public Dir(string rootDir)
{
Directories = new List<string>();
RootDir = rootDir;
foreach(string dir in Directory.GetDirectories(RootDir, #"*.mp3", SearchOption.AllDirectories))
{
Directories.Add(dir);
Debug.Print(dir);
}
Shuffle(Directories);
}
With this code, I wanted to find all the .mp3 files in one folder, but it came out to make a zero element in 'Directories'. What seems to be the problem?
*.mp3 are files. Use Directory.GetFiles();
If you are looking for all mp3s within folders. Do something like this (pseudo-code):
List<string> mp3s = new List<string>();
foreach(string directory in Directory.GetDirectories(_rootFolder)){
foreach(string file in Directory.GetFiles(directory)){
mp3s.Add(file);
}
}
Related
i am developing application in which i want that if user create folder and if it is already present then folder should automatically renamed by appending number to folder name
suppose server has folder with name Time now if user again creates folder than it new folder will be Time1 again user creates folder with same name(Time or Time1) than new Folder should be created with Time2 and so on... This is what i have done so far but recursion always return wrong value.
public string checkIfExist(String path, String ProgramName, int itteration,out string strFolderName)
{
String uploadPath = "";
strFolderName = "";
String Mappath =HttpContext.Current.Server.MapPath(path);
if (Directory.Exists(Mappath))
{
String Path = HttpContext.Current.Server.MapPath((path + "" + ProgramName.Replace(" ", "_")));
// uploadPath += ++itteration ;
if (Directory.Exists(Path))
{
ProgramName += ++itteration;
strFolderName = ProgramName;
uploadPath = checkIfExist(path, ProgramName, itteration,out strFolderName);
}
}
return ProgramName;
}
Perhaps you could adapt this, to your need. I wrote it on the fly based on a piece of code I remember in an old file manager I was using in some projects, so please test it. This doesn't include creation and so on, based on your example I'm sure you can add that yourself but if you need help just comment below.
The idea is to pass the original name of the directory you want, and then return an appropriate new name if it exists, such as Test(1), Test(2), Test(n). Then once you get the name you need, you can create it directly.
protected string GetUniqueDirectoryName(string dirName)
{
string newDirName = dirName;
for (int i = 1; Directory.Exists(Server.MapPath("PATH_HERE") + newDirName); i++)
{
newDirName = string.Format("{0}({1})", dirName, i);
}
return newDirName;
}
Note: You will need to include System.IO and probably use HttpContext.Current.Server.MapPath instead of Server.MapPath
I don't know if I really understand what you are trying to do, but I think using recursion here is a little overkill. Try something like this:
string dirName = "Time";
int counter = 0;
string dir = dirName;
while(Directory.Exists(dir))
{
dir = String.Format("{0}{1}", dirName, (++counter).ToString());
}
Directory.CreateDirectory(dir);
If files are posted to my webapp, then I read them via MultipartFormDataStreamProvider.FileData.
I Initialize the provider like this:
string root = HttpContext.Current.Server.MapPath("~/App_Data");
var provider = new MultipartFormDataStreamProvider(root);
And the provider nicely stores them as "~App_Data/BodyPart_{someguid}"
But how do I clean up those files after I'm done with them?
I know this question is old, but the best way I found to delete the temporary file was after processing it.
string root = HttpContext.Current.Server.MapPath("~/App_Data");
var provider = new MultipartFormDataStreamProvider(root);
foreach (var file in provider.Files)
{
// process file upload...
// delete temporary file
System.IO.File.Delete(file.LocalFileName);
}
You could delete all files that are older than a certain timespan. e.g.
