I have the following sass variable:
$color-config:( "white": #FFF,
"black": #303133
);
and i would like to access the 'black' value (#303133) without make a loop. Something like that:
body
color: $color-config("black")
(i know, its completely wrong, its just to explain what i want)
You can use SASS's maps to store values inside variables:
$color-config:(
white: #FFF,
black: #303133
);
Then use map-get() to access it (see here):
content: map-get($color-config, white); # will return #FFF
In other words, don't use double quotes " around your variable name.
$color-config:(
'white': #FFF, //quotes are important
'black': #303133
);
#function colors($value) {
#return map-get($color-config, $value)
}
.white-font {
color: colors('white')
}
Related
I've run into an issue where it's easier for me to define two base maps that can be flicked between using a single variable (Seems easier for base, light/dark themes)
https://codepen.io/anon/pen/bLwNaW
I'm trying to set $theme-being-used, check it in a If/Else and use a particular map based on that result.
This makes it simple for me to come in and set $theme-being-used to dark and change all of the base variables.
I've tried:
#if (#{$theme-being-used} == light) {
#if ($theme-being-used == light) {
#if (#{$theme-being-used} == "light") {, etc..
Does anyone know if this can be done? It's not a big deal either way, just saves a little bit of time when throwing up templated sites.
Before I was achieving this by simply comment/uncommenting code, i.e.
$palette: (
// Light
ui: (
primary: #FFFFFF,
secondary: #EEEEEE,
alternate: #DDDDDD
),
// Dark - COMMENTED when I want to use light variables
/*ui: (
primary: #333,
secondary: #444,
alternate: #555
),*/
);
This is fine and pretty quick, but it'd just be easier to set it in one place and not have to do this.
Thanks.
Place $theme-being-used check to _palette function. This function take only one parameter — color name. And contains all color select logic inside itself.
Sassmeister demo.
$theme-being-used: light;
$palette: (
dark: (
primary: red,
secondary: orange,
tertiary: blue
),
light: (
primary: green,
secondary: black,
tertiary: yellow
)
);
#function _palette($color-name, $theme-name: $theme-being-used) {
// Select one of available themes
// Here there may be more complex logic in choosing themes
$theme: map-get($palette, #{$theme-name});
// Get the color from theme
#return map-get($theme, #{$color-name});
}
.s-o {
background: _palette(primary);
&:hover {
background: _palette(secondary);
}
}
How can I make the following code more DRY?
I have setup bunch of variables below that are later referenced in a $colors map. Currently I have to edit the code in two places to add a new color to the system. And these variable number will grow in the future considerably.
https://codepen.io/umbriel/pen/LLvPPK
Here is the whole current code section
$red : #cc0000;
$blue : #1e8cea;
$green : #27a249;
$teal : #41bdbb;
$purple : #5c369e;
$-yellow : #ecd340;
#function color-palette($color) {
$map: (
light: scale-color($color, $lightness: 88%),
lighter: adjust-hue(scale-color($color, $lightness: 48%, $saturation: 32%), -8%),
base: $color,
darker: adjust-hue(scale-color($color, $lightness: -36%), 0%),
dark: scale-color($color, $lightness: -72%, $saturation: 100%)
);
#return $map;
}
$colors: (
red: color-palette($red),
blue: color-palette($blue),
green: color-palette($green),
teal: color-palette($teal),
purple: color-palette($purple),
yellow: color-palette($yellow)
);
// retrieve color from map ie. `color(primary, base)`
#function color($color-name, $color-variant:null) {
// color variant is optional
#if ($color-variant != null) {
// map inception
#return map-get(map-get($colors, $color-name), $color-variant);
} #else {
#return map-get(map-get($colors, $color-name), base);
}
}
I have tried looping the map inside the $colors map which didn't work.
$colorvars : (
red : #cc0000,
blue : #1e8cea,
green : #27a249,
teal : #41bdbb,
purple : #5c369e,
yellow : #ecd340
)
$colors: (
#each $key, $value in $colorsvars {
$key : color-palette($value)
}
)
DRY adding colors (and its variations):
There's an excellent article that describe how to do it better than I could ever explain. Basically you create a list of colors, then list of variations that contains what function should be applied to modify color and parameters for that function. Finally you kind of create an interface/one simple to use function for getting final color value. The important thing is that all colors and possible variations are declared in one place.
DRY generating selectors:
Another thing you might consider is the way to generate all these selectors. You could use #each directive to go through all colors and variations and generate all selectors/classes in 1 place. Something like:
#each $color in $colors {
#each $variation in $variations {
.c-#{$color}-#{$variation} {
background-color: a-nice-function-to-get-color($color, $variation);
}
}
}
However, this usually isn't such a great idea, as it makes searching selectors in your IDE way harder. If you're really going to have so many different colors, then it might be worth thinking about using this technique, though.
