Greetings I am getting an error of
Error in if (nrow(pair) == 0) { :argument is of length zero
I have checked the other answers but do not seem to work on a variable like mine. Please check code below, please assist if you can.
pair<-NULL
if(exists("p.doa.ym")) pair <- rbind(pair, p.doa.ym[,1:2])
if(exists("p.doa.yd")) pair <- rbind(pair, p.doa.yd[,1:2])
if(nrow(pair) == 0) {
print("THERE ARE NO MATCHES FOR TODAY. STOP HERE")
quit()
}
Since you set pair=NULL and then it might happen that pair stays null if those two if statements are not true, you either need to check if pair is null first, or you could set pair to an empty data frame, or something else.
One option:
if (!is.null(pair)) {
if (nrow(pair)==0) {
# your code
}
}
Another option:
pair=data.frame()
# your code
I am currently trying to run some code (if you need to know the purpose to help me, ask me, but I'm trying to keep this question short). This is the code:
par<-c(a=.5,b=rep(1.3,4))
est<-rep(TRUE,length(par))
ncat<-5
Theta<-matrix(c(-6,-5.8,-5.6,-5.4,-5.2,-5,-4.8,-4.6,-4.4,-4.2,-4,-3.8,-3.6,-3.4,-3.2,-3,-2.8,-2.6,-2.4,-2.2,-2,-1.8,-1.6,-1.4,-1.2,-1,-0.8,-0.6,-0.4,-0.2,0,0.2,0.4,0.6,0.8,1,1.2,1.4,1.6,1.8,2,2.2,2.4,2.6,2.8,3,3.2,3.4,3.6,3.8,4,4.2,4.4,4.6,4.8,5,5.2,5.4,5.6,5.8,6))
p.grm<-function(par,Theta,ncat){
a<-par[1]
b<-par[2:length(par)]
z<-matrix(0,nrow(Theta),ncat)
y<-matrix(0,nrow(Theta),ncat)
y[,1]<-1
for(i in 1:ncat-1){
y[,i+1]<-(exp(a*(Theta-b[i])))/(1+exp(a*(Theta-b[i])))
}
for(i in 1:ncat-1){
z[,i]<-y[,i]-y[,i+1]
}
z[,ncat]<-y[,ncat]
z
}
However, when I try to run the code:
p.grm(par=par,Theta=Theta,ncat=ncat)
I get the following error:
Error: dims [product 61] do not match the length of object [0]
Traceback tells me that the error is occurring in the first for loop in the line:
y[,i+1]<-(exp(a*(Theta-b[i])))/(1+exp(a*(Theta-b[i])))
Could someone point me to what I'm doing wrong? When I try to run this code step by step outside of the custom p.grm function, everything seems to work fine.
It is a common mistake. When you write the for loop and you want it from 1 to ncat -1 remember to write it as for (i in 1:(ncat-1)) instead of for(i in 1:ncat-1) they are completly different.
You may also add to the function something to return return(z). Here it is the corrected code:
par<-c(a=.5,b=rep(1.3,4))
est<-rep(TRUE,length(par))
ncat<-5
Theta<-matrix(c(-6,-5.8,-5.6,-5.4,-5.2,-5,-4.8,-4.6,-4.4,-4.2,-4,-3.8,-3.6,-3.4,-3.2,-3,-2.8,-2.6,-2.4,-2.2,-2,-1.8,-1.6,-1.4,-1.2,-1,-0.8,-0.6,-0.4,-0.2,0,0.2,0.4,0.6,0.8,1,1.2,1.4,1.6,1.8,2,2.2,2.4,2.6,2.8,3,3.2,3.4,3.6,3.8,4,4.2,4.4,4.6,4.8,5,5.2,5.4,5.6,5.8,6))
p.grm<-function(par,Theta,ncat){
a<-par[1]
b<-par[2:length(par)]
z<-matrix(0,nrow(Theta),ncat)
y<-matrix(0,nrow(Theta),ncat)
y[,1]<-1
for(i in 1:(ncat-1)){
y[,i+1]<-(exp(a*(Theta-b[i])))/(1+exp(a*(Theta-b[i])))
}
for(i in 1:(ncat-1)){
z[,i]<-y[,i]-y[,i+1]
}
z[,ncat]<-y[,ncat]
return(z)
}
p.grm(par=par,Theta=Theta,ncat=ncat)
I am trying to create a function which will look at two vectors of character labels, and print the appropriate label based on an If statement. I am running into an issue when one of the vectors is populated by NA.
