I am a chemist dealing with a significant amount of voltammetry data recently. Let me be very clear and give some research information. I run scans from a starting voltage to an ending voltage on solid state conductive films. These scans are saved as .txt files (name scheme: run#.txt) in a single folder. I am looking at how conductance changes as temperature changes. The LINEST line plotting current v. voltage at a given temperature gives me a line with slope = conductance. Once I have the conductances (slopes) for each scan, I plot conductance v. temperature to see the temperature dependent conductance characteristics. I had been doing this in Excel, but have found quicker ways to get the job done using R. I am brand new to R (Rstudio) and recognize that my coding is not the best. Without doubt, this process can be streamlined and sped up which would help immensely. This is how I am performing the process currently:
# Set working directory with folder containing all .txt files for inspection
# Add all .txt files to the global environment
allruns<-list.files(pattern=".txt")
for(i in 1:length(allruns))assign(allruns[i],read.table(allruns[i]))
Since the voltage column (a 1x1000 matrix) is the same for all runs and is in column V1 of each .txt file, I assign a x to be the voltage column from the first folder
x<-run1.txt$V1
All currents (these change as voltage changes) are found in the V2 column of all the .txt files, so I assign y# to each. These are entered one at a time..
y1<-run1.txt$V2
y2<-run2.txt$V2
y3<-run3.txt$V2
# ...
yn<-runn.txt$V2
So that I can get the eqn for each LINEST (one LINEST for each scan and plotted with abline later). Again entered one at a time:
run1<-lm(y1~x)
run2<-lm(y2~x)
run3<-lm(y3~x)
# ...
runn<-lm(yn~x)
To obtain a single graph with all LINEST (one for each scan ) on the same plot, without the data points showing up, I have been using this pattern of coding to first get all data points on a single plot in separate series:
plot(x,y1,col="transparent",main="LSV Solid Film", xlab = "potential(V)",ylab="current(A)", xlim=rev(range(x)),ylim=range(c(y3,yn)))
par(new=TRUE)
plot(x,y2,col="transparent",main="LSV Solid Film", xlab = "potential(V)",ylab="current(A)", xlim=rev(range(x)),ylim=range(c(y3,yn)))
par(new=TRUE)
plot(x,y3,col="transparent",main="LSV Solid Film", xlab = "potential(V)",ylab="current(A)", xlim=rev(range(x)),ylim=range(c(y1,yn)))
# ...
par(new=TRUE)
plot(x,yn,col="transparent",main="LSV Solid Film", xlab = "potential(V)",ylab="current(A)", xlim=rev(range(x)),ylim=range(c(y1,yn)))
#To obtain all LINEST lines (one for each scan, on the single graph):
abline(run1,col=””, lwd=1)
abline(run2,col=””,lwd=1)
abline(run3,col=””,lwd=1)
# ...
abline(runn,col=””,lwd=1)
# Then to get each LINEST equation:
summary(run1)
summary(run2)
summary(run3)
# ...
summary(runn)
Each time I use summary(), I copy the slope and paste it into an Excel sheet- along with corresponding scan temp which I have recorded separately. I then graph the conductance v temp points for the film as X-Y scatter with smooth lines to give the temperature dependent conductance curve. Giving me a single LINEST lines plot in R and the conductance v temp in Excel.
This technique is actually MUCH quicker than doing it all in Excel, but it can be done much quicker and efficiently!!! Also, if I need to change something, this entire process needs to be reexecuted with whatever change is necessary. This process takes me maybe 5 hours in Excel and 1.5 hours in R (maybe I am too slow). Nonetheless, any tips to help automate/streamline this further are greatly appreciated.
There are plenty of questions about operating on data in lists; storing a list of matrix or a list of data.frame is fast, and code that operates cleanly on one can be applied to the remaining n-1 very easily.
(Note: the way I'm showing it here is one technique: maintaining everything in well-compartmentalized lists. Other will suggest -- very justifiably -- that combing things into a single data.frame and adding a group variable (to identify from which file/experiment the data originated) will help with more advanced multi-experiment regression or combined plotting, such as with ggplot2. I'm not going to go into this latter technique here, not yet.)