TL;DR: How can you use SCSS to have CSS variables with a fallback for older browsers.
I'm trying to make sense of this article. In my opinion, you have to already be an advanced SASS user to understand it, which I'm not. To make matters worse, it's the only article I found on the subject.
Here is what I'm trying to achieve:
My scss should be along the lines of :
body {
#include v(background-color, primary)
}
then the processed CSS should be
body{
background: yellow; /* Yellow being defined above as the primary color */
background: var(--color-primary);
}
By playing around a bit, I can already get the value of the CSS variable like so:
$colors: (
primary: yellow,
);
:root {
#each $name, $color in $colors {
--color-#{$name}: $color;
}
}
#mixin background-color($color_) {
background: var(--color-#{$color_});
}
To use it:
body{
#include background-color(primary);
}
Which will result in this:
body {
background: var(--color-primary);
/* But the fallback is missing :(, I tried things with the map-get but it's really eluding me... */
}
If you're using Sass, you can automate fallbacks through a Sass mixin. Create a map of your CSS variable names and their values, and then you can look up those values in a mixin that outputs the fallback style and the preferred one
$vars: (
primary: yellow,
);
:root {
--primary: map-get($vars, primary);
}
#mixin var($property, $varName) {
#{$property}: map-get($vars, $varName);
#{$property}: var(--#{$varName});
}
The above mixin is used like so:
body {
#include var(background-color, primary);
}
and outputs the following CSS:
:root {
--primary: yellow;
}
body {
background-color: yellow;
background-color: var(--primary);
}
Et voilà :)
Update: Postcss Custom properties can do fallback and is way easier than the below code
step 1: declare scss variables
So first of all we want to put some variables in a $map, I'll go with color variables:
$colors: (
primary: #FFBB00,
secondary: #0969A2
);
step 2: automate css 4 var generation
// ripped CSS4 vars out of color map
:root {
// each item in color map
#each $key, $value in $colors {
--colors-#{$key}: $value;
}
}
What happens in root is : for each key and value in the colors map, we print the followng :
--colors-#{$key}: $value;
Which corresponds to css variable declarations. I believe the weird bit with #{} around the key is to not have spaces around the value.
Thus the result is:
--colors-primary: #FFBB00,
--colors-secondary: #0969A2
Note that the prefix (--colors-) is the same name as the scss color map above it. The why will become clear in last step.
step 3: Plenty of maps !
$props: (
background-color: $colors
);
$map-maps: (
background-color: colors
);
Here we add the map $props which maps a css property to the map containing the values. background-color will hold color, so the correct map is $colors.
map-maps is a copy of props where instead of the map we have the name of said map. (this is relative to the note in step 2).
Step 4 : let's make it work !
#mixin v($prop, $var) {
// get the map from map name
$map: map-get($props, $prop);
// fallback value, grab the variable's value from the map
$var-fall: map-get($map, $var);
// our css4 variable output
$var-output: var(--#{$map}-#{$var});
#{$prop}: $var-fall;
// css4 variable output
#{$prop}: $var-output;
}
body{
#include v(background-color, primary);
}
I simplified the code in the article quite a bit, it still works, for this example at least, the code in the article takes more into account.
Anyhow, here is what happens.
First, we call the mixin with:
#include v(background-color, primary);
Then upon entering,
$map: map-get($props, $prop); // map-get($props, background-color)
we have a variable called $map to which we assign the value that is inside the $props map at the key background-color which happen to be the $colors map. It's a bit of a maze but it's not that complicated once you resolve it.
Then for the fallback:
$var-fall: map-get($map, $var);
This simply gets the value of the map we just got (which is $colors) at the $var key (which happens to be primary). Thus the result is #FFBB00.
For the css var
$map-name: map-get($map-maps, $prop);
$var-output: var(--#{$map-name}-#{$var});
we recreate what we did to generate the var in the #each loop
Whole code would be :
$colors: (
primary: #FFBB00,
secondary: #0969A2
);
// ripped CSS4 vars out of color map
:root {
// each item in color map
#each $name, $color in $colors {
--colors-#{$name}: $color;
}
}
$props: (
background-color: $colors,
color: $colors
);
$map-maps: (
background-color: colors
);
#mixin v($prop, $var) {
// get the map from map name
$map: map-get($props, $prop);
// fallback value, grab the variable's value from the map
$var-fall: map-get($map, $var);
// our css4 variable output
$map-name: map-get($map-maps, $prop);
$var-output: var(--#{$map-name}-#{$var});
#{$prop}: $var-fall;
// css4 variable output
#{$prop}: $var-output;
}
body{
#include v(background-color, primary);
}
Now this is a simplification of what is done in the article. You should check it out to have code a bit more robust.
