Ansible include_vars into dictionary - dictionary

Question

In my ansible playbook, I read a list of directories into a list. I then want to read a "config.yml" file from each of these directories and put their content into dictionary, so that I can reference the config-data via the directory name from that dictionary.
The first part is no problem, but I cannot get the second part to work:
Step 1, load directories:
- name: Include directories
include_vars:
file: /main-config.yml
name: config
Step 2, load configs from directories:
- name: load deploymentset configurations
include_vars:
file: /path/{{ item }}/config.yml
name: "allconfs.{{ item }}" ## << This is the problematic part
with_items:
- "{{ config.dirs }}"
I tried different things like "allconfs['{{ item }}'], but none seemed to work. The playbook completed successfully, but the data was not in the dictionary.
I also tried defining the outer dictionary beforehand, but that did not work either.
The config files themselves are very simple:
/main-config.yml:
dirs:
- dir1
- dir2
- dir3
/path/dir1/config.yml:
some_var: "some_val"
another_var: "another val"
I want to be able to then access the values of the config.yml files like this:
{{ allconfs.dir1.some_var }}
UPDATE to try Konstantins approach:
- name: load deploymentset configurations
include_vars:
file: /repo/deploymentsets/{{ item }}/config.yml
name: "default_config"
with_items:
- "{{ config.deploymentsets }}"
register: default_configs
- name: combine configs
set_fact:
default_configs: "{{ dict(default_configs.results | json_query('[].[item, ansible_facts.default_config]')) }}"
Error message:
fatal: [127.0.0.1]: FAILED! => {"failed": true, "msg": "Unexpected templating type error occurred on ({{ dict(default_configs.results | json_query('[].[item, ansible_facts.default_config]')) }}): <lambda>() takes exactly 0 arguments (1 given)"}

Answer 1

Here is a piece of code from one of my projects with similar functionality:
- name: Load config defaults
include_vars:
file: "{{ item }}.yml"
name: "default_config"
with_items: "{{ config_files }}"
register: default_configs
tags:
- configuration
- name: Combine configs into one dict
# Здесь мы делаем словарь вида
# default_configs:
# config_name_1: { default_config_object }
# config_name_2: { default_config_object }
# config_name_3: { default_config_object }
# ...
set_fact:
default_configs: "{{ dict(default_configs.results | json_query('[].[item, ansible_facts.default_config]')) }}"
tags:
- configuration
default_config is a dummy var to temporary load var data.
The trick is to use register: default_configs with include_vars and parse it with the following task stripping out unnecessary fields.

Answer 2

AFAIK it isn't possible to create a single dictionary that encompasses multiple include_vars. From my testing it would create separate dictionaries for each included directory. Here's what you can do instead.
Remove allconfs. from your variable name.
- name: load deploymentset configurations
include_vars:
file: /path/{{ item }}/config.yml
name: "{{ item }}"
with_items:
- "{{ config.dirs }}"
You can then either access variables directly with
debug:
msg: "{{ dir1.some_var }}"
with_items: "{{ config.dirs }}"
Or if you need to loop through all variables in your included directories use this (hoisted from Ansible: how to construct a variable from another variable and then fetch it's value).
debug:
msg: "{{ hostvars[inventory_hostname][item].some_var }}"
with_items: "{{ config.dirs }}"