It is long decried not to do for(...) assign(..., read.csv(...)); you have the important part done, so this is relatively easy:
allruns <- sapply(list.files(pattern = "*.txt"), read.table, simplify = FALSE)
(The use of sapply(..., simplify=FALSE) is similar to lapply(...), but it has a nice side-effect of naming the individual list-ified elements with, in this case, each filename. It may not be critical here but is quite handy elsewhere.)
Extracting your invariant and variable data is simple enough:
allLMs <- lapply(allruns, function(mdl) lm(V2 ~ V1, data = mdl))
I'm using each table's V1 here instead of a once-extracted x ... though you might wonder why, I argue keeping it like for two reasons: (1) JUST IN CASE the V1 variable is ever even one-row-different, this will save you; (2) it is very easy to construct the model like this.
At this point, each object within allLMs is an lm object, meaning we might do:
summary(allLMs[[1]])
Plotting: I think I understand why you are using par=NEW, and I have to laugh ... I had been deep in R for a while before I started using that technique. What I think you need is actually much simpler:
xlim <- rev(range(allruns[[1]]$V1))
ylim <- range(sapply(allruns, `[`, "V2"))
# this next plot just sets the box and axes, no points
plot(NA, type = "na", xlim = xlim, ylim = ylim)
# no need to plot points with "transparent" ...
ign <- sapply(allLMs, abline, col = "") # and other abline options ...
Copying all models into Excel, again, using lists:
out <- do.call(rbind, sapply(allLMs, function(m) summary(m)$coefficients[,1]))
This will now be a single data.frame with all coefficients in two columns. (Feel free to use similar techniques to extract the other model summary attributes, including std err, t.value, or Pr(>|t|) (in the $coefficients); or $r.squared, $adj.r.squared, etc.)
write.csv(out, file="clipboard", sep="\t")
and paste into Excel. (Or, better yet, save it to a CSV file and import that, since you might want to keep it around.)
One of the tricks to using lists for this is to persevere: keep things in lists as long as you can, so that you don't have deal with models individually. One mantra is that if you do it once, you shouldn't have to type it again, just loop/apply/map/whatever. Don't extract too much from the lists before you have to.
Note: r2evans' answer provides good general advice and doesn't require heavy package dependencies. But it probably doesn't hurt to see alternative strategies.
The tidyverse can be quite handy for this sort of thing, here's a dummy example for illustration,
library(tidyverse)
# creating dummy data files
dummy <- function(T) {
V <- seq(-5, 5, length=20)
I <- jitter(T*V + T, factor = 1)
write.table(data.frame(V=V, I = I),
file = paste0(T,".txt"),
row.names = FALSE)
}
purrr::walk(300:320, dummy)
# reading
lf <- list.files(pattern = "\\.txt")
read_one <- function(f, ...) {cbind(T = as.numeric(gsub("\\.txt", "", f)), read.table(f, ...))}
m <- purrr::map_df(lf, read_one, header = TRUE, .id="id")
head(m)
ggplot(m, aes(V, I, group = T)) +
facet_wrap( ~ T) +
geom_point() +
geom_smooth(se = FALSE)
models <- m %>%
split(.$T) %>%
map(~lm(I ~ V, data = .))
coefs <- models %>% map_df(broom::tidy, .id = "T")
ggplot(coefs, aes(as.numeric(T), estimate)) +
geom_line() +
facet_wrap(~term, scales = "free")
Related
I have 2 csv data files. Each file has a "date_time" column and a "temp_c" column. I want to make the x-axis have the "date_time" from both files and then use 2 y-axes to display each "temp_c" with separate lines. I would like to use plot instead of ggplot2 if possible. I haven't been able to find any code help that works with my data and I'm not sure where to really begin. I know how to do 2 separate plots for these 2 datasets, just not combine them into one graph.
plot(grewl$temp_c ~ grewl$date_time)
and
plot(kbll$temp_c ~ kbll$date_time)
work separately but not together.
As others indicated, it is easy to add new data to a graph using points() or lines(). One thing to be careful about is how you format the axes as they will not be automatically adjusted to fit any new data you input using points() and the like.