private void CleanTempFiles(string dir, int ageInMinutes)
{
string[] files = Directory.GetFiles(dir);
foreach (string file in files)
{
var time = File.GetCreationTime(file);
if (time.AddMinutes(ageInMinutes) < DateTime.Now)
{
File.Delete(file);
}
}
}
Then call it with something like:
CleanTempFiles(root, 60); // Delete all files older than 1 hour
I have different plugins in my Web api project with their own XML docs, and have one centralized Help page, but the problem is that Web Api's default Help Page only supports single documentation file
new XmlDocumentationProvider(HttpContext.Current.Server.MapPath("~/App_Data/Documentation.xml"))
How is it possible to load config from different files? I wan to do sth like this:
new XmlDocumentationProvider("PluginsFolder/*.xml")
You can modify the installed XmlDocumentationProvider at Areas\HelpPage to do something like following:
Merge multiple Xml document files into a single one:
Example code(is missing some error checks and validation):
using System.Xml.Linq;
using System.Xml.XPath;
XDocument finalDoc = null;
foreach (string file in Directory.GetFiles(#"PluginsFolder", "*.xml"))
{
if(finalDoc == null)
{
finalDoc = XDocument.Load(File.OpenRead(file));
}
else
{
XDocument xdocAdditional = XDocument.Load(File.OpenRead(file));
finalDoc.Root.XPathSelectElement("/doc/members")
.Add(xdocAdditional.Root.XPathSelectElement("/doc/members").Elements());
}
}
// Supply the navigator that rest of the XmlDocumentationProvider code looks for
_documentNavigator = finalDoc.CreateNavigator();
Kirans solution works very well. I ended up using his approach but by creating a copy of XmlDocumentationProvider, called MultiXmlDocumentationProvider, with an altered constructor:
public MultiXmlDocumentationProvider(string xmlDocFilesPath)
{
XDocument finalDoc = null;
foreach (string file in Directory.GetFiles(xmlDocFilesPath, "*.xml"))
{
using (var fileStream = File.OpenRead(file))
{
if (finalDoc == null)
{
finalDoc = XDocument.Load(fileStream);
}
else
{
XDocument xdocAdditional = XDocument.Load(fileStream);
finalDoc.Root.XPathSelectElement("/doc/members")
.Add(xdocAdditional.Root.XPathSelectElement("/doc/members").Elements());
}
}
}
// Supply the navigator that rest of the XmlDocumentationProvider code looks for
_documentNavigator = finalDoc.CreateNavigator();
}
I register the new provider from HelpPageConfig.cs:
config.SetDocumentationProvider(new MultiXmlDocumentationProvider(HttpContext.Current.Server.MapPath("~/App_Data/")));
Creating a new class and leaving the original one unchanged may be more convenient when upgrading etc...
Rather than create a separate class along the lines of XmlMultiDocumentationProvider, I just added a constructor to the existing XmlDocumentationProvider. Instead of taking a folder name, this takes a list of strings so you can still specify exactly which files you want to include (if there are other xml files in the directory that the Documentation XML are in, it might get hairy). Here's my new constructor:
public XmlDocumentationProvider(IEnumerable<string> documentPaths)
{
if (documentPaths.IsNullOrEmpty())
{
throw new ArgumentNullException(nameof(documentPaths));
}
XDocument fullDocument = null;
foreach (var documentPath in documentPaths)
{
if (documentPath == null)
{
throw new ArgumentNullException(nameof(documentPath));
}
if (fullDocument == null)
{
using (var stream = File.OpenRead(documentPath))
{
fullDocument = XDocument.Load(stream);
}
}
else
{
using (var stream = File.OpenRead(documentPath))
{
var additionalDocument = XDocument.Load(stream);
fullDocument?.Root?.XPathSelectElement("/doc/members").Add(additionalDocument?.Root?.XPathSelectElement("/doc/members").Elements());
}
}
}
_documentNavigator = fullDocument?.CreateNavigator();
}
The HelpPageConfig.cs looks like this. (Yes, it can be fewer lines, but I don't have a line limit so I like splitting it up.)
var xmlPaths = new[]
{
HttpContext.Current.Server.MapPath("~/bin/Path.To.FirstNamespace.XML"),
HttpContext.Current.Server.MapPath("~/bin/Path.To.OtherNamespace.XML")
};
var documentationProvider = new XmlDocumentationProvider(xmlPaths);
config.SetDocumentationProvider(documentationProvider);
I agree with gurra777 that creating a new class is a safer upgrade path. I started with that solution but it involves a fair amount of copy/pasta, which could easily get out of date after a few package updates.
