Is there an easy way to transform this string into a meaningful date format?
date <- "Tue Apr 04 10:18:33 +0000 2017"
Right now I would use some regex and then the lubridate package. But I guess there is a less complicated way.
Try this:
as.POSIXct(date, format = "%a %b %d %H:%M:%S %z %Y")
Related
I am trying to convert a character string into a dateTime object in R
Sample data:
Following is the code that I am using for conversion
sample$Tweet_Timestamp <- lapply(sample$Tweet_Timestamp, function(x) as.POSIXct(strptime(x, "%a %b %d %H:%M:%S %z %Y")))
sample<-sample%>%unnest(Tweet_Timestamp)
The result I am getting is as follows:
Now in the result we can see that the date has converted from 18th Feb to 19th Feb. I cannot understand the reason why I am getting such result.Can someone help me decipher this?
as.POSIXct will automatically convert the date-time to the time zone of your local system. If you wish to retain the original time zone, you can do so by adding tz = "UTC" which is the defualt Universal Time.
For instance, the following code (using 1st row of your sample data):
as.POSIXct(strptime("Tue Feb 18 23:09:57 +0000 2014", "%a %b %d %H:%M:%S %z %Y", tz = "UTC"))
will produce the following output (without altering the time zone):
[1] "2014-02-18 23:09:57 UTC"
Can anybody tell me what is wrong with this command in R?
I literally have tried everything:
d0 <- "domingo 04 febrero 2018"
parse_date(d0, "%A %d %B %Y", locale = locale("es"))
When I execute the above code, I get an error that says
"invalid %%A auto parser"
I think that the problem is that the "%A" format specification is not defined in the parse_date function.
d0 <- "04 febrero 2018"
parse_date(d0, "%d %B %Y", locale = locale("es"))
[1] "2018-02-04"
The %A is a valid format per ISO8601 specification.
The actual problem is that parse_date (a function from readr package) doesnot provide support for all of ISO8601 specifications. Missing features include Week and Weekday specifications.
But we have an alternate solution in base r itself. Let me provide you few examples:
# %A is supported is base r
> as.character(Sys.Date(), "%A %d %B %Y")
[1] "Sunday 04 February 2018"
# Try to parse character string to date now
> as.POSIXct("Sunday 04 February 2018", format = "%A %d %B %Y")
[1] "2018-02-04 GMT"
# Lets execute the same code (converted to English) from OP
d0 <- "Sunday 04 February 2018"
as.POSIXct(d0, format = "%A %d %B %Y", tz = "GMT")
# Result :
[1] "2018-02-04 GMT"
I'm having some problems converting string vectors into date format. I have found a lot of information here and here but they haven't worked in my case (R 3.2.3).
> strptime("Fri Feb 05 14:10:10 +0000 2016",
format="%a %b %d %H:%M:%S %z %Y", tz="GMT")
[1] NA
I am trying to convert UTC format date format to required format using python. Simply I have the datetime in the format(Fri Dec 07 19:06:06 +0000 2012), I need to convert this into my format(2012-12-07 19:06:06:546 +0000)
Code:
created_at = "Fri Dec 07 19:06:06 +0000 2012"
d = datetime.strptime(created_at, '%a %b %d %H:%M:%S %z %Y')
date_object = d.strftime('%y-%m-%d %H:%M:%S')
result:
ValueError: 'z' is a bad directive in format '%a %b %d %H:%M:%S %z %Y'
The below link from python bugs says its fixed but i didn understand what is fixed and in which version i can use %z
http://bugs.python.org/issue6641
I am not able to use %z . Is there any other way to handle this??
Do it like that:
from datetime import datetime
TIMESTAMP = datetime.utcnow().strftime('%d/%m/%Y %H:%M:%S')
In a data.frame, I have a date time stamp in the form:
head(x$time)
[1] "Thu Oct 11 22:18:02 2012" "Thu Oct 11 22:50:15 2012" "Thu Oct 11 22:54:17 2012"
[4] "Thu Oct 11 22:43:13 2012" "Thu Oct 11 22:41:18 2012" "Thu Oct 11 22:15:19 2012"
Everytime I try to convert it with as.Date, lubridate, or zoo I get NAs or Errors.
What is the way to convert this time to a readable form?
I've tried:
Time<-strptime(x$time,format="&m/%d/%Y %H:$M")
x$minute<-parse_date_time(x$time)
x$minute<-mdy(x$time)
x$minute<-as.Date(x$time,"%m/%d/%Y %H:%M:%S")
x$minute<-as.time(x$time)
x$minute<-as.POSIXct(x$time,format="%H:%M")
x$minute<-minute(x$time)
What you really want is strptime(). Try something like:
strptime(x$time, "%a %b %d %H:%M:%S %Y")
As an example of the interesting things you can do with strptime(), consider the following:
thedate <- "I came to your house at 11:45 on January 21, 2012."
strptime(thedate, "I came to your house at %H:%M on %B %d, %Y.")
# [1] "2012-01-21 11:45:00"
Another option is to use lubridate::parse_date_time():
library(lubridate)
parse_date_time(x$time, "%a %b %d %H:%M:%S %Y")
Or more simply:
parse_date_time(x$time, "abdHMSY")
From the docs:
It differs from base::strptime() in two respects. First, it allows specification of the order in which the formats occur without the need to include separators and % prefix. Such a formating argument is refered to as "order". Second, it allows the user to specify several format-orders to handle heterogeneous date-time character representations.
The docs contain all the formats (the "abdHMSY" etc.) recognized by lubridate.