I've included a small example below that you can copy, paste, run, and examine. Pay attention to why the first plot fails to produce what you want (axes are bad). Also note how I set this example up generally - by making fake data that showcase the same "problem" you are having. Doing this is often a better strategy than simply pasting in your data since it forces you to think about the core component of the problem you are facing.
#for same result each time
set.seed(1234)
#make data
set1<-data.frame("date1" = seq(1,10),
"temp1" = rnorm(10))
set2<-data.frame("date2" = seq(8,17),
"temp2" = rnorm(10, 1, 1))
#first attempt fails
#plot one
plot(set1$date1, set1$temp1, type = "b")
#add points - oops only three showed up bc the axes are all wrong
lines(set2$date2, set2$temp2, type = "b")
#second attempt
#adjust axes to fit everything (set to min and max of either dataset)
plot(set1$date1, set1$temp1,
xlim = c(min(set1$date1,set2$date2),max(set1$date1,set2$date2)),
ylim = c(min(set1$temp1,set2$temp2),max(set1$temp1,set2$temp2)),
type = "b")
#now add the other points
lines(set2$date2, set2$temp2, type = "b")
# we can even add regression lines
abline(reg = lm(set1$temp1 ~ set1$date1))
abline(reg = lm(set2$temp2 ~ set2$date2))
I'm an R programming beginner and I'm trying to implement the clustering.plot method available in R package EMA. My clustering works fine and I can see the results populated as well. However, when I try to generate a heat map using clustering.plot, it gives me an error "Error in plot.new (): graphic edges too large". My code below,
#Loading library
library(EMA)
library(colonCA)
#Some information about the data
data(colonCA)
summary(colonCA)
class(colonCA) #Expression set
#Extract expression matrix from colonCA
expr_mat <- exprs(colonCA)
#Applying average linkage clustering on colonCA data using Pearson correlation
expr_genes <- genes.selection(expr_mat, thres.num=100)
expr_sample <- clustering(expr_mat[expr_genes,],metric = "pearson",method = "average")
expr_gene <- clustering(data = t(expr_mat[expr_genes,]),metric = "pearson",method = "average")
expr_clust <- clustering.plot(tree = expr_sample,tree.sup=expr_gene,data=expr_mat[expr_genes,],title = "Heat map of clustering",trim.heatmap =1)
I do not get any error when it comes to actually executing the clustering process. Could someone help?
In your example, some of the rownames of expr_mat are very long (max(nchar(rownames(expr_mat)) = 271 characters). The clustering_plot function tries to make a margin large enough for all the names but because the names are so long, there isn't room for anything else.
The really long names seem to have long stretches of periods in them. One way to condense the names of these genes is to replace runs of 2 or more periods with just one, so I would add in this line
#Extract expression matrix from colonCA
expr_mat <- exprs(colonCA)
rownames(expr_mat)<-gsub("\\.{2,}","\\.", rownames(expr_mat))
Then you can run all the other commands and plot like normal.
I have a table exported in csv from PostgreSQL and I'd like to create a stacked bar graph in R. It's my first project in R.
Here's my data and what I want to do:
It the quality of the feeder bus service for a certain provider in the area. For each user of the train, we assign a service quality based of synchronization between the bus and the train at the train stations and calculate the percentage of user that have a ideal or very good service, a correct service, a deficient service or no service at all (linked to that question in gis.stackexchange)
So, It's like to use my first column as my x-axis labels and my headers as my categories. The data is already normalized to 100% for each row.
In Excel, it's a couple of clicks and I wouldn't mind typing a couple of line of codes since it's the final result of an already quite long plpgsql script... I'd prefer to continue to code instead of moving to Excel (I also have dozens of those to do).
So, I tried to create a stacked bar using the examples in Nathan Yau's "Visualize This" and the book "R in Action" and wasn't quite successful. Normally, their examples use data that they aggregate with R and use that. Mine is already aggregated.
So, I've finally come up with something that works in R:
but I had to transform my data quite a bit:
I had to transpose my table and remove my now-row (ex-column) identifier.
