I am trying to use the command:
audio_play_sound()
I am trying to insert it into this piece of code, so that when the player jumps, a sound plays.
if (key_jump) && (jumps > 0)
{
jumps -=1;
vsp = -jumpspeed;
}
Code that causes problem:
if (key_jump) && (jumps > 0)
{
jumps -=1;
vsp = -jumpspeed;
audio_play_sound(snd_jump)
}
Simply inserting the line into the if statement does not work, and gives the error WRONG NUMBER OF ARGUMENTS IN FUNCTION. This is rather confusing, perhaps I am using the wrong command? Thanks in advance
The problem is stated in the error, you're providing the wrong number of arguments to the audo_play_sound function.
from the docs
audio_play_sound(index, priority, loop);
As the person above states your answer is audio_play_sound(snd_jump, 1, false).
Related
Greetings I am getting an error of
Error in if (nrow(pair) == 0) { :argument is of length zero
I have checked the other answers but do not seem to work on a variable like mine. Please check code below, please assist if you can.
pair<-NULL
if(exists("p.doa.ym")) pair <- rbind(pair, p.doa.ym[,1:2])
if(exists("p.doa.yd")) pair <- rbind(pair, p.doa.yd[,1:2])
if(nrow(pair) == 0) {
print("THERE ARE NO MATCHES FOR TODAY. STOP HERE")
quit()
}
Since you set pair=NULL and then it might happen that pair stays null if those two if statements are not true, you either need to check if pair is null first, or you could set pair to an empty data frame, or something else.
One option:
if (!is.null(pair)) {
if (nrow(pair)==0) {
# your code
}
}
Another option:
pair=data.frame()
# your code
I am trying to implement following algorithm in R:
Iterate(Cell: top)
While (top != null)
Print top.Value
top = top.Next
End While
End Iterate
Basically, given a list, the algorithm should break as soon as it hits 'null' even when the list is not over.
myls<-list('africa','america south','asia','antarctica','australasia',NULL,'europe','america north')
I had to add a for loop for using is.null() function, but following code is disaster and I need your help to fix it.
Cell <- function(top) {
#This algorithm examines every cell in the linked list, so if the list contains N cells,
#it has run time O(N).
for (i in 1:length(top)){
while(is.null(top[[i]]) !=TRUE){
print(top)
top = next(top)
}
}
}
You may run this function using:
Cell(myls)
You were close but there is no need to use for(...) in this
construction.
Cell <- function(top){
i = 1
while(i <= length(top) && !is.null(top[[i]])){
print(top[[i]])
i = i + 1
}
}
As you see I've added one extra condition to the while loop: i <= length(top) this is to make sure you don't go beyond the length of the
list in case there no null items.
However you can use a for loop with this construction:
Cell <- function(top){
for(i in 1:length(top)){
if(is.null(top[[i]])) break
print(top[[i]])
}
}
Alternatively you can use this code without a for/while construction:
myls[1:(which(sapply(myls, is.null))[1]-1)]
Check this out: It runs one by one for all the values in myls and prints them but If it encounters NULL value it breaks.
for (val in myls) {
if (is.null(val)){
break
}
print(val)
}
Let me know in case of any query.
map_wc <- function(.,lines)
{
lines_lst = unlist(strsplit(lines,"\r\n",fixed=TRUE))
l_cnt<-1;
keys_l<-c()
data_l<-c()
for (line in lines_lst)
{
words = unlist(strsplit(line,";",fixed=TRUE))
if (length(words) != 5){
next
}
}
Anyone using Rhadoop might be familiar with the code above. Can someone please explain to me the reason why ".," i.e dot(.) and (,) in the first line function are placed side-by-side. Please when answering note that am new to R.
Please see the code below. the code does not show the accurate value as everything it being set to "Others" in the new var titles:
extractTitle<- function(name){
name<-as.character(name)
if (length(grep("Miss.",name))>0){
return("Miss.")
}else if (length(grep("Master.",name))>0){
return("Master.")
}else if (length(grep("Mrs.",name))>0){
return("Mrs.")
}else if (length(grep("Mr.",name))>0){
return("Mr.")
}else {
return("Other")
}
}
titles<- NULL
for (i in 1:nrow(data.combined)){
titles<- c(titles,extractTitle(data.combined[i,"name"]))
}
data.combined$title<- as.factor(titles)
Kindly advice where is the issue.
Your code works for me when trying it with simple test data ("foobar", "fooMaster.bar" "Master.bar", "fooMaster.", etc.). So the issue probably lies with how you handle the dataset to the function. For example, if you misspelled the "name" column access this will handle NULL to the function, which in turn will cause "Other" be handed back.
PS: sorry for posting this as an answer but I'm still too low for comments :)
I have tried to write a simple code to compute the median but I got an error.
This is what I wrote
median<-function(x){odd.even<-length(x)%%2 if (odd.even = = 0)(sort(x)[length(x)/2]+sort(x)[1+length(x)/2])/2 else (sort(x)[ceiling(length(x)/2)])}
and this is the error I got
Error: unexpected 'if' in "median<-function(x){odd.even<-length(x)%%2 if"
Thanks
Try this (you forgot the brackets {)
median<-function(x){
odd.even<-length(x)%%2
if (odd.even == 0){
(sort(x)[length(x)/2]+sort(x)[1+length(x)/2])/2
} else {
(sort(x)[ceiling(length(x)/2)])
}
}
As pointed out if you want not to use bracket you can always do this, with a new line on the if statement :
median<-function(x){
odd.even<-length(x)%%2
if (odd.even == 0) (sort(x)[length(x)/2]+sort(x)[1+length(x)/2])/2 else (sort(x)[ceiling(length(x)/2)])
}
Also a return(x) at the end, might help the reading process, although it is not compulsory.