I assume you are aware of the reason why it didn't show the fallback. But since it's an answer I will explain the reasons
The current mixin block has only one background property which makes the sass compiler to generate only one property. I don't think sass can identify whether 'var' is supported in browser or not. So, we have to explicitly specify if we need the fallback.
Since you already have the map all you need is to get the value by giving the key 'primary'
#mixin background-color($color_) {
background: var(--color-#{$color_});
background: map-get($colors, primary);
}
This will add the background: yellow to the body class always. Alternatively if you want to control the addition of the fallback based on condition. You can do like this
#mixin background-color($color_, $showFall) {
background: var(--color-#{$color_});
#if $showFall {
background: map-get($colors, primary);
}
}
and call like this
body{
#include background-color(primary, true);
}
Code pen for the same
https://codepen.io/srajagop/pen/xdovON
Note: I am writing the answer under the assumption that you want only the background-color to work and not all the other properties like mentioned in that post. For that you need to create a proper data structure
Google Materialize defines their color variables in this file like so:
$red: (
"lighten-5": #FFEBEE,
"lighten-4": #FFCDD2,
"lighten-3": #EF9A9A,
"lighten-2": #E57373,
"lighten-1": #EF5350,
"base": #F44336,
"darken-1": #E53935,
"darken-2": #D32F2F,
"darken-3": #C62828,
"darken-4": #B71C1C,
"accent-1": #FF8A80,
"accent-2": #FF5252,
"accent-3": #FF1744,
"accent-4": #D50000
);
I would like to use the colors with something like this:
.light-red-border {
border: 1px solid $red-lighten-1;
}
How do I call those variables directly? They're used in other I can't find anything on this syntax mentioned anywhere.
Edit: I looked around a bit more in the Materialize Github and found some examples in _variables.scss:
$primary-color: color("materialize-red", "lighten-2") !default;
$primary-color-light: lighten($primary-color, 15%) !default;
$primary-color-dark: darken($primary-color, 15%) !default;
However, if you can direct me to an article discussing the syntax used to define the variables I would greatly appreciate it.
You're looking for map-get($red, 'lighten-5'); if you simply want the corresponding value from this map.
To expand on #weirdpanda's answer, these SASS maps need to be iterated upon, which then compiles into more CSS rules.
In the file you linked to, each of those colors is placed in a larger map of $colors:
$colors: (
"materialize-red": $materialize-red,
"red": $red,
"pink": $pink,
"purple": $purple
//...
);
This colors map is then iterated upon, producing matching class selectors like red.lighten-5 in the CSS.
#each $color_name, $color in $colors {
#each $color_type, $color_value in $color {
#if $color_type == "base" {
.#{$color_name} {
background-color: $color_value !important;
}
.#{$color_name}-text {
color: $color_value !important;
}
}
#else {
.#{$color_name}.#{$color_type} {
background-color: $color_value !important;
}
.#{$color_name}-text.text-#{$color_type} {
color: $color_value !important;
}
}
}
}
To actually use these variables within SASS files (for instance, after importing _color.scss, you can access a map value with map-get($map, $key). For instance:
.my-class{
color: map-get($red, 'lighten-5');
}
Edit: regarding the color function: The $primary-color: color("materialize-red", "lighten-2") line you posted is using a function defined in _color.scss, which ostensibly does the same thing as map-get but checks if the key exists in the map with map-has-key and raises a warning if it cannot be found.
#function color($color, $type) {
#if map-has-key($colors, $color) {
$curr_color: map-get($colors, $color);
#if map-has-key($curr_color, $type) {
#return map-get($curr_color, $type);
}
}
#warn "Unknown `#{name}` in $colors.";
#return null;
}
This syntax notation is called the SASS Maps notation and it is the SASS-equiv of a hash-map. Read more about it here.
I have a multidimensional list:
$color-set: (bg-color #888, border-color #444, active-bg-color #666, hover-bg-color #808080)
Currently I access each by using:
$color-set: (#888, #444, #666, #808080)
#div {
background: nth($color-set, 1)
}
Is there a way to use the key instead like:
#div {
background: $color-set(bg-color)
}
so I don't have to remember the order of colors in the list?
All you have is a list of lists, and lists only have numeric indexes. You would have to write a function that iterates over your list and compares the first element to some string argument. This is not something I recommend as it offers no benefit over just using ordinary variables.
#function find-value($list, $key) {
#each $item in $list {
#if ($key == nth($item, 1)) {
#return nth($item, 2);
}
}
#return false;
}
Sass does not currently support mappings, but will soon: https://github.com/nex3/sass/issues/642
Just use a separate variable for each color?
$bg-color: #888;
$border-color #444;
div {
background: $bg-color
}