Here's my code:
# load libraries
library(ggplot2)
library(reshape2)
# load data
stl <- read.csv("D:/TEMP/rabat/_stl_rabattement_stats_mtl.csv", sep=";", header=TRUE)
# reshape for plotting
stl_matrix <- as.matrix(stl)
# make a quick plot
barplot(stl_matrix, border=NA, space=0.1, ylim=c(0, 100), xlab="Trains", ylab="%",
main="Qualité du rabattement, STL", las = 3)
Is there any way that I could use my original csv and have the same result?
I'm a little lost here...
Thanks!!!!
Try the ggplot2 and reshape library. You should be able to get the chart you want with
stl$train_order <- as.numeric(rownames(stl))
stl.r <- melt(stl, id.vars = c("train_no", "train_order"))
stl.r$train_no <- factor(
stl.r$train_no,
levels = stl$train_no[order(stl$train_order)])
ggplot(stl.r, aes(x = factor(train_no), y = value, fill = variable)) + geom_bar(stat = 'identity')
It appears that you transposed the matrix manually. This can be done in R with the t() function.
Add the following line after the as.matrix(stl) line:
stl_matrix <- t(stl_matrix)
I have a set of data which contains around 150,000 observations of 800 subjects. Each observation has: subject ID, latitude, longitude, and the time that the subject was at those coordinates. The data covers a 24-hour period.
If I plot all the data at once I just get a blob. Is anyone able to give me some tips as to how I can animate this data so that I can observe the paths of the subjects as a function of time?
I've read the spacetime vignette but I'm not entirely sure it will do what I want. At this point I'm spending a whole lot of time googling but not really coming up with anything that meets my needs.
Any tips and pointers greatly appreciated!
Here my first use of animation package. It was easier than I anticipated and especially the saveHTML is really amazing. Here my scenario(even I think that my R-code will be clearer:)
I generate some data
I plot a basic plot for all persons as a background plot.
I reshape data to get to a wide format in a way I can plot an arrow between present and next position for each person.
I loop over hours , to generate many plots. I put the llop within the powerful saveHTML function.
You get a html file with a nice animation. I show here one intermediate plot.
Here my code:
library(animation)
library(ggplot2)
library(grid)
## creating some data of hours
N.hour <- 24
dat <- data.frame(person=rep(paste0('p',1:3),N.hour),
lat=sample(1:10,3*N.hour,rep=TRUE),
long=sample(1:10,3*N.hour,rep=TRUE),
time=rep(1:N.hour,each=3))
# the base plot with
base <- ggplot() +
geom_point(data=dat,aes(x=lat, y=long,colour = person),
size=5)+ theme(legend.position = "none")
## reshape data to lat and long formats
library(plyr)
dat.segs <- ddply(dat,.(person),function(x){
dd <- do.call(rbind,
lapply(seq(N.hour-1),
function(y)c(y,x[x$time %in% c(y,y+1),]$lat,
x[x$time %in% c(y,y+1),]$long)))
dd
})
colnames(dat.segs) <- c('person','path','x1','x2','y1','y2')
# a function to create the animation
oopt <- ani.options(interval = 0.5)
saveHTML({
print(base)
interval = ani.options("interval")
for(hour in seq(N.hour-1)){
# a segment for each time
tn <- geom_segment(aes(x= x1, y= y1, xend = x2,
yend = y2,colour = person),
arrow = arrow(), inherit.aes = FALSE,
data =subset(dat.segs,path==hour))
print(base <- base + tn)
ani.pause()
}
}, img.name = "plots", imgdir = "plots_dir",
htmlfile = "random.html", autobrowse = FALSE,
title = "Demo of animated lat/long for different persons",
outdir=getwd())
Your question is a bit vague, but I will share how I have done this kind of animation in the past.
Create a function that plots all the subject locations for one time slice:
plot_time = function(dataset, time_id) {
# make a plot with your favorite plotting package (e.g. `ggplot2`)
# Save it as a file on disk (e.g. using `ggsave`), under a regular name,
# frame001.png, frame002.png, see sprintf('frame%03d', time_index)
}
Call this function on each of your timeslices, e.g. using lapply:
lapply(start_time_id:stop_time_id, plot_time)
leading to a set of graphics files on the hard drive called frame001 to framexxx.
