x", -1<<4),the output is fffffff0
But when I write printf("%x", 5<<2), the output is 14
Why does the second output a decimal number?
14 is part of hexadecimal characters set, it's just the result of :
floor(20/16) and 20%16