Instead, I am keeping a collection of XmlDocumentationProvider children. For each of the implementation methods, I'm calling into the children to grab the first non-empty result.
public class MultiXmlDocumentationProvider : IDocumentationProvider, IModelDocumentationProvider
{
private IList<XmlDocumentationProvider> _documentationProviders;
public MultiXmlDocumentationProvider(string xmlDocFilesPath)
{
_documentationProviders = new List<XmlDocumentationProvider>();
foreach (string file in Directory.GetFiles(xmlDocFilesPath, "*.xml"))
{
_documentationProviders.Add(new XmlDocumentationProvider(file));
}
}
public string GetDocumentation(System.Reflection.MemberInfo member)
{
return _documentationProviders
.Select(x => x.GetDocumentation(member))
.FirstOrDefault(x => !string.IsNullOrWhiteSpace(x));
}
//and so on...
The HelpPageConfig registration is the same as in gurra777's answer,
config.SetDocumentationProvider(new MultiXmlDocumentationProvider(HttpContext.Current.Server.MapPath("~/App_Data/")));
I've a dir (with sub dirs) template that is kept as a resource inside a jar file. During run
time I need to extract it (template) to tmp dir change some content and finally publish it as a zipped artifact.
My question is: how to extract this content easily? I was trying getResource() as well as getResourceAsStream()..
Following code works fine here: (Java7)
String s = this.getClass().getResource("").getPath();
if (s.contains("jar!")) {
// we have a jar file
// format: file:/location...jar!...path-in-the-jar
// we only want to have location :)
int excl = s.lastIndexOf("!");
s = s.substring(0, excl);
s = s.substring("file:/".length());
Path workingDirPath = workingDir = Files.createTempDirectory("demo")
try (JarFile jf = new JarFile(s);){
Enumeration<JarEntry> entries = jf.entries();
while (entries.hasMoreElements()) {
JarEntry je = entries.nextElement();
String name = je.getName();
if (je.isDirectory()) {
// directory found
Path dir = workingDirPath.resolve(name);
Files.createDirectory(dir);
} else {
Path file = workingDirPath.resolve(name);
try (InputStream is = jf.getInputStream(je);) {
Files.copy(is, file, StandardCopyOption.REPLACE_EXISTING);
}
}
}
}
} else {
// debug mode: no jar
}
I am generating the zip file from this folder "D:\Nagaraj\Dotnet\Zipfile\Zipfile\Filebuild\Hi" within that "Hi" folder has 2 txt files. .....yes Now generating the Hi.zip file.But problem is Within that zip file has this particular path "D:\Nagaraj\Dotnet\Zipfile\Zipfile\Filebuild\Hi" and within that hi folder has 2 txt fils. Now I need to remove this path "D:\Nagaraj\Dotnet\Zipfile\Zipfile\Filebuild\Hi" and directly generate that Hi.zip file and within that 2 txt file......thanks ....in advance
I am using sharpziplib library enter code here
protected void Page_Load(object sender, EventArgs e)
{
StartZip("D:/Nagaraj/Dotnet/Zipfile/Zipfile/Filebuild/Hi",".zip");
}
public void StartZip(string directory, string zipFileName)
{
ZipFile z = ZipFile.Create(directory + zipFileName);
z.BeginUpdate();
string[] filenames = Directory.GetFiles(directory);
foreach (string filename in filenames)
{
z.Add(filename);
}
z.CommitUpdate();
z.Close();
}
From the help file, where you add your files, you say how to do you like to show inside the zip.
public void StartZip(string directory, string zipFileName)
{
using(ZipFile z = ZipFile.Create(directory + zipFileName))
{
z.BeginUpdate();
// Create a reference to the directory.
DirectoryInfo di = new DirectoryInfo(directory);
// Create an array representing the files in the current directory.
FileInfo[] fi = di.GetFiles();
// here the entryName is the name that you like to show inside zip
foreach (FileInfo fiTemp in fi)
z.Add(fiTemp.FullName, fiTemp.Name);
z.CommitUpdate();
z.Close();
}
}