Use a tool to render those frames into a movie, e.g. using ffmpeg, see for example.
This is a general workflow, which has been already implemented in the animation package (thanks for reminding me #mdsummer). You can probably leverage that package to get your animation.
I need to draw lines from the data stored in a text file.
So far I am able only to draw points on a graph and i would like to have them as lines (line graph).
Here's the code:
pupil_data <- read.table("C:/a1t_left_test.dat", header=T, sep="\t")
max_y <- max(pupil_data$PupilLeft)
plot(NA,NA,xlim=c(0,length(pupil_data$PupilLeft)), ylim=c(2,max_y));
for (i in 1:(length(pupil_data$PupilLeft) - 1))
{
points(i, y = pupil_data$PupilLeft[i], type = "o", col = "red", cex = 0.5, lwd = 2.0)
}
Please help me change this line of code:
points(i, y = pupil_data$PupilLeft[i], type = "o", col = "red")
to draw lines from the data.
Here is the data in the file:
PupilLeft
3.553479
3.539469
3.527239
3.613131
3.649437
3.632779
3.614373
3.605981
3.595985
3.630766
3.590724
3.626535
3.62386
3.619688
3.595711
3.627841
3.623596
3.650569
3.64876
By default, R will plot a single vector as the y coordinates, and use a sequence for the x coordinates. So to make the plot you are after, all you need is:
plot(pupil_data$PupilLeft, type = "o")
You haven't provided any example data, but you can see this with the built-in iris data set:
plot(iris[,1], type = "o")
This does in fact plot the points as lines. If you are actually getting points without lines, you'll need to provide a working example with your data to figure out why.
EDIT:
Your original code doesn't work because of the loop. You are in effect asking R to plot a line connecting a single point to itself each time through the loop. The next time through the loop R doesn't know that there are other points that you want connected; if it did, this would break the intended use of points, which is to add points/lines to an existing plot.
Of course, the line connecting a point to itself doesn't really make sense, and so it isn't plotted (or is plotted too small to see, same result).
Your example is most easily done without a loop:
PupilLeft <- c(3.553479 ,3.539469 ,3.527239 ,3.613131 ,3.649437 ,3.632779 ,3.614373
,3.605981 ,3.595985 ,3.630766 ,3.590724 ,3.626535 ,3.62386 ,3.619688
,3.595711 ,3.627841 ,3.623596 ,3.650569 ,3.64876)
plot(PupilLeft, type = 'o')
If you really do need to use a loop, then the coding becomes more involved. One approach would be to use a closure:
makeaddpoint <- function(firstpoint){
## firstpoint is the y value of the first point in the series
lastpt <- firstpoint
lastptind <- 1
addpoint <- function(nextpt, ...){
pts <- rbind(c(lastptind, lastpt), c(lastptind + 1, nextpt))
points(pts, ... )
lastpt <<- nextpt
lastptind <<- lastptind + 1
}
return(addpoint)
}
myaddpoint <- makeaddpoint(PupilLeft[1])
plot(NA,NA,xlim=c(0,length(PupilLeft)), ylim=c(2,max(PupilLeft)))
for (i in 2:(length(PupilLeft)))
{
myaddpoint(PupilLeft[i], type = "o")
}
You can then wrap the myaddpoint call in the for loop with whatever testing you need to decide whether or not you will actually plot that point. The function returned by makeaddpoint will keep track of the plot indexing for you.
This is normal programming for Lisp-like languages. If you find it confusing you can do this without a closure, but you'll need to handle incrementing the index and storing the previous point value 'manually' in your loop.
There is a strong aversion among experienced R coders to using for-loops when not really needed. This is an example of a loop-less use of a vectorized function named segments that takes 4 vectors as arguments: x0,y0, x1,y1
npups <-length(pupil_data$PupilLeft)
segments(1:(npups-1), pupil_data$PupilLeft[-npups], # the starting points
2:npups, pupil_data$PupilLeft[-1] ) # the ending points