I'll truncate my function:
eventTypepriority=function(a,b) {
if(is.na(a)) {print(b)}
if(is.na(b)) {print(a)}
if(a=="BW"& b=="BW",) {print("BW")}
if(a=="?BW"& b=="BW") {print("?BW")}
...#and so on
}
Some data:
a=c("Pm", "BW", "?BW")
b=c("PmDP","?BW",NA)
c=mapply(eventTypepriority, a,b, USE.NAMES = TRUE)
The function works fine for the first two, selecting the label I've designated in my if statements. However, when it gets to the third pair I receive this error:
Error in if (a == "?BW" & b == "BW") { :
missing value where TRUE/FALSE needed
I'm guessing this is because at that place, b=NA, and this is the first if statement, outside of the 'is.na' statements, that need it to ignore missing values.
Is there a way to handle this? I'd really rather not add conditional statements for every label and NA. I've also tried:
-is.null (same error message)
-Regular Expressions:
if(a==grepl([:print:]) & b==NA) {print(a)}
In various formats, including if(a==grepl(:print:)... No avail. I receive an 'Error: unexpected '[' or whatever character R didn't like first to tell me this is wrong.
All comments and thoughts would be appreciated. ^_^
if all your if conditions are exclusives, just call return() to avoid checking other conditions when one is met:
eventTypepriority=function(a,b) {
if(is.na(a)) {print(b);return()}
if(is.na(b)) {print(a);return()}
if(a=="BW"& b=="BW",) {print("BW");return()}
if(a=="?BW"& b=="BW") {print("?BW");return()}
...#and so on
}
You need to use if .. else statements instead of simply if; otherwise, your function will evaluate the 3rd and 4th lines even when one of the values is n/a.
Given you mapply statement, I also assume you want the function to output the corresponding label, not just print it?
In that case
eventTypepriority<-function(a,b) {
if(is.na(a)) b
else if(is.na(b)) a
else if(a=="BW"& b=="BW") "BW"
else if(a=="?BW"& b=="BW") "?BW"
else "..."
}
a=c("Pm", "BW", "?BW")
b=c("PmDP","?BW",NA)
c=mapply(eventTypepriority, a,b, USE.NAMES = T)
c
returns
Pm BW ?BW
"..." "..." "?BW"
If you actually want to just print the label and have your function return something else, you should be able to figure it out from here.
I am trying to delete all values in a list that have the tag ".dsw". My list is a list of files using the function list.files. This is my code:
for (file in GRef) {
if (strsplit(file, "[.]")[[1]][3] == "dsw") {
#GRef=GRef[-file]
for(n in 1:length(GRef)){
if (GRef[n] == file){
GRef=GRef[-n]
}
}
}
}
Where GRef is the list of file names. I get the error listed above, but I dont understand why. I have looked at this post: Error .. missing value where TRUE/FALSE needed, but I dont think it is the same thing.
You shouldn't attempt to to modify a vector while you are looping over it. The problem is your are removing items you are then trying to extract later which is causing the missing values. It's better to identify all the items you want remove first, then remove them. For example
GRef <- c("a.file.dsw", "b.file.txt", "c.file.gif", "d.file.dsw")
exts <- sapply(strsplit(GRef, "[.]"), `[`, 3)
GRef <- GRef[exts!="dsw"]
I got warnings when running this code.
For example, when I put
tm1<- summary(tmfit)[c(4,8,9)],
I can get the result, but I need to run this code for each $i$.
Why do I get this error?
Is there any way to do this instead of via a for loop?
Specifically, I have many regressants ($y$) with the same two regressors ($x$'s).
How I can get these results of regression analysis(to make some comparisons)?
dreg=read.csv("dayreg.csv")
fundr=read.csv("fundreturnday.csv")
num=ncol(fundr)
exr=dreg[,2]
tm=dreg[,4]
for(i in 2:num)
{
tmfit=lm(fundr[,i]~exr+tm)
tm1[i]<- summary(tmfit)[c(4,8,9)]
}
Any help is highly appreciated
Try storing your result into a list instead of a vector.
dreg=read.csv("dayreg.csv")
fundr=read.csv("fundreturnday.csv")
num=ncol(fundr)
exr=dreg[,2]
tm = list()
for(i in 2:num)
{
tmfit=lm(fundr[,i]~exr+tm)
tm1[[i]]<- summary(tmfit)[c(4,8,9)]
}
You can look at an element in the list like so
tm1[[2]]